We can construct the 95% confidence interval for the true proportion. To do this, we need to calculate the margin of error, which is equal to the critical value (1.96) multiplied by the standard error (0.014). This equals 0.028.
The 95% confidence interval is then the sample proportion (0.38) plus or minus the margin of error (0.028). This is [tex](0.38 - 0.028, 0.38 + 0.028) = (0.352, 0.408).[/tex]
The test statistic in this case is the Z-statistic, as we are assuming that the underlying population is normally distributed. To conduct the hypothesis test, we must first state the null and alternative hypotheses.
Null Hypothesis (H0): The proportion of students at the school who fear public speaking is equal to or greater than 40%.
Alternative Hypothesis (H1): The proportion of students at the school who fear public speaking is less than 40%.
We must then calculate the test statistic, which is the Z-statistic in this case. To do this, we need to first calculate the sample proportion, which is the number of students who fear public speaking (137) divided by the total number of students surveyed (361). This equals 0.38. We then need to calculate the standard error of the sample proportion (SE), which is the square root of [tex](pq/n)[/tex], where p is the sample proportion (0.38) and q is the complement of the sample proportion (1-0.38 = 0.62). SE = [tex](0.38 x 0.62)/361 = 0.014.[/tex] The Z-statistic is then calculated as the difference between the sample proportion (0.38) and the population proportion (0.40) divided by the standard error [tex](0.014). Z = (0.38 – 0.40)/0.014 = -0.14.[/tex]
To conclude, we can use the Z-statistic and 95% confidence interval to test the hypothesis that the proportion of students at the school who fear public speaking is less than 40%. The Z-statistic of -0.14 falls within the critical region and the 95% confidence interval does not include 0.40, suggesting that the proportion of students at the school who fear public speaking is indeed less than 40%.
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How to graph it on a coordinate plan to the right 5x-3y=18
Tο shift the graph tο the right, we can simply add a pοsitive cοnstant tο the x values οf each pοint befοre plοtting them. Fοr example, if we want tο shift the graph tο the right by 2 units.
What is cοοrdinate plan?The intersectiοn οf twο number lines creates a twο-dimensiοnal plane knοwn as a cοοrdinate plane. The x-axis, a hοrizοntal number line, and the y-axis, a vertical number line, are twο examples οf these number lines.
Tο graph the equatiοn 5x - 3y = 18 οn a cοοrdinate plane, we can fοllοw these steps:
1. Sοlve fοr y in terms οf x:
5x - 3y = 18
-3y = -5x + 18
y = (5/3)x - 6
2. Chοοse sοme values fοr x and use the equatiοn tο find the cοrrespοnding y values. Fοr example, we can chοοse x = 0, 3, and 6:
When x = 0: y = (5/3)(0) - 6 = -6
When x = 3: y = (5/3)(3) - 6 = -3
When x = 6: y = (5/3)(6) - 6 = 2
3. Plοt the pοints (0, -6), (3, -3), and (6, 2) οn the cοοrdinate plane.
4. Draw a straight line passing thrοugh these three pοints. This line represents the graph οf the equatiοn 5x - 3y = 18.
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calculate the centripetal force (in n) on the end of a 52 m (radius) wind turbine blade that is rotating at 0.3 rev/s. assume the mass is 2 kg
The centripetal force is 7384.80 N.
For the centripetal force in N on the end of a 52 m (radius) wind turbine blade that is rotating at 0.3 rev/s and assuming the mass is 2 kg.
Use the following formula:
Centripetal force = (mass x velocity²) / radius
Where; mass = 2 kg
In this case, the radius of the wind turbine blade is 52 m, and it is rotating at 0.3 rev/s, which means that the angular velocity is:
ω = 2π * f = 2π * 0.3 = 1.884 rad/s
where f is the frequency or revolutions per second.
The linear velocity at the end of the blade can be calculated as:
v = r * ω ⇒ 52 * 1.884 ⇒ 98.088 m/s
radius = 52 m
Centripetal force = (2 x 98.088²) / 52
Centripetal force = 7384.80 N
Therefore, the centripetal force on the end of a 52 m wind turbine blade rotating at 0.3 rev/s with a mass of 2 kg is 7384.80 N.
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Luke bought 4 kilograms of apples and 0.29 kilograms of oranges. How much fruit did he buy
in all?
