There are two stereoisomers of 1-tert-butyl-4-chloro-cyclohexane. One of these isomers reacts with sodium ethoxide in an E2 reaction that is 500 times faster than the reaction of the other isomer. Identify the isomer that reacts faster, and explain the difference in rate for these two isomers.

Copper has a density of 8950 kg/m3 = 8.95 kg/dm3 = 8.95 g/cm3. Water has a density of 1000 kg/m3 = 1000 g/L = 1 kg/dm3 = 1 kg/L = 1 g/cm3 = 1 g/mL.

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Answer: Hello the reaction related to your question is missing attached below is the reaction

answer : attached below

Explanation:

The structure of the neutral organic product formed in the reaction is attached below.

The neutral organic product formed is ESTER

The reaction in the question is Anhydride on reaction with alcohol

Answer: Sodium element has 1 valence electron and chlorine element has 7 valence electrons.

Explanation:

Valence electrons are defined as the electrons that are present in the outermost shell.

An ionic compound is formed when the complete transfer of electrons takes place from one element (usually metals) to another element (usually non-metals).

To know this, we need to write the electronic configuration of each element.

Sodium is the 11th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^1[/tex]

It has 1 valence electron

Chlorine is the 17th element of the periodic table and has an electronic configuration of [tex]1s^22s^22p^63s^23p^5[/tex]

It has 7 valence electrons

Hence, sodium element has 1 valence electron and chlorine element has 7 valence electrons.

Answer:

[tex]V_l=67mL[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=375mL[/tex]

Final Volume [tex]V_2=308mL[/tex]

Generally the equation for Left-Over is mathematically given by

 [tex]V_l=V_1-V_2[/tex]

 [tex]V_l=375-308[/tex]

 [tex]V_l=67mL[/tex]

Answer:

I dont get it what words are we using bc I see words on the side just it doesn't make any sense

Answer: el texto no es tan claro

Answer:

1. B

2.B

3.B

4.C

5.C

Explanation:

I hope this help you

Answer:

Explanation:

The information below explains how dehydration of alcohol occurs to produce alkene.

Under the influence of a catalyst, alcohol dehydrates to produce an alkene and water. To produce alkene and water, the reaction eliminates the OH group from alcohol containing the carbon atom and the hydrogen atom from a neighboring carbon atom via the same molecule.

The –OH group in alcohol contribute two(2) electrons to H+ out from the acid reagent, resulting in the formation of an alkyloxonium ion. This ion serves as an excellent leaving group, allowing a carbocation to form. The nucleophile which acts as the deprotonated acid subsequently attacks and creates a double bond with the hydrogen next to the carbocation.

Explanation:

Science is the pursuit and application of knowledge and understanding of the natural and social world following a systematic methodology based on evidence

Answer:

the representative elements are elements where the the s and p orbitals are filling. The transition elements are elements where the d orbitals (groups 3-11 on the periodic table) are filling, and the inner transition metals are the elements where the f orbitals are filling.

Explanation:

=)

Answer:

See explanation

Explanation:

Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.

The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.

Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.

Racemization of the optically active (R)-2-methylcyclohexanone results from the production and subsequent interconversion of intermediates during the reaction with an aqueous base or acid. This is due to the inversion of stereochemistry at the chiral centre.

Racemization can happen when an optically active molecule is exposed to an aqueous base or acid because the compound's enantiomers are interconverted. The carbon-carbon bond next to the carbonyl group in (R)-2-methylcyclohexanone breaks as a result of the chemical reaction with the aqueous base or acid. The creation of the negatively charged intermediate known as the enolate ion occurs when a base, such as hydroxide ions, is present and attacking the carbonyl carbon. The carbonyl group can then be reformated by this enolate ion after it has undergone a nucleophilic attack on a proton.

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Answer:

2.4 × 10⁻⁴ M

Explanation:

Step 1: Calculate the concentration of Mg²⁺ coming from Mg(NO₃)₂

Mg(NO₃)₂ is a strong electrolyte and the molar ratio of Mg(NO₃)₂ to Mg²⁺ is 1:1. The initial molar concentration of Mg²⁺ is 1/1 × 0.36 M = 0.36 M.

Step 2: Make an ICE chart for the solution of MgF₂

        MgF₂(s) ⇄ Mg²⁺(aq) + 2 F⁻(aq)

I                           0.36             0

C                           +S             +2S

E                         0.36+S         2S

The solubility product constant is:

Ksp = [Mg²⁺] × [F⁻]² = (0.36+S) × (2S)²

Since S <<< 0.36, 0.36+S ≈ 0.36.

Ksp = 0.36 × 4S² = 8.4 × 10⁻⁸

S = 2.4 × 10⁻⁴ M

Answer:

ethyl ethanoate and water

Explanation:

At the point when one fluid doesn't blend in with another yet glides on top of it, an isolating pipe can be utilized to isolate the two fluids. Oil glides on water. This combination can be isolated utilizing an isolating channel as demonstrated on the following page.  

Ethyl liquor and water are two miscible fluids.   Refining is a cycle that can be utilized to isolate an unadulterated fluid from a combination of fluids. An isolating channel can be utilized to isolate the parts of the combination of immiscible fluids.

The answer is ethyl ethanoate and water. Hope this helps you!

Answer:

matter i think

Explanation:

matter i am pretty sure

The law that allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed is first law of thermodynamics.

Energy cannot be generated or destroyed, only changed in form, according to the basic law of thermodynamics.

Hence first law of thermodynamics justify the given statement.

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Answer:

condensation

Explanation:

the water has condensed from the gaseous form into rain drops

Answer:

precipitation

Explanation:

Answer:

Use the observations about each chemical reaction in the table below to decide the sign (positive or negative) of the reaction enthalpy AH and reaction entropy AS. Note: if you have not been given enough information to decide a sign, select the "unknown" option observations conclusions reaction ΔΗ is (pick one) The reverse of this reaction is always spontaneous. A As is (pick one) This reaction is spontaneous except below ΔΗ is (pick one) 38. °C but proceeds at a faster rate above (pick one) 91. °C As is ΔΗ iS (pick one) Crystallization of a pure compound is C spontaneous only below 146. °C. AS is (pick one) X

Answer: The absorbance for a solution is 0.0028

Explanation:

To calculate the absorption of a solution, the equation by Beer-Lambert law is used:

[tex]A=\varepsilon \times b\times C[/tex]

OR

[tex]A=\varepsilon \times b\times \frac{\text{Given mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (mL)}}[/tex]

where,

A = absorbance = ?

[tex]\varepsilon[/tex] = molar absorptivity = [/tex]15000m^2mol^{-1}L[/tex]

b = path length = 1 cm = 0.01 m                 (Conversion factor: 1 m = 100 cm)

Given mass of [tex]\beta-[/tex] carotene = 0.1 mg = 0.0001 g     (Conversion factor: 1 g = 1000 mg)

Molar mass of [tex]\beta-[/tex] carotene = 536 g/mol

Volume of solution = 10 mL

Putting values in equation 1:

[tex]A=15000\times 0.01\times \frac{0.0001\times 1000}{536\times 10}\\\\A=0.0028[/tex]

Hence, the absorbance for a solution is 0.0028

Answer:

For each system listed in first column of the table below, decide (if possible) whether the change described in the second column will increase the entropy S of the system, decrease S , or leave S unchanged. If you don?t have enough information to decide, check the not enough information button in the last column

Answer:

2 g of H₂

Explanation:

We have:

7 g of N₂

16 g of NO₂

16 g of O₂

2 g of H₂

Let's count to verify the moles:

7 g . 1 mol / 28g = 0.25 moles of nitrogen

16 g . 1 mol / 46g = 0.348 moles of nitrogen dioxide

16 g . 1mol /32g = 0.5 moles

2 g . 1 mol / 2g = 1 mol

The biggest number of moles is in the hydrogen.

1 mol of anything contains NA particles

1 mol of oxygen contains 6.02×10²³ molecules, the maximun number

Answer: The excess weight of the luggage is 15.5 kg and its percentage is 77.5%

Explanation:

Given values:

Maximum amount of luggage allowed = 20 kg

Amount of luggage man is carrying = [3.5 + 15 + 2 + 15] kg = 35.5 kg

Excessive weight of the luggage carried = Amount of luggage carrying - Maximum amount of luggage allowed

Excessive weight of the luggage carried = [35.5 - 20] = 15.5 kg

To calculate the percentage of excess weight, we use the equation:

[tex]\% \text{excess weight}=\frac{\text{Excess weight carried}}{\text{Maximum allowed}}\times 100[/tex]

Putting values in above equation, we get:

[tex]\% \text{excess weight}=\frac{15.5kg}{20kg}\times 100\\\\\% \text{excess weight}=77.5%[/tex]

Hence, the excess weight of the luggage is 15.5 kg and its percentage is 77.5%

Answer:

Lower the pH by several units.

Exceed the buffer capacity.

Explanation:

The options are:

*Raise the pH slightly

*Lower the pH slightly

*Raise the pH by several units

*Lower the pH by several units

*Not change the pH

*Exceed the buffer capacity

The hydrochloric acid reacts with potassium hypochlorite to produce hypochlorous acid. The amount of HCl added is the HClO produced and the KClO consumed. As the moles of HCl > moles KClO, all the KClO is consumed exceeding the buffer capacity and lowering the pH by several units.

A substance will react with oxygen to form water and carbon. ... dioxide.

Answer:

it will rain and there the other defined for precipitation snow and sleet and hail

Answer:D

Explanation:

Decomposers decompose food and return it to the environment through the soil

Answer:

Final pressure = 6 atm

Final volume = 1.1 L

Final temperature = 100 K

Explanation:

We are given;

Initial Pressure; P1 = 2 atm

Initial volume; V1 = 3.3 L

Initial temperature; T1 = 27° C + 273 = 300 K

Final pressure; P2 = 6 atm

We will use Boyles law to get the final volume.

P1V1 = P2V2

V2 = (P1 × V1)/P2

P2 = (2 × 3.3)/6

V2 = 1.1 L

We can use Charles law to find the final temperature.

V1/T1 = V2/T2

T2 = (V2 × T1)/V1

T2 = (1.1 × 300)/3.3

T2 = 100 K

Explanation:

Strong acids are those that are completely ionized in body fluids, and weak acids are those that are incompletely ionized in body fluids. Hydrochloric acid (HCl) is considered a strong acid because it is present only in a completely ionized form in the body, whereas carbonic acid (H2 CO3) is a weak acid because it is ionized incompletely, and, at equilibrium, all three reactants are present in body fluids. See the reactions below.

H2 CO3 (acid)↔H+ + HCO3- (base)

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Explanation:

Given moles = 2.0 moles

1 mole of methane contains 1 mole of carbon and 4 moles of hydrogen

Moles of carbon in [tex]CH_4=(2.0\times 1)=2.0 moles[/tex]

Given moles = 0.175 moles

1 mole of ethane contains 2 moles of carbon and 6 moles of hydrogen

Moles of carbon in [tex]C_2H_6=(0.175\times 2)=0.35 moles[/tex]

Given moles = 4.21 moles

1 mole of butane contains 4 moles of carbon and 10 moles of hydrogen

Moles of carbon in [tex]C_4H_{10}=(4.21\times 4)=16.84 moles[/tex]

Given moles = 24.5 moles

1 mole of octane contains 8 moles of carbon and 18 moles of hydrogen

Moles of carbon in [tex]C_8H_{18}=(24.5\times 8)=196 moles[/tex]

Answer:

The structures of all isomeric alcohols of molecular formula C5H12O along with their IUPAC names are as shown.

Their classification of primary, secondary, and tertiary alcohols are -

1-pentanol -

2-pentanol -

3-pentanol

2-methylbutan-1-ol

2-methylbutan-2-ol

3-methylbutan-2-ol

3-methylbutan-1-ol

2,2-dimethylpropanol