Answer:
The spring constant is approximately 2.84 N/m
Explanation:
The height of the building, h = 828 m
The mass of the billionaire that has an office on the top floor, m = 120 kg
Gravitational potential energy, P.E. = m·g·h
Where;
g = The acceleration due to gravity ≈ 9.81 m/s²
The gravitational potential energy of the billionaire at the top floor is therefore;
P.E. of billionaire at top floor = 120 kg × 9.81 m/s² × 828 m = 974,721.6 J
The elastic potential energy of the spring, [tex]P.E._{spring}[/tex] is given as follows;
[tex]P.E._{spring} = \dfrac{1}{2} \cdot k \cdot h^2[/tex]
Where;
k = The spring constant of the spring in N/m
h = The extension of the spring = The height of the building = 828 m
Given that the energy of the spring is conserved, we have;
[tex]P.E._{spring}[/tex] = P.E. of billionaire = 974,721.6 J
Plugging in the values gives;
[tex]P.E._{spring} = 974,721.6 \ J = \dfrac{1}{2} \times k \times (828 \ m)^2[/tex]
Therefore;
2*974,721.6/(828^2)
[tex]k = \dfrac{2 \times 974,721.6 \ J}{(828 \ m)^2} \approx 2.84 \ N/m[/tex]
The spring constant, k ≈ 2.84 N/m.
derive an expression for resistivity of conductor of length l and area of cross section A
Answer
Resistivity R = K * L / A where resistivity is constant for material, L the length of the material and A the area of the material
K = R * A / L where R is the resistance of the material
Saul is testing an installation and discovers a short circuit what’s causing this
A.high current
B.high voltage
C.low resistance
D.low voltage
Answer:
im pretty sure that it's (A.) High current
Explanation:
pf
not 100% sure, tho