The probability that Jessica is on time for a given class is 64 percent. If there are 53 classes during the semester, what is the best estimate of the number of times out of 53 that Jessica is on time to class? Round your answer to the nearest integer.
Provide your answer below:

Answers

Answer 1

Using the principle of probability, the estimated number of times Jessica will be on time is 34.

Given the Parameters :

Probability of being on time, p = 64% = 0.64

Total number of classes, n = 53

The best estimate for the number of times Jessica will be on time can be calculated thus :

Mean = np

Hence, we have ;

Mean number of times = (0.64 × 53)

Mean number of times = 33.92

Hence, the estimated number of times Jessica will be on time is 34.

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Related Questions

A toy factory makes toys that are sold for $10 a piece. The factory has 40 workers, and they each produce 25 toys per day. The factory is open 5 days a week. What is the total value of toys the factory produces in a day?

Answers

Answer:

The total value of toys the factory produces in a day is $10,000.

Step-by-step explanation:

One Toy = $10

Workers = 40

Toys Made By Each Worker Per Day = 25

The factory makes 1,000 toys per day and 5,000 toys per week. Each toy has a value of $10 so the value of toys in one day would add up to $10,000. The toy factory would also make $50,000 a week.

in which country has involved in world war

Answers

Answer:

The following countries were involved in the world war

Germany

Austria-Hungary

Bulgaria

Ottoman Empire (the Central Powers)

These countries fought against

Great Britain

France

Russia

Italy

Romania

Japan

United States (the Allied Powers).

four and three sevents plus six and one fith.

Answers

372/35 or 10.62857143
You could find a common denominator or use a calculator

If a course starts September 2022,and last for three years, what year would it end. ​

Answers

Answer:

im pretty sure its 2025

Answer:

2025

Step-by-step explanation:

A continuous random variable X has probability density function X. Show how its
moment generating function can be used to determine the variance of this random
variable.

Answers

The moment generating function is defined by

[tex]M_X(t) = \mathbb E[e^{tX}][/tex]

Recall the power series expansion for the exponential function:

[tex]\displaystyle \sum_{n=0}^\infty \frac{x^n}{n!} = 1 + x + \frac{x^2}2 + \frac{x^3}6 + \cdots[/tex]

Then by extension, the MGF could be similarly written as

[tex]\displaystyle M_X(t) = \mathbb E \left[1 + Xt + \frac{(Xt)^2}2 + \frac{(Xt)^3}6 + \cdots\right][/tex]

There's a certain theorem (due to Fubini, in case you're interested in learning more about it) that let's us exchange the order of integration (recall the definition of expectation for continuous random variables) and summation, so that

[tex]\displaystyle M_X(t) = \mathbb E[1] + \mathbb E[Xt] + \mathbb E\left[\frac{X^2t^2}2\right] + \mathbb E\left[\frac{X^3t^3}6\right] + \cdots[/tex]

and by the linearity of expectation,

[tex]\displaystyle M_X(t) = 1 + \mathbb E[X] t + \frac12 \mathbb E\left[X^2\right] t^2 + \frac16 \mathbb E\left[X^3\right] t^3 + \cdots[/tex]

and here we see where the name MGF comes from: the coefficient of the n-th order term in the series expansion "generates" the n-th moment, which is defined as E[Xⁿ].

Now, recall the definition of variance:

[tex]\mathrm{Var}(X) = \mathbb E\left[\left(X - \mathbb E[X]\right)^2\right][/tex]

[tex]\mathrm{Var}(X) = \mathbb E\left[X^2\right] - \mathbb E[X]^2[/tex]

and this is exactly the difference between the second moment and the square of the first moment.

So if you know the MGF, then you essentially get the variance for free with little effort. By differentiating the MGF, we get

[tex]\displaystyle M_X''(t) = \mathbb E[X] + \mathbb E\left[X^2\right] t + \frac12 \mathbb E\left[X^3\right] t^2 + \cdots[/tex]

and setting t = 0 lets us recover the first moment, E[X].

Differentiating again gives

[tex]\displaystyle M_X'(t) = \mathbb E\left[X^2\right] + \mathbb E\left[X^3\right] t + \cdots[/tex]

and setting t = 0 once again recovers the second moment.

Then in terms of the MGF, we have

[tex]\boxed{\mathrm{Var}(X) = M_X''(0) - M_X'(0)^2}[/tex]

72 boxes sold out of 90 boxes what percent sold

Answers

Answer:

80%

Step-by-step explanation:

Answer:

80%

Step-by-step explanation:

90 boxes = 100%

72 boxes = ?

=> (72 * 100)/ 90 = 80%

Cheryl is planning to spend $75 on a Christmas gift for her father. He needs new socks and ties. A store has socks s and ties t on sale for $4 and $11, respectively. Which equation models this situation?

Answers

Answer:

4s + 11t = 75

Step-by-step explanation:

Assuming you are asking for an equation to find how many socks and ties Cheryl could get with $75, then the equation 4s + 11t = 75 would represent that.

s is the number of socks that are bought (assuming s = 1 means that 1 pair of socks is bought).

t is the number of ties that are bought.

4s represents the total cost of the socks that are bought (if you plug in 4 for s, then the total cost of the socks is 4(4) = 16+

11t represents the total cost of the ties that are bought

What is the equation of the line in slope-intercept form?
6
5
4
3
2
1
-5 -4
1
2
3
4
43 -2 -1
-1
-2
-3
-4
Enter your answer in the boxes.
y = IX +

Answers

Answer:

y = 4/3x + 4

Step-by-step explanation:

The y intercept is 4. So if we look the 2 points are (-3,0) and (0,4)

So the run is 3 and rise 4

so 4/3 is the slope

Give the coordinates and quadrant of Point Z.

Number graph ranging from negative ten to ten on the x and y axes. Point C is drawn at (negative four, five), point D is drawn at (negative nine, nine), point E is drawn at (five, zero), point I is drawn at (zero, nine), point J is drawn at (negative nine, zero), point L is drawn at (nine, negative nine), point P is drawn at (zero, negative nine), point X is drawn at (zero, five) and point Z is drawn at (nine, ten).


(9, 10) Quadrant II


(10, 9) Quadrant I


(9, 10) Quadrant I


(10, 9) Quadrant II

Answers

The coordinates and quadrant of Point Z is (9, 10) Quadrant I.

Which four quadrants of graph?

The X and Y axes divide the graph plane into four quadrants:

The first quarter is at the upper right corner of the plane. In this quadrant, the x and y coordinates are both positive. The second quadrant is situated in the top left corner of the plane. In this quadrant, the x-coordinate is negative while the y-coordinate is positive. The third quarter lies at the lower left-hand corner of the plane. In this quadrant, the x and y coordinates are both negative. The fourth quarter is at the lower right corner of the aircraft. In this quadrant, the x-coordinate is positive while the y-coordinate is negative.

Given:

Coordinates:

C( -4, 5), D(-9, 9), E(5, 0), I(0, 9), J(-9, 0), L(9, -9), P(0, -9), X(0, 5) and

Z(9, 10).

As, we know The upper right corner of the plane is where the first quarter is located. The x and y coordinates in this quadrant are both positive.

Hence, Z lies in Quadrant !.

Learn more about graph quadrant here:

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#SPJ2

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

Answers

Answer:

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

Tim has 2/3 cup of chocolate syrup. If he uses 1/9 cup of chocolate syrup for each serving of chocolate milk, how many servings of chocolate milk can he make

Answers

Answer:

6 servings

Step-by-step explanation:

Each serving Tim uses 1/9 cup. So, after using the amount of syrup reduces and repeated subtraction is division.

[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{9}[/tex]

[tex]=\dfrac{2}{3}*\dfrac{9}{1}[/tex]

= 2 *3

= 6

HELPPP PLZ PLZ PLZ 15 BRANULASR When x is decreased by 129 and then that number is multiplied by 129 , the result is 129. What is the value of x?

Answers

Answer:

130

Step-by-step explanation:

(x - 129) * 129 = 129

x - 129 = 129/129

x - 129 = 1

x = 129 + 1

x = 130

Answer:

x could equal 130 but I'm not sure about this one

Step-by-step explanation:

you take 130-129 which equal 1 then times 1 by 129 and it equals 129... again sorry if it's not right because I'm not entirely sure how to do this I'm pretty sure I did it correct though

Mr. Solomon, the art teacher, has 49.6 pounds of clay. If he gives every student 1.6 pounds of clay and has none left, how many students are in his class?​

Answers

Answer:

He has 31 students

Step-by-step explanation:

You know this because 49.6 ÷ 1.6 = 31

Solve 2/v + 1/w = 1/2 for v

Answers

Answer:

v=(-4w)/(-w+2)

express 1 000 000 in standard form

Answers

Answer:

10^6.

Step-by-step explanation:

There are 6 digits after the 1 so it's 1 * 10^6 or just 10^6.

x=4y-7
2x+9y=-31
What be the answer

Answers

Answer:

x=-11

y=-1

Step-by-step explanation:

x=4y-7

2x+9y=-31

2(4y-7)+9y=-31

8y-14+9y=-31

17=-31+14

17y=-17

y=-1

x=4(-1)-7

x=-11

Answer:

x = -11, y = -1

Step-by-step explanation:

solving simultaneously,

2(4y-7) + 9y = -31

17y = 14 - 31

17y = -17

y = -1

back sub, we get:

x = 4(-1)-7

x = -11

so x = -11, y = -1

Can someone tell me what the evaluated answer is?

Answers

Answer:

16)  7⁻²

17) -1⁻²

Step-by-step explanation:

plug in the x=, y=, and n= into the equation.

Solve 8T 1398lb 14oz * 6

Answers

this is soo funny

haha thanks for the points

epic gamer question i'll mark brainliest​

Answers

Answer:

I think it is parallel

Step-by-step explanation:

Please answer the question in the picture

Answers

(2x+8)(x-3)
2x + x = 3x
8 - 3 = 5
3x + 5 is expressed form.

Answer:

2x² + 2x - 24

Step-by-step explanation:

We can use the FOIL method to multiply the terms together and then find the values in our trinomial. First, the F in FOIL. It stands for first, and we need to multiply the first terms in the two expressions. These terms are 2x and x. Multiplying 2x by x gives us 2x², so that's our first term.

Next, the O in FOIL. It stands for outside, and we need to multiply the terms on the very left and the very right. These are 2x and -3, and multiplying 2x by -3 gives us -6x. That's our second term.

Now, the I in FOIL. It stands for inside, so we need to multiply the terms in the middle of the expressions. Those are 8 and x, and we multiply those together to get 8x. That's our third term.

Finally, the L in FOIL. This stands for last; we need to multiply the last terms of each expression. Those are 8 and -3, and we can multiply those to get -24. Now we can get all our terms added together and simplify as needed.

2x² - 6x + 8x - 24

We can simplify -6x and 8x since they are like terms.

2x² + 2x - 24

And there is our trinomial. Hopefully that's helpful! :)

A company makes a profit of $y (in thousand dollars) when it produces x computers,
where y is given by the formula y = a(x - 100)(x - 200) for x 20 If 120
computers are produced, the profit will be $3,200,000.
a) Find the value of a.

b) What is the maximum profit the company can make? At this profit, how many
computers should be produced?

c) If the company targets to make at least $4,800,000, what is the range of the
number of computers to be produced?


Answers

The solutions to the questions if y is represented by the formula y = a(x - 100)(x - 200) are:

a) The value of a = -2000

b) The maximum profit the company can make = $5,000,000

To make maximum profit, 150 computers must be produced

c) The company must produce between 140 and 160 computers to make at least $4,800,000

The equation representing the company's profit is:

y = a(x - 100)(x - 200)  for x > 20

If 120  computers are produced, the profit will be $3,200,000

That is, y = 3,200,000 if x = 120

a) Find the value of a

3,200,000 = a(120 - 100)(120 - 200)

3200000 = -16000a

a = -3200000/1600

a = -2000

b) Maximum profit the company can make

The equation becomes:

y = -2000(x - 100)(x - 200)

y = -2000(x² - 200x - 100x + 20000)

y = -2000(x² - 300x + 20000)

y = -2000x² + 600000x - 40000000

dy/dx = -4000x + 600000

dy/dx = 0 at maximum value

-4000x  +  600000 = 0

4000x  =  600000

x  =  600000/4000

x   =  150

To make maximum profit, 150 computers must be produced

Substitute x = 150 into y = -2000x² + 600000x - 40000000 to find the maximum profit

y  = -2000(150²) + 600000(150) - 40000000

y = 5000000

The maximum profit the company can make = $5,000,000

c) Calculate the range of the number of computers to be produced If the company targets to make at least $4,800,000

-2000x² + 600000x - 40000000 ≥ 4800000

-2000x² + 600000x - 40000000 - 4800000 ≥ 0

-2000x² + 600000x - 44800000 ≥ 0

Divide through by -2000

x² - 300x +22400 ≤ 0

(x - 140)(x - 160) ≤ 0

140 ≤ x ≤ 160

The company must produce between 140 and 160 computers to make at least $4,800,000

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Question 10 of 10
Which of the following is the solution to the inequality below?
-2/6(4-x)<4(x+1/2

Answers

Answer:

x > -11/10

Step-by-step explanation:

-2/6(4-x) < 4(x+1/2)

-1/3(4-x) < 4x + 2

-4/3 + 1/3x < 4x + 2

-4 +x < 12x + 6

x - 12 x < 6 + 4

-11x < 10

x > -11/10

These triangles
are congruent by
the triangle
congruence
postulate [? ].
A. ASA
B. Neither, they are not congruent
C. AAS

Answers

Since in the two triangles,

2 angles and the side between them is given and equal, the triangles are congruent using the Criteria ASA.

Option A is the correct answer.

PLEASE HELP DUE NOW!!!
WILL MARK BRAINLIEST!!!!

Answers

Answer:

In point form, the answer is (1, -7) and in equation form, x = 1, y = -7.

Step-by-step explanation:

I hope this helps!

Arrange the following numbers in descending order: 50,101 501,100 51,150 500,101

Answers

Answer:

Step-by-step explanation:

Hope it helps,view the image:

Find the difference (10j-7)-(-9j+2)

Answers

Answer:

19j-9

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

10+9=19j

-7-2=9

A suspension bridge with weight uniformly distributed along its length has twin towers that extend 55 meters above the road surface and are 1200 meters apart. The
cables are parabolic in shape and are suspended from the tops of the towers. The cables touch the road surface at the center of the bridge. Find the height of the
cables at a point 300 meters from the center. (Assume that the road is level.)
The height of the cables is meters.
(Simplify your answer.)

Answers

Answer:

try kopo

Step-by-step explanation:

55+1200+300=1555

Answer:

Step-by-step explanation:

start by graphing it (see picture)

formula for a parabola: y=ax²

using the coordinates (600,55) we get

55=a*600²

a=55/(600²)

so now it's just a matter of plugging in 300 for x

(55/600²)*300²= 13.75

From first principles, find the indicated derivatives​

Answers

By definition of the derivative,

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)[/tex]

[tex]\displaystyle\frac{dr}{ds} = \frac{3s^2}2[/tex]

Line ℓ has equation y=5. Find the distance between ℓ and the point Q(0,1).

Answers

Answer:

Distance = 4

Step-by-step explanation:

Given the linear equation of line ℓ, y = 5 which is a horizontal line in which its slope, m = 0 (zero slope), and each of the x-coordinates along the line have the same y-coordinate of y = 5.

In order to determine the distance of the horizontal line from the given point Q, (0, 1), use the following distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

Choose any x-coordinate to pair with the y-coordinate, y = 5. Let's use the y-intercept, (0, 5).

Let  (x₁, y₁) = (0, 1)  

      (x₂, y₂) = (0, 5)  

Substitute these values into the distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

[tex]d = \sqrt{(0 - 0)^{2} + (5 - 1)^{2}}[/tex]  

[tex]d = \sqrt{(4)^{2}}[/tex]

[tex]d = \sqrt{16}[/tex]

d = 4  

Therefore, the distance of line ℓ from point Q is 4.

10x-6x-4-1=7-12+2x+2x

Answers

Any value of

x

makes the equation true.

Always true

Interval Notation:

(−∞,∞)

Hope this helps if not I’m sorry
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