Answer:
Option A. 107 mL
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 150 mL
Initial pressure (P₁) = 500 mmHg
Final pressure (P₂) = 700 mmHg
Temperature = constant
Final volume (V₂) =?
The final volume of the gas can be obtained by using the Boyle's law equation as shown below:
P₁V₁ = P₂V₂
500 × 150 = 700 × V₂
75000 = 700 × V₂
Divide both side by 700
V₂ = 75000 / 700
V₂ = 107 mL
Therefore, the final volume of the gas is 107 mL.
Consider the following equilibrium:
HC2O4- + HSO4- <—> H2C2O4 + SO42-
The order of Bronsted-Lowry acids and bases in the reaction is_________ .
Answer:
See explanation
Explanation:
According to Bronsted-Lowry definition of acids/bases, an acid is a proton donor while a base is a proton acceptor.
Hence, in a reaction, the species that donate protons are strong acids while the species that accept protons are strong bases.
Hence, HSO4- is a stronger acid than H2C2O4 and SO42- is a weaker base than HC2O4-
Note that the conjugate base of a strong acid is a weak base and vice versa.
Convert the following with the correct number of significant figures:
1.78kg to ug
O 1.78 x 108 mg
O 1.8 x 10' ug
Ο 1.78 με
Ο 0.000000178 με
O 1.78 x 10 g
Answer:
1.78 × 10⁹ μg
Explanation:
We have to convert 1.78 kg to μg.
Step 1: Convert 1.78 kilograms to grams
We will use the conversion factor 1 kg = 10³ g.
1.78 kg × 10³ g/1 kg = 1.78 × 10³ g
Step 2: Convert 1.78 × 10³ grams to micrograms
We will use the conversion factor 1 g = 10⁶ μg.
1.78 × 10³ g × 10⁶ μg/1 g = 1.78 × 10⁹ μg
How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing
100 mg/mL?
a. 25
b. 30
c. 50
d. 60
Answer:
How many 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing
100 mg/mL?
a. 25
b. 30
c.50
d. 60
Explanation:
if mali po I'm so sorry
About 60 tablets of 250 mg tablets of metronidazole are needed to make 150 mL of suspension containing 100 mg/mL.
To calculate the number of tablets needed, we can use the following formula:
Number of tablets = (Desired total mass of metronidazole) / (Mass of one tablet)
The desired total mass of metronidazole in the suspension is given as 100 mg/mL × 150 mL = 15000 mg.
Since each tablet contains 250 mg of metronidazole, we can calculate the number of tablets as:
Number of tablets = 15000 mg / 250 mg = 60 tablets
Therefore, the correct answer is d. 60 tablets.
Learn more about metronidazole here:
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#SPJ 2
What is the name of the functional group that is attached to this hydrocarbon?
H
H
alkyl halide
alcohol
carbonyl
ketone
Answer:
ketone
Explanation:
Compound A has the formula C8H8. It reacts rapidly with acidic KMnO4 but reacts with only 1 equivalent of H2 over a palladium catalyst. On hydrogenation under conditions that reduce aromatic rings, A reacts with 4 equivalents of H2, and hydrocarbon B, C8H16, is produced. The reaction of A with KMnO4 gives CO2 and a carboxylic acid C, C7H6O2.
Required:
Draw the structure of compound B below.
Answer:
C8H16 (Ethylcyclohexane).
Explanation:
From the given information:
Compound A is an alkene because it interacts with 1 unit of hydrogen across a palladium catalyst.
Also, we are given another hint that:
Compound A needs 4 equivalence of H2 to hydrogenate under circumstances that decrease aromatic rings, indicating that it is a phenyl substituted alkene.
Compound A with formula C8H8 reacts instantly with KMnO4 to produce CO2, as well as carboxylic acid, points out that Compound acts as a terminal alkene.
Therefore, we can opine that compound A is a terminal phenyl substituted alkene whose formula = C8H8 (Styrene)
The diagrammatic expression of the compound can be seen below.
However, in the presence of the palladium catalyst, the reduction of Compound A with 4 units of hydrogen produces Compound B: C8H16 (Ethylcyclohexane).
The decomposition of SO2Cl2 is first order in SO2Cl2 and has a rate constant of 1.42 x 10-4
s
-1 at a
certain temperature.
a. If the reaction started with 75.6 g of SO2Cl2 dissolved in 1.25 L, what would be the
concentration of SO2Cl2 after 3.00 hours?
b. A student claims that the half life of SO2Cl2 changes as the reaction progresses. Do you agree
or disagree with the students claim? Explain your answer. Note: The experiment was
preformed at a constant temperature.
Answer:
a. 13.0g/L is the concentration of SO2Cl2 after 3.00h
b. FALSE
Explanation:
The first order reaction follows the equation:
ln[SO2Cl2] = -kt + ln[SO2Cl2]₀
Where [] is the concentration after time t, k is rate constant = 1.42x10⁻⁴s⁻¹
[]₀ is initial concentration:
a. []₀ = 75.6g/1.25L = 60.48g/L
t in seconds: 3h * (3600s / 1h) = 10800s
Replacing:
ln[SO2Cl2] = -1.42x10⁻⁴s⁻¹*10800s + ln[60.48g/L]₀
ln[SO2Cl2] = 2.5687
[SO2Cl2] = 13.0g/L is the concentration of SO2Cl2 after 3.00h
b. The rate constant of a reaction remains constant if temeprature remains constant.
A sample of carbon tetrachloride (CCl4) contains 3 moles of the substance. How many atoms are there in the sample?
Answer:
1.806 × 10²⁴ atoms
Explanation:
To obtain the number of atoms a substance contain, we have to multiply the number of moles in that substance (n) by Avogadro's number, which is 6.02 × 10²³.
According to this question, a sample of carbon tetrachloride (CCl4) contains 3 moles of the substance. The number of atoms in CCl4 is calculated thus:
number of atoms = 3 × 6.02 × 10²³
number of atoms = 18.06 × 10²³
number of atoms = 1.806 × 10²⁴ atoms.
The information code that an organism inherits can best be referred to as its -
O A genotype
B. territory
C. species
D. kingdom
Answer:
it will be no.A genotype
C8H18+O2=CO2+H2O. Balance this equation and identify the number H2O molecules formed when 6 molecules of C8H18 react with 75 molecules of oxygen
Answer: 54 molecules of water will be formed in the reaction.
Explanation:
A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.
For the given unbalanced chemical equation, the balanced equation follows:
[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]
We are given:
Molecules of [tex]C_8H_{18}[/tex] = 6
Molecules of [tex]O_2[/tex] = 75
By the stoichiometry of the reaction:
If 2 molecules of [tex]C_8H_{18}[/tex] produces 18 molecules of water
So, 6 molecules of [tex]C_8H_{18}[/tex] will produce = [tex]\frac{18}{2}\times 6=54[/tex] molecules of water
Hence, 54 molecules of water will be formed in the reaction.
3. Which of the following can be physically separated?
Answer:
mixture
Explanation:
an example of one is a salad you can separate the ingredients
Which type of scientist would most likely investigate how to synthesize
materials found in plants?
O A. A geologist
O B. A biologist
O C. A chemist
OD. A physicist
Answer:
Biologist
Explanation:
Not sure, but I think that is right
What happens when you increase the pressure on the following
reaction
2X(g) + 3Y(g) --> 5Z(g) + heat
Answer:
When pressure increases, there is no effect on the reaction because volume is constant.
The volume of a gas is 200.0 mL and the pressure is 2.00 atm. When the volume of the gas is 10 mL what is the pressure if the temperature remains the same?
Answer:
40 atm
Explanation:
Boyles law states that the pressure exerted on a gas is inversely proportional to the volume it occupies provided that the temperature is held constant. It is given by:
P ∝ 1/V
PV = constant
P₁V₁ = P₂V₂
Given that V₁ = initial volume = 200 ml, P₁ = initial pressure = 2 atm, V₂ = final volume = 10 ml, P₂ = final pressure. Hence:
2 atm * 200 ml = P₂ * 10 ml
P₂ = (2 atm * 200 ml) / 10 ml
P₂ = 40 atm
A 250ml sample of sir at 373.15k is warmed at 473.15 at constant pressure. What is the volume of the air sample at the new temperature
Answer:
317 mL.
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 250 mL
Initial temperature (T₁) = 373.15 K
Final temperature (T₂) = 473.15 K
Pressure = Constant
Final volume (V₂) =?
The final volume of the air sample can be obtained by using the Charles' law equation as illustrated below:
V₁/T₁ = V₂/T₂
250 / 373.15 = V₂ / 473.15
Cross multiply
373.15 × V₂ = 250 × 473.15
373.15 × V₂ = 118287.5
Divide both side by 373.15
V₂ = 118287.5 / 373.15
V₂ = 317 mL
Therefore, the final volume of the air sample is 317 mL
A buffer solution contains 0.475 M nitrous acid and 0.302 M sodium nitrite . If 0.0224 moles of potassium hydroxide are added to 150 mL of this buffer, what is the pH of the resulting solution
Answer: The pH of the resulting solution will be 3.001
Explanation:
Molarity is calculated by using the equation:
[tex]\text{Molarity}=\frac{\text{Moles}}{\text{Volume}}[/tex] ......(1)
We are given:
Moles of NaOH = 0.0224 moles
Molarity of nitrous acid = 0.475 M
Molarity of sodium nitrite = 0.302 M
Volume of solution = 150 mL = 0.150 L (Conversion factor: 1 L = 1000 mL)
Putting values in equation 1, we get:
[tex]\text{Moles of nitrous acid}=(0.475mol/L\times 0.150L)=0.07125mol[/tex]
[tex]\text{Moles of sodium nitrite}=(0.302mol/L\times 0.150L)=0.0453mol[/tex]
The chemical equation for the reaction of nitrous acid and NaOH follows:
[tex]HNO_2+NaOH\rightleftharpoons NaNO_2+H_2O[/tex]
I: 0.07125 0.0224 0.0453
C: -0.0224 -0.0224 +0.0224
E: 0.04885 - 0.0677
The power of the acid dissociation constant is the negative logarithm of the acid dissociation constant. The equation used is:
[tex]pK_a=-\log K_a[/tex] ......(2)
We know:
[tex]K_a[/tex] for nitrous acid = [tex]7.2\times 10^{-4}[/tex]
Using equation 2:
[tex]pK_a=-\log (7.2\times 10^{-4})=3.143[/tex]
To calculate the pH of the acidic buffer, the equation for Henderson-Hasselbalch is used:
[tex]pH=pK_a+ \log \frac{\text{[conjugate base]}}{\text{[acid]}}[/tex] .......(3)
Given values:
[tex][NaNO_2]=\frac{0.0677}{0.150}[/tex]
[tex][HNO_2]=\frac{0.04885}{0.150}[/tex]
[tex]pK_a=3.143[/tex]
Putting values in equation 3. we get:
[tex]pH=3.143-\log \frac{(0.0677/0.150)}{(0.04885/0.150)}\\\\pH=3.143-0.142\\\\pH=3.001[/tex]
Hence, the pH of the resulting solution will be 3.001
171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?
The complete question is as follows: 171 g of sucrose ( MW of 342, melting point 186 oC, boiling point very high, and vapor pressure is negligible) is dissolved in one liter of water at 25 oC. At 25 oC the vapor pressure of water is 24 mmHg. Which value is closest to the vapor pressure (VP) of this solution at 25 oC?
a. 16mm Hg
b. 24mm Hg
c. 20mm Hg
d. 12mm Hg
Answer: The vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.
Explanation:
Given: Mass of sucrose = 171 g
Mass of water = 1 L = 1000 g
Vapor pressure of water = 24 mm Hg
As moles is the mass of substance divided by its molar mass. Hence, moles of water (molar mass = 18.02 g) is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1000 g}{18.02 g/mol}\\= 55.49 mol[/tex]
Similarly, moles of sucrose (molar mass = 342 g/mol) is as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{171 g}{342 g/mol}\\= 0.5 mol[/tex]
Total moles = 55.49 + 0.5 mol = 55.99 mol
Mole fraction of water is as follows.
[tex]Mole fraction = \frac{moles of water}{total moles}\\= \frac{55.49}{55.99}\\= 0.99[/tex]
Formula used to calculate vapor pressure of the solution is as follows.
[tex]P_{i} = P^{o}_{i} \times \chi_{i}[/tex]
where,
[tex]P_{i}[/tex] = vapor pressure of component i over the solution
[tex]P^{o}_{i}[/tex] = vapor pressure of pure component i
[tex]\chi_{i}[/tex] = mole fraction of i
Substitute the values into above formula to calculate vapor pressure of water as follows.
[tex]P_{i} = P^{o}_{i} \times \chi_{i}\\= 24 mm Hg \times 0.99\\= 23.76 \\or 24 mm Hg\\[/tex]
Thus, we can conclude that the vapor pressure (VP) of this solution at [tex]25^{o}C[/tex] is closest to the value 24 mm Hg.
19. What is the molarity of a
solution that contains 6 liters
of solution and 2 moles of
solute?
a. 8 M
b. 0.3 mol/L
c. 12 mol/L
d. 3M
Answer:
b. 0.3 mol/L is the closest.
Explanation:
A molar solution of a substance contains 1 mole per liter of solution
So if we have 2 moles in 6 liters the there are 2/6 =1/3 of a mole in 1 liter.
Suppose that you add 29.2 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.78 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
Answer:
Suppose that you add 29.2 g of an unknown molecular compound to 0.250 kg of benzene, which has a K f of 5.12 oC/m. With the added solute, you find that there is a freezing point depression of 2.78 oC compared to pure benzene. What is the molar mass (in g/mol) of the unknown compound
Explanation:
The mass of nonvolatile solute added is ---- 29.2g
The mass of solvent benzene is ---- 0.250kg = 250g
The Kf value of benzene is ---- 5.12^oC/m.
Depression in the freezing point of the solution is --- 2.78^oC.
What is the molar mass of the unknown solute?
[tex]The depression in freezing point = Kf * molality of the solution\\molality of the solution = \frac{mass of solute}{molar mass of solute}*\frac{1}{mass of solvent in kg}[/tex]
Substitute the given values in this formula to get the molar mass of unknown solvent:
[tex]molality=\frac{29.2g}{M} * \frac{1}{0.250kg} \\depression in freezing point:\\2.78^oC=5.12^oC/m * \frac{29.2g}{M} * \frac{1}{0.250kg} \\\\=>M=5.12^oC/m * \frac{29.2g}{2.78^oC} * \frac{1}{0.250g} \\\\\\=>M=215.1g/mol[/tex]
Hence, the molar mass of unknown solute is --- 215g/mol.
Discuss the any two applications of Beer’s law with suitable justification.
Answer: It's used in chemistry to measure the concentration of chemical solutions.
Explanation:
Beer's Law is used in chemistry to measure the concentration of chemical solutions, to analyze oxidation, and to measure polymer degradation.
The law also describes the attenuation of radiation through the Earth's atmosphere
Write the molecular formula for the compound that exhibits a molecular ion at M+ = 112.0499. Assume that C, H, N, and O might be present, and use the exact masses below:
Exact mass of carbon = 12.000
Exact mass of hydrogen = 1.0078
Exact mass of nitrogen = 14.003
Exact mass of oxygen = 15.995
The order of atoms should be carbon, then hydrogen, then the others in alphabetical order.
Answer:
C₆H₁₀NO
Explanation:
In order to arrive at a molecular formula we have to make some assumptions and they are
Assuming there is one ( 1 ) N and one ( 1 ) O that is present in the said molecule
Total mass = 29.998
next step: subtract the total mass from 112.0499 = 82.501
next : assume the presence of 6 carbon atoms in said molecule
Total mass = 6 * 12 = 72
Mass of Hydrogens = 82.501 - 72 = 10.501
∴ number of hydrogens = 10.501 / 1.0078 ≈ 10
Hence Total mass = 29.998 + 82.501 ≈ 112.0499
Finally Molecular formula = C₆H₁₀NO
Boric acid, B(OH)3, acts as an acid in water, but does not do so via ionization of a proton from boric acid. Use a balanced chemical equation to show why boric acid may be described as an acid in water.
Answer:
B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺
Explanation:
Let's consider Arrhenius acid-base theory:
An acid is a substance that in aqueous media releases H⁺.A base is a substance that in aqueous media releases OH⁻.Boric acid, B(OH)₃ reacts with water according to the following equation.
B(OH)₃ + H₂O = B(OH)₄⁻ + H⁺
As we can see, boric acid releases H⁺ in aqueous media. Thus, it is an acid.
Determine the electron geometry, molecular geometry, and idealized bond angles for each of the following molecules. CF4CF4 NF3NF3 OF2OF2 H2SH2S In which cases do you expect deviations from the idealized bond angle
Answer:
CF4
Molecular geometry- tetrahedral
Electron geometry- tetrahedral
NF3
-molecular geometry - trigonal pyramidal
Electron geometry - tetrahedral
OF2
Molecular geometry - bent
Molecular geometry - tetrahedral
H2S
Molecular geometry- bent
Electron geometry - tetrahedral
Explanation:
According to Valence Shell Electron Pair Repulsion Theory, the shape of a molecule depends on the number of electron pairs on the valence shell of the central atom in the molecule.
For all the compounds listed, the central atom has four points of electron density. This correspond to a tetrahedra electron pair geometry. The presence of lone pairs on the central atom of OF2,NF3 and H2S accounts for the departure of the observed molecular geometry from the geometry and idealized bond angle predicted on the basis of the VSEPR theory.
Hydrogen bonds within liquid water are attractions between protons and hydroxide ions. are dipole-dipole attractions. are ion-induced dipole attractions. are attractions between protons and oxygen nuclei. are attractions between two hydrogen atoms.
Answer:
true because the bonds cannot be broken down
On another planet, the isotopes of titanium have the given natural abundances.
