The surface area of a globe in Mr.Patton’s classroom is about 452.39 square inches. Find its volume in cubic inches . Use 3.14 for pi. Round to the nearest whole number

Answer:

A

Step-by-step explanation:

because___________________________________

Answer:

B) True

Step-by-step explanation:

SSS or Side-Side-Side is used to prove two triangles are congruent.

The unique solution to the initial value problem of differential equation is y(t) = -t^2 + 2t + 3sin(3t) - 1 with e(t) = -t^2 + 2t + 3sin(3t) - 9, a = 2, and B = -21.

To find the solution to the initial value problem, we first need to solve the differential equation.

Taking the derivative of y(t), we get:

y'(t) = -2t + a

Taking the derivative again, we get:

y''(t) = -2

Substituting y''(t) into the differential equation, we get:

y''(t) + 2y'(t) + 10y(t) = 20sin(3t)

Substituting y'(t) and y(t) into the equation, we get:

-2 + 2a + 10(-2t + a) = 20sin(3t)

Simplifying, we get:

8a - 20t = 20sin(3t) + 2

Using the initial condition y(0) = 2, we get:

y(0) = -2(0) + a = 2

Solving for a, we get:

a = 2

Using the other initial condition y'(0) = 21, we get:

y'(0) = -2(0) + 2(21) + B = 21

Solving for B, we get:

B = -21

Therefore, the solution to the initial value problem is:

y(t) = -t^2 + 2t + 3sin(3t) - 1

Thus, we have e(t) = y(t) - 8, so

e(t) = -t^2 + 2t + 3sin(3t) - 9

and a = 2, B = -21.

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_____The given question is incomplete, the complete question is given below:

Consider the initial value problem >= [22. 2.1]+20). 361) = [2] Suppose we know that (t) = -2t + a 21? + is the unique solution to this initial value problem. Find e(t) and the constants and B. a = B= 8(t) =

Answer:

the answer would be 100 I guess

Answer:

x = 52.2

Step-by-step explanation:

Add 4x - 4y^2 = 36 and x + 2y^2 = 225

x + 2y^2 + 4x - 4y^2 = 225 + 36

5x = 261

x = 261/5=52.2

150 - 141 = 9 seniors are not enrolled in any classes.

The area of mathematics known as statistics is used to gather, analyse, and interpret data. To predict the future, determine the likelihood that a specific event will occur, or learn more about a survey, statistics can be employed.

The Venn diagram reveals the amount of seniors enrolling in at least one of the courses as follows:

80 + 41 + 54 - 10 - 19 - 12 + 7

= 141

Therefore, 150 - 141 = 9 seniors are not enrolled in any classes.

= 9

So, there are 9 seniors taking none of the courses. Answer: 9.

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By answering the presented question, we may conclude that Therefore, 1  expressions cm on the map corresponds to a real distance of 3.2 km. 

In mathematics, an expression is a collection of integers, variables, and complex mathematical (such as arithmetic, subtraction, multiplication, division, multiplications, and so on) that describes a quantity or value. Phrases can be simple, such as "3 + 4," or complicated, such as They may also contain functions like "sin(x)" or "log(y)". Expressions can be evaluated by swapping the variables with their values and performing the arithmetic operations in the order specified. If x = 2, for example, the formula "3x + 5" equals 3(2) + 5 = 11. Expressions are commonly used in mathematics to describe real-world situations, construct equations, and simplify complicated mathematical topics.

Scale 1:

320000 means that 1 unit on the map represents his 320000 units in the real world.

To find the actual distance represented by 1 cm on the map, you need to convert the units to the same scale.

1 kilometer = 100000 cm

So,

1 unit on the map = 320000 units in the real world

1 cm on the map = (1/100000) km in the real world

Multiplying both sides by 1 cm gives:

1 cm on the map = (1/100000) km * 320000

A simplification of this expression:

1 cm on the map = 3.2 km

Therefore, 1 cm on the map corresponds to a real distance of 3.2 km. 

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Answer:

To find the annual growth rate percentage, we can use the formula:

annual growth rate = [(final value / initial value)^(1/number of years)] - 1

where "final value" is the value in the ending year, "initial value" is the value in the starting year, and "number of years" is the total number of years between the starting and ending years.

