The probability that Jessica is on time for a given class is 64 percent. If there are 53 classes during the semester, what is the best estimate of the number of times out of 53 that Jessica is on time to class? Round your answer to the nearest integer.
Provide your answer below:

Answer:

4s + 11t = 75

Step-by-step explanation:

Assuming you are asking for an equation to find how many socks and ties Cheryl could get with $75, then the equation 4s + 11t = 75 would represent that.

s is the number of socks that are bought (assuming s = 1 means that 1 pair of socks is bought).

t is the number of ties that are bought.

4s represents the total cost of the socks that are bought (if you plug in 4 for s, then the total cost of the socks is 4(4) = 16+

11t represents the total cost of the ties that are bought

Answer:

I think it is parallel

Step-by-step explanation:

Any value of

x

makes the equation true.

Always true

Interval Notation:

(−∞,∞)

Answer:

10^6.

Step-by-step explanation:

There are 6 digits after the 1 so it's 1 * 10^6 or just 10^6.

Answer:

Germany

Austria-Hungary

Bulgaria

Ottoman Empire (the Central Powers)

Great Britain

France

Russia

Italy

Romania

Japan

United States (the Allied Powers).

Answer:

19j-9

HOPE THIS HELPS

- Todo ❤️

Step-by-step explanation:

10+9=19j

-7-2=9

Since in the two triangles,

2 angles and the side between them is given and equal, the triangles are congruent using the Criteria ASA.

Option A is the correct answer.

Answer:

x > -11/10

Step-by-step explanation:

-2/6(4-x) < 4(x+1/2)

-1/3(4-x) < 4x + 2

-4/3 + 1/3x < 4x + 2

-4 +x < 12x + 6

x - 12 x < 6 + 4

-11x < 10

x > -11/10

Answer:

try kopo

Step-by-step explanation:

55+1200+300=1555

Answer:

Step-by-step explanation:

start by graphing it (see picture)

formula for a parabola: y=ax²

using the coordinates (600,55) we get

55=a*600²

a=55/(600²)

so now it's just a matter of plugging in 300 for x

(55/600²)*300²= 13.75

Answer:

Step-by-step explanation:

Hope it helps,view the image:

Answer:

130

Step-by-step explanation:

(x - 129) * 129 = 129

x - 129 = 129/129

x - 129 = 1

x = 129 + 1

x = 130

Answer:

x could equal 130 but I'm not sure about this one

Step-by-step explanation:

you take 130-129 which equal 1 then times 1 by 129 and it equals 129... again sorry if it's not right because I'm not entirely sure how to do this I'm pretty sure I did it correct though

Answer:

16)  7⁻²

17) -1⁻²

Step-by-step explanation:

plug in the x=, y=, and n= into the equation.

The coordinates and quadrant of Point Z is (9, 10) Quadrant I.

The X and Y axes divide the graph plane into four quadrants:

Given:

Coordinates:

C( -4, 5), D(-9, 9), E(5, 0), I(0, 9), J(-9, 0), L(9, -9), P(0, -9), X(0, 5) and

Z(9, 10).

As, we know The upper right corner of the plane is where the first quarter is located. The x and y coordinates in this quadrant are both positive.

Hence, Z lies in Quadrant !.

Learn more about graph quadrant here:

https://brainly.com/question/12788228

#SPJ2

Answer:

HIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIIII

Answer:

x=-11

y=-1

Step-by-step explanation:

x=4y-7

2x+9y=-31

2(4y-7)+9y=-31

8y-14+9y=-31

17=-31+14

17y=-17

y=-1

x=4(-1)-7

x=-11

Answer:

x = -11, y = -1

Step-by-step explanation:

solving simultaneously,

2(4y-7) + 9y = -31

17y = 14 - 31

17y = -17

y = -1

back sub, we get:

x = 4(-1)-7

x = -11

so x = -11, y = -1

Answer:

In point form, the answer is (1, -7) and in equation form, x = 1, y = -7.

Step-by-step explanation:

I hope this helps!

Answer:

He has 31 students

Step-by-step explanation:

You know this because 49.6 ÷ 1.6 = 31

Answer:

v=(-4w)/(-w+2)

Answer:

6 servings

Step-by-step explanation:

Each serving Tim uses 1/9 cup. So, after using the amount of syrup reduces and repeated subtraction is division.

[tex]\frac{2}{3}[/tex] ÷ [tex]\frac{1}{9}[/tex]

[tex]=\dfrac{2}{3}*\dfrac{9}{1}[/tex]

= 2 *3

= 6

Answer:

2x² + 2x - 24

Step-by-step explanation:

We can use the FOIL method to multiply the terms together and then find the values in our trinomial. First, the F in FOIL. It stands for first, and we need to multiply the first terms in the two expressions. These terms are 2x and x. Multiplying 2x by x gives us 2x², so that's our first term.

Next, the O in FOIL. It stands for outside, and we need to multiply the terms on the very left and the very right. These are 2x and -3, and multiplying 2x by -3 gives us -6x. That's our second term.

Now, the I in FOIL. It stands for inside, so we need to multiply the terms in the middle of the expressions. Those are 8 and x, and we multiply those together to get 8x. That's our third term.

Finally, the L in FOIL. This stands for last; we need to multiply the last terms of each expression. Those are 8 and -3, and we can multiply those to get -24. Now we can get all our terms added together and simplify as needed.

2x² - 6x + 8x - 24

We can simplify -6x and 8x since they are like terms.

2x² + 2x - 24

And there is our trinomial. Hopefully that's helpful! :)

Answer:

The total value of toys the factory produces in a day is $10,000.

Step-by-step explanation:

One Toy = $10

Workers = 40

Toys Made By Each Worker Per Day = 25

The factory makes 1,000 toys per day and 5,000 toys per week. Each toy has a value of $10 so the value of toys in one day would add up to $10,000. The toy factory would also make $50,000 a week.

The solutions to the questions if y is represented by the formula y = a(x - 100)(x - 200) are:

a) The value of a = -2000

b) The maximum profit the company can make = $5,000,000

To make maximum profit, 150 computers must be produced

c) The company must produce between 140 and 160 computers to make at least $4,800,000

The equation representing the company's profit is:

y = a(x - 100)(x - 200)  for x > 20

If 120  computers are produced, the profit will be $3,200,000

That is, y = 3,200,000 if x = 120

a) Find the value of a

3,200,000 = a(120 - 100)(120 - 200)

3200000 = -16000a

a = -3200000/1600

a = -2000

b) Maximum profit the company can make

The equation becomes:

y = -2000(x - 100)(x - 200)

y = -2000(x² - 200x - 100x + 20000)

y = -2000(x² - 300x + 20000)

y = -2000x² + 600000x - 40000000

dy/dx = -4000x + 600000

dy/dx = 0 at maximum value

-4000x  +  600000 = 0

4000x  =  600000

x  =  600000/4000

x   =  150

To make maximum profit, 150 computers must be produced

Substitute x = 150 into y = -2000x² + 600000x - 40000000 to find the maximum profit

y  = -2000(150²) + 600000(150) - 40000000

y = 5000000

The maximum profit the company can make = $5,000,000

c) Calculate the range of the number of computers to be produced If the company targets to make at least $4,800,000

-2000x² + 600000x - 40000000 ≥ 4800000

-2000x² + 600000x - 40000000 - 4800000 ≥ 0

-2000x² + 600000x - 44800000 ≥ 0

Divide through by -2000

x² - 300x +22400 ≤ 0

(x - 140)(x - 160) ≤ 0

140 ≤ x ≤ 160

The company must produce between 140 and 160 computers to make at least $4,800,000

Learn more here: https://brainly.com/question/25471478

Answer:

im pretty sure its 2025

Answer:

2025

Step-by-step explanation:

Answer:

80%

Step-by-step explanation:

Answer:

80%

Step-by-step explanation:

90 boxes = 100%

72 boxes = ?

=> (72 * 100)/ 90 = 80%

this is soo funny

haha thanks for the points

Answer:

y = 4/3x + 4

Step-by-step explanation:

The y intercept is 4. So if we look the 2 points are (-3,0) and (0,4)

So the run is 3 and rise 4

so 4/3 is the slope

By definition of the derivative,

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}[/tex]

[tex]\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)[/tex]

[tex]\displaystyle\frac{dr}{ds} = \frac{3s^2}2[/tex]

Answer:

Distance = 4

Step-by-step explanation:

Given the linear equation of line ℓ, y = 5 which is a horizontal line in which its slope, m = 0 (zero slope), and each of the x-coordinates along the line have the same y-coordinate of y = 5.

In order to determine the distance of the horizontal line from the given point Q, (0, 1), use the following distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

Choose any x-coordinate to pair with the y-coordinate, y = 5. Let's use the y-intercept, (0, 5).

Let  (x₁, y₁) = (0, 1)  

      (x₂, y₂) = (0, 5)  

Substitute these values into the distance formula:

[tex]d = \sqrt{(x_2 - x_1)^{2} + (y_2 - y_1)^{2}}[/tex]

[tex]d = \sqrt{(0 - 0)^{2} + (5 - 1)^{2}}[/tex]  

[tex]d = \sqrt{(4)^{2}}[/tex]

[tex]d = \sqrt{16}[/tex]

d = 4  

Therefore, the distance of line ℓ from point Q is 4.

The moment generating function is defined by

[tex]M_X(t) = \mathbb E[e^{tX}][/tex]

Recall the power series expansion for the exponential function:

[tex]\displaystyle \sum_{n=0}^\infty \frac{x^n}{n!} = 1 + x + \frac{x^2}2 + \frac{x^3}6 + \cdots[/tex]

Then by extension, the MGF could be similarly written as

[tex]\displaystyle M_X(t) = \mathbb E \left[1 + Xt + \frac{(Xt)^2}2 + \frac{(Xt)^3}6 + \cdots\right][/tex]

There's a certain theorem (due to Fubini, in case you're interested in learning more about it) that let's us exchange the order of integration (recall the definition of expectation for continuous random variables) and summation, so that

[tex]\displaystyle M_X(t) = \mathbb E[1] + \mathbb E[Xt] + \mathbb E\left[\frac{X^2t^2}2\right] + \mathbb E\left[\frac{X^3t^3}6\right] + \cdots[/tex]

and by the linearity of expectation,

[tex]\displaystyle M_X(t) = 1 + \mathbb E[X] t + \frac12 \mathbb E\left[X^2\right] t^2 + \frac16 \mathbb E\left[X^3\right] t^3 + \cdots[/tex]

and here we see where the name MGF comes from: the coefficient of the n-th order term in the series expansion "generates" the n-th moment, which is defined as E[Xⁿ].

Now, recall the definition of variance:

[tex]\mathrm{Var}(X) = \mathbb E\left[\left(X - \mathbb E[X]\right)^2\right][/tex]

[tex]\mathrm{Var}(X) = \mathbb E\left[X^2\right] - \mathbb E[X]^2[/tex]

and this is exactly the difference between the second moment and the square of the first moment.

So if you know the MGF, then you essentially get the variance for free with little effort. By differentiating the MGF, we get

[tex]\displaystyle M_X''(t) = \mathbb E[X] + \mathbb E\left[X^2\right] t + \frac12 \mathbb E\left[X^3\right] t^2 + \cdots[/tex]

and setting t = 0 lets us recover the first moment, E[X].

Differentiating again gives

[tex]\displaystyle M_X'(t) = \mathbb E\left[X^2\right] + \mathbb E\left[X^3\right] t + \cdots[/tex]

and setting t = 0 once again recovers the second moment.

Then in terms of the MGF, we have

[tex]\boxed{\mathrm{Var}(X) = M_X''(0) - M_X'(0)^2}[/tex]