the principles which underlie balancing chemical equations include

Answer:

a. The gluing together of any two atoms that don't have full outer shells.

b. The separation of electrons from the main atom.

c. The joining of atoms by a shared interested of valence electrons which ends up

creating new substances.

d. The melting of substances to form new solids.

Explanation:

a. The gluing together of any two atoms that don't have full outer shells refers to chemical bonding, which can occur through different mechanisms such as covalent bonding, ionic bonding, and metallic bonding.

b. The separation of electrons from the main atom refers to ionization, where an atom or molecule loses or gains one or more electrons and becomes charged.

c. The joining of atoms by a shared interest of valence electrons which ends up creating new substances refers to covalent bonding, where atoms share electrons to form a stable molecule.

d. The melting of substances to form new solids does not necessarily create new substances; it is a physical change where a solid is transformed into a liquid due to an increase in temperature. Upon cooling, the liquid may solidify again, either forming the original substance or a different solid phase.

The complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows: 2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq)

It is important to write the complete ionic equation when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed. The reaction of lithium sulfide with copper (II) nitrate is a double displacement reaction. Lithium sulfide reacts with copper (II) nitrate to form copper sulfide and lithium nitrate.

The balanced chemical equation for the reaction is given as follows:Li2S(aq) + Cu(NO3)2(aq) → CuS(s) + 2 LiNO3(aq)The complete ionic equation can be written by representing all the ions in the aqueous solutions as dissociated ions.

Thus, the complete ionic equation for the reaction that occurs when aqueous solutions of lithium sulfide and copper (II) nitrate are mixed is as follows:2 Li+(aq) + S2-(aq) + Cu2+(aq) + 2 NO3-(aq) → CuS(s) + 2 Li+(aq) + 2 NO3-(aq.

)In the above equation, the lithium and nitrate ions do not take part in the reaction and are present in the same form in the reactant and product side. Hence, they are called spectator ions.

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The main difference between a saturated solution and a supersaturated solution is concentration of the solute.

A saturated solution contains the maximum amount of solute that can be dissolved under the given conditions, while a supersaturated solution contains more solute than is normally possible. A saturated solution contains the maximum amount of solute that can be dissolved in a given solvent at a specific temperature and pressure. In a saturated solution, the concentration of solute is in equilibrium with the concentration of undissolved solute, which is in dynamic equilibrium with the dissolved solute. A supersaturated solution, on the other hand, is a solution that contains more solute than is normally possible to dissolve in the solvent under the given conditions.

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A spontaneous reaction under standard conditions is indicated by the value of K being greater than 1. Thus, the answer to the given question is option C, K = 2.2 x 10².

Standard conditions- Standard conditions are a set of environmental conditions that are considered to be the standard conditions for conducting an experiment. They serve as a reference point to compare the effects of varying environmental conditions on the properties of a substance or the results of an experiment.

Standard conditions in chemistry are considered to be a temperature of 298K (25°C), a pressure of 1 atm (101.3 kPa), and a concentration of 1 mol/L (for solutions).

Spontaneous reaction- A spontaneous reaction is one that proceeds without any external force or intervention. That is, a spontaneous reaction proceeds without the need for energy input from an external source. In other words, it is an exothermic reaction where the products are more stable than the reactants.

The Gibbs free energy change of a spontaneous reaction is negative. The sign of ΔG indicates the spontaneity of a reaction. A negative value indicates that the reaction is spontaneous, whereas a positive value indicates that the reaction is non-spontaneous. The value of ΔG° is used to determine the spontaneity of a reaction under standard conditions.

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The difference in electrochemical potential between two electrodes of an electrochemical cell is called as the cell potential.

The potential difference or voltage that exists between two electrodes in an electrochemical cell when no current is flowing through the cell is called the cell potential. Cell potential, also known as electromotive force (emf), is a measure of the driving force that drives a chemical reaction in an electrochemical cell forward.

