The temperature of a 350. mL sample of gas increases from 27 °C to 227 °C. What is the final volume of the sample of gas, if the pressure and amount of gas in the container is kept constant?
Group of answer choices

Answers

Answer 1

Answer:

[tex]V_2=583.3mL[/tex]

Explanation:

Hello,

In this case, for the given constant amount and pressure of the, we apply the Charles' law which allows us to understand the volume-pressure behavior as a directly proportional relationship:

[tex]\frac{V_1}{T_1} =\frac{V_2}{T_2}[/tex]

Thus, since we need to compute the volume after the temperature increase (which must be expressed in absolute Kelvins), we obtain V2 as:

[tex]V_2=\frac{V_1T_2}{T_1} =\frac{350.0mL*(227+273.15)K}{(27+273.15)K}\\ \\V_2=583.3mL[/tex]

Best regards.


Related Questions


What is the molar mass of ethanol (C2H60)?

Answers

Answer:

46.07 g/mol is the molar mass of ethonal

Which picture shows how the moon from earth when it’s in the position

Answers

Explanation:

This picture shows how the moon from earth when it is in position

If an insufficient amount of liquid unknown had been used, how would this have effected the value of the experimental molar mass

Answers

Answer:

Actual yield reduces the more.

Explanation:

An actual yield of the course of a chemical reaction is the mass of a product actually obtained from the reaction.

In practice you see it and It is usually less than the theoretical yield.

Various reasons may come up to explain this away but here is one:

• incomplete reactions, simply put here some of the reactants do not react to form the product.

The same applies in the question about the actual yield will reduce significantly in molar mass now that insufficient amount of reagent are used.

4. A taxi ride costs $5 plus .75 cents per mile. If I
ride for 120 miles, how much will be charged?​

Answers

Answer:

$95

Explanation:

.75 x 120 = 90

90+5 = 95

What are 3 stages of the water cycle are

Answers

Evaporation,condensation, and precipitation.

How many moles
are equal to
4.11x1023
molecules of
CO2?

Answers

Explanation:

6.02×1023 culture atoms have a mass of 63.5g. 12.0g. c +23.0g O2__44.0g CO2.(12.0+16.0+16.0=44.0g).1 mol 1 mol. 1 mol number molecules weight

The number of molecules in one mole of carbon dioxide is 6.02 × 10²³. Therefore, the number of moles of carbon dioxide which contains 4.11 × 10²³ molecules is 0.68.

What is Avogadro number ?

The number of atoms that constitutes one mole of a substance is called Avogadro number. It is equal to  6.02 × 10²³. Thus, one mole of every elements contains Avogadro number of atoms.

Similarly, one mole of a compound contains  6.02 × 10²³ number of molecules. Thus, one mole of carbon dioxide contains these much molecules.

Given the number of molecules of carbon dioxide = 4.11 × 10²³

Then, no.of moles = number of molecules/ Avogadro number.

no.of moles = 4.11 × 10²³ /6.022 × 10²³  = 0.68.

Therefore, the number of moles of CO₂ that contains 4.11 × 10²³  molecules is 0.68.

Find more on Avogadro number:

https://brainly.com/question/28834341

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What is the symbol for the entity that has 17 protons, 20 neutrons, and 18 electrons?

Answers

hEy!!!

Chlorine(CL) is the symbol for the entity that has 17 protons,20 neutrons and 18 electrons.

Hope it will be helpful to you...

Answer:chlorine

Explanation:

Two identical light bulbs are connected to a battery in a series circuit.
An ammeter is wired into the circuit at measures a current of the
battery to be 0.5 Amps. The two light bulbs are then wired in parallel.
The ammeter shows that the current:

Answers

Answer:

0.10 amps

Explanation:

18.35 mL of an HCN solution were titrated with 35.4mL of a 0.268M NaOH solution to reach the equivalence point. What is the molarity of the HCN solution

Answers

Answer:

0.517

Explanation:

HCN + NaOH → NaCN + H2O [balanced as written]

(35.4 mL) x (0.268 M NaOH) x (1 mol HCN / 1 mol NaOH) / (18.35 mL HCN) = 0.517 M HCN

Answer: 0.517

Explanation:

What is the molarity of sodium hydroxide solution made by combining 2.0 L of 0.60
NaOH With 495 mL 3.0 M NaOH? Assume the volumes of the two solutions to be additive___M

Answers

Answer:

[tex]M=1.1M[/tex]

Explanation:

Hello,

In this case, since we are mixing two NaOH solutions, the first step is to compute the total moles once the mixing is done, by using the volumes and concentrations of each solutions and subsequently adding them:

[tex]n_T=2.0L*0.60\frac{mol}{L}+495mL*\frac{1L}{1000mL}*3.0\frac{mol}{L}= 2.7molNaOH[/tex]

Next, we compute the total volume by adding the volume of each solution:

[tex]V_T=2.0L+495mL*\frac{1L}{1000mL}= 2.495L[/tex]

Finally, we compute the molarity of the resulting solution by the division between the total moles and the total volume:

[tex]M=\frac{2.7mol}{2.495L}\\ \\M=1.1M[/tex]

Best regards.

What is the mass defect of a mole of nuclei with 1.8 x 10^15 J/mol binding
energy?

Answers

Answer:

2.0 x 10^-2 kg/mol

Explanation:

Describe an autopsy table

Answers

After the body is cleaned, the body is weighed and measured before being placed on the autopsy table for reexamination. The autopsy table is typically a slanted, aluminum table with raised edges that has several faucets and drains used to wash away collecting blood during the internal investigation.

Answer:

A table used to scientifically determine the cause of death of a human or animal

Explanation:

The change in entropy, ΔS∘rxn , is related to the the change in the number of moles of gas molecules, Δngas . Determine the change in the moles of gas for each of the reactions and decide if the entropy increases, decreases, or has little or no change. A. 2H2(g)+O2(g) ⟶ 2H2O(l) Δngas= mol The entropy, ΔS∘rxn , increases. decreases. has little or no change.

Answers

Explanation:

Entropy of a reaction ΔS∘rxn is the degree of disoderliness in a system. Gases generally have a higher degree of disorder compared to liquids. Hence for the reaction 2H2(g)+O2(g) ⟶ 2H2O(l), the entropy decreases sice the reactants are in the gaseous state and the products is in the liquid state of matter

What is the hydronium ion concentration of a 0.100 M acetic acid solution with Ka = 1.8 × 10-5? The equation for the dissociation of acetic acid is: CH3CO2H(aq) + H2O(l) ⇌ H3O+(aq) + CH3CO2-(aq) What is the hydronium ion concentration of a 0.100 M acetic acid solution with Ka = 1.8 × 10-5? The equation for the dissociation of acetic acid is: CH3CO2H(aq) + H2O(l) ⇌ H3O+(aq) + CH3CO2-(aq) 1.3 × 10-2 M 4.2 × 10-2 M 1.3 × 10-3 M 4.2 × 10-3 M

Answers

Answer:

1.3×10⁻³ M

Explanation:

Hello,

In this case, given the dissociation reaction of acetic acid:

[tex]CH_3CO_2H(aq) + H_2O(l) \rightleftharpoons H_3O^+(aq) + CH_3CO_2^-(aq)[/tex]

We can write the law of mass action for it:

[tex]Ka=\frac{[H_3O^+][CH_3CO_2^-]}{[CH_3CO_2H]}[/tex]

Of course, excluding the water as heterogeneous substances are not included. Then, in terms of the change [tex]x[/tex] due to the dissociation extent, we are able to rewrite it as shown below:

[tex]1.8x10^{-5}=\frac{x*x}{0.100-x}[/tex]

Thus, via the quadratic equation or solve, we obtain the following solutions:

[tex]x_1=-0.00135M\\x_2=0.00133M[/tex]

Obviously, the solution is 0.00133M which match with the hydronium concentration, thus, answer is: 1.3×10⁻³ M in scientific notation.

Regards.

Answer:

1.3×10^-3 M

Explanation:

Step 1:

Data obtained from the question:

Equilibrium constant (Ka) = 1.8×10^-5

Concentration of acetic acid, [CH3COOH] = 0.100 M

Concentration of hydronium ion, [H3O+] =..?

Step 2:

The balanced equation for the reaction.

CH3CO2H(aq) + H2O(l) ⇌ H3O+(aq) + CH3CO2-(aq)

Step 3:

Determination of concentration of hydronium ion, [H3O+].

This can be obtained as follow:

Ka = [H3O+] [CH3CO2-] / [CH3CO2H]

Initial concentration:

[CH3COOH] = 0.100 M

[H3O+] = 0

[CH3CO2-] = 0

During reaction

[CH3COOH] = – y

[H3O+] = +y

[CH3CO2-] = +y

Equilibrium:

[CH3COOH] = 0.1 – y

[H3O+] = y

[CH3CO2-] = y

Ka = [H3O+] [CH3CO2-] / [CH3CO2H]

1.8×10^-5 = y × y / 0.1

Cross multiply

y^2 = 1.8×10^-5 x 0.1

Take the square root of both side

y = √(1.8×10^-5 x 0.1)

y = 1.3×10^-3 M

[H3O+] = y = 1.3×10^-3 M

Therefore, the concentration of the hydronium ion, [H3O+] is 1.3×10^-3 M

At what temperature will a gas be, if you allow it to expand from its original volume of 756 mL at 65.0 °C to 1.40 L? (hint volume needs to be the same)

Answers

Answer:

120.4 gradius Celcius

Explanation:

Please see the step-by-step solution in the picture attached below.

Hope this answer can help you. Have a nice day!

Which diagram correctly describes the changes that occur as a small piece of rock falls from space and hits the earth

Answers

Answer:

the motion of gravity

Explanation:

Answer:

its c

Explanation

advhuosijoklxcmnjdabsuhggggabciaciudeifweingivg eygerigsygfe97rsghisdcvhbsduigwiugfu9uigdgiurfgyisdgfsdgfegiygewifgsdygfewusgfuyesigf7wgfiesgfiusgdfies

The largest contributed to water pollution is

Answers

Answer:

this si from google hope it helps

Explanation:

The Main Causes of Water Pollution in the U.S.

Runoff from Agricultural Operations. Agriculture represents one of the biggest sources of water pollution in the country. ...

Runoff and Nonpoint Source Pollution. ...

Industrial Activities. ...

Leakage from Underground Storage and Piping. ...

Leaking Sewers. ...

Vehicle Emissions. ...

Landfill Leakage. ...

Hazardous Waste.

Answer:

Runoff and Non-point Source Pollution.

Explanation:

it's caused by rainfall or snow-melt moving over and through the ground. As the runoff moves, it picks up and carries away natural and human-made pollutants, finally depositing them into lakes, rivers, wetlands, coastal waters and ground and NPS is it's abbreviation.

It takes 300 N to move a box 10 meters in 10 seconds. How much power is
required?
A. 30,000 W
B. 100 W
C. 3,000 J
D. 300 W
Plz help

Answers

Answer:

Power, P = 300 W

Explanation:

We have,

Force acting on the box to take it is 300 N

It is moved to a distance of 10 m in 10 seconds

It is required to find the power required to move the box. The rate at which work is done is called power required by an object. It can be given by the formula as follows :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{Fd}{t}\\\\P=\dfrac{300\times 10}{10}\\\\P=300\ W[/tex]

So, the power required is 300 W.

Use the graph to determine which is greater, the heat of fusion or the heat of vaporization. Explain how you used the graph to determine that.
(The substance is water)

Answers

Answer:

mdjnibfziedosnninjd.zjcssksskskbsksbivfdlvdxkvfuwhiwhwonsk jsbudwuvsaeigdOhgrauvdslnzarm cxwmvakbxsabxwrifwzpgsdoh

ds

When you add a controlled amount of substance known as an impurity to a pure semiconductor, its conductivity increases. This process is known as doping. The addition of an impurity can increase or decrease the number of available electrons. If the number of electrons is increased, the extra electrons conduct electricity. If the number of electrons is decreased, a vacant hole is created. The adjacent electron enters the vacant hole and conducts electricity. Thus, it seems like the holes act as charge carriers. They are considered to be positive charge carriers. Depending upon the charge carriers that conduct electricity, there are two types of semiconductors: p-type semiconductors and n-type semiconductors.Which of the following statements are correct with respect to semiconductors?
a) The addition of group 3A elements to group 4A semiconductors decreases the conductivity of the group 4A semiconductors.
b) The conductivity of semiconductors can be increased by the doping process.
c) As the temperature increases, the conductivity of semiconductors decreases.
d) The addition of group 5A elements to group 4A semiconductors increases the conductivity of the group 4A semiconductors.
e) Holes are charge carriers in p-type semiconductors.
f) Electrons are charge carriers in n-type semiconductors.

Answers

Answer:

See explaination

Explanation:

1. The addition of group 3A elements to group 4A semiconductors decreases the conductivity of the group 4A semiconductors: Wrong

The addition of 3A group elements inreases the conductivity and make them extrinsic semiconductors( p-type)

2. The conductivity of semiconductors can be increased by the doping process.: Correct

3.As the temperature increases, the conductivity of semiconductors decreases.. wrong

As the temperature increases, the conductivity of semiconductors increases.

4. The addition of group 5A elements to group 4A semiconductors increases the conductivity of the group 4A semiconductors: Correct : They will create n-type semicoductor.

5.Holes are charge carriers in p-type semiconductors: Correct

6. Electrons are charge carriers in n-type semiconductors: Correct

How to make isopropyl alcohol

Answers

Answer:

.It is easily synthesized from the reaction of propylene with sulfuric acid, followed by hydrolysis. Isopropyl alcohol (2-propanol) is made by indirect hydration of propylene (CH2CHCH3).… In some cases the hydration of propylene is carried out in one step, using water and a catalyst at high pressure.

Hope it'll help!

stay safe:)

A chemist wants to increase the solubility of a solid in water. Which of the
following will NOT help? *
-increase the temperature
-decrease the particle size
-Increase stirring
-increase pressure

Answers

Answer:

- Increase pressure .

Explanation:

Hello,

In this case, during the dissolution process, the solute's molecules rearrange in order to get together with the solvent's molecules, in this case water.

Now, since we are talking about a solid whose particles are intimately held together, the only way to separate them is by increasing the temperature because the molecules start moving so they can join water's molecules, decreasing particle size since they will be more likely to separate to each other and increasing stirring since the applied energy will break the solid's intramolecular forces.

In such a way, since pressure significantly affects gases and slightly affects liquid, it is not able to modify a solid, just extreme pressures such as it needed to produce diamonds, is able to affect a solid. For that reason, increasing the pressure will not increase the solid's solubility.

Best regards.

HELP PLEASE ILL GIVE 25 pointsWhich of the following practices could help reduce erosion of water banks? a. buffer strips b. natural fertilizers and pesticides c. decrease in fossil fuel emissions d. all of the above Please select the best answer from the choices provided A B C D

Answers

Answer:

A. Buffer strips

Explanation:

The practice that could help reduce erosion of water banks is buffer strips.

What is erosion?

Erosion is the action of surface processes that removes soil, rock or dissolved material from one location on the Earth's crust, and then transports it to another location where it is deposited.

One of the practices that could be used to reduce the effect of erosion is buffer strips.

What buffer strips do is slow and filter storm runoff while helping to hold soil in place.

Learn more on buffer strips here; https://brainly.com/question/26872640

5) Low iron concentration (as low as 0.02 nM) in the open ocean limits phytoplankton growth. Preconcentration is required to determine such low concentrations. Trace Fe3 from a large volume of seawater is concentrated onto a 1.2 mL chelating resin column, the column is then rinsed with 30 mL of high purity water and eluted with 10 mL of 1.5 M high purity HNO3. a.) For each sample, seawater is passed through the column of 17 h at 10 mL./min. How much is the concentration of Fe3 in the 10 mL of HNO3 eluate increased by this preconcentration procedure

Answers

Answer:

Check the explanation

Explanation:

Sample volume V= 10 mL/min x 17 h x 60 min/h / 1000 mL/L = 10.2 L

The concentration is increased

             10200 mL (sample volum) / 10 mL (eluted sample) = 1020 times.

