The volume of a sphere whose diameter is 18 centimeters is
π cubic centimeters. If its diameter were reduced by half, its volume would be
of its original volume.

Answer:

B. 110

Step-by-step explanation:

z is supplemental to 70°, so the add up to 180°

z+70°=180°

z=180°-70°

z=110°

Option B is correct. The required value of z is 110 degrees

Supplementary angles are angles summing up to 180 degrees. According to the circle geometry, we can see that z and 70 degrees lie on the same line, this shows that both angles are supplementary.

Since supplementary angles sum up to 180degrees, hence;

[tex]z + 70 = 180\\[/tex]

Subtract 70 from both sides

[tex]z+70-70=180-70\\z=110^0[/tex]

Hence the value of z is 70 degrees

Learn more here: https://brainly.com/question/22261921

Answer:

-(1/3 · 1/3 · 1/3 · 1/3 )

Step-by-step explanation:

-(3)^-4= -1/3 ^4 = -1/81

-(1/3 · 1/3 · 1/3 · 1/3 )= -1/81

Answer:

Answer:

[tex] = - ( \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} )[/tex]

Step-by-step explanation:

[tex] - {(3)}^{ - 4} = \\ - ( { 3}^{ - 4} )= \\ - (\frac{1}{ {3}^{4} } )[/tex][tex] = - ( \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} )[/tex][tex] = - \frac{1}{81} [/tex]

Answer:

The balloon contains 456.3 kg of helium

Step-by-step explanation:

Density=mass / volume

Volume=2600 cubic meters of helium

Density=0.1755 kilograms per cubic meters

Mass=x

Find mass, x

Density=mass / volume

Mass=Density × volume

=0.1755 * 2600

=456.3 kg

The balloon contains 456.3 kg of helium

Answer:

x=42

Step-by-step explanation:

Answer:

Therefore, perimeter of the given triangle is 18.300 cm.

Step-by-step explanation:

Area of the triangle ABC = [tex]\frac{1}{2}(\text{AB})(\text{BC})(\text{SinB})[/tex]

10 = [tex]\frac{1}{2}(3.2)(8.4)(\text{SinB})[/tex]

Sin(B) = [tex]\frac{10}{3.2\times 4.2}[/tex]

B = [tex]\text{Sin}^{-1}(0.74405)[/tex]

B = 48.08°

By applying Cosine rule in the given triangle,

(AC)² = (AB)² + (BC)²-2(AB)(BC)CosB

(AC)² = (3.2)² + (8.4)² - 2(3.2)(8.4)Cos(48.08)°

(AC)² = 10.24 + 70.56 - 35.9166

(AC)² = 44.88

AC = [tex]\sqrt{44.8833}[/tex]

AC = 6.6995 cm

Perimeter of the ΔABC = m(AB) + m(BC) + m(AC)

                                      = 3.200 + 8.400 + 6.6995

                                      = 18.2995

                                      ≈ 18.300 cm

Therefore, perimeter of the given triangle is 18.300 cm

Answer:

y- intercept= -8

slope= 1

Step-by-step explanation:

Looking at the question, the y- intercept is always the number were the line on the graph passes over on the y- axis. The slope is always the number with x in front of it.

Answer:

Y-intercept = -8

Slope = 1

Step-by-step explanation:

The Y-intercept is the constant or the integer in the equation.

So, the y-intercept is "-8".

The slope is the number with which "x" is multiplied with.

So, the slope is 1, because 'x' and '1x'  are similar; therefore the slope is 1.

Answer:

[tex]\Large \boxed{\mathrm{78 \ units^2 }}[/tex]

Step-by-step explanation:

The area of the trapezoid can be found by adding the area of the triangle and the area of the rectangle.

Area of rectangle = base × height = 2 × 12 = 24 units²

Area of triangle = base × height × 1/2

The base is missing for the triangle. Apply Pythagorean theorem to solve for the base.

12² + b² = 15²

b = 9

9 × 12 × 1/2 = 54 units²

Adding the areas.

54 units² + 24 units² = 78 units²

Answer:

its 78 units on khan academy :)))

Step-by-step explanation:

Answer:

the constant term of the expression represents the difference between Shelly and Terrence points.

Answer:

Option (B).

Step-by-step explanation:

Since "measure of an angle formed between the tangent and a chord measure the half of the intercepted arc."

Therefore, x = 2 × (65)°

x = 130°

Since, measure of the inscribed angle is half of the measure of the intercepted arc.

Therefore, x = 2y

y = [tex]\frac{x}{2}[/tex]

y = [tex]\frac{130}{2}[/tex]

y = 65°

Therefore, Option (B). 65° will be the correct option.

Answer: Choice B)

The relation is a function because there are no vertical lines that can be drawn on the graph that pass through more than one point.

This graph passes the vertical line test. Any input (x) leads to one and only one output (y). An example of a graph failing the vertical line test would be a graph that is a sideways parabola.

Answer:

181.8yd

Step-by-step explanation:

Answer:

Option B.

Step-by-step explanation:

The measure of cage is 90 feet by 40 feet.

Length of rope [tex]=40\sqrt{2}[/tex] foot

It is clear that, length of rope is greater than one side of cage and raw a line which divides the cage in two parts as shown in below figure.

We need to find the shaded area.

By Pythagoras theorem:

[tex]hypotenuse^2=base^2+perpendicular^2[/tex]

[tex](40\sqrt{2})^2=(40)^2+perpendicular^2[/tex]

[tex]3200=1600+perpendicular^2[/tex]

[tex]3200-1600=perpendicular^2[/tex]

[tex]1600=perpendicular^2[/tex]

[tex]40=perpendicular[/tex]

So, it is a square.

From the figure it is clear that the shaded area contains 1/8th part of circle are half part of square.

Area of circle is

[tex]A_1=\pi r^2[/tex]

[tex]A_1=\pi (40\sqrt{2})^2[/tex]

[tex]A_1=3200\pi[/tex]

Area of square is

[tex]A_2=a^2[/tex]

[tex]A_2=(40)^2[/tex]

[tex]A_2=1600[/tex]

Area of shaded portion is

[tex]A=\dfrac{A_1}{8}+\dfrac{A_2}{2}[/tex]

[tex]A=\dfrac{3200\pi}{8}+\dfrac{1600}{2}[/tex]

[tex]A=400\pi+800[/tex]

[tex]A=400(\pi+2)[/tex]

The required area is [tex]400(\pi+2)[/tex] sq. ft.

Therefore, the correct option is B.

Answer:

Step-by-step explanation:

Solving trig equations are just like solving "regular" equations. Let's get to it. First and foremost we are going to make a "u" substitution. You'll use that all the time in calculus, if you choose to go that route. Let

[tex]sin^2 \theta=u^2[/tex] and sinθ = u. Making the substitution, the equation becomes:

[tex]2u^2-u-1=0[/tex]

That looks like something that can be factored, right? If you throw it into the quadratic formula you get the factors:

(u - 1)(2u + 1) = 0

By the Zero Product Property, either u - 1 = 0 or 2u + 1 = 0, so we will solve those, but not until after we back-substitute!

Putting sinθ back in for u:

sinθ - 1 = 0 so

sinθ = 1 and in the other equation:

2sinθ + 1 = 0 so

2sinθ = -1 and

[tex]sin\theta=-\frac{1}{2}[/tex]

Get out the unit circle and look to where the sinθ has a value of 1. There's only one place in your interval, and it's at 90 degrees.

Now look to where the sinθ has a value of -1/2. There are 2 places within your interval, and those are at 210° and 330°. Now you're done!

Answer:

y = 0.8x + 10

Step-by-step explanation:

From the given graph,

Graphed line passes through two points (0, 10) and (50, 50)

Let the equation of the given line is,

y = mx + b

Where m = slope of the line

b = y-intercept

Since slope 'm' = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

m = [tex]\frac{50-10}{50-0}[/tex]

m = [tex]\frac{4}{5}[/tex] = 0.8

y-intercept of the line 'b' = 10

Therefore, equation of the line of best fit will be,

y = 0.8x + 10

Answer:

That’s ez pz

Step-by-step explanation:

Answer:

The slope is -3 and the y intercept is -44

Step-by-step explanation:

6X+ 2Y= -88

The slope intercept form of a line is y= mx+b where m is the slope and b is the y intercept

Solve for y

6X-6x+ 2Y= -88-6x

2y = -6x-88

Divide by 2

y = -3x -44

The slope is -3 and the y intercept is -44

Answer:

£600

Step-by-step explanation:

1 months= 30 days

here,

money made in 1 day= £20

now,

money made in 30 days= 20×30

= 600

[:• In one month you earn £600]

Answer:560 pounds

Step-by-step explanation:

If 1 day is equal to 20 pounds, to find how much pounds will you have a month, first check how many days are there in a month. Then multiply the number of days in a month to the given pound in one day.

So =1 month = 28 days

=1 day = 20 pounds

So= 20 pounds × 28 = 560 pounds

Answer:

Step-by-step explanation:

expression = (x + 4) / 3

x = 5

(5 + 4) / 3

= 9/3

= 3

Hope this helps

plz mark as brainliest!!!!!!

Answer:

Domain : any real number

Range : y ≥0

Step-by-step explanation:

The domain is the values that x can be

X can be any real number

The range is the values the y can be

Y can be zero or any positive value since y = x^2

Domain : any real number

Range : y ≥0

Answer:

[tex]\boxed{\sf Option \ A}[/tex]

Step-by-step explanation:

[tex]y=x^2[/tex]

[tex]\sf The \ domain \ of \ a \ function \ is \ all \ possible \ values \ for \ x.[/tex]

[tex]\sf There \ are \ no \ restrictions \ on \ the \ value \ of \ x.[/tex]

[tex]\sf The \ domain \ is \ all \ real \ numbers.[/tex]

[tex]\sf The \ range \ of \ a \ function \ is \ all \ possible \ values \ for \ y.[/tex]

[tex]\sf When \ a \ number \ is \ squared \ the \ result \ is \ always \ greater \ than \ or \ equal \ to \ 0.[/tex]

[tex]\sf The \ range \ is \ \{y:y\geq 0\}[/tex]

Answer:

box 1 and box2 are correct.

Answer:

Step-by-step explanation:

Answer:

about 51 ft

Step-by-step explanation:

I am not sure if this is the correct answer

16:9 = 16/9

90/x = 16/9

Remember that i am not sure about this answer, but I hope this helps!

Answer:

The correct answer is

Step-by-step explanation:

11 square centimeters.

Hope this helps....

Have a nice day!!!!

Answer:

??????????????????????????????????????????????????????????????

Step-by-step explanation:

Answer:

where is Point or picture

Answer:

140°

Step-by-step explanation:

[tex] \because m\widehat{BG} = 360\degree - m\widehat{GCB} \\

\therefore m\widehat{BG} = 360\degree - 300\degree \\

\therefore m\widehat{BG} = 60\degree \\

\because m\widehat{BGD} = m\widehat{BG}

+m\widehat{GD}\\

\therefore m\widehat{BGD} = 80\degree+60\degree\\

\therefore m\widehat{BGD} = 140\degree\\

\because m\angle BAD = m\widehat{BGD} \\

\huge\purple {\boxed {\therefore m\angle BAD =140\degree}} [/tex]

Answer:

Step-by-step explanation

hope this helps you alot

Step-by-step explanation:

If r and h are the radius and height of the cylinder, then its surface area A is given by :

[tex]A=2\pi r^2+2\pi rh[/tex] ....(1)

We need to find the cylinder's height in terms of its radius and surface area. Subtracting [tex]2\pi rh[/tex] on both sides, we get :

[tex]A-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\A-2\pi r^2=2\pi rh[/tex]

Dividing both sides by [tex]2\pi r[/tex]. So,

[tex]\dfrac{A-2\pi r^2}{2\pi r}=\dfrac{2\pi rh}{2\pi r}\\\\h=\dfrac{A-2\pi r^2}{2\pi r}[/tex]

Hence, this is the required solution.