He bought 4.29 Kilos of fruit.
4+0.29=4.29
Luke bought 4.29 kilograms of fruit in all
Step-by-step explanation:
Simple addition will be used to find the total fruit Luke bought.
Given
Amount of apples he bought = 4 kilograms
Amount of oranges he bought = 0.29 kilograms
so the total fruit will be:
[tex]\text{total fruit}=\text{Apples}+\text{oranges}[/tex]
[tex]=4+0.29[/tex]
[tex]=4.29[/tex]
So,
Luke bought 4.29 kilograms of fruit in all
Keywords: Measurement, addition
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Coin A is tossed three times and coin B is tossed two times. What is the probability that more heads are tossed using coin A than coin B?
The probability that more heads are tossed using coin A than coin B is 5/16.
The given data is: Coin A is tossed three times and coin B is tossed two times. We have to find the probability that more heads are tossed using coin A than coin B.
P(E) = Number of favorable outcomes/ Total number of possible outcomes
Coin toss:
There are two possible outcomes in a coin toss, Head or Tail. The probability of getting a head in a coin toss is
1/2 = 0.5.
Therefore, the probability of getting a tail in a coin toss is also 1/2 = 0.5.
Let's calculate the possible outcomes when coin A is tossed three times.
There are 2 possible outcomes when one coin is tossed.
Number of possible outcomes when three coins are tossed = 2 * 2 * 2 = 8
Likewise, the possible outcomes when coin B is tossed two times are:
The number of possible outcomes = 2 * 2 = 4
Therefore, the total number of possible outcomes = 8 * 4 = 32
Now, we will find out the cases where the number of heads is more when coin A is tossed three times.
HHH HHT HTH HTT THH THT TTH TTT HHT HTT THT TTT TTH TTT HTT TTT THT TTT TTT TTT
Therefore, the number of times when more heads are obtained when coin A is tossed three times is 10. (We have to exclude the case when there is an equal number of heads.)
Therefore, the required probability is: P = Number of favorable outcomes/ Total number of possible outcomes
P = 10/32P = 5/16
Therefore, the probability that more heads are tossed using coin A than coin B is 5/16.
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Please help quick with this question.
Answer:
b = [tex]\frac{S-2la}{h+l}[/tex]
Step-by-step explanation:
S = bh + lb + 2la ( reversing the equation )
bh + lb + 2la = S ( subtract 2la from both sides )
bh + lb = S - 2la ← factor out b from each term on the left side
b(h + l) = S - 2la ← divide both sides by (h + l)
b = [tex]\frac{S-2la}{h+l}[/tex]
Apply De Morgan's law repeatedly to each Boolean expression until the complement operations in the expression only operate on a single variable. For example, there should be no xy¯ or x+y¯ in the expression. Then apply the double complement law to any variable where the complement operation is applied twice. That is, replace x¯¯ with x.
a. 1/ x + yz + u b. 1/x(y + 2)u c. 1/(x + y)(uv + x y) d. 1/xy + yz + xz
The simplified expression using De Morgan's law are a)x'y'z'u b)x'y'u c): x'y'u and d)x'y'z'+xy'z'+xyz.
The main idea is to simplify each Boolean expression by repeatedly applying De Morgan's law until each complement operation operates on a single variable.
Then, apply the double complement law to simplify the expression further. In the end, the simplified expression should contain only AND and OR operations without any complement operators acting on multiple variables.
a. 1/ x + yz + u can be simplified using De Morgan's law to: (x'y'z')u'. Then, applying the double complement law, we get the simplified expression as: x'y'z'u.
b. 1/x(y + 2)u can be simplified using De Morgan's law to: x'(y'+2')u'. Then, applying the double complement law, we get the simplified expression as: x'y'u.
c. 1/(x + y)(uv + xy) can be simplified using De Morgan's law to: (x'y')(u' + x'y'). Then, applying the double complement law, we get the simplified expression as: x'y'u.
d. 1/xy + yz + xz can be simplified using De Morgan's law to: (x'+y')(y'+z')(x'+z'). Then, applying the double complement law, we get the simplified expression as: x'y'z'+xy'z'+xyz.
In summary, to simplify Boolean expressions, we can apply De Morgan's law repeatedly and then use the double complement law to remove complement operators acting on a single variable twice.
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20x50x30x50 = ?
Please answer someone!!
