The low-pressure fuel system is being discussed. Technician A says that the system must provide an adequate volume of fuel to the high-pressure fuel injection system. Technician B says that the system must provide fuel at a minimum pressure to the high-pressure fuel injection system. Which technician is correct

Answers

Answer 1

Answer:

Hence Both technicians A and B are correct that is Technician A says that the system must provide an adequate volume of fuel to the high-pressure fuel injection system. Technician B says that the system must provide fuel at a minimum pressure to the high-pressure fuel injection system are true.

Explanation:

The low-pressure fuel system contains the fuel filters; A fuel level sending unit/tank pick-up; A transfer pump. So from considering both technicians statements both are applicable.

Answer 2

Explanation:

MARK ME AS A BRIANLIEST .........
The Low-pressure Fuel System Is Being Discussed. Technician A Says That The System Must Provide An Adequate

Related Questions

9. SAFELY BACKING UP YOUR VEHICLE INCLUDES ALL OF THE FOLLOWING
EXCEPT:
A. Looking over your right shoulder as you back up
O B. Checking behind your vehicle before you get in
C. Tapping your horn before you back up

Answers

C, that is the most logical answer

Determine the dimensions for R if R = m V / (d^2 Q) where m is a mass, V is a velocity, d is a diameter, and the dimensions of Q are M/(LT).


No dimensions


M / (L T^2)


M L / T^2


M


L / T

Answers

Answer:

No dimension

Explanation:

The given equation is [tex]R = \dfrac{m \cdot V}{d^2 \cdot Q}[/tex], where;

m = Mass

V = Velocity

d = A diameter

The dimension of mass quantity = M

The dimension of the velocity quantity = L/T

The dimension of the dimeter quantity = L

The given dimension of Q = M/(L·T)

Therefore, we get;

[tex]The \ dimension \ of \ R = \dfrac{M \times L/T}{L^2 \times (M/LT)} = \dfrac{M \times L/T}{L \times M/T} = 1[/tex]

Therefore, R has no dimensions

George is replacing a burned out resistor in a circuit board. The board has a 10, a 20, and a 40 on resistor, all in parallel. When George has sided in the new component in the circuit is fixed, he checks his multimeter. What reading does he get?

Answers

Answer:

5.71 ohms

Explanation:

put it in the calculator

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