Using the confidence interval relation, the confidence interval at 95% would be (189.790 ; 246.370)
The confidence interval could be defined thus :
[tex] μ ± Z_{crit}(\frac{σ}{\sqrt{n}}) [/tex] σ = 50Zcrit at 95% = 1.96Since we are given the population standard deviation, we the Z distribution :
μ = ΣX / n = (2617 / 12) = 218.08 M.E = [tex] 1.96(\frac{50}{\sqrt{12}}) = 28.290 [/tex]Substituting the values into the relation :
Lower boundary : 218.08 - 28.290 = 189.790
Upper boundary : 218.08 + 28.290 = 246.370
Hence, the confidence interval is (189.790 ; 246.370)
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Aura is having fish and green beans for dinner. Aura is _____.
A a producer
B an omnivore
C a carnivore
D an herbivore
Answer:
b . omnivore is right answer