the zinc plate is coated with mercury ​

Answer:20watts

Explanation:

Answer:

The solution is given below

Explanation:

The computation is shown below;

We know that

Work done = Fs cosθ

But before that we need to determine the force i.e.  

We know that

Force (F) = mass (m) × Acceleration (a)

= 100 × 5

= 500 N

Now,  work done by the go-cart is  

Work done (W) = Fs cosθ

= 500 × 25 × cos(0°)

=  500 × 25 × 1

= 12,500 J

Answer:

The magnitude of the impulse is 1.4 Ns in the West direction.

Explanation:

The impulse equation is given by:

[tex]\Delta p=m\Delta v[/tex]

Where:

So we will have:

[tex]\Delta p=0.140(25-15)[/tex]

[tex]\Delta p=1.4\: Ns[/tex]

Therefore, the magnitude of the impulse is 1.4 Ns in the West direction.

I hope it helps you!

Answer:

The argument make the assumption that;

(A) The exploration of Mars will be carried out by people travelling in spacecraft and not by robots alone

Explanation:

The argument is made for the importance of a space station where astronauts live for an appreciable time to aid in the understanding of human capacities for living in the space so as to increase the successful space travel human to Mars, which is a distance further than the Moon and therefore, will require sufficient time travel

Option B. The mechanical advantage of a handle on a water well that requires 5 newtons of force to lift a 40-Newton bucket of water is 8.

Mechanical advantage is a measure of the force amplification completed by means of the usage of a device, mechanical tool or gadget device. The device trades off input forces towards motion to gain a preferred amplification in the output pressure.

The version for this is the regulation of the lever. The mechanical advantage is the degree how which tons of force is increased with the aid of using a device or gadget. it is equal to the pressure exerted with the aid of the tool or system divided via the carried-out effort.

calculation:-

Mechanical advantage = load/effort

                                       = 40/5

                                       = 8

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Answer:

If you are talking about the experiment in which mouse and plants are kept in a closed glass jar in sunlight so in that case, they both survive because the CO2 released by the respiration of mouse is being utilized by the plants and fixed ( phosynthesis) and O2 is released as by product, which is taken by the mouse for respiration.

Answer:

Explanation:

moment of inertia of flywheel = 1/2 m R²

= .5  x 1500 x .6²

= 270 kg m²

If required angular velocity be ω

rotational kinetic energy = 1/2 I ω²

= .5 x 270 x ω² = 135 ω²

kinetic energy of bus when its velocity is 20 m/s

= 1/2 x 10000 x 20²

= 2000000 J

Given 90 % of rotational kinetic energy is converted into bus's kinetic energy

135 ω² x 0.9 = 2000000 J

ω²=16461

ω = 128.3 radian /s

b )

Let the height required be h .

Total energy of bus at the top of hill = mgh + 1/2 m v²

m ( gh + .5 v²)

= 10000 ( 9.8h + .5 x 3²)

From conservation of mechanical energy theorem

10000 ( 9.8h + .5 x 3²) = 2000000

9.8h + .5 x 3² = 200

9.8h  = 195.5

h = 19.95 m .

Answer:

hippocrates

I guess..........

Explanation:

The energy of a wave is given by :

[tex]E=\dfrac{hc}{\lambda}[/tex]

Where

h is Planck's constant

c is the speed of light

[tex]\lambda[/tex] is wavelength

Energy is inversely proportional to wavelength. Also, the relation between frequency and wavelength is inverse.

If the frequency is high, the wavelength will be shorter.

Hence, the correct options are :

Higher frequencies have shorter wavelengths.

Shorter wavelengths have lower energy.

Lower frequencies have lower energy.

Answer:

sorry buh I don't get the question

Answer:

Height of tower = 480 meter

Explanation:

Given:

Initial velocity = 20 m/s

Time taken to reach ground = 8 second

So,

Final velocity = 0 m/s

Acceleration due to gravity = 10 m/s²

Find:

Height of tower

Computation:

s = ut + (1/2)(g)(t)²

s = (20)(8) + (1/2)(10)(8)²

s = 160 + (1/2)(10)(64)

s = 160 + (10)(32)

s = 160 + 320

s = 480 meter

Height of tower = 480 meter

Answer:

If I was the white mouse, I would either find somewhere to hide that matches my fur color to camoflouge with or dig into the dirt so less visible.

To find white colour habitat.

If I was the white mouse, I would find white colour place for living because in that white colour the predators can't see me and i will be safe from them so we can conclude that finding white colour habitat is the best choice to safe myself.

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Answer:

1/2 m u^2     initial Kinetic Energy of body

m g h        Potential Energy body attains as it rises to height

1/2 m u^2 = m g h      conversion of KE to PE

h = u^2 / ( 2  g)

Answer:

The Earth spins on its axis once a day.

Explanation:

In simple words,The Earth revolves on its axis once every 24 hours and circles the sun once every 365 days. The Earth's rotation on its axis, not its orbit throughout the sun causes day as well as night. The word 'one day' refers to the period it requires the Earth to spin entirely on its axis, which involves both day as well as night.

Answer:

The impulse experienced by the car is 52,500 kg.m/s.

Explanation:

Given;

mass of the car, m = 1500 kg

initial velocity of the car, u = 55 m/s

final velocity of the car, v = 90 m/s

The impulse experienced by the car is the change in linear momentum, calculated as follows;

J = ΔP = mv  - mu

ΔP = m(v - u)

ΔP = 1500(90 - 55)

ΔP = 52,500 kg.m/s

Therefore, the impulse experienced by the car is 52,500 kg.m/s.

Answer:

uhm you can get all these answers from go ogle but just so you dot get in trouble click the tree dots at the top right of your screen (this is if your using crome) and go to history click the square and there should be a delete thing

Explanation:

Answer:

4. I and II   9. tornado

Explanation:

Answer: [tex]0.708\ mA[/tex]

Explanation:

Given

[tex]E_o=20\ V/m[/tex]

[tex]\omega =10^7\ s^{-1}[/tex]

Cross-sectional area [tex]A=0.40\ m^2[/tex]

Current density is given by

[tex]J=\epsilon_o \dfrac{dE}{dt}[/tex]

Displacement current

[tex]\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A[/tex]

The required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

Given data:

The intensity of electric field is, [tex]E_{0}=20 \;\rm V/m[/tex].

The angular frequency of electric field is, [tex]\omega=1.0 \times 10^{7} \;\rm s^{-1}[/tex].

The cross-sectional area of space is, [tex]A =0.40 \;\rm m^{2}[/tex].

In the given problem, the instantaneous electric field is given by [tex]E = E_{0} \times cos(\omega t)[/tex]

So, the expression for the current density is,

[tex]J= \epsilon_{0} \times \dfrac{dE}{dt}[/tex]

Here, [tex]\epsilon_{0}[/tex]  is the permittivity of free space. Solving as,

[tex]J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)[/tex]

And the expression for the maximum displacement current is,

[tex]I = J \times A[/tex]

And the maximum displacement current is possible only when, J is positive and J will be positive for  [tex]sin(\omega t)=-1[/tex].

Then solving as,

[tex]I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A[/tex]

Thus, we can conclude that the required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

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Answer:

I reckon towards b. Let me know if im right

Answer:

Mount Everest is Earth's highest mountain above sea level, located in the Mahalangur Himal sub-range of the Himalayas. The China–Nepal border runs across its summit point. Its elevation of 8,848.86 m was most recently established in 2020 by the Nepali and Chinese authorities.

Explanation:

Answer:

The anomalous expansion of water helps preserve aquatic life during very cold weather. When temperature falls, the top layer of water in a pond contracts, becomes denser and sinks to the bottom. If the temperature falls further, the top layer expands and remains on the top till it freezes.

Answer:

A) d_o = 20.7 cm

B) h_i = 1.014 m

Explanation:

A) To solve this, we will use the lens equation formula;

1/f = 1/d_o + 1/d_i

Where;

f is focal Length = 20 cm = 0.2

d_o is object distance

d_i is image distance = 6m

1/0.2 = 1/d_o + 1/6

1/d_o = 1/0.2 - 1/6

1/d_o = 4.8333

d_o = 1/4.8333

d_o = 0.207 m

d_o = 20.7 cm

B) to solve this, we will use the magnification equation;

M = h_i/h_o = d_i/d_o

Where;

h_o = 3.5 cm = 0.035 m

d_i = 6 m

d_o = 20.7 cm = 0.207 m

Thus;

h_i = (6/0.207) × 0.035

h_i = 1.014 m

Answer:

Explanation:

Energy stored in a solenoid per unit volume = B₀² / (2μ₀)

B₀= μ₀ n I₀

n is no of turns per unit length .

Energy stored in a solenoid per unit volume = ( μ₀ n I₀)² / (2μ₀)

=μ₀n²I₀²/2

n = 40 turns / cm = 40 x 100 turns per meter.

I₀ = 5000A .

Putting the values

Energy stored in a solenoid per unit volume

= 4π x 10⁻⁷ x 40 x 10² x 5000² /2

= 1256 J/ m³

Volume of solenoid = cross sectional area  x length

= 28 x 10⁻⁴ x .10 = 2.8 x 10⁻⁴ m³

Total energy stored = 1256  J / m³ x 2.8 x 10⁻⁴ m³

= .35 J .

Answer:

600 J

Explanation:

KE = 1/2 mv^2

Answer:

They both involve wave interactions.

Explanation:

Diffraction is defined as the bending of waves around obstacles. Refraction can be defined as the bending of the light when it transfers from one substance to another. The main similarity between the diffraction and refraction is that both involves the interaction of the waves with the substance and also causes the waves to bend and change their direction. Hence, they both involve wave interaction is the correct option.

What diffraction and refraction have in common is that they both involve wave interactions. This is further explained below.

When waves travel from one medium to another and refract, This causes them to change direction. while Diffraction is simply defined as the bending of waves around barriers.

In conclusion, diffraction and refraction are properties of waves.

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