Answer: 1500000
Step-by-step explanation:
use a calculator
Answer:
1,500,000
Step-by-step explanation:
Breaking it up into an easier problem:
20x50 = 1,000
30x50=1,500
1,000 x 1,500, aka "adding three zeros" to the end of 1,500, as 1,000 is simply 1 x 10 x 10 x 10, and each 10 has one 0 to it.
Thus, the answer is 1,500,000
You are dealt five cards from a standard deck of 52 playing cards (A full house consists of three of one kind and two of another. For example, A A A 5-5 and K-K-K 10-10 are full houses) (a) in how many ways can you get a full house? ______ Ways (b) in how many ways can you get a five card combination containing two jacks and three aces ___ ways
The 32 ways to get a five-card combination containing two jacks and three aces.
(a) A full house consists of three of one kind and two of another kind. Therefore, there are 13 different choices for the rank of the triplet and 4 cards of the same rank. Once the triplet has been chosen, there are 12 choices for the rank of the pair and 4 cards of the same rank. Therefore, the number of ways to get a full house is as follows:$${13}{\times}{4}{\times}{12}{\times}{4}={7488}$$Therefore, there are 7488 ways to get a full house.(b) In this case, the two jacks and three aces must be chosen out of the 4 jacks and 4 aces in the deck. Therefore, the number of ways to get a five-card combination with two jacks and three aces is as follows:$$\frac{{4\choose2}{4\choose3}{44\choose0}}{5!}={32}$$Therefore, there are 32 ways to get a five-card combination containing two jacks and three aces.
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Square root of
3a^2/10b^6
Answer:
Step-by-step explanation:
Rewrite
3
a
2
10
b
6
as
(
a
b
3
)
2
3
10
.
√
(
a
b
3
)
2
3
10
Pull terms out from under the radical.
a
b
3
√
3
10
Rewrite
√
3
10
as
√
3
√
10
.
a
b
3
⋅
√
3
√
10
Combine.
a
√
3
b
3
√
10
Multiply
a
√
3
b
3
√
10
by
√
10
√
10
.
a
√
3
b
3
√
10
⋅
√
10
√
10
Combine and simplify the denominator.
√
3
√
10
b
3
⋅
10
Simplify the numerator.
Tap for more steps...
a
√
30
b
3
⋅
10
Move
10
to the left of
b
3
.
a
√
30
10
b
3
Step-by-step explanation:
[tex]{ \tt{ \sqrt{ \frac{3 {a}^{2} }{10 {b}^{6} } } }} = { \tt{ \frac{ {(3a {}^{2}) }^{ \frac{1}{2} } }{ {(10b {}^{6} )}^{ \frac{1}{2} } } }} \\ \\ = { \tt{ \frac{a \sqrt{3} }{ {b}^{3} \sqrt{10} } }} \\ \\ = { \tt{ \frac{a \sqrt{3} }{ {b}^{3} \sqrt{10} } }}[/tex]
A classroom is rectangular in shape. If listed as ordered pairs, the corners of the classroom are (−12, 15), (−12, −9), (9, 15), and (9, −9). What is the perimeter of the classroom in feet?
By answering the presented question, we may conclude that Therefore, the perimeter of the classroom is 96√2 + 42 feet (approx. 155.27 feet).
What is rectangle?In Euclidean geometry, a rectangle is a parallelogram with four small angles. It may also be defined as a hexagon that is fundamental rule, or one in which all of the angles are equal. Another alternative for the parallelogram is a straight angle. Four of the vertices of a square are the same length. A quadrilateral with four 90° angle vertices and equal parallel sides has a rectangle-shaped cross section. As a result, it is also known as a "equirectangular rectangle." A rectangle is sometimes referred to as a parallelogram due to the equal and parallel dimensions of its two sides.
The perimeter-
d = √[(x2 - x1)² + (y2 - y1)²]
So, the perimeter of the classroom is:
d1 = √[(-12 - (-12))² + (15 - (-9))²] = √(24² + 24²) = √(2² × 24²) = 48√2
d2 = √[(-12 - 9)² + (15 - 15)²] = √(21²) = 21
d3 = √[(9 - 9)² + (15 - (-9))²] = √(24² + 24²) = √(2² × 24²) = 48√2
d4 = √[(9 - (-12))² + (-9 - 15)²] = √(21²) = 21
perimeter = d1 + d2 + d3 + d4
= 48√2 + 21 + 48√2 + 21
= 96√2 + 42
Therefore, the perimeter of the classroom is 96√2 + 42 feet (approx. 155.27 feet).
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what is the product of any two invertible matrices is invertible.
The product of any two invertible matrices is invertible that is (BC) = A⁻¹
Now, let's consider the product of two invertible matrices, say A and B. Since A and B are invertible, they both have an inverse, denoted by A⁻¹ and B⁻¹, respectively.
To show that the product AB is also invertible, we need to find a matrix that satisfies the definition of an inverse. Let's call this matrix C.
If C is the inverse of AB, then we should have:
(AB)C = C(AB) = I
where I is the identity matrix.
Now, we can use the associativity of matrix multiplication to expand the left-hand side of the equation:
(AB)C = A(BC)
Notice that B and C are both matrices, so their product BC is also a matrix. Thus, we can write:
A(BC) = I
Since A is invertible, we can multiply both sides by A⁻¹ to get:
A⁻¹A(BC) = A⁻¹I
The left-hand side simplifies to:
(BC) = A⁻¹
Now, we have found a matrix C that satisfies the definition of an inverse for AB, which means that AB is invertible.
To summarize, the product of two invertible matrices is invertible, and the proof relies on the fact that the inverse of a matrix is unique and the associativity of matrix multiplication.
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What are the zeros of the function? Set the function = 0, factor, and use the zero-product property. Show your steps!
f(x) = x² + 7x – 60
(100 POINTS AND BRAINLIEST)
The zeroes of the function are -12 and 5.
What is meant by Zeros of the function?Zeros of a function are the values of the input variables that make the output of the function equal to zero. The zeros are the solutions of equation f(x) = 0.
According to the question:
To find the zeros of the function
f(x) = x² + 7x - 60, we must set f(x) equal to zero and solve for x.
So we start with the equation:
x² + 7x - 60 = 0
Next, we need to factor the left side of the equation. We are looking for two numbers that multiply to -60 and add to 7. After some trial and error, we find that the numbers are 12 and -5:
x² + 7x - 60 = (x + 12)(x - 5) = 0
Now we can apply the zero product property, which states that if the product of two factors is zero, then at least one of the factors must be zero. Therefore, we set each factor equal to zero and solve for x:
x + 12 = 0 or x - 5 = 0
Solving for x, we get:
x = -12 or x = 5
The zeros of the function f(x) = x² + 7x - 60 are therefore x = -12 and x = 5.
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The graph shows the velocity, v metres per second, of a car at time t seconds. Work out an estimate for the distance the car travelled for the first 8 seconds. Use 4 strips of equal width. -1-500- -1000- -500 0 V t
please help!!!
To estimate the distance traveled we need to find the area under the velocity-time graph from 0 to 8 seconds So,The estimate for the distance the car traveled for the first 8 seconds is 4000 meters.
Define velocity-time graph?A velocity-time graph is a graphical representation that shows the velocity of an object on the y-axis and time on the x-axis. It is used to depict the change in velocity over time and can provide information about the acceleration or deceleration of an object.
The height of each strip can be estimated by taking the average of the velocities at the beginning and end of the strip.
Using the trapezium rule, the estimated area of each strip is:
Strip 1: 0.5 x (0 + 2) x (0 + (-500)) = -500 m/s
Strip 2: 0.5 x (2 + 4) x (-500 + (-1000)) = -1500 m/s
Strip 3: 0.5 x (4 + 6) x (-1000 + (-500)) = -1500 m/s
Strip 4: 0.5 x (6 + 8) x (-500 + 0) = -500 m/s
The total estimated area is the sum of the areas of the 4 strips:
Total estimated area = -500 + (-1500) + (-1500) + (-500) = -4000 m/s
Since the area represents the distance traveled by the car, we can take the absolute value of the area to get the estimated distance traveled:
Estimated distance traveled is = |-4000| = 4000 meters
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El Sr. Milton Escobar se presenta al banco de los Trabajadores de Tegucigalpa a constituir un depósito a Plazo Fijo #2250 a 6 meses por L100,000. 00 al 10. 5% de interés anual entregando el valor total con cheque #0045 a cargo del mismo banco. Haga la partida de apertura
As the banker at the Banco de los Trabajadores de Tegucigalpa, I greet Mr. Milton Escobar and thank him for choosing our bank for his fixed term deposit. I verify his identification and confirm the details of his deposit, which are:
Fixed Term Deposit number: #2250
Deposit amount: L100,000.00
Deposit term: 6 months
Interest rate: 10.5% per annum
I inform Mr. Escobar that the interest on his deposit will be calculated and credited to his account at the end of the deposit term. I also explain that he can choose to receive the interest in cash or reinvest it in the fixed term deposit.
