The nth term of a sequence is 3n2 - n + 10 where n is a positive integer. Which term in the sequence is equal to 54?
Answers
Answer:
4th term
Step-by-step explanation:
Equate the nth term formula to 54 and solve for n
3n² - n + 10 = 54 ( subtract 54 from both sides )
3n² - n - 44 = 0
Consider the factors of the product of the n² term and the constant term which sum to give the coefficient of the n- term.
product = 3 × - 44 = - 132 and sum = - 1
The factors are - 12 and + 11
Use these factors to split the n- term
3n² - 12n + 11n - 44 = 0 ( factor the first/second and third/fourth terms )
3n(n - 4) + 11(n - 4) = 0 ← factor out (n - 4) from each term
(n - 4)(3n + 11) = 0
Equate each factor to zero and solve for n
n - 4 = 0 ⇒ n = 4
3n + 11 = 0 ⇒ 3n = - 11 ⇒ n = - [tex]\frac{11}{3}[/tex]
Since n > 0 then n = 4
The 4th term of the sequence is 54.
What is a sequence ?A sequence is a set of numbers with a constant difference or a constant ratio or it have a certain relation with the next and previous term.
According to the given question the nth term of a sequence is 3n² - n + 10.
We have to determine which term is equal to 54 or the value of and it must be an integer.
So, 3n² - n + 10 = 54.
3n² - n - 44 = 0.
3n² - 12n + 11n - 44 = 0.
3n(n-4) +11(n-4) = 0.
(3n+11) = 0 OR (n-4) = 0.
n = - 11/3 OR n = 4. ( given the term no. is a positive integer ).
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Answers
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