Answer:
C: time of contact is increased
Explanation:
When a ball is falling from height, it maintains the same mass but velocity may change depending on the conditions in that environment.
Now, to catch the ball on your palm, you need to find a way to reduce the momentum of the ball upon hitting your hand.
Now, to reduce the momentum, we need to apply impulse.
This is because we know that;
Impulse(I) = F × t = change in momentum (m(v - u))
Thus;
I = Ft
F = I/t
We are told that extending the hand reduces the force of contact on your hand.
Thus;
For F which is the force to be reduced, the denominator (t) has to be increased.
Thus, the correct answer is that time of contact is increased
what will be the magnitude of work if a force of 25N pulls a stone through a distance of 5m in its direction?
Explanation:
125 is your answer........
1.10) For a fixed mass of gas at constant temperature, if the volume of the gas (V) increases to twice its original amount, the pressure of the gas (P) will be
A)2P
В )1/2 Р
C)P
D)4P
Answer:
B
Explanation:
According to boyle's law for a gas the pressure and volume are inversely proportional.this simply means when one increases the other one reduces and when the other one reduces the other increases.so in this case the volume increased to twice it original amount meaning the pressure will reduce to half the volume.
I hope this helps
Calculate the maximum absolute uncertainty for R if:
R = B - A
A = 32 +/- 2 seconds
B = 11 +/- 3 seconds
43 seconds
1 second
21 seconds
5 seconds
6 seconds
Answer:
ΔR = 5 s
Explanation:
The absolute uncertainty or error in an expression is
ΔR = | [tex]\frac{dR}{dB}[/tex] | ΔB + | [tex]\frac{dR}{dA}[/tex] | ΔA
the absolute value guarantees to take the unfavorable case, that is, the maximum error.
We look for the derivatives
[tex]\frac{dR}{dB}[/tex] = 1
[tex]\frac{dR}{dA}[/tex] = -1
we substitute
ΔR = 1 ΔB + 1 ΔA
of the data
ΔB = 3 s
ΔA = 2 s
ΔR = 3 + 2
ΔR = 5 s
A steel ball is released just below the surface of thick oil in a cylinder.
During the first few centimetres of travel, what is the acceleration of the ball?
A constant and equal to 10 m / s2
B constant but less than 10 m / s2
C decreasing
D increasing
Answer:
Increasing
Explanation:
I Hope it Helps
What is the volume of a cone with a height of 27 cm
and a radius of 13 cm? Round your answer to the
nearest tenth.
Use the button on your calculator to complete this
problem.
V =
cm?
Explanation:
→ Volume of cone = πr² × h/3
Here,
Radius (r) = 13 cmHeight (h) = 27 cm→ Volume of cone = π(13)² × 27/3 cm³
→ Volume of cone = 169π × 9 cm³
→ Volume of cone = 1521π cm³
→ Volume of cone = 1521 × 22/7 cm³
→ Volume of cone = 33462/7 cm³
→ Volume of cone = 4780.28 cm³
Answer:
4,778.4 is correct
Explanation:
Using your Periodic Table, which element below has the smallest atomic radius? A.) Sodium, B.) Chlorine, C.) Phosphorus, D.) Iron
will mark brainliest. The speed of sound is 340 m/s where a tuning fork produces the second resonance position above a closed air column that is 49.8 cm in length. The frequency of the tuning fork is ___ Hz.
Answer:
Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)
Explanation:
Given:
Speed of sound = 340 m/s
Length of resonance position above a closed air column = 49.8 cm = 0.498 m
Find:
Frequency of the tuning fork
Computation:
Frequency of the tuning fork[second resonance] = 3v / 4l
Frequency of the tuning fork[second resonance] = 3(340) / 4(0.498)
Frequency of the tuning fork[second resonance] = 512.04
Frequency of the tuning fork[second resonance] = 512 Hz (Approx.)
Answer:
The frequency is 512 Hz.
Explanation:
speed, v = 340 m/s
length, L = 49.8 cm = 0.498 m
let the frequency is f.
