Answer:
0.8
Step-by-step explanation:
To get to C, you must start by taking the lower of the first two branches
That has a probability of 0.4
C is the branch on your right and has a probability of 0.2
P(C) = 0.4 * 0.2 = 0.8
Answer:
.26
Step-by-step explanation:
What are the first and third quartiles for the following data set?
12, 15, 18, 16, 14, 9, 12, 21
A 9 and 21
C 12 and 17
B 12 and 16
D 15 and 17
Answer:
A
Step-by-step explanation:
I guess that is it may be
The perimeter of a rectangular garden is 120 feet The garden is two times as long as it’s why the system of equation can be used to find the width in the length what is the length
Answer:
Step-by-step explanation:
Garden is two times as long as it is wide.
L = 2W
Perimeter is 120 feet
2L + 2W = 120
L +W = 60
(2W) + W = 60
3W = 60
W = 20 feet
L = 2W = 40 feet
Find the value of x and y is (3x_6) (12,y-1)
Answer:
x=4
y=7
Step-by-step explanation:
12=3x
x=4
6=y-1
y=6+1
y=7
Answer:
x=4
Step-by-step explanation:
verify cos(a+b)/cos(a) cos(b) =1-tan(a) tan(b)
The identity as been verified/proved as:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Given that:
[tex]\frac{\cos(a + b)}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Apply cosine identity to the numerator
[tex]\frac{\cos\ a\ cos\ b - \sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Split the fraction:
[tex]\frac{\cos\ a\ cos\ b}{\cos\ a\cos b} - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
Cancel out common terms
[tex]1 - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]
In trigonometry, we have:
[tex]\frac{\sin \theta}{\cos \theta} = \tan \theta[/tex]
So, the equation becomes:
[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]
Hence, the identity has been verified
Read more about trigonometry identities at:
https://brainly.com/question/21055284
Which table represents a linear function
Answer:
3rd option (top right)
Step-by-step explanation:
3rd option represents a linear equation
y = -2x-1
Answered by GAUTHMATH
5/\sqrt{x} +1+4/\sqrt{x} -1-8\sqrt{x}/x-1
Answer:
535525-62635-$6#62626636$66$6$63663636$6$62
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2. The volume of a cube is 8 cm", find the length of one of its sides
Answer:
Step-by-step explanation:
The question has an error. Volume is expressed in cubic units. You probably mean cm³ .
Volume = 8 cm³
Length of each edge = ∛8 = 2 cm
Answer:
2cm
Step-by-step explanation:
Volume of cube=a^3 cubic units
8=a^3
a=cuberoot of 8
which is 2
In an annual report to investors, an investment firm claims that the share price of one of their bond funds had very little variability. The report shows the average price as $15.00 with a variance of 0.19. One of the investors wants to investigate this claim. He takes a random sample of the share prices for 22 days throughout the last year and finds that the standard deviation of the share price is 0.2517. Can the investor conclude that the variance of the share price of the bond fund is different than claimed at α = 0.05. Assume the population is normally distributed.
Required:
State the null and alternative hypotheses. Round to four decimal places when necessary
In this question, the variance of the population is tested. From the data given in the exercise, we build the hypothesis, then we find the value of test statistic and it's respective p-value, to conclude the test. From this, it is found that the conclusion is:
The p-value of the test is 0.0038 < 0.05, which means that the investor can conclude that the variance of the share price of the bond fund is different than claimed at α = 0.05.
----------------
Claimed variance of 0.19:
This means that at the null hypothesis, it is tested if the variance is of 0.19, that is:
[tex]H_0: \sigma^2 = 0.19[/tex]
----------------
Test if the variance of the share price of the bond fund is different than claimed at α = 0.05.
At the alternative hypothesis, it is tested if the variance is different of the claimed value of 0.19, that is:
[tex]H_1: \sigma^2 \neq 0.19[/tex]
The test statistic for the population standard deviation/variance is:[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]
In which n is the sample size, is the value tested for the variance and s is the sample standard deviation.
----------------
0.19 is tested at the null hypothesis, as the variance:
This means that [tex]\sigma_0^2 = 0.19[/tex]
----------------
He takes a random sample of the share prices for 22 days throughout the last year and finds that the standard deviation of the share price is 0.2517.
This means that [tex]n = 22, s^2 = (0.2517)^2 = 0.0634[/tex]
----------------
Value of the test statistic:
[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]
[tex]\chi^2 = \frac{21*0.0634}{0.19}[/tex]
[tex]\chi^2 = 7[/tex]
----------------
P-value of the test and decision:
The p-value of the test is found using a chi-square for the variance calculator, considering a test statistic of [tex]\chi^2 = 7[/tex] and 22 - 1 = 21 degrees of freedom, and a two-tailed test(test if the mean is different of a value).
Using the calculator, the p-value of the test is 0.0038.
The p-value of the test is 0.0038 < 0.05, which means that the investor can conclude that the variance of the share price of the bond fund is different than claimed at α = 0.05.
For more on hypothesis tests using variances/standard deviation, you can check https://brainly.com/question/13993951
please find the answer
Answer:
I hope this is correct but 8.5 or 8 1/2 Units
Answer:
i think it is 8 1/2.
Step-by-step explanation:
my reasoning is that because v=lwh. the length is 4 and hw is 2 1/8. so i multiplied those together.
What are the solutions of the equation (x + 2)2 + 12(x + 2) – 14 = 0? Use u substitution and the quadratic formula to
solve.
..... Here
This is the answer
The produce of three and the sum of a number and eight
Answer:
3(x + 8)
Step-by-step explanation:
"The product of three and the sum of a number and eight".
First, note that:
1) Product means multiply.
2) Sum means addition.
With that in mind, also note the order of operations. The order of operations is defined as PEMDAS, or:
Parenthesis
Exponents (& Roots)
Multiplication
Division
Addition
Subtraction
Also, let "a number" be denoted as the variable, x.
~
Firstly, "the sum of a number and eight": x + 8
Next, "The product of...": 3 *
Putting the two parts together will generate: 3(x + 8)
3(x + 8) is your answer.
~
so, sunny is 16 he is 132 pounds
the song my time lasts 3:33 and sunny is falling for an entire 3 minutes
the gravitational pull which is pulling sunny back down to the ground is about 10m/s²
we have the new height of the hospital, is 49312,674 meters, or 161.787 feet
upon theory, sunny died upon coming to contact with the ground if you fall head first from 100 feet you're bound to die
you can break just your legs from falling from atleast 16-18 feet so imagine that
??????
Determine which type of error is most likely to arise from the following situations. a 1. the time in which individuals are contacted to take a survey occurs during work hours f 2. the last part of a newspaper article asks readers to mail or email the newspaper their opinion about universal health coverage 3. subjects are asked to recall how often they snacked between meals in the past 30 days 4. a survey to assess teachers' opinions about Common Core uses a member list for the largest teachers' union as the sampling frame a. question wording b. undercoverage c. processing error d. bad sampling method e. response error f. nonresponse g. random sampling error
Answer:
Determination of type of error arising from the situations
Situation Type of Error
1. Nonresponse
2. Bad sampling method
3. Question wording
4. Undercoverage
Step-by-step explanation:
Types of errors:
a. question wording means that the manner a question is worded elicits some particular responses, which may not accurately reflect reality.
b. undercoverage occurs when some elements of the target population is not represented on the survey frame.
c. processing error arises from data processing
d. bad sampling method is caused by the voluntariness of those who choose to respond.
e. response error is caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.
f. nonresponse error arises as a result of incomplete information or partial response.
g. random sampling error arises from the limited sample size when compared with the population size.
I need help in math please, if you can
Answer:
Step-by-step explanation:
400*e^(.09*3)
$523.97
answer is b
Answer: Option B
$523.97
Explanation:
= 400×e^(0.09×3)
= $523.97
Must click thanks and mark brainliest
10x^3 - 25x^2 + 20
How to factor this
5(2x^2-x-2)(x-2)
Step-by-step
Answer: [tex]5(\frac{10x^3}{5}+\frac{-25x^2}{5}+\frac{20}{5}) \\\\5(2x^3-5x^2+4)\\\\5(2x^2-x-2)(x-2)[/tex]
solve for x : 2(x^2+9)-4=0
Answer:
no solution
Step-by-step explanation:
multiply 2 and get 2x^2+18-4=0
combine like terms
2x^2+14=0
subtract 14
2x^2=-14
there can't be a square root of a negative number so there's no solution
Answer:
x = ±i sqrt(7)
Step-by-step explanation:
2(x^2+9)-4=0
Add 4 to each side
2(x^2+9)-4+4=0+4
2(x^2+9)=4
Divide by 2
2(x^2+9)/2=4/2
(x^2+9)=2
Subtract 9 from each side
x^2 +9-9 = 2-9
x^2 = -7
Taking the square root of each side
sqrt(x^2) =sqrt(-7)
x = sqrt(-1 *7)
x = ±i sqrt(7)
The width of a rectangle is 9 less than twice its length. If the area of the rectangle is 129cm^2. What is the length of the diagonal? Give your answer to 2 decimal places.
==========================================================
Explanation:
L = x = length of the rectangleW = 2x-9 = width of the rectangle, since its 9 less than twice the lengtharea of rectangle = L*W = 129
L*W = 129
x*(2x-9) = 129
2x^2-9x = 129
2x^2-9x-129 = 0
Apply the quadratic formula. We'll use a = 2, b = -9, c = -129.
[tex]x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(-9)\pm\sqrt{(-9)^2-4(2)(-129)}}{2(2)}\\\\x = \frac{9\pm\sqrt{1113}}{4}\\\\x \approx \frac{9\pm33.36165464}{4}\\\\x \approx \frac{9+33.36165464}{4}\ \text{ or } \ x \approx \frac{9-33.36165464}{4}\\\\x \approx \frac{42.36165464}{4}\ \text{ or } \ x \approx \frac{-24.36165462}{4}\\\\x \approx 10.59041366\ \text{ or } \ x \approx -6.09041364\\\\[/tex]
We ignore the negative solution because a negative length makes no sense.
The length is approximately L = 10.5904 cm.
The width is 2L-9 = 2*10.5904-9 = 12.1808 cm approximately.
As a quick check,
L*W = 10.5904*12.1808 = 128.99954432
which isn't too far off from 129. We have rounding error which is why we don't perfectly land on the target area value. If you wanted to get closer to the value 129, then use more decimal digits in the approximations of L and W.
----------------------------
If you draw a diagonal in the rectangle, then you form two identical or congruent right triangles.
Focusing on one of those triangles, we have
a = 10.5904b = 12.1808c = unknown hypotenuse = diagonal lengthApply the pythagorean theorem
a^2+b^2 = c^2
c = sqrt( a^2 + b^2 )
c = sqrt( (10.5904)^2 + (12.1808)^2 )
c = 16.1408940520653
c = 16.14
The diagonal is roughly 16.14 cm long.
Solve x/4 > 2 Question 10 options: x ≥ 8 x < –8 x > 8 x ≤ –8
Answer:
x > 8
Step-by-step explanation:
You can start y multiplying both sides by 4 to cancel out the division by 4:
x/4 > 2
*4 *4
x > 8
Answer:
x > 8
Step-by-step explanation:
x/4 > 2
=> x > 2 × 4
=> x > 8
-27
Which of the following is equivalent to
نان-۴
?
N
O
(197)
NI
12
22
(22)
2².2
Answer:
3rd option
Step-by-step explanation:
(1/2)^-2t
= (2^-1)^-2t
= 2^2t
= (2^2)^t
Answered by GAUTHMATH
Find the length of AB
Answer:
C. 44.98
Step-by-step explanation:
Hi there!
We are given the right triangle ABC, m<B=12°, and CB =44
We want to find the length of AB
We can use trigonometry to do it
Let's find the ratio in reference to angle B, as that angle is given.
