Answer:
2 hours
Step-by-step explanation:
Since Tory and Emilio's motorboats travel at the same speed, they are traveling at the speed of 30 km/h. Therefore, it should take Tory two hours to travel 60 km.
Tory took 2 hours to navigate the 60 kilometers.
What is speed?Velocity is the pace and direction of an item's movement, whereas speed is the time rate at which an object is travelling along a route.
Given:
Tory pilots her boat 60 km before docking.
Emilio continues for another 4 hours traveling, a total of 120 km before docking.
The speed of Emilio's boat = 120 / 4 = 30 kilometers per hour.
Tory and Emilio's motorboats travel at the same speed.
Tory's boat speed,
= 60/30 = 2 hours.
Therefore, Tory takes 2 hours.
To learn more about the speed;
https://brainly.com/question/7359669
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[tex](v+6)^{2}=2v^{2}+14v+12[/tex]
Answer:
v=-6 or 4
Step-by-step explanation:
Answer:
the answer would be 5
Step-by-step explanation:
have to do the question multiply add and divide to find your answer
Help please!!!!!!!!!!!
Answer:
AB IS THE ANSWER !!!!!!!!!!
Answer: AB
Step-by-step explanation:
Hi! I don't know if you need help anymore ,but here you go!
Because BC=ED, I asume that AE=AB
There is a bag with only red marbles and blue marbles.
The probability of randomly choosing a red marble is
7/10th
There are 42 red marbles in the bag and each is equally likely to be chosen.
Work out how many marbles in total there must be.
Answer:
60 marbles in total
Step-by-step explanation:
Find how many marbles there are in total by dividing 42 by 0.7:
42/0.7
= 60
So, there are 60 marbles in total
A circle has a circumference of 2cm. Which statement about the circumference and area is true?
A comparison of the area and circumference is not possible since the area cannot be determinec
The numerical values of the circumference and area of the circle are equal.
The numerical value of the circumference is greater than the numerical value of the area.
The numerical value of the circumference is less than the numerical value of the area.
ОО
Answer:
The numerical values of the circumference and area of the circle are equal.
find the measure of angle c of a triangle ABC, if m
Solve for X.
-6x + 14 < -28
AND 3x + 28 < 25
Answer:
1. -6x + 14 < -28
6x<42
x<7
2. 3x + 28 < 25
3x < -3
x<-1
Hope This Helps!!!
I need help with this word problem.
Answer:
$3.22 per square feet
Step-by-step explanation:
To solve, I usually set up an equation:
sq ft = 12 1/2 = 1
$ 40.21 x
Then, use cross multiplication.
(12 1/2)x=40.21
Divide both sides by 12 1/2 or 12.5
x = 3.2168
Round to the hundredths place [because we're dealing with money]
$3.22
I hope this helps!
Answer:
3.22 per sq ft
Step-by-step explanation:
Take the total cost and divide by the amount of tiles
40.21 / 12.5
3.2168 per sq ft
Rounding to the nearest cent
3.22 per sq ft
A large on-demand, video streaming company is designing a large-scale survey to determine the mean amount of time corporate executives watch on-demand television. A small pilot survey of 10 executives indicated that the mean time per week is 12 hours, with a standard deviation of 3 hours. The estimate of the mean viewing time should be within 0.25 hour. The 95% level of confidence is to be used. How many executives should be surveyed? (Use z Distribution Table.)
How many executives should be surveyed? (Round the final answer to the next whole number.)
Answer:
554 executives should be surveyed.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]
Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].
That is z with a pvalue of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.
Now, find the margin of error M as such
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
Standard deviation of 3 hours.
This means that [tex]\sigma = 3[/tex]
The 95% level of confidence is to be used. How many executives should be surveyed?
n executives should be surveyed, and n is found with [tex]M = 0.25[/tex]. So
[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]
[tex]0.25 = 1.96\frac{3}{\sqrt{n}}[/tex]
[tex]0.25\sqrt{n} = 1.96*3[/tex]
[tex]\sqrt{n} = \frac{1.96*3}{0.25}[/tex]
[tex](\sqrt{n})^2 = (\frac{1.96*3}{0.25})^2[/tex]
[tex]n = 553.2[/tex]
Rounding up:
554 executives should be surveyed.
PLEASE HELP
The function in the table is quadratic:
TRUE
FALSE
Answer:
False
Step-by-step explanation:
Each f(x) increases by 8 therefore this equation is a linear function. If you where to graph it would be a straight line
Hope this helped :)
Answer:
False
Step-by-step explanation:
The slope is the same between all pounts which means the function is linear.
Hope this helps!
Prove that the square of an odd number is always 1 more than a multiple of 4
Answer:
By these examples you are able to see that the square of an odd number is always 1 more than a multiple of 4.
Step-by-step explanation:
For examples,
Let's consider squares of 3, 11, 25, 37 and 131.
[tex] {3}^{2} = 9[/tex]
8 is a multiple of 4, and 9 is more than 8.
[tex] {11}^{2} = 121[/tex]
120 is a multiple of 4 and 121 is one more than it.
[tex] {25}^{2} = 625[/tex]
624 is a multiple of 4 and 625 is one more than it.
[tex] {37}^{2} = 1369[/tex]
1368 is a multiple of 4 and 1369 is one more than 1368.
[tex] {131}^{2} = 17161[/tex]
17160 is a multiple of 4.
Marla scored 70% on her last unit exam in her statistics class. When Marla took the SAT exam, she scored at the 70th percentile in mathematics. Explain the difference in these two scores.
Answer:
The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.
Step-by-step explanation:
Marla scored 70% on her last unit exam in her statistics class.
This means that in her statistics class, Marla got 70% of her test correct.
When Marla took the SAT exam, she scored at the 70th percentile in mathematics.
This means that on the SAT exam, graded on a curve, Marla scored better than 70% of the students.
Explain the difference in these two scores.
The difference is that Marla's exam in her statistics class was graded by percent of correct answers, in her case 70%, while the SAT is graded into a curve, taking other students' grades also into account, and since she scored in the 70th percentile, Marla scored better than 70% of the students.
Which operation will solve the following word problem? Jaylene bought a blouse for $20.00. The next day she returned the blouse and got 90% of her money back, she was charged a restocking fee of 10%. How much money did she get back?
Division
Addition
Subtraction
Multiplication
Answer:
division is right i hope you understand
9514 1404 393
Answer:
Multiplication
Step-by-step explanation:
The amount Jaylene got back is 90% of the amount she spent. That value is found by multiplying 90% times $20.
Jaylene got back ...
90% × $20 = $18
Solve this
4 X (10 - 3+2)
Answer:
36
Step-by-step explanation:
10-3=7+2=9
4×9=36
36 is the answer
Find m angle NML; m angle QML=115^ and m angle NMQ=28^
Answer:
We're provided - m ∠ QML = 115° , m ∠ NMQ = 28° and we're asked to find out m ∠ NML. Set up an equation and solve for m ∠ NML.[tex] \large{ \tt{❀ \: m \: \angle \: NML= m \: \angle \:QML + m \: \angle \: NMQ}}[/tex]
[tex] \large{ \tt{⤇m \: \angle \:NML= 115 \degree + 28 \degree }}[/tex]
[tex] \boxed{ \large{ \tt{⤇ \: m \: \angle \:NML = 143 \degree }}}[/tex]
Hence , Our final answer is 143° . Hope I helped! Let me know if you have any questions regarding my answer and also notify me , if you need any other help! :)▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁▁
Romans Food Market, located in Saratoga, New York, carries a variety of specialty foods from around the world. Two of the store's leading products use the Romans Food Market name: Romans Regular Coffee and Romans DeCaf Coffee. These coffees are blends of Brazilian Natural and Colombian Mild coffee beans, which are purchased from a distributor located in New York City. Because Romans purchases large quantities, the coffee beans may be purchased on an as-needed basis for a price 10% higher than the market price the distributor pays for the beans. The current market price is $0.47 per pound for Brazilian Natural and $0.62 per pound for Colombian Mild. The compositions of each coffee blend are as follows: Blend
Bean Regular DeCaf
Brazilian Natural 75% 40%
Columbian Mild 25% 60%
Romans sells the regular blend for $3.60 per pound and the Decaf blend for $4.40 per pound. Romans would like to place an order for the Brazilian and Columbian coffee beans that will enable the production of 1000 pounds of Romans Regular coffee and 500 pound of Romans DeCaf coffee. The production cost is $0.80 per pound for the Regular blend. Because of the extra steps required to produce DeCaf, the production cost for the DeCaf blend is $1.05 per pound. Packaging costs for both products are $0.25 per pound. Formulate a linear programming model that can be used to determine the pounds of Brazilian Natural and Columbian Mild that will maximize the total contribution to profit. What is the optimal solution and what is the contribution profit?
