Answer:
The answer is "As [tex]Q=336[/tex], at high-temperature [tex]\Delta G_{rxn}>0[/tex] and When[tex]K>1,[/tex][tex]\Delta G^{\circ}_{rxn}>0[/tex]."
Explanation:
The equation for the reaction is:
[tex]A(g) \leftrightharpoons B(g)[/tex]
[tex]K=5.8\\\\Q=336[/tex]
At equilibrium,
[tex]\Delta G^{\circ}_{rxn}>0[/tex][tex]=-RT \ln \ K[/tex]
When k=5.8(>1), the value of [tex]\ln k[/tex] would be positive
So, [tex]\Delta G^{\circ}_{rxn}[/tex] is negative (< 0)
So if K > l, [tex]\Delta G^{\circ}_{rxn}<0[/tex]
If the reaction is not in equilibrium so the equation is :
[tex]\Delta G_{rxn}>0[/tex]=[tex]\Delta G^{\circ}_{rxn}[/tex][tex]+RT \ln Q[/tex]
Substituting the expression:
[tex]\Delta G_{rxn}>0[/tex][tex]= (-RT \ln K) + RT \ln Q[/tex]
[tex]= RT(\ln Q- \ln K)\\= RT(\ln (336)-\ln (5.8))\\= RT(4.06)[/tex]
It is the positive value for all temperatures.
So, As Q = 336, at the high temperature [tex]\Delta G_{rxn}>0[/tex].
100 pointts pls answer quick and no link :In the reaction, Hydrogen + Iodine --> Hydrogen Iodide at equilibrium, some Iodine is is added. What happens to the equilibrium?
Answer:
the concentration of hydrogen iodide will be higher than it was in the original equilibrium conditions.
PLEASE HELP!! ASAP WILL GIVE BRAILIST (please explain how you got there or show a picture of work)
a) Write the word equation for the reaction of silver chlorate reacts with sodium phosphate to produce silver phosphate and sodium chlorate.
b) Write the balanced formula equation for this reaction.
c) If 287 g of silver chlorate reacts with 52.8 g of sodium phosphate, what is the maximum number of grams mass of silver phosphate will be produced?
d) Identify which reactant is the limiting reactant and which is the excess reactant.
e) How many grams of the excess reactant reacts and how many grams are left over?
Answer:
See Explanation
Explanation:
a) The word equation is;
silver chlorate + sodium phosphate ------> silver phosphate + sodium chlorate
b) The balanced reaction equation of the reaction is;
3AgClO3(aq) + Na3PO4(aq) ------->Ag3PO4(s) + 3NaClO3(aq)
c) amount of silver chlorate reacted = 287 g/191.319 g/mol = 1.5 moles
3 moles of silver chlorate yields 1 mole of silver phosphate
1.5 moles of silver chlorate yields 1.5 * 1/3 = 0.5 moles of silver phosphate
Amount of sodium phosphate reacted = 52.8 g/163.94 g/mol = 0.3 moles
1 mole of sodium phosphate yields 1 mole of silver phosphate
0.3 moles of sodium phosphate yields 0.3 moles of silver phosphate.
Hence the maximum number of grams mass of silver phosphate produced = 0.3 moles * 418.58 g/mol = 125.6 g
d) The excess reactant is silver chlorate while the limiting reactant is sodium phosphate
e) 3 moles of silver chlorate reacts with 1 mole of sodium phosphate
x moles of silver chlorate reacts with 0.3 moles of sodium phosphate
x = 3 * 0.3 = 0.9 moles of silver chlorate reacted
Mass of 0.9 moles of silver chlorate = 0.9 moles * 191.319 g/mol = 172 g of silver chlorate
Hence mass of silver chlorate left over = 287 g - 172 g = 115 g
Describe your observations of how the waves are behaving in the photograph.
Answer:
The waves are behaving this way due to the simultaneous water drops landing in the water.
Explanation:
because ima smart baddie (≧▽≦)
When the medium is uniform, how do light waves travel through it? vibrating motion circular motion irregular motion straight line motion
Answer:
straight line
Explanation:
Answer:
All K12 ppl say yeye
Explanation:
A sample of gas is inside of a rigid container with fixed volume of 350mL. The initial pressure of the system is 366kPa, and the initial temperature is 88 degrees Celsius. How would the pressure of the system change if the temperature was increased to 110 degrees Celsius?
Answer:
457.5kPa
Explanation:
Given data
V1=V2=350mL (fixed volume )
P1=366kPa
T1= 88 degrees Celsius
P2=??