Isotope Abundance Mass (u)
46Ti 77.100% 45.95263
48Ti 17.100% 47.94795
50Ti 5.800% 49.94479
What is the average atomic mass of titanium on that planet?
Answer:
46.525 u
Explanation:
From the question given above, the following data were obtained:
Isotope A (⁴⁶Ti)
Abundance (A%) = 77.100%
Mass of A = 45.95263 u
Isotope B (⁴⁸Ti):
Abundance (B%) = 17.100%
Mass of B = 47.94795 u
Isotope C (⁵⁰Ti):
Abundance (C%) = 5.800%
Mass of C = 49.94479 u
Average atomic mass =?
The average atomic mass of titanium can be obtained as follow:
Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] + [(Mass of C × C%)/100]
= [(45.95263 × 77.1)/100] + [(47.94795 × 17.1)/100] + [(49.94479 × 5.8)/100]
= 35.429 + 8.199 + 2.897
= 46.525 u
Therefore, the average atomic mass of titanium is 46.525 u
Which of the following has the highest pH?
A. 0.01 M HCI
B. 0.1 M HCI
C. 1 M HCI
D. 0.001 M HCI
Answer:
D
Explanation:
pH=-log(x)
x=0.001M,pH=3
x=0.01M,pH=2
x=0.1M,pH=1
x=1M,pH=0
Highest pH is for option D
Answer:
D.
Explanation:
The highest pH is D because
0.01 M HCL => 2
0.1 M HCL => 1
1 M HCL => 0
0.001 M HCL => 3
so the answer is D.
Elements beyond iron are not formed by a-particle capture. It is believed they are formed by neutron capture. Once the nucleus gets enough neutrons, one neutron converts to an electron and a proton. Show how you can make zinc from copper by neutron capture.
Answer: The equation is [tex]_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e[/tex]
Explanation:
Neutron capture is a process where a neutron is converted into a proton and an electron. The released particle is known as beta particle and it carries a charge of -1 units and has a mass of 0 units. It is also known as an electron. The general equation for this process is:
[tex]_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+ _{-1}^0\e[/tex]
The nuclear equation for the formation of zinc via neutron capture of copper follows:
[tex]_{29}^{63}\textrm{Cu}\rightarrow _{30}^{63}\textrm{Zn}+_{-1}^0e[/tex]
Please select the word from the list that best fits the definition
Include skin, the respiratory system, the circulatory system, and inflammation
A. antibody
B. antigen
C.Natural Defences
D.active immunity
Answer:
I choose D option because may be it's correct
I believe it is c
Explanation:
because if u think about it and also do some research you would see that the circulatory system is a strong part of your body which can help u through natural defences if this sounds weird it's all in research but if it ain't c dont blame me for ruining your life- lol but yeah I think its c
THE DIAMETER OF A TAMBOURINE IS 10 INCHES.FIND THE AREA OF ITS SURFACE.USE π=3.14.
1.What is ask in the problem?
2.What are the given facts?
3.What operation to be used?
4.What is the number sentence
5.What is the answer?
Answer:
22/7 × [tex]10^{2}[/tex]
Explanation:
The area of a circle can be found out using π[tex]r^{2}[/tex]. Since r is the radius so if they multiply, they will give you an area of a square then multiply by 22/7 since it is a circle.
The surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.
Area of the TambourineA Tambourine has circular shape, and the area of the Tambourine can be determined by applying formula for area of a circle as shown below;
A = πr²
where;
r is the radius of the circleRadius of the Tambouriner = ¹/₂D
r = ¹/₂ x 10 in
r = 5 in
A = π(5)²
A = 25π in²
A = 78.54 in²
Thus, the surface area of the Tambourine at the given diameter of 10 inches is determined as 78.54 square inches.
Learn more about surface area here: https://brainly.com/question/76387
A 575.4575.4 mL sample of carbon dioxide was heated to 377377 K. If the volume of the carbon dioxide sample at 377377 K is 824.7824.7 mL, what was its temperature at 575.4575.4 mL
Answer:
263 K
Explanation:
Assuming ideal behaviour and constant pressure, we can solve this problem by using Charles' law, which states that at constant pressure:
T₁V₂=T₂V₁In this case:
T₁ = ?V₂ = 824.7 mLT₂ = 377 KV₁ = 575.45 mLWe input the data:
T₁ * 824.7 mL = 377 K * 575.45 mLAnd solve for T₁:
T₁ = 263 KHow does the law of conservation of mass relate to the number of atoms of each element that are present before a reaction vs. the number of atoms of each element that are present after a chemical reaction?