Using the given values, we have:

annual growth rate = [(148,000 / 108,000)^(1/20)] - 1

= 0.0226 or 2.26%

So the house appreciated at an annual growth rate of 2.26%.

To find the value of the house in 2010, we can use the same growth rate to project the value from 2005 to 2010:

value in 2010 = 148,000 * (1 + 0.0226)^5

= $175,465.11 (rounded to the nearest cent)

Therefore, the value of the house in the year 2010 was $175,465.11.

In equation 7(5x + 2) = -4(6 - 5x), Using the Distributive Property, we get 35x + 14 = -24 + 20x. So, the correct option is D).

To solve the equation 7(5x + 2) = -4(6 - 5x), a good first step is to use the Distributive Property to simplify both sides of the equation. Distributing the 7 and -4 on the left and right sides, respectively, we get

35x + 14 = -24 - 20x.

Next, we can combine like terms by adding 20x to both sides to get 55x + 14 = -24. Then, subtracting 14 from both sides, we get 55x = -38. Finally, we can solve for x by dividing both sides by 55, giving us x = -38/55. Therefore, the solution to the equation is x = -38/55.

The evaluation process involves performing arithmetic operations in a logical order to simplify the equation step-by-step until a solution is reached. So, the correct answer is D).

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The given prescription lacks important information about the frequency and route of administration. Knowing how often a medication should be taken and how it should be administered is crucial for ensuring that patients receive the appropriate dose and achieve the desired therapeutic effect.

Without the frequency information of how (e.g., orally, intravenously, etc.) and when  (e.g., daily, twice daily, etc.)  to take medicine on prescription, patients may take the medication incorrectly or miss doses, potentially leading to ineffective treatment or adverse effects.

Healthcare providers should always provide clear and complete instructions for medication use to ensure patient safety and optimal treatment outcomes.

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In the diagram given IJK≅LJK ,the length cannot be negative, the only valid solution is g = 6. Therefore, the length of the segment KJ is 6 meters.

Length is a physical dimension that measures the distance between two points or the size of an object along one dimension.

It is commonly measured using standard units of length such as meters, feet, inches, and centimeters.

Given that KM is the bisector line of line IM and J is the bisector point on line IL. Two triangles are formed, △IJK and △LJK, on line IL in the upward and downward direction, respectively. We are given the lengths of IK, JN, LM, and KJ, and we need to find the value of g such that IJK≅LJK.

Since the two triangles are similar, their corresponding sides are proportional. Using the side proportionality theorem, we have:

KJ/LM = IJ/JL

Substituting the given values, we get:

g/10 = 5/(4+g)

Cross-multiplying, we get:

g(4+g) = 50

Expanding and simplifying, we get:

g²+ 4g - 50 = 0

Using the quadratic formula, we get:

g = (-4 ± √(4² + 4(50)))/2

g = (-4 ± √(256))/2

g = (-4 ± 16)/2

g = -10 or g = 6

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Answer: 37.5

Step-by-step explanation:

75 - 180 = 105

105 degrees = the obtuse angle, bottom triangle.

75/2= 37.5 (since both sides of the bottom triangle are equal angles)

Answer:

A linear function would be the best type of equation to model this situation. The total cost of renting the truck increases linearly with the number of miles driven. The initial charge of $60 can be considered as the y-intercept of the linear function, and the additional fee per mile driven can be considered as the slope of the line. Therefore, the equation that models this situation can be written in the form y = mx + b, where y is the total cost of renting the truck, x is the number of miles driven, m is the additional fee per mile driven (the slope of the line), and b is the initial charge of $60 (the y-intercept).

Answer:

A linear function would be the best type of equation to model this function.

Step-by-step explanation:

The total cost of renting the truck is composed of two parts:

The initial charge of $60 is the fixed charge, and the additional fee is the variable charge that is proportional to the number of miles driven.

Let "x" be the number of miles driven and "y" be the total cost of the rental (in dollars), then the linear equation is:

y = mx + 60

where "m" is the additional fee (in dollars) per mile driven.

Therefore, a linear function, in the form y = mx + b, where m represents the slope or rate of change, and b represents the initial fixed charge, is the most appropriate function to model this situation.