Next, I ask Mr. Escobar to provide me with a check for the full deposit amount, payable by the Banco de los Trabajadores de Tegucigalpa, and I confirm that the check number is #0045. I inform him that the check will be deposited in his account and that he will receive a deposit confirmation letter.
Finally, I thank Mr. Escobar for his business and remind him to keep his deposit confirmation letter in a safe place, as it is a crucial document that he will need to produce at the time of maturity to withdraw his funds. I assure him that our bank will provide him with the highest quality service and look forward to his continued patronage.
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Translated Question ;
Mr. Milton Escobar appears at the Banco de los Trabajadores de Tegucigalpa to set up a Fixed Term Deposit #2250 for 6 months for L100,000. 00 to 10.5% annual interest, delivering the total amount by check #0045 payable by the same bank. Play the opening game
Solve the inequalities 1/3x-1/4(x+2)>3x-4/3
Answer: x < -46/17
Step-by-step explanation:
To solve the inequality:
1/3x - 1/4(x + 2) > 3x - 4/3
First, we simplify the left-hand side by finding a common denominator:
4(1/3x) - 3/4(x + 2) > 3x - 4/3
4/3x - 3/4x - 9/2 > 3x - 4/3
Next, we simplify the equation:
7/12x - 9/2 > 3x - 4/3
To isolate the variable x on one side of the inequality, we will move all the x terms to the left-hand side and all the constants to the right-hand side:
7/12x - 3x > 9/2 - 4/3
-17/12x > 23/6
Finally, we can solve for x by dividing both sides by -17/12, remembering to reverse the inequality because we are dividing by a negative number:
x < (23/6) ÷ (-17/12)
x < -46/17
Therefore, the solution to the inequality is:
x < -46/17
machines at a factory produce circular washers with a specified diameter. the quality control manager at the factory periodically tests a random sample of washers to be sure that greater than 90 percent of the washers are produced with the specified diameter. the null hypothesis of the test is that the proportion of all washers produced with the specified diameter is equal to 90 percent. the alternative hypothesis is that the proportion of all washers produced with the specified diameter is greater than 90 percent. which of the following describes a type i error that could result from the test? responses the test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%. the test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%. the test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%. the test does not provide convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%. the test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%. the test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is equal to 90%. the test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%. the test provides convincing evidence that the proportion is greater than 90%, but the actual proportion is greater than 90%. a type i error is not possible for this hypothesis test.
Answer:
the test does not provide convincing evidence that the proportion is greater than 90%
the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth. what is the effect on the weight when the distance is multiplied by 2?
The weight becomes 1/4 of its original value when the distance is multiplied by 2.
According to the question, "the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth." We need to determine the effect on the weight when the distance is multiplied by 2.
Let w be the weight of a body, d be the distance from the center of the earth, and k be the constant of variation. According to the question,
w = k / d²
When the distance is multiplied by 2, the new distance is 2d. Therefore, the new weight is given by:
w' = k / (2d)²
w' = k / 4d²
w' = w / 4
Therefore, the weight becomes 1/4 of its original value when the distance is multiplied by 2.
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Write down the smallest possible answer.
Answer:
3
Step-by-step explanation:
We have to find the smallest possible factor of 15 and multiple of 3.
The smallest factor of any positive integer is 1.
The smallest multiple of any positive integer is the integer itself. So the smallest multiple of 3 would be 3 itself.
[tex]1 * 3 = 3[/tex]
And 3 is the answer.
Stefanie bought a package of pencils for 1. 75$ and some erasers that cost 0. 25 each. She paid a total of 4. 25 for these items, before tax. Exactly how many erasers did stefanie buy?
Stefanie bought a package of pencils for 1. 75$ and some erasers that cost 0. 25 each. She paid a total of 4. 25 for these items, before tax. Stefanie bought total 10 erasers.
Equation:
In mathematics, an equation is a formula that connects two expressions with the equal sign = to indicate that they are equal.
According to the Question:
The number of erasers bought by Stefanie:
Let we denote the number of erasers bought by her by x (an unknown variable)
Then we will have:
Total amount before tax = cost of one package of pencil + cost of erasers
$4.25 = $1.75 + X × $0.25
⇒ 4.25 = 1.75 + 0.25x
Now,
we will perform subtraction by 1.75 and division by 0.25 on both sides.
4.25 = 1.75 + 0.25x
Subtracting 1.75 both side:
4.25 -1.75 = 0.25x
⇒ 2.5 = 0.25x
Dividing by 0.25 on both sides:
2.5/0.25 = 0.25x/0.25
⇒ x = 10
Thus, Stefanie bought total 10 erasers.
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A restaurant owner is buying new tableware for her restaurant. She wants the new pieces to be proportionate, and needs to know the measurements of the different pieces she is buying. The circle-shaped part of the bottom of the glass above has an area of 12.56 in2. What is the radius? Use = 3.14. A. 4 in B. 5 in C. 1 in D. 2 in Reset Submit
The answer is d please
I NEED HELPP PLEASEEEEEEEE
The slope between the points (-3, 0) and (0, -1) is -1/3.
What is slope?The slope of a line serves as a gauge for its steepness. It may be calculated by dividing the difference in y-coordinate by the difference in x-coordinate between any two points on a line. A line's slope might be zero, positive, negative, or undefinable. A line with a positive slope is moving upward from left to right, a negative slope is moving downward from left to right, and a line with a zero slope is level. The line is vertical if the slope is undefinable.
Let us consider the first two points (-3, 0) and (0, -1).
The slope of the line is given as:
m = (y2 - y1) / (x2 - x1)
Substituting the values we have:
m = (-1 - 0) / (0 - (-3)) = -1/3
Hence, the slope between the points (-3, 0) and (0, -1) is -1/3.
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Simplify these radicals (ASAP!!!)
Answer:
[tex]3.\quad 2\sqrt{7}\\\\4.\quad \dfrac{2}{\sqrt{5}}[/tex]
[tex]5.\quad \dfrac{1}{\sqrt{2}}[/tex]
[tex]6.\quad\dfrac{5}{7}[/tex]
Step-by-step explanation:
To simplify radicals find the factors and simplify the square roots of the factors
#3 : √28
28 = 4 x 7
√28 = √(4 x 7) = √4 x √7 = 2 x √7 = 2√7
========================================================
[tex]\#4:\quad \sqrt{ \dfrac{4}{5}}\\\\\sqrt{ \dfrac{4}{5}} = \dfrac{\sqrt{4}}{\sqrt{5}} = \dfrac{2}{\sqrt{5}}[/tex]
========================================================
[tex]\#5\quad \dfrac{3}{\sqrt{18}}\\\text{Denominator } \sqrt{18 }= \sqrt{9 \times 2} = 3\sqrt{2}\\\\ \dfrac{3}{\sqrt{18}}= \dfrac{3}{3\sqrt{2}} = \dfrac{1}{\sqrt{2}}[/tex]
========================================================
[tex]\# 6 \quad \sqrt{\dfrac{25}{49}}\\\\\sqrt{25} = 5\\\\\\\sqrt{49} = 7\\\\[/tex]
[tex]\sqrt{\dfrac{25}{49}}= \dfrac{5}{7}[/tex]
The cost price of a book is Rs 20 . It is sold at 10% profit. Find its sale price
Answer:
Cost price (CP) = Rs20
% Profit = 10%
Selling price (SP) = y
By formula:
% Profit = (Profit/CP) x 100%
But Profit= SP - CP
Therefore;
% Profit = [(SP-CP)/C.P)] x 100%
Substituting, we have:
10% = [(y-20)/20] x 100%
10/100 = (y-20)/20
1/10 = (y-20)/20
1 = (y-20)/2
Cross multiply
y - 20 = 2
y = 2 + 20
y = 22
Therefore, the Sale price is Rs 22
Algebra question help asap
If the value of the Bulls Eye stock has fallen 8% annually since 2010, it will be worth $32.90 in 2015.
What is the mathematical formula for profit?The formula Profit = Selling Price - Cost Price can be used to determine the profit when the selling price and the cost price of a product are known. The formula for calculating profit percentage is then applied, which is profit percentage = (profit/cost price) x 100.
