The noble-gas notation for the element indium, (In, atomic #49) is:
A.
?
[Kr]5p?
B.
?
[KrJ5524d105p
C.
?
[Kr]5s25d 105p1
D. ?
[Kr]5524f1450 105p1

Answers

Answer 1

Answer:[tex][Kr]4d^{10}5s^25p^1[/tex]

Explanation:

The element Indium with atomic number 49 will have 49 protons and 49 electrons in it.

Electronic configuration represents the total number of electrons that a neutral element contains. We add all the superscripts to know the number of electrons in an atom. The electrons are filled according to Afbau's rule in order of increasing energies and the nearest noble gas is Krypton with 36 electrons.

The electronic configuration in terms of noble gas configuration is:  

[tex]In:49:[Kr]4d^{10}5s^25p^1[/tex]

Answer 2

The noble-gas notation for the element indium is [Kr} 4d¹⁰5s²5p¹. The correct option is B.  [Kr] 5s2 4d10 5p1

From the question,

We are to write the electron configuration of the element Indium, using the appropriate noble gas notation.

The noble gas that comes before Indium (In) is Krypton (Kr). Therefore, the noble gas that will be used in the notation is Krypton.

Indium has an atomic number of 49 while Krypton has an atomic number of 36. This means we will fill in 13 more electrons.

The electron configuration for the element indium using the noble-gas notation is

[Kr} 4d¹⁰5s²5p¹

Hence, the noble-gas notation for the element indium is [Kr} 4d¹⁰5s²5p¹. The correct option is B.  [Kr] 5s2 4d10 5p1

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Related Questions

A 25 cm sample of dilute sulfuric acid contains 0.025 moles of the acid.
What is the hydrogen ion concentration in the solution?
A. 0.2 mol/dm3
B. 0.05 mol/dm3
C. 1.00 mol/dm3
D. 2.00 mol/dm3

Answers

Answer:B. 0.05 mol/dm3

Explanation:

The hydrogen ion concentration in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

We'll begin by calculating the molarity of the solution.

Volume = 25 cm³ = 25 / 1000 = 0.025 dm3

Mole of H₂SO₄ = 0.025 mol

Molarity of H₂SO₄ =?

Molarity = mole / Volume

Molarity of H₂SO₄ = 0.025 / 0.025

Molarity of H₂SO₄ = 1 mol/dm³

Finally, we shall determine the concentration of Hydrogen ion in the solution.

H₂SO₄(aq) —> 2H⁺(aq) + SO₄²¯(aq)

From the balanced equation above,

1 mole of H₂SO₄ contains 2 moles of H⁺.

Therefore,

1 mol/dm³ H₂SO₄ will also contain 2 mol/dm³ H⁺.

Thus, the concentration of Hydrogen ion in the solution is 2 mol/dm³

The correct answer to the question is Option D. 2 mol/dm³

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