The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

A cylinder is a three-dimensional geometric form made up of two circular bases that are parallel to one another and are joined by a curved lateral surface. It can be pictured as a solid item with a constant circular cross-section along its entire length. The measurements of a cylinder, such as the radius and height of the circular bases, affect its characteristics. The surface area, volume, and horizontal surface area of a cylinder are some of its typical characteristics. Mathematical formulas can be used to determine these properties.

given

The following algorithm determines a cylinder's surface area:

[tex]A = 2\pi r^2 + 2\pi rh[/tex]

where r is the cylinder's base's radius, h is the cylinder's height, and (pi) is a mathematical constant roughly equivalent to 3.14.

Inputting the numbers provided yields:

[tex]A = 2\pi (9)^2 + 2\pi (9)(14)\\[/tex]

A = 2π(81) + 2π(126) 

A = 162π + 252π

A = 414π

The cylindrical has a surface area of 414 square units due to its 9-unit radius and 14-unit height.

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Step-by-step explanation:

A + B = 188

A = 188 - B - (1)

Now,

A - B = 34

188 - B - B = 34 (Substituting eqn 1 in A)

188 - 34 = 2B

154 = 2B

• B = 77 tons

Now

A = 188 - B

A = 188 - 77

A = 111 tons

To determine whether a transformation is one-to-one or onto, one must analyze its behavior and properties, such as passing the horizontal line test for one-to-one or checking if the range equals the codomain for onto.

In mathematical terms, a transformation refers to a function that maps elements from one set, called the domain, to another set, called the range. A transformation is said to be one-to-one if no two distinct elements in the domain are mapped to the same element in the range. This means that each element in the range is associated with a unique element in the domain.

On the other hand, a transformation is onto if every element in the range is mapped to by at least one element in the domain. In other words, for each element in the range, there exists at least one element in the domain that maps to it.

To determine whether a transformation is one-to-one or onto, one can analyze its properties and behavior. For example, a transformation is one-to-one if and only if it passes the horizontal line test. This means that no two points in the domain map to the same point on a horizontal line. To determine if a transformation is onto, one can check if the range of the transformation equals the codomain.

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The given question is incomplete, the complete question is:

How to determine the transformation is one to one and/or onto?

Answer:

V=lwh

=2×2×2=8

720÷8=90

90 cubes

Answer:

[tex] 2^\frac{3}{10} [/tex]

Step-by-step explanation:

[tex] \dfrac{2^\frac{2}{5}}{2^\frac{1}{10}} = [/tex]

[tex]= 2^{\frac{2}{5} - \frac{1}{10}}[/tex]

[tex]= 2^{\frac{4}{10} - \frac{1}{10}}[/tex]

[tex] = 2^\frac{3}{10} [/tex]

The required probability of W being greater than 6 is 0.065 or 6.5%.

A probability value represents the likelihood that an occurrence will take place. In terms of percentage notation, it is stated as a number between 0 and 1, or between 0% and 100%. The higher the probability, the more probable it is that the event will take place.

The complement of an event A is the event that A does not occur. In this case, the event A is "W ≤ 6", and its complement is "W > 6".

We are given that P(W ≤ 6) = 0.935. Using the complement rule of probability, we can find the probability of W > 6 as follows:

[tex]$$P(W > 6) = 1 - P(W \leq 6)$$[/tex]

Substituting the given value, we have:

P(W > 6) = 1 - 0.935 = 0.065

Therefore, the probability of W being greater than 6 is 0.065 or 6.5%.

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Answer: The total cost of buying 5 balls individually is $2.00 x 5 = $10.00.

The box costs $8.50, which means it is $10.00 - $8.50 = $1.50 cheaper to buy the box.

To calculate the percentage difference, we can use the formula:

% difference = (difference ÷ original value) x 100%

In this case, the difference is $1.50, and the original value is $10.00.

% difference = ($1.50 ÷ $10.00) x 100%

% difference = 0.15 x 100%

% difference = 15%

Therefore, it is 15% cheaper to buy the box than to buy 5 individual balls.

Step-by-step explanation:

Answer:

57

57

123

123

57

57

123

that's all.

Answer:

m<1 = 57°

m<2 = m<1 = 57°

m<3 = x = 123°

m<4 = x = 123°

m<5 = m<1 = 57°

m<6 = m<5 = 57°

m<7 = m<4 = 123°

Step-by-step explanation:

[tex]{ \tt{m \angle 1 + x = 180 \degree}} \\ { \colorbox{silver}{corresponding \: angles}} \\ { \tt{m \angle 1 = 180 - 123}} \\ { \tt{ \underline{ \: m \angle 1 = 57 \degree \: }}}[/tex]

The equation of the tangent line is y = (-1/49)x + 8/49. 2. The equation of the normal line is y = 49x - 342.

A line that meets a curve at a point and has the same slope as the curve there is said to be the tangent line to that curve. A line that is perpendicular to the tangent line at a given position is the normal line to a curve at that location. In other words, the normal line's slope equals the tangent line's slope's negative reciprocal. The normal line is helpful for determining the direction of greatest change of the curve at a place whereas the tangent line gives information about the instantaneous rate of change of the curve at that point.

The given function is f(x) = 1/x.

The slope of the function is the derivative of the function thus,

f(x) = 1/x

f'(x) = -1/x²

f'(7) = -1/49

The equation of the line is given as:

y - y1 = m(x - x1)

where, m is the slope of the equation.

The equation of the tangent line is:

y - f(7) = f'(7)(x - 7)

y - 1/7 = -1/49(x - 7)

y = (-1/49)x + 8/49

b. The equation of the normal line to the graph is given as:

The slope of the normal line is negative and opposite of the tangent line.

That is,

m = 49.

y - f(7) = 49(x - 7)

y - 1/7 = 49(x - 7)

y = 49x - 342

Hence, the equation of the tangent line is y = (-1/49)x + 8/49. 2. The equation of the normal line is y = 49x - 342.

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In response to the stated question, we may state that Hence, the 95% CI function for u is (16.72, 19.48), rounded to two decimal places in increasing order.

In mathematics, a function is a connection between two sets of numbers in which each member of the first set (known as the domain) corresponds to a single element in the second set (called the range). In other words, a function takes inputs from one set and produces outputs from another. Inputs are commonly represented by the variable x, whereas outputs are represented by the variable y. A function can be described using an equation or a graph. The equation y = 2x + 1 represents a linear function in which each value of x yields a distinct value of y.v

We use the following formula to create a confidence interval around the population mean u:

CI = x ± z*(s/√n)

where x represents the sample mean, s represents the sample standard deviation, n represents the sample size, z represents the z-score associated with the desired degree of confidence, and CI represents the confidence interval.

Because the degree of confidence is 95%, we must calculate the z-score that corresponds to the standard normal distribution's middle 95%. This is roughly 1.96 and may be determined with a z-table or calculator.

CI = 18.1 ± 1.96*(4.1/√34)

CI = 18.1 ± 1.96*(0.704)

CI = 18.1 ± 1.38

Hence, the 95% CI for u is (16.72, 19.48), rounded to two decimal places in increasing order.

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The area under the curve y = 1/ (x^2 + 6x -16) from x = t to x = 6 is 1/10( ln(4) - 1/10 ln(t+8))

To find the area under the curve y = 1/ (x^2 + 6x -16) from x = t to x = 6, where t > 2, we need to evaluate the definite integral:

∫[t,6] 1/ (x^2 + 6x -16) dx

To solve this integral, we can use partial fraction decomposition. First, we factor the denominator:

x^2 + 6x -16 = (x+8)(x-2)

Then, we can write:

1/ (x^2 + 6x -16) = A/(x+8) + B/(x-2)

Multiplying both sides by (x+8)(x-2), we get:

1 = A(x-2) + B(x+8)

Setting x = -8, we get:

1 = A(-10)

So, A = -1/10.

Setting x = 2, we get:

1 = B(10)

So, B = 1/10.

Therefore, we can write:

1/ (x^2 + 6x -16) = -1/10(x+8) + 1/10(x-2)

Substituting this into the integral, we get:

∫[t,6] 1/ (x^2 + 6x -16) dx = ∫[t,6] (-1/10(x+8) + 1/10(x-2)) dx

Integrating, we get:

= [-1/10 ln|x+8| + 1/10 ln|x-2|] from t to 6

= 1/10 ln|6-2| - 1/10 ln|t+8|

= 1/10 ln(4) - 1/10 ln(t+8)

Therefore, the area is: 1/10( ln(4) - 1/10 ln(t+8))

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_____The given question is incomplete, the complete question is given below:

begin by finding the area under the curve from to y = 1/ (x^2 + 6x -16) from x = t to x = 6, t>2 this area can be written as the definite integral

a) The standard error of mean for this data set is approximately 0.141.

b) The approximate 95% margin of error is approximately 0.282.

c) The approximate 95% confidence interval for the population mean age is 19.824 to 20.376.

a) The standard error of mean (SEM) is given by the formula: SEM = s / sqrt(n), where s is the sample standard deviation and n is the sample size. Plugging in the values given, we have:

SEM = 1.8 / sqrt(163) ≈ 0.141

So the standard error of the mean is approximately 0.141.

b) The approximate 95% margin of error (MOE) can be calculated using the formula: MOE ≈ 2 * SEM. Plugging in the SEM value from part 1, we get:

MOE ≈ 2 * 0.141 ≈ 0.282

So the approximate 95% margin of error is approximately 0.282.

c) The approximate 95% confidence interval (CI) for the population mean age can be calculated using the formula: CI = x ± (z*SEM), where x is the sample mean, z is the critical value from the standard normal distribution corresponding to the desired level of confidence (95% in this case), and SEM is the standard error of the mean. The critical value for 95% confidence is approximately 1.96. Plugging in the values, we get

CI = 20.1 ± (1.96 * 0.141) ≈ 19.824 to 20.376

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The set of all x-values that are at a distance of 13 or less from the number 8 in the interval notation is given by  [ -5, 21 ].

The distance between x and 8 is |x - 8|.

Find all the values of x such that |x - 8| ≤ 13.

This inequality can be rewritten as follow,

|x - 8| ≤ 13

⇒ -13 ≤ x - 8 ≤ 13

Now,

Adding 8 to all sides of the inequality we get,

⇒  -13 +  8 ≤ x - 8 + 8 ≤ 13 + 8

⇒ -5 ≤ x ≤ 21

Therefore, all the x-values which are at a distance of 13 or less from the number 8 represented in the interval notation as [ -5, 21 ].

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The chance that both numbers drawn are even numbers is 8/21.

The probability refers to the measure of the likelihood or chance of an event occurring. It is a numerical value between 0 and 1, where 0 indicates that the event is impossible, and 1 indicates that the event is certain.

There are 4 even numbers and 3 odd numbers in the first box, and 2 even numbers and 1 odd number in the second box.

The probability of drawing an even number from the first box is 4/7, and the probability of drawing an even number from the second box is 2/3.

By the multiplication rule of probability, the probability of drawing an even number from both boxes is

(4/7) × (2/3) = 8/21

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Option B: The ratio of the volume of soil to the volume of sand is 1:4.

Looking at the table, we can see that for every 100 m³ increase in soil, the sand volume increases by 25 m³. This gives us a ratio of 4:1, which means that the volume of sand is one-fourth of the volume of soil. Therefore, option B is correct.

Option D: The equation y = 4x models the relationship.

We can see that the volume of sand is always one-fourth of the volume of soil. Therefore, we can write y = (1/4)x or y = 0.25x. This equation is the same as y = 4x. Therefore, option D is also correct.

So, the correct statements are B and D.

In mathematics, a graph is a visual representation of data or a mathematical function. It consists of a set of points or vertices connected by lines or curves called edges or arcs, which represent the relationships between the points. Graphs can be used to show trends, patterns, and relationships in data, and they are commonly used in fields such as statistics, economics, and computer science. Some common types of graphs include line graphs, bar graphs, pie charts, scatterplots, and network graphs.

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The table mentioned in the question has been attached below.

Answer: c

Step-by-step explanation: i dont have one

1/2 x (6.08 - 2) (6.08 - 2) is the correct numerical expression for "one-half the difference of 6 and 8 hundredths and 2 " .

An expression, as used in computer programming, is a grouping of values, variables, operators, and/or function calls that the computer evaluates to produce a final value. For instance, the equation 2 + 3 combines the numbers 2 and 3 using the + operator to produce the number 5. Similar to this, the equation x * (y + z) produces a value based on the current values of the variables x, y, and z by combining the variables x, y, and z with the * and + operators.

given

In terms of numbers, the phrase "one-half the difference of 6 and 8 hundredths and 2" is expressed as follows:

1/2 x (6.08 - 2) (6.08 - 2)

1/2 x (6.08 - 2) (6.08 - 2) is the correct numerical expression for "one-half the difference of 6 and 8 hundredths and 2 " .

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