Through (-3,-5), Perpendicular to y = -x-5 in point slope and slope intercept form
Answers
Step-by-step explanation:
I really hope this helps :)
Related Questions
Kindly solve and explain
Answers
[tex] \frac{{12}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{(3 \times 4) ^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = \frac{ {3}^{ \frac{1}{2} } \times {4}^{ \frac{1}{2} } }{ {3}^{ \frac{3}{2} } } \\ = {3}^{ (\frac{1}{2} - \frac{3}{2}) } \times 2 ^{2 \times \frac{1}{2} } \\ = {3}^{ - \frac{2}{2} } \times 2 \\ = 3 ^{ - 1} \times 2 \\ = \frac{2}{3} [/tex]
Answer:[tex] \frac{2}{3} [/tex]
Hope it helps.
Do comment if you have any query.
Solve for x x^2 + 6x + 1 = 0
Answers
Answer:
x = -.1715 ≈ - .172 or x = -5.83
Step-by-step explanation:
x² + 6x + 1 = 0
x² + 6x = -1
Complete the square Add to both sides (1/2 of the x-term, then square it.)
x² + 6x + 9 = -1 + 9
(x + 3)(x + 3) = 8
(x + 3)² = 8
[tex]\sqrt{(x + 3)^{2}[/tex] = [tex]\sqrt{8}[/tex]
x + 3 = ± [tex]\sqrt{8}[/tex]
x = -3 ± [tex]\sqrt{8}[/tex]
x = -3 + [tex]\sqrt{8}[/tex] or x = -3 - [tex]\sqrt{8}[/tex]
x = -.1715 ≈ - .172 or x = -5.83
Which is greater, 2 to the fifth power or 5 squared?
Answers
Answer: 2^5
Step-by-step explanation:
2^5= 2x2x2x2x2=32
5^2=5×5=25
1. Which of the following equations is equivalent to y = ? 048 = 7x - 21 28 = 12x - 36 O 4x - 3 = 84 O4x - 12 = 84
Answers
Answer:
4x - 12 = 84
Step-by-step explanation:
The last answer choice is correct because when you cross-multiply:
[tex]4(x-3) = 12(7)[/tex] [tex]4x - 12 = 84[/tex]you get 4x - 12 = 84.
Therefore, the last option is correct.
Answer:
D would be the answer (4x-12=84)
Step-by-step explanation:
4/7=12/x-3
=>1/7=3/x-3
=>x-3=21
Multiplying both sides by 4
4(x-3)=4x21
=>4x-12=84
Hope this helped :)
If we convert 0.14 x10^3 to scientific notation, which direction should the
decimal move and how spaces should it move?
Answers
Answer:
Move it to the right by 3 spaces.
Step-by-step explanation:
10^3 is 1000
On a number line the negative numbers are on the left and the positive numbers are on the right. So since the exponent is a positive 3 we move it to the right by 3 spaces to get 140
write a peacewise function for the graph
please help me
Answers
Answer:
[tex]\left \{ {{y=x; \ \ x\le 0} \atop {y=4+ \frac12x;\ \ x>0}} \right.[/tex]
Step-by-step explanation:
If you look at the graph you see that:
before 0, the graph has same y as it has x, or y=x.
after 0, the graph starts at 4, and increases by 1 every 2 steps horizontally, or has a slope of 1/2.
Finally, the 0 has to be included in the blue part of the graph based on where the solid dot is.
find the value of x. only type the “number”
Answers
Step-by-step explanation:
5x - 6 = 3x + 2
5x - 3x = 2 + 6
2x = 8
x = 8/2
x = 4
HELPPP OMGGG
10, 10, 18, 18, 10, 5, 12, 13
Find the median and mean number of hours for these students.
If necessary, round your answers to the nearest tenth.
Answers
5,10,12,13,18
12 is the number in the middle so it’s your median.
Mean:Add all the numbers and then divide your answer by how many numbers there are.
10+10+18+18+10+5+12+13=96
There are 8 numbers so 96 divided by 8=12
meaning your median is also 12
Which ratio is equivalent to 7:3?
217
49:9
12: 8
28:12
Answers
Answer:
i think it is 49:9
Step-by-step explanation:
because number going in 49:9 by which multiple it is 7x7 is 49 3x3 is 9 so the answer is 49:9
Answer:
28:12
Step-by-step explanation:
Multiply both 7 and 3 by 4 and you get the ratio 28:12.
Which best describes the error in finding the area of the parallelogram?
15 meters was used for the height instead of 13 meters.
15 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
8 meters was used for the height instead of 13 meters.
The product of 8 and 15 is not 120.
The product of 8 and 15 is not 120.
The formula to use should have been A=12bh instead of A=bh.
The formula to use should have been, cap A is equal to 1 half b h instead of cap A is equal to b h.
Question 2
Correct the error.
A=
=
m2
Answers
Answer:
104
Step-by-step explanation:
Solve for n.
9 =
n
2
+ 7
n =
Answers
Answer:
9/n-2=7
We move all terms to the left:
9/n-2-(7)=0
Domain of the equation: n!=0
n∈R
We add all the numbers together, and all the variables
9/n-9=0
We multiply all the terms by the denominator
-9*n+9=0
We add all the numbers together, and all the variables
-9n+9=0
We move all terms containing n to the left, all other terms to the right
-9n=-9
n=-9/-9
n=1
Answer:
n = 1
Step-by-step explanation:
2 x 1 = 2
2 + 7 = 9
Please help! I will give brainlist
Answers
2)x=7+square root of 33/2
3)x=1+square root of 5/2
4)x=1 or x=-10
5)2+square root of 7 or 2-square root of 7
6)i don’t now this
7)x=0
8)3+ square roof of 41/2
9)-3+square root of 13/2
10)x=2 or x=1
11)y=6 or y=1
12)z=4 or z=1
Formula for this equation is:
ax^2+bx+c=0
X=-b+ or - square root of b^2-4ac/2a
Hope this help
Directions: Directions: Identify x1, x2, y1, and y2. Solve for the of the line passing through the given points. Identify if the slope is positive, negative, zero, or undefined.
1.(2,1) and (5,3)
2.(-2,1) and (1, -3)
3.(4,1) and (5,1)
4.(7,-1) and (7,5)
5.(-2,1) and (3,6)
Answers
Step-by-step explanation:
Number 1
m = (y2 - y1)/(x2 - x1)
m = (3 - 1)/(5 - 2)
m = 2/3 POSITIVE
Number 2
m = (y2 - y1)/(x2 - x1)
m = (-3 - 1)/(1 + 2)
m = -4/3 NEGATIVE
Number 3
m = (y2 - y1)/(x2 - x1)
m = (1 - 1)/(5 - 4)
m = 0/1
m = 0 ZERO
Number 4
m = (y2 - y1)/(x2 - x1)
m = (5 - 1)/(7 - 7)
m = 4/0
m = UNDEFINED
Number 5
m = (y2 - y1)/(x2 - x1)
m = (6 - 1)/(3 + 2)
m = 5/5
m = 1 POSITIVE
You want to have $200,000 when you retire in 25 years. If you can earn 3% interest rate compounded continuously, how much would you need to deposit now into the account to reach your retirement goal?
Answers
9514 1404 393
Answer:
$94,473.31
Step-by-step explanation:
The multiplier in 25 years is ...
e^(rt) = e^(0.03·25) = e^0.75 ≈ 2.117
To have an account value of $200,000 in 25 years, you need to deposit now ...
$200,000/2.117 = $94,473.31
_____
When this amount is multiplied by 2.117, the result is 200,000.
Write two Pythagorean triplets each having one of the numbers as 5.
Answers
Answer:
3, 4, 5 and 5, 12, 13
Step-by-step explanation:
The square of the largest side is equal to the sum of the squares of the other 2 sides.