If the value of the Bulls Eye stock has dropped by 8% annually, it has dropped to 92% (100% - 8%) of its value from the prior year.
Since we're moving from 2010 to 2015, we must multiply this loss five times to determine the stock's value in 2015:
Value in 2011 = 92% of $50 = $46
Value in 2012 = 92% of $46 = $42.32
Value in 2013 = 92% of $42.32 = $38.89
Value in 2014 = 92% of $38.89 = $35.77
Value in 2015 = 92% of $35.77 = $32.90
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The value of 5^2000+5^1999/5^1999-5^1997
Answer:
Step-by-step explanation:
We can simplify the expression by factoring out a common factor of 5^1999 from the numerator:
5^2000 + 5^1999
= 5^1999(5 + 1)
= 5^1999(6)
And we can also factor out a common factor of 5^1997 from the denominator:
5^1999 - 5^1997
= 5^1997(5^2 - 1)
= 5^1997(24)
So the entire expression simplifies to:
(5^2000 + 5^1999) / (5^1999 - 5^1997)
= (5^1999 * 6) / (5^1997 * 24)
= (6/24) * 5^2
= 5/2
Therefore, the value of the expression is 5/2.
Stacy rented a truck for one day there was a base fee of $16.95 and there was an additional charge of 93 cents for each model driven. stacy had to pay $143.43 when he returned the truck. for how many miles did she drive the truck
Answer:
Stacy rented a truck for one day there was a base fee of $16.95 and there was an additional charge of 93 cents for each model driven. stacy had to pay $143.43 when he returned the truck. for how many miles did she drive the truck
Step-by-step explanation:
Let's start by subtracting the base fee from the total cost:
$143.43 - $16.95 = $126.48
Now, we can divide the remaining cost by the cost per mile:
$126.48 ÷ $0.93/mile ≈ 136 miles
Therefore, Stacy drove the truck for approximately 136 miles.
I need help with these 2 please
Question 7. C (rectangular pyramid)
Question 8. 17 cm
Answer:
Question 7:C rectangular pyramid
Question 8: C 120 in
A=2(wl+hl+hw)=2·(10·2+5·2+5·10)=160
Step-by-step explanation:
Use spherical coordinates to find the volume of the region outside the cone phi = pi /4 and inside the sphere rho = 4 cos phi. The volume is ____ . (Type an exact answer, using pi as needed.)
The volume is 63.717 cubic units
The limits of integration for rho are 0 and 4 cos phi, since the sphere has radius 4 cos phi. The limits for phi are π/4 and π/2, since we want to consider the region outside the cone but inside the sphere, and phi is the angle between the positive z-axis and the position vector of a point. Finally, the limits for theta are 0 and 2π, since theta is the azimuthal angle and we want to integrate over the entire azimuthal angle.
Thus, the volume of the region is given by:
V = 8 x ∫(0 to 2π) ∫(π/4 to π/2) ∫(0 to 4 cos phi) ρ² sin phi dρ dphi dtheta
Simplifying the integral using basic calculus, we get:
V = 8 x (64/3 - 16/3√2π) = 63.717
Therefore, the volume of the region outside the cone phi = π/4 and inside the sphere rho = 4 cos phi is 8(64/3 - 16/3√2π), which is an exact answer using π as needed.
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Which angles would the Alternate Exterior Angles Theorem state are congruent?
Which angles would the Alternate Exterior Angles Theorem state are congruent?
Answer:
Choice 2
∠1 and ∠7, ∠2 and ∠8
Step-by-step explanation:
This is a good example of a problem that can be solved by POE(process of elimination)
First choice: ∠2 and ∠3 are on the same straight line so they cannot be congruent. They are supplementary in that they add up to 180°
The same applies for ∠3 and ∠4 (third choice)
The same applies for ∠1 and ∠4 (fourth choice)
That leaves choice 2
We can prove ∠1 ≅ ∠7 as follows:
∠1 ≅ ∠3 since they are vertically opposite angles
∠3 ≅ ∠7 since they are exterior angles
So ∠1 ≅ ∠7
By similar reasoning,
∠2 ≅ ∠8
So correct choice is Choice 2
Measure the diameter of the tin mm and write down the real diameter in mm
Answer:
Step-by-step explanation:
