The temperature rose by 15°C from morning till noon. If the temperature
was less than 50°C at noon, write and solve an inequality to show the
possible temperature in the morning (use t to represent the temperature
in the morning)

Please help meeee

Answer:

measure of angle GEO.....

Answer:

x=21

Step-by-step explanation:

they are corresponding to each other

Answer:

integers are { 3 , 4 , 5 }

Step-by-step explanation:

- 1 < 2x - 5 ≤ 5

- 1 + 5 < 2x - 5 + 5 ≤ 5 + 5                           [ adding by 5 ]

4 < 2x + 0 ≤ 10

4 < 2x ≤ 10

2 < x ≤ 5                                                     { divide by 2 ]

Therefore, integers are { 3 , 4 , 5 }

Answer:

The range of the following relation is(-5,2,-4)

Answer:

y = square root x2 - 5

Step-by-step explanation:

y=[tex]\sqrt{x} -5[/tex]

(the top option)

Answer:

[tex] \large{ \tt{❃ \: EXPLANATION}} : [/tex]

[tex] \boxed{ \boxed{ \large{ \tt{۵ \: OUR \: FINAL \:ANSWER : \underline{ \tt{12}}}}}}[/tex]

-Yey! We're done ツ

▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁

Answer:

Problem 1: 25

Problem 2: 693

Step-by-step explanation:

Problem 1:

f(x) = -5n + 1

g(x) = -6n + 2

(f + g)(-2) = f(-2) + g(-2)

f(-2) = -5(-2) + 1

f(-2) = 10 + 1

f(-2) = 11

g(-2) = -6(-2) + 2

g(-2) = 12 + 2

g(-2) = 14

(f + g)(-2) = 11 + 14

(f + g)(-2) = 25

Problem 2:

f(x) = 7 + 2x

g(x) = 5x - 2

fg(7) = f(7) × g(7)

f(7) = 7 + 2(7)

f(7) = 7 + 14

f(7) = 21

g(x) = 5(7) - 2

g(x) = 35 - 2

g(x) = 33

Therefore:

fg(7) = 21 × 33

fg(7) = 693

Answer:

The picture is the answer

Step-by-step explanation:

a rule in quadratic equ states that

if summation of the roots should be -b/a of the equa

comparing the equ x² - 6x + y=0

with. ax² + bx +c =0

we see that in the equ, a= 1, b=-6

so the sum of the roots is -(-6)/1= +6

looking the the option the only one that agreed is option A

-2 + 8= 6

there fore the values of x are -2 or 8

Answer:

It will still be 9.  y=9 is a horizontal line.  No matter the x value, the answer will be the same.

Step-by-step explanation:

Step-by-step explanation:

by referring to the diagram,

a = 8

Answer:

The Correct Answer is [tex]\frac{11}{2}[/tex]    (11/2)

Decimals Form: 5.5

Answer:

5 1/2 or 5.5

Step-by-step explanation:

11/5 ÷ 2/5

11/5 × 5/2 = 11/2 = 5 1/2

Answer:

y-acis

Step-by-step explanation:

the function graph is symmetric about

- y-axis when it is an even function

-the origin ehen it is an even function

A symmetrical graph about the x-axis is not a function graph

f(×) is a even if and only if f(×) =f(×)

f(×) is a odd if and only f(×)=f(×)

We have the function r(0) = 4cos (50)

(only symmetry about the y-acis or about the origin)

Check r(-0)

r(-0) = 4cos (5-0) = 4cos (-50 = 4 cos (50)

Used cos (-× = cos ×

We have r(0). Therefore the graph of r(0) is symmectric about the y-axis.

Answer:

3.0019009e+15

Step-by-step explanation:

the word and is multiplication so multiply the two numbers

Answer:

3.001900896*10^15 is the answer

Answer:

$34,341

Step-by-step explanation:

Given :

Job Salary Percent of Employees Entry 23,264 60% 47,480 38% 117,027 2%

To obtain the best value for the mean salary ; we obtain the weighted average ;

Σ(salary * weight factor) / Σ weight

[(23264 * 0.60) + (47480 * 0.38) + (117027 * 0.02)] ÷ (0.60 + 0.38 + 0.02)

= 34341.34 / 1

Average salary = 34341.34

= $34,341 ( nearest dollar)

Answer:

x = 58

y = 39

Step-by-step explanation:

x = 58 (Vertically opposite angles)

x + 2y + (x-14) = 180 (Angles in a straight line)

=> x + 2y + x - 14 = 180

=> 2x + 2y = 180 + 14

=> 2(58) + 2y = 194

=> 116 + 2y = 194

=> 2y = 194 - 116

=> 2y = 78

=> y = 78/2

=> y = 39

Answer:

Doughnuts are sold in bags and cartons

A bag holds four doughnuts and a carton holds ten doughnuts

Tom buys B bags of doughnuts and C cartons of doughnuts

He buys a total T doughnuts

Writs down a formula for T in terms of B and C

Step-by-step explanation:

Doughnuts are sold in bags and cartons

A bag holds four doughnuts and a carton holds ten doughnuts

Tom buys B bags of doughnuts and C cartons of doughnuts

He buys a total T doughnuts

Writs down a formula for T in terms of B and C

Answer:

5

Step-by-step explanation:

Given that 3 is a root of the equation x²-px+6=0

To find the value of p, substitute 3 into the equation for x

Hence x²-px+6=0

becomes

3^2 - 3p + 6 = 0

9 -3p + 6 = 0

collect like terms

-3p = -9 - 6

-3p = -15

Divide both sides by -3

p = -15/-3

p = 5

Answer:

The answer is 113.10 ft²

Step-by-step explanation:

The square feet which is the area of a 12 ft circle is 113.10. If there is a option for that

Answer:

113.04 ft^2

Step-by-step explanation:

use formule A = πr^2

Answer:

the answer is 4

...