Answer:
z(max) = 2996.13 $
x₁ = 968 x₂ = 430 ( quantities of regular and Decaf coffee respectevely)
Total quantity of BN = 898 pounds
Total quantity of CM = 500 pounds
Step-by-step explanation:
Cost of the beans
Brazilian natural = Price market + 10 % = 0.47 + 0.047
BN Cost = 0.517 $/lb
Clombian Mild = Price market + 10 % = 0.62 + 0.062
CM Cost = 0.682 $/lb
Composition of the coffee blend
Regular coffee 0.75 BN + 0.25 CM
De Caf coffee 0.40 BN + 0.60 CM
PRICES
Regular Roman = 3.60 $
Decaf = 4.40 $
Production costs:
Regular Roman = 0.80 $/lb
Decaf = 1.05 $/lb
Packaging costs: 0.25 $/Lb both
Profit = Price - cost
Profit of regular coffee = 3.60 - 0.80 - 0.25 -Cost of bean
for regular coffee cost of BN + CM
BN is : 0.75*BN cost = 0.75*0.517 = 0.38775 and
CM is : 0.25*0.682 = 0.1705
Profit of regular coffee = 1.99175 $
Profit for Decaf coffee = 4.4 - 1.05 - 0.25 - ( 0.517*0.4 + 0.6*0.682)
Profit for Decaf coffee = 4.4 - 1.30 - 0.616
Profit for Decaf coffee = 2.484 $
Let´s call x₁ pounds of regular coffee and x₂ pounds of Decaf coffee then:
Objective Function is:
z = 1.99175*x₁ + 2.484*x₂ to maximize
Subject to:
Availability of beans for 1000 pounds of Regular coffee means:
750 pounds of BN + 250 pounds of CM
Availability of beans for 500 pounds of Decaf coffee means
200 pounds of BN + 300 pounds of CM
Then 750 + 200 = 900 pounds of BN
And 250 + 300 = 550 pounds of CM
Availability of beans for 1000 pounds of Decaf coffee correspond to
0.75 *x₁ + 0.40*x₂ ≤ 900
Availability of beans for 500 pounds of Regular coffee correspond to
0.25*x₁ + 0.60*x₂ ≤ 500
Then the model is:
z = 1.99175*x₁ + 2.484*x₂ to maximize
Subject to:
0.75 *x₁ + 0.40*x₂ ≤ 900
0.25*x₁ + 0.60*x₂ ≤ 500
General constraints x₁ ≥ 0 x₂ ≥ 0 both integers
After 6 iterations optimal solution ( maximum z) is
z(max) = 2996.13 $
x₁ = 968 x₂ = 430
x₁ and x₂ are quantities of Regular and Decaf coffee respectively, to find out quantities of Brazilian Natural and Colombian Mild
we proceed as follows
Regular coffee is : 0.75*968 = 726 pounds of BN
Decaf coffee is : 0.40*430 = 172 pounds of BN
Total quantity of BN = 898 pounds
Regular coffee is : 0.25*968 = 242 pounds of CM
Decaf coffee is : 0.6*430 = 258 pounds of CM
Total quantity of CM = 500 pounds
Can someone help me please..
Answer:
linear function
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
The graph is a straight line, so it's a linear function.
Answer: B
A display case of toy rings are marked 5 for $1. If Zach wants to buy 50 toy rings, how much will Zach spend (not including tax)
Answer:
$10
Step-by-step explanation:
5 toys = $1
Zach wants 50 of these
50 ÷ 5 = 10
10 x 1 = 10
= $10
Answer:
10 dollars
Step-by-step explanation:
We can use a ratio to solve
5 rings 50 rings
---------- = --------------
1 dollar x dollars
Using cross products
5*x = 1 * 50
5x = 50
Divide by 5
5x/5 = 50/5
x = 10
Find the slope of the line that passes through the two points. 4,4 & 4,9
HELPPPPPPP
Answer:
is 22
Step-by-step explanation:
Answer:
It doesn't have a slope?
Step-by-step explanation:
Knowing that the slope equation is y2-y1/x2-x1
9-4 5
----- = ------ = 0
4-4 0
this means that the slope is 0...
Subtract and show work.
Answer:
[tex]31y^{3} -28y^{2}[/tex]+35y
Step-by-step explanation:
angle P and angle Q are complementary. The measure of angle Q is 33.5°. What is the measure of angle P?
Answer:
56.5 degrees
Step-by-step explanation:
Because complementary angles are when their sum is 90, you get the equation:
P + Q = 90
Since Q is 33.5,
P + 33.5 = 90
Subtracting 33.5 from both sides,
P = 56.5
Solve the expression using the correct order of operations.
0.75x3.2+ (9.1)2-((-2.3)-(-0.9))2
Answer:
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
Step-by-step explanation:
Given
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2[/tex]
Required
Solve
Start with the bracket
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ (9.1)^2-(-1.4)^2[/tex]
Evaluate all exponents
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 0.75 * 3.2+ 82.81-1.96[/tex]
Evaluate all products
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 2.4+ 82.81-1.96[/tex]
[tex]0.75 * 3.2+ (9.1)^2-((-2.3)-(-0.9))^2 = 83.25[/tex]
Find the radius of a circle with a diameter whose endpoints are (-7,1) and (1,3).
Answer:
r = 4.1231055
Step-by-step explanation:
So to do this, you need to find the distance between the two points:
(-7,1) and (1,3).
To do this, the distance or diameter (d) is equal to:
d = sqrt ((x2-x1)^2 + (y2-y1)^2)
In this case:
d = sqrt( (1 - (-7))^2 + (3 - 1)^2 )
d = sqrt( 8^2 + 2^2)
d = sqrt( 64 + 4)
d = sqrt( 68 )
The radius is half of the diameter, so:
r = 1/2 * d
r = 1/2 * sqrt( 68 )
r~ 4.1231055
Identify the level of measurement of the data, and explain what is wrong with the given calculation. Ina set of data, alert levels are represented as 1 for low, 2 for medium, and 3 for high. The average mean of the 522 alert levels is 1.3. The data are at the ________ level of measurement. a. Nominalb. Ordinalc. Ratiod. IntervalWhat is wrong with the given calculation?a. Such data should not be used for calculations such as an average.b. One must use a different method to take the average of such datac. The true average is 2.5d. There is nothing wrong with the given calculation.
Answer:
(1) Ordinal
(2) Such data should not be used for calculations such as an average.
Step-by-step explanation:
Given
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
[tex]Average = 1.3[/tex]
Solving (a): The level of measurement
When observations are presented in ranks such as:
[tex]1 \to Low[/tex]
[tex]2 \to Medium[/tex]
[tex]3 \to High[/tex]
The level of measurement of such observation is ordinal
Solving (b): What is wrong with the computation?
Ordinal level of measurement are not numerical values whose average can be calculated because they are used as ranks.
Hence, (a) is correct
Determine if a quadrilateral with the given vertices is an isosceles trapezoid. Show and explain all steps to prove or disprove.
A(3, 3) B(5, 3) C(8,1) D(1,1)
Answer:
No, a quadrilateral with the given vertices is not an isosceles trapezoid.
Step-by-step explanation:
We are given that
A(3,3), B(5,3), C(8,1), D(1,1)
Slope formula:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
Slope of AB=[tex]\frac{3-3}{5-3}=0[/tex]
Slope of BC=[tex]\frac{1-3}{8-5}=\frac{-2}{3}[/tex]
Slope of CD=[tex]\frac{1-1}{1-8}=0[/tex]
Slope of AD=[tex]\frac{1-3}{1-3}=1[/tex]
Slope of AB=Slope of CD
When slopes of two lines are equal then the lines are parallel.
Therefore, AB is parallel to CD.
When one pair of quadrilateral is parallel then the quadrilateral is trapezoid.
[tex]\implies [/tex]ABCD is a trapezoid.