57x10-9 M / 1020 = 5.6x10-12 M    

1.5 M HNO3 will contain ≤ 2ppm x (1.5M/15.7M ) ≤ 0.190 ppm ≤ 190 ppb

Ignoring this is reagent impurity and calculating for sea water

≤ 190 ppb /1020 = 0.186 ppb = 0.186 x 10-9g/mL = 0.186 x 10-6g/L =

0.186 x 10-6g/L / 56 g/mol = 0.003 x10-6 M = 3 nM

The glass of a lit 75-watt incandescent bulb is hotter to the touch than the glass of a 25-watt compact fluorescent (CFL) bulb that emits the same amount of light. What could be a reason for this

Answers

Incandescent bulbs have very low efficiency when compared to other types of bulbs, as they only transmit 5% of their given energy as useful light. This also means that 95% of the energy is transferred into stores we make no use of.

CFL bulbs on the other hand are 7-10% efficient and thus need less Watts to supply the same light to that of the aforementioned bulb.

A sample of helium gas at room temperature is compressed from 100 cm3 to 20 cm3. Its new pressure is now 30 cm Hg. What was the original pressure of the gas?

Answers

Answer:

6 cm Hg

Explanation:

Boyles Law: P1V1=P2V2

(100 mL)(x)=(20 mL)(30 cm Hg)

x = 6 cm Hg

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Considering the limiting reactant, what is the mass of zinc sulfide produced from 0.250 g of zinc and 0.750 g of sulfur? Zn(s)+S(S) ZnS(s)

Answers

Answer:

The mass of zinc sulfide produced is  [tex]M_{ZnS} = 0.76 \ g[/tex]

Explanation:

From the question we are told that

   The mass of zinc is  [tex]m_z = 0.750 \ g[/tex]

    The mass of sulfur is  [tex]m_s = 0.250 \ g[/tex]

The molar mass   of  [tex]Zn_{(s)}[/tex]  is a constant with value  65.39 g /mol

The molar mass of [tex]S_{(s)}[/tex]  is a constant with value  32.01 g/mol

The molar mass of  [tex]ZnS_{(s)}[/tex] is a constant with value 97.46  g/mol

The reaction is  

        [tex]Zn_{(s)} + S_{(s)} ------> ZnS_{(s)}[/tex]

   So from the reaction

       1 mole of  [tex]Zn_{(s)}[/tex] react with 1 mole of  [tex]S_{(s)}[/tex] to produce 1 mole of [tex]ZnS_{(s)}[/tex]

This implies that

65.39 g /mol of  [tex]Zn_{(s)}[/tex] react with 32.01 g/mol of  [tex]S_{(s)}[/tex] to produce   97.46  g/mol  of [tex]ZnS_{(s)}[/tex]

From the values given we can deduce that the limiting reactant is sulfur cause  of the smaller mass

 So  

    0.250 g of  [tex]Zn_{(s)}[/tex] react with 0.250 of  [tex]S_{(s)}[/tex] to produce [tex]x \ g[/tex] of  [tex]ZnS_{(s)}[/tex]

So

      [tex]x = \frac{97.46 * 0.250}{32.01}[/tex]

       [tex]x = 0.76 \ g[/tex]

Thus the mass of the mass of zinc sulfide produced is

    [tex]M_{ZnS} = 0.76 \ g[/tex]

 

     


At constant pressure, what generally happens to the solubility of solids and gases when the temperature of a solution is increased?


A. The solubility of solids and gases increases.
B. The solubility of solids and gases decreases.
C. The solubility of solids increases, and the solubility of gases decreases.
D. The solubility of solids decreases, and the solubility of gases increases.

Answers

Answer:

C)

Explanation:

JUST DID IT

Answer:

A D E

Explanation:

just did it

If a solution has a pOH=12, what is its pH?

Answers

Answer:

2

Explanation:

pH+pOH=14

- Hope that helps! Please let me know if you need further explanation.

Answer:

2

Explanation:

Ph+PoH=14

If you start with 64g of a radioactive element how many half-lives would occur before 8g remain?

Answers

Answer:

3 half-lives

Explanation:

The half-life is the time that it takes to a radioactive element to decay to half of its initial amount.

Let's suppose we start with 64 g of the radioactive element.

After 1 half-life, the mass of the element will be 32 g.After 2 half-lives, the mass of the element will be 16 g.After 3 half-lives, the mass of the element will be 8 g.
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