T2= 110 degrees Celsius
For the general gas equation
P1V1/T1= P2V2/T2
V1=V2
P1/T1= P2/T2
Substitute
366/88= P2/110
Cross multiply we have
P2*88=366*110
P2*88= 40260
P2= 40260/88
P2= 457.5 kPa
Hence the pressure will change to 457.5kPa
How many calories of heat were added to 167.9 g of water to raise its temperature from 25oC to 55oC?
Answer:
Q = 5036.9 calories
Explanation:
Given that,
Mass, m = 167.9 g
The temperature raises from 25°C to 55°C.
The specific heat of water,c = 4.184 J/g °C
We need to find the heat added to water. We know that,
[tex]Q=mc\Delta T\\\\=167.9 \times 4.184\times (55-25)\\\\=21074.8\ J[/tex]
or
Q = 5036.9 calories
So, 5036.9 calories of heat is added.
Que representa en la reacción química
Na2SO4(s)+H2O(1)=
Answer: The given reaction is a double displacement reaction.
Explanation:
A chemical reaction equation in which both positive and negative ions of two different reactants are exchanged then it is called a double displacement reaction.
For example, [tex]Na_{2}SO_{4} + H_{2}O \rightarrow H_{2}SO_{4} + Na_{2}O[/tex]
Here, hydrogen ions of [tex]H_{2}O[/tex] are replaced by the sodium ions of [tex]Na_{2}SO_{4}[/tex]. Also, sulfate ion of [tex]Na_{2}SO_{4}[/tex] are replaced by oxygen ion of [tex]H_{2}O[/tex].
Thus, we can conclude that the given reaction is a double displacement reaction.
Who are the scientists that contributed in arranging of the periodic table?
Will mark brainliest!!!
Can someone please help me with this???
Review the chart of all the domesticated rabbits. The different types of rabbits are listed by their scientific names. If you were a
rabbit breeder, which rabbits could you breed to produce fertile offspring? Explain.
A)
All of the rabbits listed. They are all rabbits.
B)
None of these rabbits. They are all different species.
C)
Any of the cottontail rabbits They are the same species.
D)
Any of the rabbits on the same branch in the chart because that means
they are closely related.
Answer: None of these rabbits listed. they are all different species
Explanation:
I got it right on usatestprep
Explain how the iron pipes change into rust?
in which of these compounds are there twice as many oxygen atoms as hydrogen atoms?
Answer:
G - H2SO4
Explanation:
two hydrogen atoms and 4 oxygen atoms
If I plant a green bean seed in the desert, will it grow thick, barrel-shaped stems full of water like a cactus? Why or why not?
Answer:
No, although the bean crop can grow perfectly in full sun or a little shade in very warm places. It does not mean that they will adopt the growth patterns of the cactus, especially because this plant needs constant watering (in small quantities), very constant. Beans require good drainage for their growth.
Each vegetation have its own characteristics and the power of adaptation. A green bean cannot survive in a desert like a cactus in desert without water. It can only grow thick in soil with proper water content and nutrients.
What is cactus?Cactus is a type of plant grow in dry regions such as deserts. It can adapt in deserts without water for long time because, the plant have enough water storage in its stem.
Domestic vegetation such as bean, pea, nuts etc ill not grow in dry regions because they cannot adapt in deserts without water. The soil in deserts is dry and have no nutrients.
These conditions prevent the growth of vegetables in desert areas. Moreover, desert have summer season only. The extreme temperature over there will cause the normal plants to diminish.
Therefore, planting green bean in deserts will not make it grow thick like a cactus plant.
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An aqueous solution has a hydroxide-ion concentration of 1.0x10^-3M. What is the pH of the solution?
a.11
b.3
c.-3
d.7
What is the wavelength of spectral line resulted from the electron transition from n=3 to n=2 in a hydrogen atom.
Answer:
[tex]\lambda=6.56x10^{-7}m[/tex]
Explanation:
Hello there!
In this case, it possible to use the Rydberg equation in order to calculate the wavelength for this transition from n=3 to n=2 as shown below:
[tex]\frac{1}{\lambda} =R_H(\frac{1}{n_f^2}-\frac{1}{n_i^2} )[/tex]
Thus, we plug in the corresponding energy levels and the Rydberg constant to obtain:
[tex]\frac{1}{\lambda} =10973731.6m^{-1}(\frac{1}{2^2}-\frac{1}{3^2} )\\\\\frac{1}{\lambda} =1524129.4m^{-1}\\\\\lambda=\frac{1}{1524129.4m^{-1}} \\\\\lambda=6.56x10^{-7}m[/tex]
Best regards!
how much heat is required to increase the temperature of 20 grams of water by 26 degrees celsius?
Answer: 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.
Explanation:
Given: Mass = 20 g
Change in temperature = [tex]26^{o}C[/tex]
The standard value of specific heat of water is [tex]4.184 J/ g^{o}C[/tex]
Formula used to calculate the heat energy is as follows.
[tex]q = m \times C \times \Delta T[/tex]
where,
q = heat energy
m = mass of substance
C = specific heat of substance
[tex]\Delta T[/tex] = change in temperature
Substitute the values into above formula as follows.
[tex]q = m \times C \times \Delta T\\= 20 g \times 4.184 J/g ^{o}C \times 26^{o}C\\= 2175.68 J[/tex]
Thus, we can conclude that 2175.68 J heat is required to increase the temperature of 20 grams of water by 26 degrees celsius.
¿
Que es la materia y qué es el volumen que ocupa la materia?
Todo en un estado sólido de materia tiene una forma y una longitud distintas. El volumen de un objeto es la cantidad de espacio que ocupa. Un sólido es un bloque de madera que conserva su forma y volumen cuando se coloca sobre una mesa.
Hope that helps!!!
¡Espero que ayude!
At 35.0°C and 3.00 atm pressure, a gas has a volume of 1.40 L. What pressure does the gas have at 0.00°C and a volume of 0.950 L? Which equation should you use? P subscript 2 equals StartFraction P subscript 1 V subscript 1 T subscript 2 over T subscript 1 V subscript 2 EndFraction. P subscript 2 equals StartFraction T subscript 1 V subscript 2 over P subscript 1 V subscript 1 T subscript 2 EndFraction. P subscript 2 StartFraction equals V subscript 1 V subscript 2 over T subscript 1 T subscript 2 EndFraction P subscript 1.
Answer:
a
3.92
Explanation:
A gas of certain mass occupies volume of 1.2 L at 37°C and 3 atm. At what temperature will the volume and pressure of this gas become one-third of their initial values?
Answer: At a temperature of 34.44 K the volume and pressure of this gas become one-third of their initial values.
Explanation:
Given : [tex]V_{1}[/tex] = 1.2 L, [tex]T_{1} = 37^{o}C = (37 + 273) K = 310 K[/tex]
[tex]P_{1}[/tex] = 3 atm, [tex]V_{2} = \frac{1.2}{3} = 0.4 L[/tex] , [tex]P_{2} = \frac{3}{3} = 1 atm[/tex]
Formula used to calculate the final temperature is as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{3 atm \times 1.2 L}{310 K} = \frac{1 atm \times 0.4 L}{T_{2}}\\T_{2} = \frac{1 atm \times 0.4 L \times 310 K}{3 atm \times 1.2 L}\\= \frac{124}{3.6} K\\= 34.44 K[/tex]
Thus, we can conclude that the final temperature is 34.44 K.
Select the correct answer.
Which unit is used for measuring atomic mass?
AMU-aka
Atomic mass unit
Answer:
The unit of Atomic mass is "amu"
Explanation:
Atomic mass unit
The total pressure of all the gases inside a metal container is 9.8 atm. If the partial pressure of the oxygen in the container is 4.2 atm, what is the partial pressure of the rest of the gases in the container other than the oxygen?
5.6 atm is the partial pressure of the rest of the gases in the container other than the oxygen.
What is partial pressure?Each gas in a mixture adds to the overall pressure of a mixture. This portion represents the pressure. The pressure a gas would have if it were in its own volume and at its own temperature is known as the partial pressure. According to Dalton's law, the pressure distribution of an ideal gas mixture is equal to the combined partial pressures of the component gases.
The study of partial pressure is significant in the domains of physics, chemistry, and biology. The partial pressure of oxygen or carbon dioxide in the blood is used to calculate blood levels of each substance. The overall pressure in a container is equal to the sum of the partial pressures. The remaining gases must make up the remaining 5.6 atm if the oxygen partial pressure equals 4.2 atm and the sun reaches 9.8 atm in pressure.
Therefore, 5.6 atm is the partial pressure of the rest of the gases in the container other than the oxygen.
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What is the amount of moles of NaOH, if the solution molarity is .33 M NaOH in 0.75 L solution
Answer:
The amount of moles of NaOH is 0.0495
Explanation:
Molarity is a measure of concentration that is defined as the number of moles of solute that are dissolved in a given volume.
In symbolic form molarity is presented as:
[tex]Molarity=\frac{number of moles of solute}{volume}[/tex]
Molarity is expressed in units [tex]\frac{moles}{liter}[/tex].
In this case:
Molarity= 0.33 MNumber of moles of solute= ?Volume= 0.75 LReplacing in the definition of molarity:
[tex]0.33 M=\frac{number of moles of solute}{0.75 L}[/tex]
number of moles of solute= 0.33 M* 0.75 L
number of moles of solute= 0.0495 moles
The amount of moles of NaOH is 0.0495
Answer:
0.248 moles of NaOH
Explanation:
Concept of Molarity is mol/L
[x] = 1 M
1 mol of x contained in 1 L of solution. We write molar concentrations between []
M = mol/L then M . L = mol
Our solution is NaOH
0.33 M . 0.75L = mol
This solution contains 0.248 moles of NaOH
Given the following data set, calculate the unknown quantity.
P= 1.23 mmHg atm, V=? kL, n= .773 mol, T= 152 °C
Answer:
V ≈ 16,662.63 L
Explanation:
The data given in the question includes;
The pressure in the medium, P = 1.23 mmHg
The number of moles of the substance present in the medium, n = 0.773 mol
The temperature of the substance in the medium, T = 152 °C = 425.15 K
The unknown quantity, V = The volume filled by the substance
The ideal gas law equation that can be used to find the unknown volume is given here as follows;
P × V = n × R × T
Where;
R = The Universal Gas Constant = 62.363 mmHg·L·mol⁻¹·K⁻¹
From the ideal gas law equation, we get;
V = n × R × T/P
Plugging in the values, gives;
V = 0.773 mol × 62.363 mmHg·L·mol⁻¹·K⁻¹ × 425.15 K/(1.23 mmHg) = 16,662.6305405 L
The volume occupied, which is the unknown quantity, V ≈ 16,662.63 L.
identify the state of matter in the box,
Answer:
gas
Explanation:
particles are very far apart
The given diagram represents gaseous state of matter. Both a volume and a definite form are absent from a gas. The separation of gas particles is great.
What is state of matter?Solids, liquids, gases, plus plasma are the four states of matter that may be found in daily life. However, a number of additional states of matter have indeed been found.
Some of these additional states are created when a material transitions among two states of matter and doesn't actually exhibit the characteristics of either state. The most exotic are others. Both a volume and a definite form are absent from a gas. The separation of gas particles is great. The gas in a balloon and the air are two examples of gases. The given diagram represents gaseous state of matter.
Therefore, the given diagram represents gaseous state of matter.
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What happens to the pH of the solution as you add more substance to it?
Answer:
If it's a buffer solution, the pH remains unchanged.
If it's a normal solution, and an acidic substance is added to it, the pH lowers.
If a basic substance is added to it, the pH increases.
you have a coin with a volume of 10cm3 and a mass of 23g. What is the density of the coin
Answer:
2.3 grams per cubic cm
Explanation:
Density is equal to mass over volume, so
23/10=2.3
Hi can anyone help me ?
Answer:
its 4
Explanation:
When calcium carbonate is heated strongly, carbon dioxide gas is evolved. CaCO3(s) → CaO(s) + CO2 (g) If 4.74 g of calcium carbonate is heated, what volume of CO2 (g) would be produced when collected at STP?
Answer:
1.06 liters of gas are produced
Explanation:
Our reaction is:
CaCO₃(s) → CaO(s) + CO₂ (g)
This is the decomposition of calcium carbonate.
Ratio is 1:1:1
1 mol of carbonate can decompose to 1 mol of oxide and 1 mol of oxygen.
We convert mass to moles:
4.74 g . 1 mol /100.08g = 0.0474 moles
These are the moles of oxygen produced.
We know that 1 mol of any gas at STP is contained in 22.4L
0.0474 mol . 22.4L /mol = 1.06 L
The atomic model that describes an atom as a spherical object containing a certain number of electrons trapped in a mass of positive charge is often called the ___________ model.
help
Go to the To Scale tab at the bottom of the simulation, and select Path from the central menu on the right. Set up a Planet-Moon simulation. Use the sliders to make both the planet and the moon as massive as possible, and then begin the simulation. What do you notice about the moon’s motion when it is closest to the planet? What about when it is farthest away?
When it could be closest to the Earth and farthest from it, the Moon passes the fastest as well as the slowest.
What is Earth?The only cosmic object known to contain life is Earth, which would be located third from the Sun. Although the Solar System contains enormous amounts of water, only Earth is home to liquid surface water. The oceans cover over 71% of Earth's crust, dwarfing its polar ice, lakes, including rivers.
What is moon?The sole natural satellite of Earth would be the Moon. It makes up the Earth-Moon satellite system with Earth. Its diameter is equivalent to one-fourth of Earth. It should be the biggest satellite of a planet compared to the main, bigger than any existing dwarf planet, as well as the fifth biggest satellite in the Planetary System.
When sliders to make both the planet and the moon as massive as possible, and then begin the simulation. they noticed, it could be closest to the Earth and farthest from it, the Moon passes the fastest as well as the slowest.
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