Distance formula:
[tex]\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Using the formula
Length of BC=[tex]\sqrt{(8-5)^2+(1-3)^2}[/tex]
Length of BC=[tex]\sqrt{9+4}=\sqrt{13}[/tex] units
Length of AD=[tex]\sqrt{(1-3)^2+(1-3)^2}[/tex]
Length of AD=[tex]\sqrt{4+4}=2\sqrt{2}[/tex]
Length of AD is not equal to length of BC.
Hence, trapezoid is not an isosceles trapezoid.
I WILL MARK THE ANSWER AS BRAINLIEST BE CORRECT BEFORE YOU ANSWER PLEASE
LOOK AT THE PROBLEM
Answer:
yes I look this problem in this figure
An item is regularly priced at $84. Ashley bought it on sale for 70% off the regular price.
Use the ALEKS calculator to find how much Ashley paid
Answer:
58.80
Step-by-step explanation:
84 x .7(70%) =58.80
Kamala marked the price of a cosmetic item as Rs 400. She offered her customers a discount of 20% and made a loss of Rs 30, what was the actual cost of the item to her?
Answer:
350
Step-by-step explanation:
400- 80 ( 20% discount)
=320+30(loss)
=350
Type the correct answer in each box.
Jessica has $24 and plans to spend it all at the grocery store. She wants to purchase bags of carrots and bagels. Bags of
carrots cost $2 each, and bagels cost $3 per bag. Let x represent the number of bags of carrots and y represent the
number of bags of bagels. Complete the equation in standard form that models this scenario.
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y=(
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Step-by-step explanation:
Jessica has $24 and plans to spend it all at the grocery store.Bags of carrots cost $2 each, and bagels cost $3 per bag.Let x represent the number of bags of carrots and y represent the number of bags of bagels.the cost for the 'x' bags of carrots = $2xand the cost for the 'y' bags of bagels = $3ySo, the equation would be,so the equation in standard form that models the given scenario is
2x + 3y = 24
2x + 3y = 24Matthew earns extra money by doing odd jobs for his neighbors. He charges a flat fee of $20 plus $7 per hour for each job. If he earned $90 for a job he did last week, how many hours did he work?
Answer:
10 hours
Step-by-step explanation:
ok so we know he is getting payed $20 + $7 every hour so what i would do is keep the multiply the 7 till you get 70 so thats 7x10=70 and 70+20=90 so he worked for 10 hours last week :) i hope this helps, i tried my best to explain it
Symposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use ???? = 0.01.
Complete Question
ymposium is part of a larger work referred to as Plato's Dialogues. Wishart and Leach† found that about 21.4% of five-syllable sequences in Symposium are of the type in which four are short and one is long. Suppose an antiquities store in Athens has a very old manuscript that the owner claims is part of Plato's Dialogues. A random sample of 498 five-syllable sequences from this manuscript showed that 129 were of the type four short and one long. Do the data indicate that the population proportion of this type of five-syllable sequence is higher than that found in Plato's Symposium? Use = 0.01.
a. What is the value of the sample test statistic? (Round your answer to two decimal places.)
b. Find the P-value of the test statistic. (Round your answer to four decimal places.)
Answer:
a) [tex]Z=2.45[/tex]
b) [tex]P Value=0.0073[/tex]
Step-by-step explanation:
From the question we are told that:
Probability of Wishart and Leach [tex]P=21.4=>0.214[/tex]
Population Size [tex]N=498[/tex]
Sample size [tex]n=12[/tex]
Therefore
[tex]P'=\frac{129}{498}[/tex]
[tex]P'=0.2590[/tex]
Generally the Null and Alternative Hypothesis is mathematically given by
[tex]H_0:P=0.214[/tex]
[tex]H_a:=P>0.214[/tex]
Test Statistics
[tex]Z=\frac{P'-P}{\sqrt{\frac{P(1-P)}{n}}}[/tex]
[tex]Z=\frac{0.2590-0.214}{\sqrt{\frac{0.214(1-0.214)}{498}}}[/tex]
[tex]Z=2.45[/tex]
Therefore P Value is given as
[tex]P Value =P(Z\geq 2.45)[/tex]
[tex]P Value =1-P(Z\leq 2.45)[/tex]
[tex]P Value =1-0.99268525[/tex]
[tex]P Value=0.0073[/tex]
