There are 10 boys and 13 girls in Mr. Benson's fourth-grade class and 12
boys and 11 girls in Mr. Johnson fourth-grade class. A picnic committee
of six people is selected at random from the total group of students in both
clasties.
(a) What is the probability that all the committee members are girls?
(b) What is the probability that the committee has three girls and three
boys?

Answer:

Step-by-step explanation:

(0,-3.5)

Answer:

(0, -3.5)

Step-by-step explanation:

The x coordinate is first

We stay on the y axis so the x coordinate is 0

The y coordinate is second

We go down 3 1/2 units so the y coordinate is -3 1/2

(0, -3.5)

maybe 108 is the answer.

V(volume of pyramid) = ⅓ x V(volume of prism)

___________________________

And, to get the volume of prism, simply multiply the volume of pyramid by 3.

if volume of pyramid=12m³, then volume of prism is 36 m³.

Solution;:

V(volime of prism) = V(volume of pyramid) x 3

___________________________

Hence, there are 3 pyramids, and each pyramid has a volume of 12m³, these can exactly fit inside a prism with a volume of 36m³.

Answer:

736 units squared (c)

Step-by-step explanation:

Took the quiz

Answer:

∨∨∨∨see below∨∨∨∨∨∨

Step-by-step explanation:   6  26  18  13

The two outside angles are congruent.  The two inside angles are supplemental thus they are equal.  The last two angles the high one and the lower one must sum to 180° in their respective triangles so they are equal since their similar angles are equal.

find x

4 is to x as 5 is to 7.5

   4/x = 5/7.5      solve for x

   4 × 7.5 / 5  = x

    30 / 5  =  x

       6 = x

Answer:

(b-9)^2

Step-by-step explanation:

b^2-18b+81

=b^2-(9+9)b+81

=b^2-9b-9b+81

=b(b-9)-9(b-9)

=(b-9)(b-9)

=(b-9)^2

Hope this helps u!!

Answer:

[0, ∞)

0≤y<∞

Step-by-step explanation:

The range is the possible values that y can take

y  goes from 0 to positive infinity

[0, ∞)

0≤y<∞

Answer:

[tex]y\geq 0\\[/tex]

y ∈ [0, ∞)

Step-by-step explanation:

The range of a function is the set of all possible output values. In this case, one can see that the graph never goes below the value (0), therefore the range is y will always be greater than or equal to (0).

Answer:

x could be 0 or it could be 5/2

Step-by-step explanation:

Answer:

x= 5/2

Step-by-step explanation:

4x^2 + 4x - 14x = 0

subtract 4x from 14x because they are like terms

4x^2 - 10x=0

4x^2 = 0 + 10x

4x^2 = 10x

x^2/x = 10/4

x=10/4

x=5/2

Given:

Total number of cubes = 40

Red cubes = 18

Blue cubes = 13

Yellow cubes = 9

Aysha adds some more red cubes into the bag.

The probability now that she will take a red cube is 0.5.

To find:

The probability that she will take a yellow cube.

Solution:

Let Aysha adds x red cubes into the bag. Then,

Number of total cubes = 40+x

Number of red cubes = 18+x

Probability of getting a red cube is:

[tex]P(Red)=\dfrac{18+x}{40+x}[/tex]

The probability now that she will take a red cube is 0.5. So,

[tex]\dfrac{18+x}{40+x}=0.5[/tex]

[tex]18+x=0.5(40+x)[/tex]

[tex]18+x=20+0.5x[/tex]

[tex]x-0.5x=20-18[/tex]

[tex]0.5x=2[/tex]

Divide both sides by 0.5.

[tex]x=\dfrac{2}{0.5}[/tex]

[tex]x=4[/tex]

It means Aysha adds 4 more red cubes into the bag.

Now, the total number of cubes int he bag is:

[tex]40+4=44[/tex]

Probability of getting a yellow cube is:

[tex]P(Yellow)=\dfrac{\text{Number of yellow cubes}}{\text{Total number of cubes}}[/tex]

[tex]P(Yellow)=\dfrac{9}{44}[/tex]

Therefore, the required probability is [tex]P(Yellow)=\dfrac{9}{44}[/tex].

Answer:

[tex]-48x^5 y^{10} z^3[/tex] should be the answer

Step-by-step explanation:

Answer:

The height of the tree is 430cm

Step-by-step explanation:

Given

The attached illustration

Required

The height of the tree

Let:

[tex]h \to[/tex]  Hank's height

[tex]H \to[/tex] Tree height

[tex]d \to[/tex] distance between Hank and Mirror

[tex]D \to[/tex] distance between tree and Mirror

From the question, we have:

[tex]\angle 1 = \angle 2[/tex]

This means that:

[tex]\frac{H}{D} = \frac{h}{d}[/tex]

Make H the subject

[tex]H = \frac{h}{d} * D[/tex]

So, we have:

[tex]H = \frac{172cm}{190cm} * 475cm[/tex]

[tex]H = \frac{172* 475cm}{190}[/tex]

[tex]H = \frac{81700cm}{190}[/tex]

[tex]H = 430 cm[/tex]

Answer:

Prime numbers less than 20 are 2, 3, 5, 7, 11, 13, 17 and 19

Step-by-step explanation:

Answer:

[tex]A = 19.63cm^2[/tex]

Step-by-step explanation:

Given

[tex]d =5cm[/tex]

[tex]Weight = 1.6g/cm^2[/tex]

Required

The area (A) of the disk

This is calculated as:

[tex]A = \frac{\pi * d^2}{4}[/tex]

So, we have:

[tex]A = \frac{3.14 * 5^2}{4}[/tex]

[tex]A = \frac{3.14 * 25}{4}[/tex]

[tex]A = \frac{78.5}{4}[/tex]

[tex]A = 19.625[/tex]

[tex]A = 19.63cm^2[/tex] --- approximated

Step-by-step explanation:

x = 180-106 = 74°

y = x/2 = 74/2 = 37°

4z+6 =106

4z = 100

z = 25°

Answer:

x = 53

Step-by-step explanation:

The sum of the angles of a triangle are 180

x + ( x+2) + 72 = 180

Combine like terms

2x+74  =180

2x+74-74 = 180-74

2x =106

Divide by 2

2x/2 = 106/2

x =53

Answer:

[tex] \displaystyle d) 36 \: {in}^{2} [/tex]

Step-by-step explanation:

the polygon can be separated in two parts

let's figure out the area of the rectangle

recall that,

given that,

thus substitute:

simplify multiplication:

let's figure out the area of the triangle

remember that,

[tex] \displaystyle A_{ \rm triangle} = \frac{1}{2} \times b\times h[/tex]

substitute the value of b and h:

[tex] \displaystyle A_{ \rm triangle} = \frac{1}{2} \times 9\times 2[/tex]

reduce fraction:

[tex] \displaystyle A_{ \rm triangle} = 9[/tex]

now the area of the polygon would be the total area of the rectangle and triangle thus

[tex] \displaystyle A_{ \rm polygon} = 27 + 9[/tex]

simplify addition:

[tex] \displaystyle A_{ \rm polygon} = 36[/tex]

hence our answer is D)

Answer:

Volume of soda in soda can = 43.1 inches³ (Approx.)

Step-by-step explanation:

Given:

Height of soda can = 7 inches

Diameter of soda can = 2.8 inches

Find:

Volume of soda in soda can

Computation:

Radius of soda can = Diameter of soda can / 2

Radius of soda can = 2.8 / 2

Radius of soda can = 1.4 inches

Volume of soda in soda can = Volume of cylinder

Volume of soda in soda can = πr²h

Volume of soda in soda can = (3.14)(1.4)²(7)

Volume of soda in soda can = (3.14)(1.96)(7)

Volume of soda in soda can = 43.1 inches³ (Approx.)

Answer:

7.391

Step-by-step explanation:

Find 10% of 8.19

8.19*10%

8.19 *.10

.819

Subtract this from 8.19

8.19-.819

7.391

A)they have 20 dollar's in total

b)she is left with -12 dollar's

Explanation

total money = 5 + 7 + 8

                    = 20

Money Dalila had = 7 dollars

Money she spent = 12 dollars

money she is left with = 7 - 12 dollars

                                     = -5 dollars

Answer:

(2x + 3)(x + 1)

Step-by-step explanation:

you didn't show them, the factors are

(2x + 3)(x + 1)

Answer:

[tex](x+1)(2x+3)[/tex]

Step-by-step explanation:

[tex]2x^{2} +5x+3[/tex]

[tex]2x^{2} +3x+2x+3[/tex]

[tex]x(2x+3)+2x+3[/tex]

[tex](x+1)(2x+3)[/tex]

Set up a ratio:

16/12 = 28/?

Cross multiply:

16? = 12 x 28

16? = 336

Divide both sides by 16:

? = 336/16

? = 21

Answer:

(x+1)^3=x^3+3x^2+3x+1

Answer:

[tex](x+1)^{3} = x^{3} + 3x^{2} +3x+1[/tex]

Step-by-step explanation:

[tex](x+1)^{3} = x^{3} + 3x^{2} +3x+1[/tex]

[tex](A+B)^{3} = A^{3} + 3A^{2}B+3AB^{2} + B^{3}[/tex]

Answer:

0.75

Step-by-step explanation:

d = FE = 4

e = DF = 3

f = ED = 5

f/sin(F) = e/sin(E)

5/sin(90) = 3/sin(E)

5 = 3/sin(E)

sin(E) = 3/5 =0.6

E = asin(0.6) = 36.869898... degrees

tan(E) = tan(36.869898...) = 0.75

Answer:

the answer is number 4 h(x) = 1/4 x

Answer:

the  answer is 4 h(x) = 1/4 x.

Step-by-step explanation:

Step-by-step explanation:

you need to find:

uw:

uv:

vw= 8(already known)

Measure of W= 35

Measure of u= 90

measure of v= 180-90+35= 55

finding uv:

sin(35)= uv/8

0.57=uv/8

4.56=uv

finding uw:

sin(55)= uw/8

0.82= uw/8

6.56= uw

The answer is 2 ez.

Answer:

2

Step-by-step explanation:

hope i helped :))

Answer:

BC

Step-by-step explanation:

BECAUSE BC IT'S EQUAL TO EF

Answer:

B. BC

Step-by-step explanation:

By SSS rule in ∆ ABC and DEF,