The list price on slacks is $22, and the list price on jumpers is $37. If Petit’s Clothing Store orders 30 pairs of slacks and 40 jumpers at a discount rate of 11%, what is the trade discount on the purchase?

9514 1404 393

Answer:

  21.5 cm

Step-by-step explanation:

Consider rectangle PQRS. Its area is ...

  A = LW

  90 cm² = PQ×QR = PQ×(20 cm)

  (90 cm²)/(20 cm) = PQ = 4.5 cm . . . . . . BC has this value, too

__

Consider the perimeter of ABCD. It is given by ...

  P = 2(L +W)

  52 cm = 2(AB +BC) . . . . substitute known value for P

  26 cm = AB +4.5 cm . . . . use known value for BC, divide by 2

  21.5 cm = AB

Hope this helps. Please mark brainliest

Answer: 20

let the number be x

1/4 x = 5

x=5*4

x=20

Answer:

x=20

Step-by-step explanation:

[tex]\frac{1}{4}x=5\\x=20[/tex]

divide [tex]\frac{1}{4}[/tex] on both sides, which gives you 20.

Answer:

Step-by-step explanation:

-1<x<3.   I hope it helpful!

Answer:

Cost of adult ticket = $12.5

Cost of child ticket = $7.5

Step-by-step explanation:

Given:

Cost of 6 adult ticket and 5 child ticket = $112.5

Cost of 8 adult ticket and 4 child ticket = $130

Find:

Equation and solution

Computation:

Assume;

Cost of adult ticket = a

Cost of child ticket = b

So,

6a + 5b = 112.5....eq1

8a + 4b = 130 ......eq2

Eq2 x 1.25

10a + 5b = 162.5 .....eq3

eq3 - eq1

4a  = 50

Cost of adult ticket = $12.5

8a + 4b = 130

8(12.5) + 4b = 130

Cost of child ticket = $7.5

Answer:

-3

Step-by-step explanation:

My knowledge ;D

Answer:

b.  [tex]\frac{7+\sqrt{61} }{6} ,\frac{7-\sqrt{61} }{6}[/tex]

Step-by-step explanation:

[tex]3x^{2} -1=7x[/tex]

Quadratic equations are suppose to be written as: [tex]ax^2+bx+c=0[/tex]

so the new quadratic equation for this problem will be: [tex]3x^{2} -1-7x=0[/tex]

Now rearrange the terms: [tex]3x^{2} -7x-1=0[/tex]

Then use the Quadratic Formula to Solve for the Quadratic Equation

Quadratic Formula = [tex]x=\frac{-b±}{} \frac{\sqrt{b^2-4ac} }{2a}[/tex]

Note: Ignore the A in the quadratic formula

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

[tex]3x^{2} -7x-1=0[/tex]

a = 3

b = -7

c = -1

[tex]x=-(-7)±\frac{\sqrt{(-7)^2-4(3)(-1)} }{2(3)}[/tex]

Evaluate The Exponent

[tex]x=\frac{7±\sqrt{(49)-4(3)(-1)} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{49+12} }{2(3)}[/tex]

Add The Numbers

[tex]x=\frac{7±\sqrt{61} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{61} }{6}[/tex]

Step-by-step explanation:

I am not critically certain but the ways you have jotted down your enquiry..

13 × (4×11)

13 × 44

=572 - 44= 528

528+13 =541

541 ×13=7033

Answer:

2, 3, 5, 8, 13 missing number is 18.

Answer

No solution

Step-by-step explanation:

4y + 2x = 18

3x + 6y = 26

You need either the x's or the y's to have the same coefficients.

let's line things up first.

4y + 2x = 18   (multiply by 3)

6y + 3x = 26  (multiply by 2)

to keep numbers relatively small we will multiply the top equation by 3 and the bottom equation by 2. Multiply all terms. This will make the coefficients equal.

12y + 6x = 54

12y + 6x = 52

So, if you subtract them from each other you get :

0 = 2

When this happens the solution set is : no solution

Answer:

Impossible

Step-by-step explanation:

Ok, so we first rearrange for convenience:

2x+4y=18

3x+6y=26

We multiply the two equations to eliminate x:

2x+4y=18 * -3

3x+6y=26 * 2

So:

-6x-12y=-54

6x+12y=52

And now we add the two equations:

0+0= -2

Try multiplying the two equations by any other number which will lead to them cancelling, (eg. -9, 6), still the equation will not work.

is 20 ÷ 5 the question? if so he was penalized 4 times. 5 × 4 is 20

C.(f-g)(x) = 4x^3 +5x²-7x-1

Step-by-step explanation:

Given information :

[tex]f(x) = 4 {x}^{3} + 5 {x}^{2} - 3x - 6 \\ g(x) = 4x - 5[/tex]

Find :

[tex](f - g)(x) = \\ (4 {x}^{3} + 5 {x}^{2} - 3x - 6) \\ - 4x -5[/tex]

Open bracket and Simplify

[tex]4 {x}^{3} + 5 {x}^{2} - 3x - 6 - 4x + 5 \\ 4 {x}^{3} + 5 {x}^{2} - 7x - 1[/tex]

Step-by-step explanation:

jnx-avkj-uup p.l.z join

Answer:

Profit = Selling price - Variable cost  

Formulas:  

F2 =SUMPRODUCT(B2:E2,$B$16:$E$16) copy to F2:F12, F14  

Optimal solution: The company should produce the following quantities (in pounds) of the four varieties of nuts.  

Whole = 1000  

Cluster = 500  

Crunch = 80  

Roasted = 200  

Total profit = $ 2913.20

Step-by-step explanation:

Step-by-step explanation:

the answer is already as simplified as it could be

Answer:

10

Step-by-step explanation:

26×3=78

78÷8=9.75

round up to 10 since you can't buy .75 of a pizza

Answer:

(a) A = 5 to 10 years old

B = 11 to 13 years old

C = adequate calcium intake

I = inadequate calcium intake.

(b) P(A) = 0.52, P(B) = 0.48, P(I|A) = 0.18, P(I|B) = 0.57.

Step-by-step explanation:

Complete question

Please find the attached image

(a) A = 5 to 10 years old

B = 11 to 13 years old

C = adequate calcium intake

I = inadequate calcium intake.

b) P(A) = 0.52, P(B) = 0.48, P(I|A) = 0.18, P(I|B) = 0.57.

PART A

Given:

f(x) = 0.69(1.03)x

To find:

If the price of the product is increasing or decreasing and by what percentage

Steps:

we know the formula to find the price of Product A per year, so

f(1) = 0.69 * 1.03 * 1

Price = $0.7107

f(2) = 0.69 * 1.03 * 2

Price = $1.4214

Here the Price of Product after 2 years is greater than the price of Product after one year. So the price of the product A is increasing.

Now to find percentage increase,

Percentage increase = [tex]\frac{FV-SV}{SV}*100[/tex]        (FV = final value, SV = starting value)

Percentage increase = [tex]\frac{1.4214 - 0.7107}{0.7107}*100[/tex]

Percentage increase = [tex]\frac{0.7107}{0.7107}*100[/tex]

Percentage increase = 100 %

Therefore, the percentage increase of Product A is 100%

PART B

Given:

Price of product B in 1st year = $10,100

Price of product B in 2nd year = $10,201

Price of product B in 3rd year = $10,303.01

Price of product B in 4th year = $10,406.04

To find:

Which product recorded a greater percentage change over the previous year

Steps:

We need to find the percentage change of Product B and Product A of each year. We know that the percentage change of product A is 100 % for each year, so we only need to calculate for product B

PC of product B from 1st to 2nd year = [tex]\frac{10,201-10,100}{10,100}*100[/tex]

                                                             = [tex]\frac{101}{10,100}*100[/tex]

                                                             = 0.01 * 100

                                                             = 1 %

PC of product B from 2nd to 3rd year = [tex]\frac{10,303.01-10,201}{10,201} *100[/tex]

                                                              = 1%

PC of product B from 3rd to 4th year [tex]=\frac{10,406.04-10,303.01}{10,303.01}*100[/tex]

                                                              ≈ 1%

So, percentage change of product B is 1% per year

Therefore, Product A has greater percentage change

Happy to help :)

If u need more help, feel free to ask

Answer:

A) The price of product A is increasing by 3% per year.

(B) The product A recorded a greater percentage change in price over the previous year.

Step-by-step explanation:

(A)

The function representing the price, in dollars, of product A after x years is:

FA(x)=0.69*(1.03)x

The function  FA(x)can be written as:

FA(x)=0.69*1+(0.03)x

The function FA(x) is similar to the exponential growth function, y=a(1+r)x .

Here r is the growth rate.

Thus, it can be said that the price of product A is increasing by 3% per year.

(B)

Consider the data of product B for the year 3 and 4.

The price of product B for year 3 and 4 are 10,303.01 and 10,406.04.

Compute the percent price change from year 3 to 4 as follows:

10406.04-10303.01/10303.01*100

which is 0.999%

~1%

The price of product B is increasing by 1% per year.

Thus, the product A recorded a greater percentage change in price over the previous year.

Yes, they are quite similar. the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation - based method (p < 0.0001)

P- value is the probability of obtaining a value of test statistic more extreme in the direction of alternative hypothesis than the observed one. In easy words if p -value < level of significance we reject H0 in favor of H1.

Here:

p-value < 0.0001 => we reject H0.

If the statistical software renders a p value of 0.000 it means that the value is very low, with many "0" before any other digit.

So the interpretation would be that the results are significant, same as in the case of other values below the selected threshold for significance.

Therefore, yes they are quite similar.

Learn more about balsa wood here:

https://brainly.com/question/33256379

#SPJ2

Incomplete Question:

Student researchers investigated whether balsa wood is less elastic after it has been immersed in water. They took 60 pieces of balsa wood and randomly assigned half to be immersed in water and the other half not to be. They measured the elasticity by seeing how far (in inches) the piece of wood would project a dime into the air.

Does the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation-based method (p < 0.0001)?

A. No, they are different.

B. Yes, they are quite similar.

Answer:

The answer is 5284.35 using the conversion

Answer:

5284.4

Explanation:

Tbh if you have a conversion table then see the conversion for what 1 oz is equal to in mL and do the math like that… •_•

Hope this helps, have a good day!

Answer:

15 mph

Step-by-step explanation

i used a calculator but correct me if im wrong pls

Answer:

Always a parabola or U Shaped

U shaped or by rotating U it will be like intersect symbol.. You can see it in attached file

Answer:

the y intercept is -4 (as a point it is (0,-4))

Step-by-step explanation:

Hi there!

We are given a slope (m) of 3 and the point (-1,-7).

We need to find the y intercept of the line that has the slope of 3 and passes through (-1,-7)

One way to find the y intercept is to write the equation of the line in slope-intercept form (y=mx+b, where m is the slope and b is the y intercept).

Since we are given the slope, we can immediately substitute it into the equation

Here it is so far:

y=3x+b

now we need to find b (the y intercept)

since the line passes through the point (-1,-7), we can use it to solve for b

substitute -1 as x and -7 as y into the equation

-7=3(-1)+b

multiply

-7=-3+b

add 3 to both sides

-4=b

so the y intercept is -4 . If you need it as a point, its (0,-4) as the y intercept is the point where the equation passes through the y axis, so the value of x is 0.

Hope this helps! :)

A1/ the difference of 3 and x divided by 7

A2/ 3e - 5

A3/ -1

A4/ g + (g - 8)

A5/ One half the difference between eight and a number y

I'm not sure, but I hope it helps :)

Answer:

562,354 votes

Step-by-step explanation:

1/11 of 6,185,894

=>1/11 x 6,185,894

=>562,354

Given:

In quadrilateral ABCD, angle B=90° , AB=9m, BC=40m, CD=15m, DA=28m.

To find:

The area of the quadrilateral ABCD.

Solution:

In quadrilateral ABCD, draw a diagonal AC.

Using Pythagoras theorem in triangle ABC, we get

[tex]AC^2=AB^2+BC^2[/tex]

[tex]AC^2=9^2+40^2[/tex]

[tex]AC^2=81+1600[/tex]

[tex]AC^2=1681[/tex]

Taking square root on both sides, we get

[tex]AC=\sqrt{1681}[/tex]

[tex]AC=41[/tex]

Area of the triangle ABC is:

[tex]A_1=\dfrac{1}{2}\times base\times height[/tex]

[tex]A_1=\dfrac{1}{2}\times BC\times AB[/tex]

[tex]A_1=\dfrac{1}{2}\times 40\times 9[/tex]

[tex]A_1=180[/tex]

So, the area of the triangle ABC is 180 square m.

According to the Heron's formula, the area of a triangle is

[tex]Area=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where,

[tex]s=\dfrac{a+b+c}{2}[/tex]

In triangle ACD,

[tex]s=\dfrac{28+15+41}{2}[/tex]

[tex]s=\dfrac{84}{2}[/tex]

[tex]s=42[/tex]

Using Heron's formula, the area of the triangle ACD, we get

[tex]A_2=\sqrt{42(42-28)(42-15)(42-41)}[/tex]

[tex]A_2=\sqrt{42(14)(27)(1)}[/tex]

[tex]A_2=\sqrt{15876}[/tex]

[tex]A_2=126[/tex]

Now, the area of the quadrilateral is the sum of area of the triangle ABC and triangle ACD.

[tex]A=A_1+A_2[/tex]

[tex]A=180+126[/tex]

[tex]A=306[/tex]

Therefore, the area of the quadrilateral ABCD is 306 square meter.

Answer:

first you have to find the number of ways 3 men can be chosen, then the number of ways 2 women can be chosen, and then you need to multiply these numbers together to get the number of ways because multiplication will show the total arrangements possibilities. use combination since order does not matter.

number ways for 2 out of 10 women total: 10 choose 2= 45

number of ways for 3 out of 9 men total: 9 choose 3= 84

84x45= 3780

3780 total ways

number of ways

Answer:

0.73 = 73% probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year.

Step-by-step explanation:

I am going to treat these events as Venn probabilities, considering that:

Event A: Lying to the teacher.

Event B: Male

48% of high school students would admit to lying at least once to a teacher during the past year and that 25% of students are male and would admit to lying at least once to a teacher during the past year

This means that [tex]P(A) = 0.48, P(A \cap B) = 0.25[/tex]

Assume that 50% of the students are male.

This means that [tex]P(B) = 0.5[/tex]

What is the probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year?

This is:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

Considering the values we were given:

[tex]P(A \cup B) = 0.48 + 0.5 - 0.25 = 0.73[/tex]

0.73 = 73% probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year.