[tex]f =\frac{3 v}{4 L}\\\\f = \frac{3 \times 340 }{4\times 0.498}\\\\f = 512 Hz[/tex]
satellite does not need any energy to revolve around the earth why
Answer:
An artificial satellites revolves around the earth under the influence of its gravitational force. So it does not require any energy to revolve around energy.
or maybe god:)))(
The current in a light bulb is 2 A. How long does it take for a total charge of 4 C to pass a point in the wire
Answer:
2min
Explanation:
i think it will be clear from photo
Answer: The formula for current is charge/time
so here we have to change subject so we are asked to look for time
Explanation: so it would be T=Q/I
T=4/2
T=2s
hope this helpss
An object of 4 cm length is placed at a distance of 18 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image ,its nature and size?
Answer:
The position is 8.18cm from the mirror.
Nature is b=virtual
Size is 1.82cm
Explanation:
Note that for a convex mirror, the image distance and the focal length are negative;
Given
Object height H0 = 4cm
object distance u = 18cm
Radius of curvature R = 30cm
Since f = R/2
f = 30/2
f = -15cm
Recall that:
[tex]\frac{1}{f} =\frac{1}{u}+ \frac{1}{v}\\\frac{1}{-15}=\frac{1}{18}+\frac{1}{v} \\\frac{1}{v} =\frac{1}{-15} -\frac{1}{18}\\ \frac{1}{v} = \frac{-18-15}{270}\\\frac{1}{v} = \frac{-33}{270}\\v=\frac{-270}{33}\\v=-8.18cm[/tex]
Since the image distance is negative, this shows that the image is a virtual image.
To get the size:
[tex]\frac{H_1}{H_0}=\frac{v}{u}\\\frac{H_1}{4}=\frac{8.18}{18}\\18H_i=32.72\\H_i=\frac{32.72}{18}\\H_i= 1.82cm[/tex]
State two sources of EMF cell other than the chemical cell
Answers
Explanation:
A photodiode or solar cell may be considered as a source of emf, similar to a battery, resulting in an electrical voltage generated by charge separation driven by light rather than chemical reaction. Other devices that produce emf are fuel cells, thermocouples, and thermopiles.
What does the m stand for in the enthalpy equation?
Answer:
Use the formula ∆H = m x s x ∆T to solve.
Explanation:
Once you have m, the mass of your reactants, s, the specific heat of your product, and ∆T, the temperature change from your reaction, you are prepared to find the enthalpy of reaction. Simply plug your values into the formula ∆H = m x s x ∆T and multiply to solve.
the resultant capacitance of four capacitorconnected in series is --------the smalest individual capacitance
Answer:
This question is misleading since
1/C = 1/C1 + 1/C2 + 1/C3 + 1/C4
so it would have to be less than the smallest individual capacitance
Convert 60 km/ hr into m/s
Answer:
1 KM per minute is the real speed in minutes, turn that into 1000 meters per minute and divided by 60, you get a good number of 16.6666666667 which means you could go 50 meters per 3 seconds
Explanation:
so it would be 16.6666666667 meters per second
¿Cuál de las siguientes no es un tipo de fuerza de roce
An electron travelling at 7.72 x 107 m/s [E] enters a force field that reduces its velocity to 2.46 x 107 m/s [E]. The acceleration is constant. The displacement during the acceleration is 0.478 m [E]. Determine (a) the electron’s acceleration (b) the time interval over which the acceleration occurs.
Answer:
Acceleration of this electron: [tex]-5.60 \times 10^{15}\; \rm m \cdot s^{-2}[/tex].
Time taken: approximately [tex]9.39 \times 10^{-9}\; \rm s[/tex].
Explanation:
Let [tex]u[/tex] denote the velocity of this electron before the change.Let [tex]v[/tex] denote the velocity of this electron after the change.Let [tex]x[/tex] denote the displacement.Let [tex]a[/tex] denote the acceleration.Let [tex]t[/tex] denote the time taken.Apply the SUVAT equation that does not involve time:
[tex]v^{2} - u^{2} = 2\, a \, x[/tex].
Equivalently:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x}\end{aligned}[/tex].
By this equation, the acceleration of this electron would be:
[tex]\begin{aligned}a &= \frac{v^{2} - u^{2}}{2\, x} \\ &= \frac{(7.72 \times 10^{7}\; \rm m \cdot s^{-1})^{2} - (2.46 \times 10^{7} \; \rm m \cdot s^{-1})^{2}}{2 \times 0.478\; \rm m} \\ &\approx -5.60 \times 10^{15}\; \rm m \cdot s^{-2}\end{aligned}[/tex].
