The rate of this reaction is markedly increased if a small amount of sodium iodide is added to the reaction mixture. The sodium iodide is not consumed by the reaction and is therefore considered to be a catalyst. Explain how the presence of iodide can speed up the rate of the reaction.
Answers
Answer:
See explanation
Explanation:
SN2 reaction is a synchronous reaction in which the leaving group departs as the nucleophile is being attached to the substrate in a single step. This makes it imperative to use a good leaving group when carrying out an SN2 reaction such as the one shown in the question.
The addition of a small amount of NaI acts as a sort of external nucleophile which assists the departure of the leaving group thereby enabling the reaction to proceed faster. This occurs because the iodide ion is very good leaving group.
Related Questions
Using the periodic table,
choose the more reactive nonmetal. Br or as
Answers
Answer:
Br
Explanation:
because bromine is more reactive as reactivity increases on moving from left to right in p-block. hope this make sense :)
Plss help me solve question 7
Thank you.
Answers
Answer:
4- ethyl- 6-methylocta- 1,2,5- triene
Explanation:
See attached. Please give me brainliest I worked hard. ;(
A 1.375 g sample of mannitol, a sugar found in seaweed, is burned completely in oxygen to give 1.993 g of carbon dioxide and 0.9519 g of water. The empirical formula of mannitol is
Answers
Answer:
[tex]C_3H_7O_3[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out possible for us to infer that the empirical formula of mannitol contains carbon, hydrogen and oxygen, so that the first step is to calculate the moles of C and H contained in the CO2 and H2O, respectively, as the only sources of these two elements in the formula:
[tex]n_C=1.993gCO_2*\frac{1molCO_2}{44.01gCO_2}*\frac{1molC}{1molCO_2} =0.0453molC\\\\n_H=0.9519gH_2O*\frac{1molH_2O}{18.02gH_2O}*\frac{2molH}{1molH_2O} =0.106molH[/tex]
Next, we calculate the grams and moles of O by subtracting the mass of C and H from the mass of the sample:
[tex]m_O=1.375g-0.0453molC*\frac{12gC}{1molC}-0.106molH*\frac{1.01gH}{1molH}=0.724gO\\\\n_O=0.724gO*\frac{1molO}{16.0gO} =0.0453molO[/tex]
Finally, we divide the moles of C, H and O by 0.0453 as the fewest moles of both C and O to find the mole ratios in the formula:
[tex]C:\frac{0.0453mol}{0.0453mol} =1\\\\H:\frac{0.106mol}{0.0453mol} =2.34\\\\O:\frac{0.0453mol}{0.0453mol} =1[/tex]
To get:
[tex]CH_{2.34}O[/tex]
Which must be multiplied by 3 to get whole numbers for all the subscripts, and therefore obtain:
[tex]C_3H_7O_3[/tex]
Regards!
A sample of gas with an initial volume of 9.35 L at a pressure of 784 torr and a temperature of 295 K is compressed to a volume of 2.84 L and warmed to a temperature of 310 K. What is the final pressure of the gas in atmospheres (atm)?
a. 4.97 atm.
b. 0.113 atm.
c. 5.95 atm.
d. 7.03x10^3 atm.
Answers
Answer:
D
Explanation:
In the picture this is my last question pls.
Answers
Answer:
Chromosomes and I think its too many
Explanation:
Question on the image
Answers
Answer: The mass of carbon dioxide required is 308 g
Explanation:
The number of moles is defined as the ratio of the mass of a substance to its molar mass.
The equation used is:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)
Given mass of octane = 100.0 g
Molar mass of octane = 114.23 g/mol
Putting values in equation 1, we get:
[tex]\text{Moles of octane}=\frac{100.0g}{114.23g/mol}=0.875mol[/tex]
For the given chemical reaction:
[tex]2C_8H_{18}+25O_2\rightarrow 16CO_2+18H_2O[/tex]
By the stoichiometry of the reaction:
2 moles of octane produces 16 moles of carbon dioxide
So, 0.875 moles of octane will produce = [tex]\frac{16}{2}\times 0.875=7mol[/tex] of carbon dioxide
Molar mass of carbon dioxide = 44 g/mol
Plugging values in equation 1:
[tex]\text{Mass of carbon dioxide}=(7mol\times 44g/mol)=308g[/tex]
Hence, the mass of carbon dioxide required is 308 g
Consider the reaction of Copper with Sulfur: Cu +S → Cus. Using the
below data, which of following is true?
A. Sulfur was the limiting reactant; 1.61 g of sulfur were reacted.
B. Copper was the limiting reactant; 1.32 g of sulfur were unreacted
C. Copper (II) sulfide was the limiting reactant; 4.78 g was formed.
D. There was no limiting reactant; both reactants remained in excess.
Answers
Answer:
B. Copper was the limiting reactant; 1.32 g of sulfur were unreacted
Explanation:
Cu + S → CuS
As there was no Cu left after the reaction was completed, Cu was not the reactant in excess but rather the limiting reactant.Copper (II) sulfide (CuS) cannot be the limiting reactant, because it is not a reactant but a product.With the two points above in mind, the only option left is B.
P4 + NaOH + H2O——> PH3 + Na2HPO3
Balance given equation by oxidation no. Method
Answers
Answer:
P4 + 4NaOH + 2H2O → 2PH3 + 2Na2HPO3
Explanation:
A chemical equation is said to be balanced if the quantity of each type of atom in the reaction is the same on both the reactant and product sides. In a balanced chemical equation, the mass and the charge are both equal.
A chemical equation must balance according to the rule of conservation of mass. According to the rule, mass cannot be generated or removed during a chemical process.
Chemical equations must be balanced, which means that the atom types and numbers on both sides of the reaction arrow must match. Coefficients are the values added in front of formulas to balance equations; they multiply each atom in a formula.
Here the given equation is balanced as:
P₄ + 4NaOH + 2H₂O——> 2PH₃ + 2Na₂HPO₃
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Beer's Law states that A=ebc, where A is the absorbance, ε is the molar absorptivity of the solute, b is the path length, and c is the concentration. Identify the experimental evidence from the activity that you have for the dependence of absorbance on each variable
The evidence for the dependence of absorbance on the variable ε is:_________
a. increasing the cuvette width increases the absorbance.
b. changing the compound changes the absorbance behavior.
c. adding more water decreases the absorbance.
Answers
Answer:
b. changing the compound changes the absorbance behavior.
Explanation:
Option a) would be akin to modifying the path length, b.Option b) would involve using a different solute, as such, there would be another molar absortivity, ε.Option c) would decrease the concentration (c) of the solute, which would explain why the absorbance would decrease as well.A certain shade of blue has a frequency of 7.28×1014 Hz.
What is the energy of exactly one photon of this light? Planck's constant is ℎ=6.626×10−34 J⋅s.
Answers
Explanation:
the enerfy of of one photon of this light is 4.85x10^-19 J
E= 6.63 x 10^-34 J/S x 7.32 x10^14 S ^-1E= 4.85x10^-19 J
g a commercial product for treating injuries contains 35.0 g of MgSO4 in one bag and 250 mL of water in a seperate bag. When the bags are broken and their contents mixed, the temperature of the system changes. Calculate this temperature change
Answers
Answer:
he a real G
Explanation:
og tripple og
the mass of a single potassium atom is 6.50×10-23 grams. How many potassium atoms would there be in 114 milligrams of potassium?
Answers
Answer:LOL
42
Explanation:
The mass of a single potassium atom is 6.50×10⁻²³ grams potassium atoms would be in 114 milligrams of potassium 17.53 ×10⁻²³.
What is an atom?
An atom is the most diminutive form of any chemical compound that takes part in the chemical reaction to form any product and it is equal to the one mole which is 2.303 ×10²³ moles of the Avogadros number.
To calculate the number of atoms we have, 6.50×10⁻²³ grams of potassium and the value of one particle is 2.303 ×10²³ moles,
atoms = 6.50×10⁻²³ / 114 milligrams of potassium
atoms of potassium = 17.53 ×10⁻²³. atoms.
Therefore, 17.53 ×10⁻²³.atoms are present if the mass of a single potassium atom is 6.50×10⁻²³ grams potassium atoms would there be in 114 milligrams of potassium.
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Electrons are in ___________ ___________ surrounding the nucleus.
Answers
Answer:
electron shells
Explanation:
Eletrons are on the outeermost part of the atom called electron shells.
The largest number of stable nuclei have an ________ number of protons and an ________ number of neutrons.
Answers
Answer:
did it give you answers to in blanks
Phosphorus trichloride can be made by the following reaction: P4(s) 6Cl2(g) - 4) 4PCl3(l) What is the maximum amount of phosphorus trichloride that can be formed if 15 molecules of P4 are mixed with 42 molecules of chlorine
Answers
Answer:
48 molecules
Explanation:
From the given reaction:
[tex]\mathtt{P_4 + 6Cl_2\to 4PCl_3}[/tex]
i.e. 1 mole of Phosphorus react 6 moles of chlorine to yield 4 moles of PCl₃
This implies that for each P₄ molecule, we will require 6 molecules of Cl₂
We are provided with 15 molecules of P₄ and 42 molecules of Cl₂
Suppose we utilized the whole 15 molecules of P₄, we will require:
= 15 × 6 = 90 moles of Cl₂ which is not readily available except 42 are available.
If we utilized 42 molecules of Cl₂, we will require 42/6 = 7 molecules of P₄ which is readily available.
From this analysis, we can opine that Cl₂ serves as the limiting agent
∴
P₄ : Cl₂ : PCl₃ = 1 : 6 : 4 = 7 : 42 : 48
It implies that only 48 molecules of phosphorus trichloride will be formed.
how many s electrons are there in potassium?
Answers
Answer: 19
Explanation:
In order to write the Potassium electron configuration we first need to know the number of electrons for the K atom (there are 19 electrons). When we write the configuration we'll put all 19 electrons in orbitals around the nucleus of the Potassium atom.
20)
Which substance is an acid?
A)
Ba(OH)2
B)
CH3COOCH3
C)
H3PO4
D)
NaCl
help
Answers
Answer:
C.
Explanation:
Also, please help me in my questions tab if you can! Thank you so much
Write the precipitation reaction for cobalt(II) hydroxide in aqueous solution: Be sure to specify the state of each reactant and product.
Answers
Answer:
The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Explanation:
Cobalt (ii) hydroxide is an inorganic compound consisting of cobalt (ii) ions, Co²+ and hydroxide ions, OH-. It is insoluble in water and the pure form known as the beta form is a pink-coloured solid. The impure form which incorporates other anions in its molecular structure is blue in colour and is ustable.
Cobalt (ii) hydroxide is formed as precipitate when an alkaline metallic hydroxide such as sodium hydroxide is mixed with an aqueous cobalt (ii) salt such as cobalt (ii) sulfate. The equation for the precipitation reaction of cobalt (ii) hydroxide is given below:
CoSO₄ (aq) + NaOH (aq) ----> Co(OH)₂ (s) + Na₂SO₄ (aq)
Being a basic hydroxide, cobalt (ii) hydroxide neutralizes acids to form cobalt (ii) salts and water. For example: Co(OH)₂ (s) + H₂SO₄ (aq) ---> CoSO₄ (aq) + H₂O
Thus, cobalt (ii) hydroxide is soluble in acids.
Cobalt(II) hydroxide is used mostly as a drying agent for paints, varnishes, and inks. It is also useful in the preparation of other cobalt compounds.
The shielding of electrons gives rise to an effective nuclear charge, Zeff, which explains why boron is larger than oxygen. Estimate the approximate Zeff felt by a valence electron of boron and oxygen, respectively.
a. +5 and +8.
b. +3 and +6.
c. +5 and +6.
d. +3 and +8.
e. +1 and +4.
Answers
Answer:
b. +3 and +6.
Explanation:
Zeff = Z - S
The Z denotes the no of protons i.e. atomic number
S denotes the non-valence electrons
For boron,
the electronic configuration is 1s₂ 2s₂ 2p₄
Now
Z = 5, S = 2
So,
Zeff = 5-2
= +3
For O, the electronic configuration is 1s₂ 2s₂ 2p₄
So,
Z = 8, S = 2
= 8-2
= +6
Hence, the second option is correct
Describe uses of H2S as analytical regent
Answers
Answer:
Hydrogen sulfide is used primarily to produce sulfuric acid and sulfur. It is also used to create a variety of inorganic sulfides used to create pesticides, leather, dyes, and pharmaceuticals. Hydrogen sulfide is used to produce heavy water for nuclear power plants (like CANDU reactors specifically).
Explanation:
Sana Po it's help
What is one way in which a field investigation can differ from a classroom or laboratory experiment?
Answers
Answer:
□In field investigations, you are usually working with much larger animals than in the lab. In field investigations, it is much more difficult to separate your control and experimental groups.
There are many ways in which a field experiment can differ form of a classroom or a laboratory experiment, one of which can be the environmental condition.
What is a field experiment?A field experiment Is an experiment which is performed in practically Outside the classroom or a laboratory in live situtations .
Environmental factors may deter the results of a field experiment or may alter the physical conditions of the object, For example an anhydrous substance may become hygroscopic, Which may Alter the result of the field experiment.
Hence, field experiment can differ from a classroom or a laboratory experiment due to environmental conditions .
Learn more about laboratory Experiment.
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What was one idea Dalton taught about atoms?
Answers
Explanation:
All atoms of one type were identical in mass and properties.
how many grams of p2o3 can be produced from 95l o2 at STP
Answers
Explanation:
Balanced Equation
P
2
O
3
+
3H
2
O
→
2H
3
PO
3
First use the balanced equation to determine the mole ratio between
H
3
PO
3
and
P
2
O
3
. This ratio will be used to determine the moles
P
2
O
3
required to produce
10.2
moles
H
3
PO
3
.
Mole Ratio Between
P
2
O
3
and
H
3
PO
3
from the balanced equation.
1
mol P
2
O
3
2
mol H
3
PO
3
and
2
mol H
3
PO
3
1
mol P
2
O
3
Multiply the moles
H
3
PO
3
by the molar mass that cancels
H
3
PO
3
and leaves
P
2
O
3
10.2
mol H
3
PO
3
×
1
mol P
2
O
3
2
mol H
3
PO
3
=
5.10 mol P
2
O
3
Now that the moles
P
2
O
3
required to produce
10.2 mol H
3
PO
3
are known, multiply the number of moles by its molar mass,
109.945 g/mol
. https://www.ncbi.nlm.nih.gov/pccompound?term=P2O3 This will give the mass in grams needed for
P
2
O
3
to produce
10.2 mol H
3
PO
3
.
5.10
mol P
2
O
3
×
109.945
g P
2
O
3
1
mol P
2
O
3
=
561 g P
2
O
3
rounded to three significant figures
given two equations representing reactions: which type of reaction is represented by each of these equations?
Answers
Answer:
Equation 1 - nuclear fission
Equation 2 - nuclear fusion
Explanation:
Nuclear fission is a reaction in which a large nucleus is split into smaller nuclei when it is bombarded by neutrons. The process produces more neutrons to continue the chain reaction. This is clearly depicted in equation 1 as shown in the question.
Nuclear fusion is a reaction in which two light nuclei combine in order to form a larger nuclei. This is clearly depicted in equation 2 as shown in the question.
In the first reaction, a neutron is released, and in the second a helium atom is released. The given two equations represent nuclear fission and fusion.
What are nuclear reactions?A nuclear reaction is a reaction that involves the nuclei of the atom and the absorption and release of energy. In the first reaction, a big nucleus is split by the neutron bombardment into smaller nuclei.
In the second reaction the process of nuclear fusion, two nuclei combine into a single larger nucleus that is shown as:
₁¹H+ ²₁H → ³₂He
Therefore, nuclear fission and fusion are represented by each of these equations.
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sound waves? like what they do.
Answers
Answer:
A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords.
HEY. HOPE THIS HELPS♡
Before the lab student needs to make necessary chemical reagent solutions, the teacher asked them to make 50.0mL of 1.0 M H2SO4 from a 6.0 M sock
M1=
V1=
M2=
V2=
Answers
Answer:
M1 = 6.0M
V1 = 8.33mL
M2 = 1.0M
V2 = 50.0mL
Explanation:
It is possible to find the volume that we need to prepare a diluted solution from a stock using the equation:
M1V1 = M2V2
Where M is molar concentration and V volume of 1, stock solution and 2, diluted solution.
Replacing:
M1 = 6.0M
V1 = Our incognite
M2 = 1.0M
V2 = 50.0mL
6.0M*V1 = 1.0M*50.0mL
V1 = 1.0M * 50.0mL / 6.0M
V1 = 8.33mL of the stock solution are needed
Which of these is NOT a characteristics of minerals?
A) organic
B) inorganic
C) crystalline structure
D) definite chemical composition
Answers
Answer:a) organic
Explanation:
3. How many electrons are in the M shell?
Answers
Answer:
i believe the answer is D: 18
Explanation:
Answer:
18
M shell can actually hold 18 electron as you move higher atomic number
Draw the structural formula for both of these alcohols:
2,3, 4-trimethyl, 3-heptanol
4-ethyl, 4-octanol
Answers
Answer:
Check the image above
explanation:
When naming organic compounds based on IUPAC; we take note of functional group, position of functional group.
In 2,3,4-trimethyl-3-heptanol, the functional group is hydroxyl group ( OH ). It is on position 3 (2,3,4-trimethyl-3-heptanol. Then we put it on the third carbon. Another functional group is methyl group, with three positions, 2, 3, and 4.
In 4-ethyl-4-octanol, the functional group is hydroxyl group ( OH ) which is in position 4 on the fourth carbon. Another functional group is ethyl group in position 4 on the fourth carbon. In this case, the functional groups that have same position, are put on that same carbon.
What is the volume of alcohol present in 200.0 mL of a 55\%(v/v) solution of alcohol ?
Answers
Answer:
110 mL
Explanation:
Equation for % v/v (volume concentration) is:
volume concentration = volume of solute / volume of solution
[tex]55\% v/v = v_{solute} /200\\v_{solute} =200 \times 55\%\\v_{solute} =110[/tex]