In reference to angle B the opposite angle is AC, the adjacent side is CB, and the hypotenuse is AB
Now let's recall the 3 most commonly used functions:
[tex]sine=\frac{opposite}{hypoptenuse}[/tex]
[tex]cosine=\frac{adjacent}{hypotenuse}[/tex]
[tex]tangent=\frac{opposite}{adjacent}[/tex]
Let's find the cosine of angle B, as it uses CB and AB, which are the given side and the side we need to find
In that case,
cos(12)=[tex]\frac{CB}{AB}[/tex]
cos(12)=[tex]\frac{44}{AB}[/tex]
Multiply both sides by AB
[tex]AB[/tex]*cos(12)=44
Divide both sides by cos(12)
AB=[tex]\frac{44}{cos(12)}[/tex]
Now plug [tex]\frac{44}{cos(12)}[/tex] into your calculator. Make sure your calculator is on degree mode
AB≈44.98
So the answer is C
Hope this helps!
A school sports team contains 68 students. 33 do field events, 40 do track events, 23 do swimming, 14 do both field and track events, 8 do both swimming and field events. If 15 students do field events only and 10 do both swimming and track events, how many students do a. Swimming only b. Track events only c. All three events?
Answer:
a. 9 students
b. 20 students
c. 4 students
Hal's business made $500,000 last year. This year, his business made $650,000. What is the percentage difference? [?]%
Answer:
the answer is 30 percent.
Step-by-step explanation:
i did it on acellus.
What is the difference between the centroid and the center of mass?A: When (), ,, ,x y zc x y zthen the center of mass is the centroid.
The centroid and center of mass need not be the same point. They are the same only when a body's mass is uniformly distributed.
The place value of 7 in 87534 is____________
What is 50g as a percentage of one kg?
Answer:
5 %
Step-by-step explanation:
1000 g = 1 kg
50 kg = 0.05 kg
0.05 = 5%
Therefore, 50 g as a percentage of 1kg is 5%.
A hexagonal pyramid is located ontop of a hexagonal prism. How many faces are there?
A. 15
B. 24
C. 6
D. 13
Answer:
15
Step-by-step explanation:
The figure has total 15 faces, the correct option is A.
What is a Hexagon?A hexagon is a polygon with six sides.
A hexagonal pyramid has 8 faces
From (2 hexagonal base + 6 lateral surfaces)
A hexagonal prism has 7 faces
From ( A hexagonal base + 6 lateral faces)
Total faces the figure has is 8 +7 = 15
To know more about Hexagon
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The price of a car has been reduced from $16,500 to $11,055. What is the percentage decrease of the price of the car?
Answer:
33%
Step-by-step explanation:
$16,500-$11,055= $5,445
$5,445÷$16,500= 0.33 which in percentage format is 33%
HOPE THIS HELPS! MARK BRAINLIEST PLEASE!!!!!
Suppose (-13,2) is a point on the graph of y=f(x). What is a point that will be on the graph of y=9f(x)-5
9514 1404 393
Answer:
(x, y') = (-13, 13)
Step-by-step explanation:
At the given value of x, f(x) = 2. Then 9f(x)-5 = 9(2) -5 = 13.
The point on the scaled, translated graph will be ...
(x, y') = (-13, 13)
_____
The graph shows a function f(x) with a distinct feature (vertex) at (-13, 2). It also shows where that distinct feature moves to when the function is scaled and translated.
[tex]\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }[/tex]
Answer:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]
General Formulas and Concepts:
Calculus
Limits
Limit Rule [Variable Direct Substitution]: [tex]\displaystyle \lim_{x \to c} x = c[/tex]
L'Hopital's Rule
Differentiation
DerivativesDerivative NotationBasic Power Rule:
f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹Derivative Rule [Chain Rule]: [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]
Step-by-step explanation:
We are given the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]
When we directly plug in x = 0, we see that we would have an indeterminate form:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]
This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:
[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]
Plugging in x = 0 again, we would get:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]
Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]
Substitute in x = 0 once more:
[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]
And we have our final answer.
Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Limits
Shaswant lent a sum of 44,000 to his friend Rahul at 10 percent p a. After 2 years and 6months his friend paid him To 40,000 with a cow. What was the price of cow.?
Answer:
4000 because a cow is 4000 and he gave 40000
cause he used it for sinething