..

..

..

..

Answer:

y >= x/2 - 1

Step-by-step explanation:

the slope (rise/run) is 1/2 and the y-intercept is -1 so in point-slope form

y = x/2 - 1 but everything above the line (unshaded part) is valid so y is equal to or greater than.

Answer:

Hence, Eric's elevation changed [tex]4\frac{1}{4}[/tex] meters above. So after the 2 moves, he is up by [tex]4\frac{1}{4}[/tex] meters.

Step-by-step explanation:

Let us assume "negative" as climbing up and  "positive" as climbing up. Here we need to find the change in elevation.

Now we have:  

[tex]=-2\frac{1}{2} + 6\frac{3}{4}\\\\=-\frac{5}{2} +\frac{27}{4} \\\\=\frac{-5(2)+27}{4} \\\\=\frac{-10+27}{4} \\\\=\frac{17}{4} = 4\frac{1}{4}[/tex]

Answer:

b

Step-by-step explanation:

Answer:

Graph the system on linear equations.

Step-by-step explanation:

(-4, 4) & (-4, -6)

Answer:

[tex]\frac{x}{x-1}[/tex]

Step-by-step explanation:

[tex]\frac{3x^2 - 1}{x^2 - 1} - \frac{2x + 1}{x + 1}[/tex]                                          [tex][ \ x^ 2- 1 = (x-1)(x + 1) \ ][/tex]

[tex]= \frac{3x^2 - 1}{(x-1)(x + 1 )} - \frac{2x + 1}{x + 1}\\\\=\frac{(3x^2 - 1)-(2x + 1)(x-1)}{(x + 1)(x-1)}[/tex]                        [tex][\ Taking \ LCM \ ][/tex]

[tex]= \frac{(3x^2 - 1)- (2x^2 - 2x + x - 1)}{(x+1)(x-1)}\\\\=\frac{3x^2 - 1 - 2x^2 + x + 1 }{(x+1)(x-1)}\\\\=\frac{x^2 +x}{(x+1)(x-1)}\\\\=\frac{x(x+1)}{(x+1)(x-1)}\\\\=\frac{x}{x-1}[/tex]

Finding LCM :

Example :

                 [tex]\frac{1}{6} + \frac{1}{3}[/tex]

6 = 2  x   3

3 = 1   x   3

                [tex]\frac{1}{2 \times 3} + \frac{1}{ 3}[/tex] [tex]= \frac{1}{2 \times 3} + \frac{1 \times 2}{ 3 \times 2}[/tex]  

[ To make the denominators same : the second fraction is multiplied and divided by 2 ]

Similarly :

 [tex](x^2 - 1 ) = (x -1)(x+1)\\\\(x + 1) = 1 \times (x + 1)[/tex]

Same rule we applied : multiplied the numerator and denominator of the second term with ( x - 1 )

Therefore the second term becomes ,

                                       [tex]\frac{2x + 1}{x + 1} = \frac{(2x + 1)(x - 1)}{(x + 1)( x - 1)}[/tex]

Answer:

48 months

Step-by-step explanation:

12 times 4 48

Answer:

48 months

There's 12 months in 1 year.

So we would multiply 12 months by 4 years to get 48 months

Step-by-step explanation:

"must be used first" is a very hard phrasing. multiplication is commutative.

and I am not sure that the problem is stated correctly.

I read here

(i×y²) to the power of 1/3.

i is the imaginary constant sqrt(-1) ?

exponents brought themselves to the power of something else multiply.

e.g.

[tex]({2}^{3})^{4} = {2}^{12} [/tex]

exponents in multimedia expressions of the same base simply add up.

e.g.

[tex] {2}^{3} \times {2}^{4} = {2}^{7} [/tex]

a negative exponent means that the expression with the same positive exponent is just at the bottom of a division.

e.g.

[tex] {2}^{ - 3} = 1 \div {2}^{3} [/tex]

and a fraction as exponent specifies a root to be taken.

e.g

[tex] {2}^{1 \div 3} = \sqrt[3]{2} [/tex]

so, I would do all the exponent multiplications to simplify the expression.

[tex] \sqrt[3]{i \times {y}^{2} } = ({i \times {y}^{2} })^{1 \div 3} = [/tex]

[tex] = ( { - 1}^{1 \div 2} \times {y}^{2} ) ^{1 \div 3} [/tex]

1/2 × 1/3 = 1/6

2 × 1/3 = 2/3

[tex] = { - 1}^{1 \div 6} \times {y}^{2 \div 3} = \sqrt[6]{ - 1} \times \sqrt[3]{ {y}^{2} } [/tex]

so, as we can see, we can move freely from multiplying the fraction exponents to converting them into root expressions and vice versa.