5² = 3² + 4²
13² = 5² + 12²
The 2 triplets are (3, 4, 5 ) and (5, 12, 13)
[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪ {\huge\mathfrak{Question ~}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]
Prove that ~
[tex] \dfrac{d}{dx}\sec(x) = \sec(x) \tan(x) [/tex]
by using first principle of differentiation ~
Answers
Answer:
METHOD I:(by using the first principle of differentiation)
We have the "Limit definition of Derivatives":
[tex]\boxed{\mathsf{f'(x)= \lim_{h \to 0} \{\frac{f(x+h)-f(x)}{h} \} ....(i)}}[/tex]
Here, f(x) = sec x, f(x+h) = sec (x+h)
Substituting these in eqn. (i)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \{\frac{sec(x+h)-sec(x)}{h} \} }[/tex]
sec x can be written as 1/ cos(x)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{1}{cos(x+h)} -\frac{1}{cos(x)} \} }[/tex]
Taking LCM[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{1}{h} \{\frac{cos(x)-cos(x+h)}{cos(x)cos(x+h)} \} }[/tex]
By Cosines sum to product formula, i.e.,[tex]\boxed{\mathsf{cos\:A-cos\:B=-2sin(\frac{A+B}{2} )sin(\frac{A-B}{2} )}}[/tex]
=> cos(x) - cos(x+h) = -2sin{(x+x+h)/2}sin{(x-x-h)/2}
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{2sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{sin(\frac{h}{2} )}{h} }[/tex]
I shifted a 2 from the first limit to the second limit, since the limits ar ein multiplication this transmission doesn't affect the result[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{2sin(\frac{h}{2} )}{h} }[/tex]
2/ h can also be written as 1/(h/ 2)[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: \lim_{h \to 0} \frac{1\times sin(\frac{h}{2} )}{\frac{h}{2} } }[/tex]
We have limₓ→₀ (sin x) / x = 1.[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+\frac{h}{2} )}{cos(x+h)cos(x)}\:.\: 1 }[/tex]
h→0 means h/ 2→0Substituting 0 for h and h/ 2
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x+0)}{cos(x+0)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)cos(x)} }[/tex]
[tex]\implies \mathsf{f'(x)= \lim_{h \to 0} \frac{sin(x)}{cos(x)}\times \frac{1}{cos x} }[/tex]
sin x/ cos x is tan x whereas 1/ cos (x) is sec (x)[tex]\implies \mathsf{f'(x)= tan(x)\times sec(x) }[/tex]
Hence, we got
[tex]\underline{\mathsf{\overline{\frac{d}{dx} (sec(x))=sec(x)tan(x)}}}[/tex]
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
METHOD II:(by using other standard derivatives)
[tex] \boxed{ \mathsf{ \frac{d}{dx} ( \sec \: x) = \sec x \tan x }}[/tex]
sec x can also be written as (cos x)⁻¹We have a standard derivative for variables in x raised to an exponent:
[tex] \boxed{ \mathsf{ \frac{d}{dx}(x)^{n} = n(x)^{n - 1} }}[/tex]
Therefore,
[tex] \mathsf{ \frac{d}{dx}( \cos x)^{ - 1} = - 1( \cos \: x) ^{( - 1 - 1} } \\ \implies \mathsf{\ - 1( \cos \: x) ^{- 2 }}[/tex]
Any base with negative exponent is equal to its reciprocal with same positive exponent[tex] \implies \: \mathsf{ - \frac{1}{ (\cos x) {}^{2} } }[/tex]
The process of differentiating doesn't just end here. It follows chain mechanism, I.e.,
while calculating the derivative of a function that itself contains a function, the derivatives of all the inner functions are multiplied to that of the exterior to get to the final result.
The inner function that remains is cos x whose derivative is -sin x.[tex] \implies \mathsf{ - \frac{1}{ (\cos x )^{2} } \times ( - \sin x) }[/tex]
cos²x can also be written as (cos x).(cos x)[tex] \implies \mathsf{ \frac{ \sin x }{ \cos x } \times ( \frac{1}{cos x} ) }[/tex]
sin x/ cos x is tan x, while 1/ cos x is sec x[tex] \implies \mathsf{ \tan x \times \sec x }[/tex]
= sec x. tan x
Hence, Proved!PLEASE HELP ASAP GIVING BRAINLIEST
Answers
Answer:
brainliest mo munako
Step-by-step explanation:
bago answer pede maliwaag ba
solve pls brainliest
Answers
Answer:
first put 2 in the numerator for the first blank and 2/9 in the second blank
Step-by-step explanation:
1/3 equals 3/9 and 3/9-1/9=2/9
Answer:
[tex]\frac{3}{9}[/tex]
Step-by-step explanation:
HELP GIVING BRAINLIEST (NO LINKS) 50 POINTS
Expression A: 2(x + 1)
Expression B: 2x + 2
which statement does not show that these expressions are equivalent
A.subsitiuting any value of x makes the expressions equivalent
B. Both expressions involve addition
C. The expressions name the same number regardless of the value of x
D. 2(x +1) can be rewritten as 2x + 2 using the distributive property
Answers
h(x)=2x^(2)
evaluate for h(3/2)
Answers
Answer:
hope it helps you.........
Find the value if f(x) = -3x -8 and g(x) = x2 + 3. f(-3) =
Answers
Step-by-step explanation:
f(x) = -3x - 8
f(-3) = -3(-3) - 8
f(-3) = 9 - 8
f(-3) = 1
The graph of the function y = -2x + 4 is shown below.
If the line is translated 2 units up, which equation will best
describe the new line?
Answers
Answer:
y= -2x +6
Step-by-step explanation:
What is the 4th equivalent fraction to 1/12?
Answers
Answer:
Where's the Answer? There's No
Hello there!
Remember that equivalent fractions have the same value.
[tex]\frac{1}{2} , \frac{2}{24} ,\frac{3}{36}, \frac{4}{48}[/tex]
Therefore, the 4th equivalent fraction to 1/12 is [tex]\frac{4}{48}[/tex]Hope this helps you!
~Just a felicitous girlie
#HaveASplendidDay
[tex]SilentNature :)[/tex]
Find the x
1/2x+3/4=x5/6
Answers
Answer:
[tex]x=\frac{9}{4}[/tex]
Step-by-step explanation:
Answer:
[tex]\boxed{\boxed{\sf x=\frac{9}{4} }\:\sf or \:\boxed{x=2.25}}[/tex]
Step-by-step explanation:
[tex]\sf \cfrac{1}{2}\:x+\cfrac{3}{4}=\:x\cfrac{5}{6}[/tex]
Subtract x (5/6) from both sides:
[tex]\longmapsto\sf \cfrac{1}{2}\: x+\cfrac{3}{4} -x\left(\cfrac{5}{6}\right)=0[/tex]
Subtract 3/4 from both sides:
** Anything subtracted from zero gives its negation.**
[tex]\longmapsto\sf -\cfrac{1}{3}\:x=-\cfrac{3}{4}[/tex]
Multiply both sides by -3, reciprocal of - 1/3
[tex]\longmapsto\sf x=-\cfrac{3}{4} (-3)[/tex]
Express - 3/4 (-3) as single fraction:
[tex]\longmapsto\sf x=\cfrac{-3(-3)}{4}[/tex]
Multiply -3 and -3 = 9
[tex]\longmapsto\sf x= \cfrac{9}{4}[/tex]
______________________________________
A car is moving at 12 m/s and has a mass of 600 kg. What is the kinetic energy of the car? (Formula: KE = 1/2mv^2) WILL GIVE BRAINLEST
Answers
Answer:
The kinetic energy of the car is 43,200 Joules.
Step-by-step explanation:
KE = (1/2)mv^2
KE = (1/2)(600 kg)(12 m/s)^2
KE = (1/2)(600 kg)(144 m^2/s^2)
KE = 43,200 kg*m^2/s^2 = 43,200 Joules
Answer:
Step-by-step explanation:
KE= 1/2mv^2
KE = 1/2(600) 12^2
KE = 300 * 144 = 43200J
help!! !,
is it right or not
Answers
Answer:
No
Step-by-step explanation:
The answer is to find the sum of each number, because factors are pulling out from total numbers, but when multiplying you don't need to pull out anything so it would be number
Yep!!! Your correct
the perimeter of this triangle is 46cm find x
Answers
Answer:
the value of x is 12
......
if y varies inversely as n and m = 8 when n = 3 find m whenn =12
Answers
Answer:
24
Step-by-step explanation:
m=8x4 n=3x4 so that is the answer
help me please asap
Answers
Answer:
5/6
Step-by-step explanation:
2/
3
: 4/
5
= 2/
3
· 5/
4
= 2 · 5/
3 · 4
= 10/
12
= 2 · 5/
2 · 6
= 5/
6
Hope you get it right
I need help I will give 40 points and Brainliest!!!!!!Finding the Slope of a Line from a Table
x
y
What is the slope of the linear function represented in
the table?
O-7
-7
0
17
oi
0
O 7
Answers
Answer:
hmmmmm
Step-by-step explanation:
