Answer:
The correct answer is - 29.45 / 100 x 25.6 = 7.5392 grams
Explanation:
It is given in the question that in 100 gms of CaSO4 there are 29.45 grams of Ca present and there is 25.6 gram of total CaSO4 sample present, So, to calculate the exact value of calcium in this given sample is:
mass of Ca = total amount of sample*percentage of calcium in sample /100
M of Ca =25.6*29.45/100
M of Ca = 7.5392 grams
Thus, the correct procedure is given by 29.45 / 100 x 25.6 = 7.5392 grams
What makes this inauguration different from the past?
Answer:
there's just a lot of drama around grumpy trumpy's StOlEN eLecTiOn which are all just fake claims. all his hardcore followers are brainwashed into believing anything he says, so people (especially people who are inside the capitol) fear that trump's followers might incite violence AGAIN even after they broke into the Capitol on the 6th.
That's why they have the National Guard and thousands of people to keep the building secure during Biden's Inauguration.
hope this helps!
what is the volume of the rock? if the water rose from 50L to 70mL
water H2O is a molecule made of oxygen and hydrogen. The bonds that hold water molecules together are due to share ___, and known as covalent bonds.
Why is there no sound in outer space? PLEASE HELP IF YOU WANT BRAINLEIST AND A LIKE ON URE COMMENT!
A. The speed of sound is too slow for space.
B. There is no medium in which it can travel.
C. There are too many other noises.
D. There is only echolocation in space.
Answer:
B
Explanation:
What carpet Burns in a deficiency of O2 a mixture of CO and CO2 forms.Carbon Burns in excess O2 to form only CO2 and CO Burns in excess O2 to form only CO2. Calculate ΔH for C(graphite +1/2O2) →CO(g).
Answer:
Explanation:
From the combustion of carbon, the reactions occurring in limited oxygen conditions are:
[tex]C(graphite) + \dfrac{1}{2}O_{2(g)} \to CO_{(g)}[/tex]
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex]
If it occurs in excess, then any leftover CO changes to CO2. i.e.
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)}[/tex] ---- (1)
[tex]CO_{(g)} + \dfrac{1}{2}O_{(g)} \to CO_{2(g)}[/tex] ----- (2)
From (1), the enthalpy change is:
[tex]\Delta H_{rxn1} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{f C(graphite)}+ \Delta H^0_{fCO_2(g)}[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol -(0+0)[/tex]
[tex]\Delta H_{rxn1} =-393.5 \ kJ/mol[/tex]
From (2), the enthalpy change is:
[tex]\Delta_{rxn2} = \Delta H^0_{fCO_2(g)} - ( \Delta H^0_{fCO(g)} + \dfrac{1}{2} \Delta H^0_{fO_2(g)})[/tex]
[tex]\Delta_{rxn2} = -393.5 \ kJ/mol -(-110.5 + \dfrac{1}{2}(0))[/tex]
[tex]\Delta_{rxn2} = -283.0 \ kJ/mol[/tex]
Subtracting (2) from (1), we get:
[tex]C(graphite) + O_{2(g)} \to CO_{2(g)} \ \ \ \Delta H_{rxn} = -393.5 \ kJ/mol}[/tex]
[tex]CO_{(g)} + \dfrac{1}{2} O_2(g) \to CO_{2(g)}} \ \ \ \Delta H _{rxn2} = -283.0 \ kJ/mol[/tex]
[tex]C(graphite) + O_{2(g)} \to CO (g) + \dfrac{1}{2}O_{2(g)} \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
[tex]C(graphite) + \dfrac{1}{2} O_{2(g)} \to CO (g) \ \ \ \Delta H_{rxn} = -110.5 \ kJ/mol[/tex]
The enthalpy change ΔH of the reaction = -110.5 kJ/mol
If one force on an object is 5 N upward and the other is 10 N downward what is the objects motion?
To solve this we must be knowing each and every concept related to force. Therefore, the objects motion will be towards downward with a force of 5 N.
What is force?A force is an outside entity that has the power to alter a body's state of rest or motion. It has a direction and a magnitude. The point where forces are applied is determined by the the force's direction as well as the application of the force.
Newton and dyne units are used to measure the force exerted on an item. When using the centimeter kilogram second system of units, force is measured in dynes (CGS unit). In the common international system of units, it is denoted by the letter Newton (N) (SI unit).
upward force=5 N
downward force= 10 N
total force acting on body=downward force-upward force
= 10 N - 5 N
=5 N downward force
The objects motion will be towards downward with a force of 5 N.
Therefore, the objects motion will be towards downward with a force of 5 N.
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what element is in group 13, period 4
Answer:
Gallium
Explanation:
Answer:
Gallium
Explanation:
Which of the following would be most likely to experience strong intermolecular forces?
A. Molecules that contain no electrically charged regions.
B. Molecules that contain atoms of oxygen.
C. Molecules that are composed of solely ions.
D. Molecules that have both negatively and positively charged parts.
Answer:
The correct answer is D
Explanation:
Just took quiz
What is the systematic name of the following compound?
Li2S
Answer:
the systematic name is called Lithium sulfide.
An inorganic substance composed of the elements lithium (Li) and sulfur (S) is known as lithium sulfide [tex](Li_2S)[/tex].
It is a substance that solidifies in the shape of a crystal. Lithium ions in lithium sulfide have a positive charge, while sulfide ions have a negative charge. The chemical lithium sulfide is important in many industries. It is often employed in the synthesis of various lithium compounds, the manufacture of lithium batteries, and the manufacture of ceramics. Due to their high energy density, lithium batteries are often employed in portable electronics and electric vehicles.
Lithium sulfide is an ionic compound that has a high melting point in terms of physical characteristics. Although it is insoluble in water, many organic solvents can help dissolve it.
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The order is Solumedrol 3 mg/kg for a child weighing 20 kg. Solumedrol is available as 125 mg/2ml. How many ml will be given
Answer:
0.96mL must be given
Explanation:
First, we need to obtain the mass of Solumedrol required for the child by using its mass. Then, with this mass we can solve the volume that must be administered:
Mass of solumedrol required:
20kg * (3mg / kg) = 60mg of solumedrol are required.
Volume given:
60mg Solumedrol * (2mL / 125mg) =
0.96mL must be given
1.7 x 10 cm= significant figures
Answer:
its 2
Explanation:
PLEASE HELP FREE BRAINLIEST DUE AT 1:40 PM EST
A block with a volume of 20 cm3 has a density of 5 g/cm3. The block is cut into two pieces. One piece has a volume of 15 cm3, and the other piece has a volume of 5 cm3. What are the densities of the two pieces?
Answer:
wouldnt they still have the same density?
Explanation:
for example, the density of iron is 7.874 g/cm^3 no matter how big the piece is. I hope this helps.
Prokaryotic is an example of a/an-
A:tissue
B:cell type
C:organ
D:organism
Answer:
B. Cell Type
Explanation:
that is the answer i believe
Answer:
option b- cell type
Explanation:
almost absolutely positive
(1) Phosphorus silicon is a semi-conductor
When Silicone is altered with Phosphorus, 4 of its electrons form covalent bonding and the 5th electron becomes delocalized and thus it increases electrical conduction
Answer:
blue blah blue blah
Explanation:
What is a molecule contains the genetic instructions for the development and functioning of all living organisms found in the nucleus of a cell
what is the empirical formula for a compound that is 40% S, and 59.9% O?
Answer:
O3S
Sulfur Trioxide
Explanation:
How many atoms are in .938 moles of CO2?
Answer: 1.695x10^24 atoms
Explanation: 0.938 moles CO2 = 0.938xavogadro number molecules CO2, so number of atoms = 3x0.938x6.02214076x10^23 = 1.695x10^24
Write ashort note on the
first battle of
of panipat
Answer:
The First Battle of Panipat was fought between the invading forces of Babur and the Lodi Empire, which took place on 21 April 1526 in North India. It marked the beginning of the Mughal Empire. This was one of the earliest battles involving gunpowderfirearms and field artillery.
For you to write an essay on Panipat first bring into view
Introduction body conclusionThen write a brief story using this format.
How to write a short note on the first battle of Panipat?In writing this essay, you must consider the structure and content of the essay or short note
For structure kick off with
Introduction body conclusionIn conclusion, for the content of the short note you can consider this,
Panipat fought its first battle on 21 April 1526 in the North of India, This battle was fought between the invading powers of Babur and the Lodi Empire.
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How many milliliters of 60% carbonic acid must be mixed with how many milliliters of 15% carbonic acid to make 650 milliliters of a 38% carbonic acid solution
Answer:
348.9 mL of the 60% solution and 251.1 mL of the 15% solution.
Explanation:
First, we calculate how many mililiters of pure carbonic acid are there in 650 mL of a 38% solution:
650 mL * 38/100 = 247 mLThen we can express the sum of both initial solutions as:
1) x * 60/100 + y * 15/100 = 247for the volume of carbonic acid; and
2) x + y = 600 mLFor the volume of the solutions.
We now have a system of two equations and two unknowns (x is the volume of the 60% solution and y is the volume of the 15% solution).
We express x in terms of y in equation 2):
x = 600 - yAnd replace x in equation 1):
(600 - y) * 60/100 + y * 15/100 = 247360 - 0.6y + 0.15y = 247-0.45y = -113y = 251. 1 mLFinally we calculate x using equation 2):
x + 251.1 = 600x = 348.9 mLdetermine the molar mass for ammonia (NH3) in g/mol.
Answer:
17.031 g/mol
Explanation:
Equilibrium occurs in what type of reactions?
A. Catalytic
B. Irreversible
C. Reversible
D. Combustion
Answer:
B. Irreversible
Explanation:
Answer: C Reversible
Explanation:
Founder's Education Quiz
Which word describes the amount of matter an object contains?
altitude
density
mass
pressure
Answer:
Mass
Explanation:
Answered this question multiple times and got it correct
Hope this helped!
Stay safe!
(1132 CHCH2CH = CH2
12. Give the complete IUPAC name for each of the following compounds:
(a) (CH3)2CHF
(b) CH3CHCICHCICH3
(C)
CH3CHCH;
CH2CH3
(d) CH3 CH2 CH = CHCHZ
(e)
CH3CH2CH2CHBCH2CH3
CH2CH=CH2
Answer:
Ok:
Explanation:
a) 2-fluoropropane
b) 2,3 dichlorobutane
c) pent-2-ene or 2 pentene (I assume the semicolon was a typo)
d) Same as c (I assume Z is a typo too)
e) non-1-ene or 1-nonene (I assume the B is a 2)
A patient is prescribed 100mg/day of antibiotic for 2 weeks. The antibiotic is available in vials that contain 20mg/vial of the drug. How many vials are necessary for the entire treatment?
What is the molecular formula for a compound with a molar mass of 42.08g/mol and an empirical formula of ch2
Answer:
[tex]C_3H_6[/tex]
Explanation:
Hello!
In this case, since the empirical formula is the smallest representation of the molecular formula, it is known that the times in which the empirical formula is into the molecular formula is a whole number and is computed by dividing the molar mass of the molecular formula by that of the empirical formula as shown below:
[tex]\frac{42.08g/mol}{12.01+1.01x2}= \frac{42.08g/mol}{14.03g/mol}=3[/tex]
Thus, the molecular formula times the empirical formula by 3 to obtain:
[tex]C_3H_6[/tex]
Regards!
What element corresponds to period 5, group 2
Answer:
Strontium is the second element placed in the 5th period
Hope this will help you if not so advance sorry :)
I need a answer ASAP
Answer:
3.2 millions years oldExplanation:
i hope it helps :)
How would a long period without sunlight affect the food web?
It would cause consumers to consume more food.
It would have no effect on the food web.
It would stop decomposers from breaking down matter.
It would stop producers from producing food.
Answer: it would stop producers from producing food.
Explanation: why? Without the action of the producers to turn sunlight into food, the producers would die, and consumers that rely on them would lose their food source and die too.
Answer:
It would stop producers from producing food
Explanation:
Producers would die, and if producers died, consumers would die too.
Hope this helps
Which of these is not a property of minerals?
A) Clevage
B) Fracture
C) Color
D) Smell
Give the IUPAC name for each compound.
Answer:
a. 1-fluoro-3,3,4-trimethyl-pentane.
b. 1-iodo-3-ethyl-2-methyl-hexane.
c. 1,3-dichloro-5-dimethyl-hexane.
d. 1-bromo-3-methyl-cyclopentane.
Explanation:
Hello!
In this case, according to the IUPAC rules for the listed alkyl halides, we first need to name the halogens (considering periodic order) then alkyl radicals and finally the parent chain; thus, the names are given below:
a. 1-fluoro-3,3,4-trimethyl-pentane.
b. 1-iodo-3-ethyl-2-methyl-hexane.
c. 1,3-dichloro-5-dimethyl-hexane.
d. 1-bromo-3-methyl-cyclopentane.
e. 5-chloro-1-bromo-1,1,5-trimethyl-pentane (radicals are not clear).
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