The potential difference between the anode and cathode of an electrochemical cell is a quantitative measurement of the cell's capacity to generate electrical energy. The cell potential is usually measured in volts (V), and its sign is determined by the direction in which the electrons flow through the cell. When electrons flow spontaneously from the anode to the cathode, the cell potential is positive, whereas if electrons are forced to flow from the cathode to the anode, the cell potential is negative.

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The correct answer is that none of the substances listed actually speeds up the absorption of alcohol.

As the rate of alcohol absorption depends on various factors such as the amount of alcohol consumed, the rate of gastric emptying, and the presence of food in the stomach. However, carbonated water and starchy foods may help slow down the absorption of alcohol by delaying the emptying of the stomach, which can result in a slower increase in blood alcohol concentration. Meat products may also help in slowing down the absorption of alcohol due to their high protein content, which can reduce the rate of gastric emptying. Plain water, on the other hand, may actually dilute the alcohol content in the stomach but will not speed up its absorption. It is important to note that while these substances may help to delay the absorption of alcohol, they do not reduce its effects on the body or prevent intoxication. The only effective way to reduce the effects of alcohol is to consume it in moderation or to avoid it altogether. It is also important to never drink and drive, and to seek medical attention if one experiences severe symptoms of alcohol consumption.

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The balloon that is one size larger than the others serves to symbolise the area in a molecule inhabited by lone pairs of electrons, signifying unshared electron pairs in a particular region.

The Lewis structure is a chemical model that depicts how atoms and valence electrons are arranged in a molecule. The atoms are represented by symbols, and the valence electrons, which are the electrons at the highest energy level, are shown as dots or lines. In organic chemistry, the bigger balloon often designates a region of a molecule where electrons are not shared with any other atoms or groups. The structure and reactivity of the molecule are impacted by this region, which is referred to as a lone pair. The wider balloon makes it easier to see where these unshared electron pairs are located and how they affect the molecule's overall structure and behaviour.

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The electron transport chain (ETC) is an essential part of cellular respiration, which is a series of molecules that transfer electrons from one molecule to another used by cells to convert nutrients into energy.

This starts with the oxidation of molecules such as glucose, which releases electrons that are then transferred to a series of electron carriers in the ETC. The electron carriers are molecules that hold the electrons and can transfer them to other molecules which is known as redox reactions. As the electrons move through the ETC, they release energy which is used to form a proton gradient that is then used to drive the synthesis of ATP, the energy currency of the cell. The ETC is an essential part of cellular respiration as it is the process responsible for generating the energy necessary for cells to function.

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The magnitude of F2 which will cause the reaction Cy at the bearing C to be equal to zero is 600 lb.

Let's assume the direction of F2 is x-axis and direction of Cy is y-axis. Apply the force balance equation along x-axis:

F2 = F1 + F3F3 = F2 - F1

As we know, the force along the y-axis is zero. So, there is no force balance equation along y-axis. Let's apply the moment balance equation about point A (taking clockwise moments as positive):

F1 × 4 + F2 × 6 = F3 × 2F1 × 4 + F2 × 6 = (F2 - F1) × 2

Now substitute F1 = 300 lb in the above equation.

300 × 4 + F2 × 6 = (F2 - 300) × 2300 × 4 + 6F2 = 2F2 - 600F2 = 600 lb

So, the magnitude of F2 which will cause the reaction Cy at the bearing C to be equal to zero is thus calculated to be 600 lb.

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The correct option is 'A' 12.5 mL of the minimum volume of 2.00 M NaOH needed to reach a pH of 10.00.

To reach a pH of 10.00, what is the minimum volume of 2.00 M NaOH needed to titrate 50.0 mL of a 1.00 M solution of a diprotic acid [tex]H_2A[/tex], where [tex]Ka_1[/tex] = 1.0 × [tex]10^-^6[/tex] and [tex]Ka_2[/tex] = [tex]10^-^1^0[/tex].

The reaction can be written as:

[tex]H_2A[/tex](aq) + 2 NaOH(aq) → [tex]Na_2A[/tex](aq) + 2 [tex]H_2O[/tex]

(l)In this diprotic acid, there are two stages of dissociation:

Therefore, the dissociation constant can be calculated as follows:

Ka1 = [H+][HA-] / [[tex]H_2A[/tex]]

     = 1.0 × [tex]10^-^6[/tex]

Ka2 = [H+][[tex]A^2^-[/tex]] / [HA-]

      = [tex]10^-^1^0[/tex]

The number of moles of the [tex]H_2A[/tex] solution = 50.0 mL * 1.00 M = 0.050 moles.

Since NaOH is a strong base, the number of moles of OH- ions in 1.00 M solution = 2 * 1.00 = 2.00 M.

The total number of moles of OH- ions that can react with 0.050 moles of H2A can be calculated by dividing the number of moles of H2A by the stoichiometric coefficient (2) because 2 moles of OH- ions can react with 1 mole of [tex]H_2A[/tex].

0.050 / 2 = 0.025 moles of OH- ions, which are available to react.

To react completely, 0.025 moles of OH- ions require 0.025 * 50 = 1.25 mL of 2.00 M NaOH.

Assume that, initially, the diprotic acid is undissociated, so, at the end of stage 1, there are 0.025 moles of [tex]H_2A[/tex] and 0.025 moles of H+ ions.

Using the Ka1 value, it can be calculated that:

[H+][HA-] / [[tex]H_2A[/tex]] = 1.0 × [tex]10^-^6[/tex]

[H+][0.025] / [0.025] = 1.0 × [tex]10^-^6[/tex]

[H+] = [tex]10^-^8[/tex]

The number of moles of NaOH required to react with [tex]H^+[/tex] ions can be calculated by dividing the concentration of NaOH by the volume of the solution.

2.00 M NaOH * V = [tex]10^-^8[/tex] moles of [tex]H^+[/tex] ions

V = 5.00 × [tex]10^-^9[/tex]mL

This is the minimum amount of NaOH required to react with [tex]H^+[/tex] ions.

So, the total amount of NaOH required to reach a pH of 10.00 is 1.25 mL + 5.00 × [tex]10^-^9[/tex] mL = 1.25 mL

Therefore, the minimum volume of 2.00 M NaOH required to reach a pH of 10.00 is 12.5 mL.

[tex]H^+[/tex]

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The best material for insulation in this case would be Styrofoam. Styrofoam is lightweight, strong, and an excellent thermal insulator. It is composed of tiny bubbles of air that are suspended in a matrix of plastic. The air trapped inside the bubbles acts as a thermal barrier, keeping heat out or in, depending on the application.

Its lightweight nature makes it easier to manipulate, while its strength gives it the durability needed to keep a drink hot or cold. Its insulation properties also make it the perfect material for the student's insulated drink cup.

Styrofoam can be cut and shaped easily, making it a great material for use in drink cups. The material is also easy to clean and resistant to water and other liquids, which makes it ideal for frequent use. Additionally, Styrofoam is both affordable and widely available, making it an ideal choice for the student's project.

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The molecule which would have the highest boiling point is 2-methylhexane. Thus, the correct option will be D.

The boiling point is the temperature at which the vapor pressure of a liquid is equal to the external pressure. The boiling point of a liquid is a measure of its vapor pressure. The higher the boiling point, the higher the vapor pressure of the liquid, and the more heat is required to vaporize it.

The boiling point of a substance is affected by the strength and types of intermolecular forces. The stronger the intermolecular forces, the higher the boiling point. 2-methylhexane has highest boiling point because it has the highest number of carbons and branches, which contribute to its strong intermolecular forces that lead to a higher boiling point.

Therefore, the correct option is D.

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For the first unknown concentration with an absorbance of 1.72, the concentration will be, c = 1.72/(ɛ × b). For the second unknown concentration with an absorbance of 0.75, the concentration will be: c = 0.75/(ɛ × b).

Beer lambert's law states that the concentration of a solution is directly proportional to the absorbance of a solution. Mathematically, Beer's Law: A = εlc

where, A is absorbance, ε is the molar absorptivity, l is the path length, and c is the concentration.

We can rewrite the equation as, c = A / εl

where, c is the concentration, A is the absorbance, ε is the molar absorptivity, and l is the path length.

We have two absorbance values, which we will use to determine the concentration of the unknowns. Let's substitute the given values into the equation to determine the concentration of the first unknown.

where, c₁ = A₁ / εlc₁ = 1.72 / εl (1)

Now, let's substitute the second absorbance value to determine the concentration of the second unknown.

c₂ = A₂ / εlc₂ = 0.75 / εl(2)

The concentrations of the unknowns are c₁ and c₂, which we have expressed in terms of the concentration of the solution. The total concentration of the solution is not provided. Thus, we cannot determine the concentration of the unknown solutions.

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When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.

The amount of energy required to raise a substance's temperature is measured in terms of specific heat. It is the amount of energy (measured in joules) required to increase a substance's temperature by one degree Celsius per gram.

We must first determine the water sample's original temperature. The formula is as follows:

Q = mcΔT

Inputting the values provided yields:

700.00 cal = 25.0 g x 1.00 cal/g °C x (50°C - 22.0°C)

When we simplify this equation, we obtain:

ΔT = 700.00 cal / (25.0 g x 1.00 cal/g °C) = 28.0°C

Therefore, the initial temperature of the water sample is 22.0°C + 28.0°C = 50.0°C.

Inputting the values provided yields:

1.00 kcal = 25.0 g x 1.00 cal/g °C x (T - 50.0°C)

When we simplify this equation, we obtain:

T - 50.0°C = 1.00 kcal / (25.0 g x 1.00 cal/g °C) = 40.0°C

Therefore, When 1.00 kcal of heat is applied, the water sample's final temperature is T = 50.0°C + 40.0°C = 90.0°C.

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The green metal carbonate is decomposed according to the given equation: MCO₃(s) → MO(s) + CO₂(g)

What is molar mass of MCO₃?

The number of moles of CO₂(g) produced can be used to determine the number of moles of the green metal carbonate (MCO₃) that decomposed.0.222 g of CO₂ (g) represents 1 mol of CO₂ (g), since its molar mass is 44 g/mol.

Therefore,1 mol of MCO₃ will produce 1 mol of CO₂ (g) in the reaction. So, 0.222 g of CO₂ (g) corresponds to 1 mol of MCO₃.

Hence, the number of moles of MCO₃ is:

moles of MCO₃= mass/Molar

mass= 0.598 g/Molar mass of MCO₃

The molar mass of MCO₃ can be calculated using the following:

mass percent of MCO₃ = [(mass of M)/(molar mass of M)] × 100%molar mass of MCO₃ = mass of MCO₃/moles of MCO₃

By substituting the value of moles of MCO₃ and the mass of MCO₃ into the equation above, the molar mass of MCO₃ can be calculated.

molar mass of MCO₃= (mass of MCO₃) / (moles of MCO₃)

Finally, to determine the molar mass of metal M, subtract the molar mass of CO3 from the molar mass of MCO₃.

MCO₃ = 12.011 + 3(15.999) + M(55.845)

= 181.76 + 55.845MM

= 55.845 - 60.01MM

= -4.165

The molar mass of the metal M is 4.165 g/mol.

To summarize, the metal M is sodium (Na) and its molar mass is 4.165 g/mol.

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The reaction in the gas mixture will proceed non-spontaneously in the forward direction when the standard free energy change (∆G°) is positive or zero.

In chemical reactions, the term spontaneity refers to whether the reaction proceeds on its own or requires an input of energy to occur. When ∆G° is negative, a reaction is said to be spontaneous in the forward direction, meaning it occurs naturally without any external input of energy. When ∆G° is positive or zero, on the other hand, the reaction proceeds nonspontaneously in the forward direction.

In other words, the reaction requires energy input to proceed. The free energy change (∆G) of a reaction is related to its standard free energy change (∆G°) through the equation:

∆G = ∆G° + RT ln(Q)

where, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

If Q = 1, the reaction is at equilibrium and ∆G = ∆G°. If Q < 1, the reaction proceeds spontaneously in the forward direction (∆G < 0), and if Q > 1, the reaction proceeds spontaneously in the reverse direction (∆G > 0).

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The correct options for the radiations that would produce electrons with some kinetic energy in an experiment of the photoelectric effect are given below: Infrared, Ultraviolet, X-ray, Gamma ray, and Photoelectric effect.

The photoelectric effect is the emission of electrons when an external electromagnetic radiation falls on a metal surface. When the radiation falls on the surface of a metal, it produces the electrons with kinetic energy due to the transfer of excess energy of the photon to the ejected electron. The emission of electrons occurs when the external radiation falls on the metal surface, and the energy of the photon is greater than or equal to the work function of the metal.

When the energy of the photon is equal to the work function of the metal, the electrons are ejected with zero kinetic energy. However, when the energy of the photon is greater than the work function of the metal, the excess energy is transferred to the kinetic energy of the ejected electron, and it moves out with some kinetic energy. Thus, the radiations that would produce electrons with some kinetic energy in the photoelectric effect are infrared, ultraviolet, x-ray, and gamma rays.

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Answer:

(A).Liquid water has a specific heat of 4.184J/g.k

(B)Volume = 39,420 LSo, kilograms= 44.7 kg

Explanation:

(a) The specific heat at constant volume of nitrogen (N2) gas is 20.8 J/K.mol. Compare it with the specific heat of liquid water.Liquid water has a specific heat of 4.184 J/g.K

(b) For the same amount of heat, we would be able to warm 44.7 kg of 20.0 °C air to 30.0 °C. Air has a molar mass of 28.97 g/mol. We can use the ideal gas law to determine the volume of 44.7 kg of air at 20.0 °C and 1.00 atm pressure.

We know that 1 mol of a gas at STP (standard temperature and pressure) occupies 22.4 L. Since air is 100% N2, its molar mass is 28.0 g/mol. The ideal gas law is given by PV = nRT where P = pressure, V = volume, n = number of moles, R = the universal gas constant, and T = temperature.

Substituting values, we have:

PV = nRTV = nRT/PAt

20.0 °C and 1.00 atm, T = 293 K and P = 1.00 atm.

Therefore, we have:

n = mass/molar mass = 44.7 kg / (28.97 g/mol) = 1543.8 mol

R = 0.082 L.atm/K.mol

Substituting these values into the equation, we have:

V = (1543.8 mol)(0.082 L.atm/K.mol)(293 K) / (1.00 atm)

V = 39,420 LSo, 44.7 kg of 20.0 °C air occupies a volume of 39,420 L at 20.0 °C and 1.00 atm pressure.

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Actually, when atomic radius grows, electronegativity often decreases.

The capacity of an atom to draw electrons into a chemical connection is known as electronegativity. The separation between the nucleus and the farthest electrons grows with increasing atomic radius. As a result, the nucleus's attraction to the electrons is reduced, making it more challenging for the atom to draw electrons to itself. The electronegativity values of bigger atoms are therefore often lower than those of smaller ones. Despite this general tendency, there are certain outliers since electronegativity also depends on other elements including nuclear charge and electron configuration. For instance, the rising nuclear charge in halogens causes the electronegativity to rise as the atomic radius falls.

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The amount of potassium chloride that will dissolve in 50 grams of water at 50°C depends on the solubility of the salt at that temperature. The solubility of potassium chloride in water at 50°C is approximately 42 grams per 100 grams of water. Therefore, about 21 grams of potassium chloride will dissolve in 50 grams of water at 50°C.

Adding either hydrochloric acid or acetic acid to a solution of sodium acetate can produce a buffer. The chemical equation for the reaction between sodium acetate and hydrochloric acid is NaAc + HCl → NaCl + HAc, and for the reaction between sodium acetate and acetic acid is NaAc + HAc → NaCl + AcOH.
Sodium acetate can be used to make buffer solutions. A buffer is a solution that resists changes in pH when an acid or base is added. The two most important components of a buffer are a weak acid and its corresponding conjugate base. Acetic acid and sodium acetate are two such components that can be used to create a buffer. As a result, the answer to the question is acetic acid. Hence, option (c) acetic acid or hydrochloric acid is correct. Therefore, adding acetic acid to a sodium acetate solution would produce a buffer. The buffer solution can withstand pH changes when hydrochloric acid is added. Since hydrochloric acid is a strong acid, it ionizes completely in the solution and lowers the pH significantly. Acetic acid is a weak acid, on the other hand. It ionizes partially in solution, resulting in a small decrease in pH. When hydrochloric acid is added to the acetic acid-sodium acetate buffer, the additional hydrogen ions react with the buffer's acetate ion to form more acetic acid, which consumes the hydrogen ions and prevents a drastic decrease in pH. This is how a buffer works.

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As sodium acetate is added to the solution, the sodium ions (Na+) will replace the hydrogen ions (H+) in the equation. This causes a shift in the equilibrium as the number of hydrogen ions (H+) decreases, while the number of acetate ions (CH3COO-) increases.

Sodium acetate is an ionic compound composed of Na⁺ and CH₃COO⁻ ions.

It dissociates in water to create these ions, which are then available to affect the dissociation of acetic acid.

The equilibrium of acetic acid dissociation is influenced by the addition of sodium acetate.

Acid dissociation equilibria are influenced by salt addition (usually sodium salts), particularly when the acid is weak.

This is due to the fact that the anion of the salt reacts with hydrogen ions from the acid's dissociation.

This decreases the concentration of hydrogen ions in the solution, causing the reaction to shift towards more dissociation.

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As the molar mass calculated is 24.90 g/mol, hence the gas is most likely to be NO.

The ratio between mass and the amount of substance of any sample is called molar mass.

To determine whether the gas is NO, NO2, or N2O5, we need to calculate the molar mass of the gas and compare it to the molar masses of these three possible gases.

n = PV/RT

Given, P = 760.0 mmHg, V = 250.0 mL = 0.2500 L, T = 17.00°C + 273.15 = 290.15 K, and R = 0.08206 L atm/mol K.

So, n = (760.0 mmHg)(0.2500 L)/(0.08206 L atm/mol K)(290.15 K) = 0.01003 mol

M = m/n

Given m = 0.2500 g.

M = 0.2500 g/0.01003 mol = 24.90 g/mol

Comparing this molar mass to the molar masses of NO (30.01 g/mol), NO2 (46.01 g/mol), and N2O5 (108.01 g/mol), we see that the gas is most likely NO.

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Note: The question given on the portal is incomplete. Here is the complete question.

Question: A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. Is the gas NO, NO2, or N2O5?

The phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out is known as Shielding.

Electrons in an atom are negatively charged particles, and they are attracted to the positively charged nucleus. However, the outer electrons of an atom are also repelled by the inner electrons that are closer to the nucleus. This repulsion is due to the negative charges of the electrons, and it partially cancels out the attraction of the nucleus for the outer electrons.

Shielding is the phenomenon in which electrons that are closer to the nucleus slightly repel those that are farther out. This makes it possible for electrons in higher energy levels to be farther from the nucleus, so they are less strongly attracted and easier to remove.

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The volume of H₂ gas produced from 1.30 g of Mg in excess HCl is 0.0019 L.

The balanced equation for the reaction of magnesium metal with HCl is:

Mg + 2HCl → MgCl₂ + H₂

The molar mass of Mg is 24.31 g/mol.

The mass of Mg that reacted = 1.30 g

The moles of Mg that reacted = 1.30 g ÷ 24.31 g/mol = 0.0535 mol

According to the balanced equation, 1 mol of Mg reacts with 1 mol of H₂

Therefore, 0.0535 mol of Mg will produce 0.0535 mol of H₂.

Since, the volume of gas produced is proportional to the number of moles of the gas, we can use the ideal gas equation to find the volume of H₂

PV = nRT

Where, P = 720 torr = 720/760 atm (1 atm = 760 torr)

T = 34 + 273 = 307 K

R = 0.0821 L·atm/mol·K

V = n × 0.0821 L·atm/mol·K × 307 K/ 720 torr = 0.0535 mol/ 720 torr × 25.2047 L/molK =0.0019 L

At 720 torr and 34 °C, 0.0535 mol of hydrogen occupies a volume of 0.0019 L.

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The potassium tert-butoxide is final product of the reaction is (CH3)3COH.

Why potassium tert-butoxide is (CH3)3COH?

The product for the given reaction is (CH3)3COH.

Reaction: (CH3)3CBr + KOtBu →(CH3)3COH + KBr

Potassium tert-butoxide (KOtBu) is a strong base that can deprotonate hydrogen from (CH3)3COH to form (CH3)3CO-.On the other hand,

(CH3)3CBr is a tertiary halide that can undergo an E2 reaction.

E2 is the abbreviation for bimolecular elimination reactions,

which involve the abstraction of a proton from the adjacent carbon and the removal of the halide anion.

The hydrogen that is abstracted by KOtBu can only come from the carbon that is adjacent to the bromine in (CH3)3CBr, according to Saytzeff's rule, because this is the carbon with the least number of hydrogens.

As a result, an alkene intermediate will be formed.

The KBr salt will be the by-product.

The alkene intermediate, however, is not present in the end product because it is a reactive molecule and quickly reacts with any available hydrogen.

The hydrogen is provided by the KOtBu base.

As a result, the final product of the reaction is (CH3)3COH.

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When benzoquinone is treated with excess butadiene, the products obtained are 2,5-dimethylcyclohexadiene-1,4-dione and cyclohexene.

Benzoquinone is also known as 1,4-benzoquinone or cyclohexa-2,5-diene-1,4-dione, is a colorless organic compound. The presence of two carbonyl groups in its structure provides it its characteristic quinone chemistry.

Butadiene, also known as 1,3-butadiene, is a conjugated diene. The reaction between benzoquinone and butadiene is called a Diels-Alder reaction.

The Diels-Alder reaction is a conjugate addition reaction that joins a diene and a dienophile to create a new six-membered ring. The most important characteristic of the Diels-Alder reaction is its stereospecificity. This reaction occurs between a cyclic diene and an alkene or alkyne dienophile.

The products obtained when benzoquinone is treated with excess butadiene are:2,5-dimethylcyclohexadiene-1,4-dioneCyclohexeneThe reaction proceeds with the dienophile (benzoquinone) being attacked by the diene (butadiene) in the Diels-Alder reaction to produce a cyclic adduct. The product is 2,5-dimethylcyclohexadiene-1,4-dione. Cyclohexene is formed as a byproduct of the reaction.

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After 12 minutes, the amount of 2N-71 remaining would be 25 grams. This is because the half-life of 2N-71 is 2.4 minutes, meaning that after 2.4 minutes, half of the initial amount (50 grams) will remain. After 12 minutes, half of the remaining 25 grams will have decayed, leaving 25 grams.

The initial amount of 2n-71 is 50 g, and the half-life of 2n-71 is 2.4 minutes. We need to determine how many grams of 2n-71 would be left after 12 minutes. During radioactive decay, the amount of a radioactive substance decreases exponentially over time. The formula for determining the amount remaining of a radioactive substance after time t is:A = A₀(1/2)^(t/h)Where, A₀ = the initial amount of the substance,A = the amount of the substance after time t,h = the half-life of the substance, and t = time elapsedPlugging the given values in the formula, we get:A = 50(1/2)^(12/2.4)A = 50(1/2)^5A = 50(1/32)A = 1.5625Therefore, the amount of 2n-71 left after 12 minutes is 1.5625 g.

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The statement that best identify the main idea of the article are, A and C

A) Fingerprints are still the most accurate way to identify a person.

C) Biometric features are slightly different in everyone.

The article seems to focus on biometric technology and the different ways it can be used for identification, security, and health purposes.

It explains that fingerprints remain the most accurate way to identify a person, but also discusses the unique features of other biometric identifiers such as facial recognition and blood vessels.

Lastly, the article emphasizes the importance of recognizing that biometric features are unique to each individual.

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