The width of a rectangle is 4 feet and the diagonal length of he rectangle is 13 feet what is the measurement is the closest to the length of the rectangle in feet

Answer:

The length is APPROXIMATELY equal to 12.4.

Step-by-step explanation:

Use the converse of the Pythagorean Theorem ([tex]a^{2}[/tex]+[tex]b^{2}[/tex]=[tex]c^{2}[/tex] [where "c" is both the longest side and the hypotenuse]) since a rectangle's diagonals will always cut it into two right triangles:

[tex]13^{2} = 169[/tex]

[tex]4^{2} =16[/tex]

169-16=153.

[tex]\sqrt{153}[/tex] ≈ 12

or

[tex]\sqrt{153}=12.36931688[/tex]

or if the problem has to be exact (using radicals)

3*[tex]\sqrt{17}[/tex]

I hope this helps ;)

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