The speed of this electron has changed from [tex]u = 7.72 \times 10^{7}\; \rm m\cdot s^{-1}[/tex] to [tex]v = 2.46 \times 10^{7}\; \rm m \cdot s^{-1}[/tex]. Calculate the time required to achieve this change at a rate of [tex]a \approx -5.60 \times 10^{15}\; \rm m\cdot s^{-2}[/tex]:
[tex]\begin{aligned}t &= \frac{v - u}{a} \\ &\approx \frac{2.46\times 10^{7}\; \rm m \cdot s^{-1} - 7.72 \times 10^{7}\; \rm m\cdot s^{-1}}{-5.60 \times 10^{15}\; \rm m\cdot s^{-2}} \\ &\approx 9.39 \times 10^{-9}\; \rm s\end{aligned}[/tex].
the pages of a book are numbered 1 to 300. Each leaf is 0.1 mm thick . If each cover is 0.25 mm thick. what is the thickness of the book
Answer:
30.5mm
Explanation:
There are 300 pages, so to find the number of pages we do 0.1mm*300 to get 30mm. There are two covers in the book (the front and the back). 0.25mm*2 = 0.5mm. To determine the total thickness of the book we do 30mm+0.5mm to get a total of 30.5mm
Your answer is 30.5mm.
Answer:
15.5mm
Explanation:
there are 150 pages(one page has 2 sides so 300/2 = 150) and 2 covers
page's thickness is 0.1mm, cover's thickness is 0.25
so books thickness = 150*0.1+0.25*2 = 15.5mm
I’m steel, the solvent is And the solute is. .
prepare for the module exam,
Question 1
1 pts
If a 6 ohm wire is connected to a 10 volt battery, what will the current be?
O 6 amperes
O ,67 amperes
O 1.67 amperes
60 amperes
Answer:
1.67 amperes
Explanation:
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex] V = IR [/tex] ......equation 1
Where;
V represents voltage measured in voltage.I represents current measured in amperes.R represents resistance measured in ohms.Making I the subject of formula, we have;
[tex] I = \frac {V}{R} [/tex] .....equation 2
Given the following data;
Voltage = 10 VoltsResistance = 6 OhmsTo find the current flowing through the battery, we would use eqn 2;
[tex] I = \frac {10}{6} [/tex]
Current, I = 1.67 amperes
Example to measure the interval of time of a small stone dropped from 1m height.
Answer:
The time required is 0.45 s.
Explanation:
Height, h = 1 m
initial velocity, u = m/s
Let the time is t.
Use second equation of motion
[tex]h = u t + 0.5 at^2\\\\1 = 0 +0.5 \times 9.8 \times t^2\\\\t = 0.45 s[/tex]
Calculate the mass in grams of a toy car if a force of 2 N causes it to accelerate by 10 m/s2
Answer:
m=0.2kg=200g
Explanation:
F=2N, a=10m/s²
F=ma⇒ m=F/a=2/10=0.2kg=200g
Answer:
[tex]\boxed {\boxed {\sf 200 \ grams}}[/tex]
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
[tex]F=m*a[/tex]
The force is 2 Newtons and the acceleration is 10 meters per square second. First, we should convert the units of Newtons to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared. The force of 2 N equals 2 kg*m/s²
Substitute the known values into the formula.
F= 2 kg*m/s²a= 10 m/s²[tex]2 \ kg*m/s^2 = m * 10 \ m/s^2[/tex]
We are solving for the mass, so we must isolate the variable m. It is being multiplied by 10 meters were second squared. The inverse of multiplication is division. Divide both sides by 10 m/s².
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}=\frac{ m* 10 m/s^2}{10 \ m/s^2}[/tex]
[tex]\frac { 2 \ kg *m/s^2}{10 \ m/s^2}= m[/tex]
The units of meters per second squared cancel.
[tex]\frac { 2 \ kg}{10}= m[/tex]
[tex]0.2 \ kg =m[/tex]
Now, we must convert the mass to grams. There are 1000 grams in 1 kilogram. We can multiply the mass by 1000 or set up a ratio.
[tex]0.2 \ kg * \frac{1000 \ g}{1 \ kg}= 0.2 * 1000 \ g = 200 \ g[/tex]
The toy car's mass is 200 grams.
If the electric force between two charges is 4.2 × 10-2 N, what would the new force be if the distance between the charges is doubled and the charge on one of the charges is tripled?
Answer:
New force = 0.063 N
Explanation:
Given that,
The electric force between two charges is[tex]4.2\times 10^{-2}\ N[/tex]
The formula for the electric force is:
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
If the distance between the charges is doubled, r' = 2r and one of the charges is tripled, q₁' = 2q₁, q₂' = 3q₂
Put all the values,
[tex]F'=\dfrac{kq_1'q_2'}{r'^2}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{kq_1q_2}{r^2}}{\dfrac{kq_1'q_2'}{r'^2}}\\\\\dfrac{F}{F'}=\dfrac{\dfrac{q_1\times q_2}{r^2}}{\dfrac{2q_1\times 3q_2}{(2r)^2}}\\\\\dfrac{F}{F'}=\dfrac{4}{6}=\dfrac{2}{3}\\\\F'=\dfrac{3\times 4.2\times 10^{-2}}{2}\\\\F'=0.063\ N[/tex]
So, the new force is 0.063 N.
Answer:
The force becomes 0.0315 N.
Explanation:
Force, F = 4.2 x 10^-2 N
When the distance is doubled, a charge is tripled, Let the force is F'.
The force between the two charges is
[tex]F = \frac{K qq'}{r^2}\\[/tex]
when, q' = 3 q' and r is 2 r so
[tex]F' = \frac{K 3qq'}{4r^2} = \frac{3 F}{4} = \frac {3\times 4.2\times 10^{-2}}{4}=0.0315 N[/tex]
The direction equivalent to {40° W of S} is:
A. 40 ° E of S
B. 40° W of N
C. 40° E of N
D. 50° S of W
E. 50° E of N
Answer:
c
Explanation:
Why are simple everyday actions considered
thermodynamic reactions?
they transform energy
they destroy energy
they create energy
Answer:
They transform energy
Explanation:
thermodynamics deals with transfers of energy from one place to another and from one form to another and it's also deal with the relationship between heat and other forms of energy
4. A body in motion is said to be in equilibrium when it is
A moving with uniform velocity.
B at rest.
C accelerated by a force.
D moving in an indefinite path.
Answer:
A. moving with uniform velocity.
Explanation:
Was this hepfull
Answer:
A
Explanation:
Equilibrium is a state in which opposing forces or influences are balanced hence A being correct
You slide a 325-N trunk up a 20.0° inclined
plane with a constant velocity by exerting a
force of 211 N parallel to the inclined plane.
a. What is the component of the trunk's
weight parallel to the plane?
b. What is the sum of your applied force, fric-
tion, and the parallel component of the
trunk's weight? Why?
C. What is the size and direction of the friction
force?
d. What is the coefficient of friction?
Answer:
A) 111 N
B) F_net = 0 N
C) 100 N, in the opposite direction of the motion.
D) μ = 0.3274
Explanation:
A) The component of the trunks weight acts parallel to the plane but in the vertical direction and so;
W = Fsin θ
W = 325 sin 20
W = 325 × 0.3420
W ≈ 111 N
B) We are told the trunk is moving with a constant velocity and for this reason the sun of the forces will equal to zero.
Thus; F_net = 0 N
C) Since the kinetic friction force needs to balance the component of the weight, the magnitude is;
F_f = 211 - 111 = 100 N
The direction will be in the opposite direction since it's against the motion.
D) From friction formula, we know that;
F_f = μW cos θ
100 = μ × 325 × cos 20
μ = 100/(325 × cos 20)
μ = 0.3274
A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the school is _________ m? The direction of the student's displacement, relative to the school is ______?
Answer:
1. 7.5 m
2. towards west side
explanation:
I hope it will help you
C is not less than 0
Give reasons for the following,
a. Pascal is a derived unit.
b. Mass is a fundamental quantity,
c. Unit of power is a derived unit,
d. Unit of length is a fundamental unit.
Answer:
a) Pascal is a derived unit because it is derived from the unit of force and area
b)Mass is a fundamental quantity because it doesn't depends upon others physical quantity and made up of only one unit
c) unit of power is a derived unit because they are dependent quantities
D) unit of length is a fundamental unit because it cannot be expressed in terms of another quantity.
Drag each label to the correct location on the image. Identify the particles and characteristics on this model of an atom.
Positively charged
Electron
Proton
Neutron
Negatively charged
Answer:
cant see picture
Explanation:
Answer:
please add picture so i can help you
Explanation:
