Triangle A'B'C' is the image of triangle ABC after a dilation with a scale factor of 1/2 and centered at point A. Is triangle ABC congruent to triangle A'B'C'? Explain your answer.

Answer:K=-2

Step-by-step explanation:

becuase you do the opposite of +9 which is -9 and you do 7-9 which is -2 so K=-2

Given:

In quadrilateral ABCD, angle B=90° , AB=9m, BC=40m, CD=15m, DA=28m.

To find:

The area of the quadrilateral ABCD.

Solution:

In quadrilateral ABCD, draw a diagonal AC.

Using Pythagoras theorem in triangle ABC, we get

[tex]AC^2=AB^2+BC^2[/tex]

[tex]AC^2=9^2+40^2[/tex]

[tex]AC^2=81+1600[/tex]

[tex]AC^2=1681[/tex]

Taking square root on both sides, we get

[tex]AC=\sqrt{1681}[/tex]

[tex]AC=41[/tex]

Area of the triangle ABC is:

[tex]A_1=\dfrac{1}{2}\times base\times height[/tex]

[tex]A_1=\dfrac{1}{2}\times BC\times AB[/tex]

[tex]A_1=\dfrac{1}{2}\times 40\times 9[/tex]

[tex]A_1=180[/tex]

So, the area of the triangle ABC is 180 square m.

According to the Heron's formula, the area of a triangle is

[tex]Area=\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where,

[tex]s=\dfrac{a+b+c}{2}[/tex]

In triangle ACD,

[tex]s=\dfrac{28+15+41}{2}[/tex]

[tex]s=\dfrac{84}{2}[/tex]

[tex]s=42[/tex]

Using Heron's formula, the area of the triangle ACD, we get

[tex]A_2=\sqrt{42(42-28)(42-15)(42-41)}[/tex]

[tex]A_2=\sqrt{42(14)(27)(1)}[/tex]

[tex]A_2=\sqrt{15876}[/tex]

[tex]A_2=126[/tex]

Now, the area of the quadrilateral is the sum of area of the triangle ABC and triangle ACD.

[tex]A=A_1+A_2[/tex]

[tex]A=180+126[/tex]

[tex]A=306[/tex]

Therefore, the area of the quadrilateral ABCD is 306 square meter.

Answer:

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 64.4 inches, standard deviation of 2.91

This means that [tex]\mu = 64.4, \sigma = 2.91[/tex]

Sample of 50 women

This means that [tex]n = 50, s = \frac{2.91}{\sqrt{50}}[/tex]

What is the probability that the mean height for the sample is greater than 65 inches?

This is 1 subtracted by the p-value of Z when X = 65. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

By the Central Limit Theorem

[tex]Z = \frac{X - \mu}{s}[/tex]

[tex]Z = \frac{65 - 64.4}{\frac{2.91}{\sqrt{50}}}[/tex]

[tex]Z = 1.46[/tex]

[tex]Z = 1.46[/tex] has a p-value of 0.9279

1 - 0.9279 = 0.0721

0.0721 = 7.21% probability that the mean height for the sample is greater than 65 inches.

Answer

No solution

Step-by-step explanation:

4y + 2x = 18

3x + 6y = 26

You need either the x's or the y's to have the same coefficients.

let's line things up first.

4y + 2x = 18   (multiply by 3)

6y + 3x = 26  (multiply by 2)

to keep numbers relatively small we will multiply the top equation by 3 and the bottom equation by 2. Multiply all terms. This will make the coefficients equal.

12y + 6x = 54

12y + 6x = 52

So, if you subtract them from each other you get :

0 = 2

When this happens the solution set is : no solution

Answer:

Impossible

Step-by-step explanation:

Ok, so we first rearrange for convenience:

2x+4y=18

3x+6y=26

We multiply the two equations to eliminate x:

2x+4y=18 * -3

3x+6y=26 * 2

So:

-6x-12y=-54

6x+12y=52

And now we add the two equations:

0+0= -2

Try multiplying the two equations by any other number which will lead to them cancelling, (eg. -9, 6), still the equation will not work.

Answer:

I think you are missing something unless the answer is a horizontal line.

Step-by-step explanation:

Answer:

square root

Step-by-step explanation:

just took the test :)

Answer:

[tex] x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]

Step-by-step explanation:

Since, given is a 30°-60°-90° triangle.

[tex] \therefore \sqrt 7 = \frac{\sqrt3}{2} \times x[/tex]

[tex] \therefore 2\sqrt 7 = \sqrt3 \times x[/tex]

[tex] \therefore x=\frac{2\sqrt 7}{\sqrt 3}[/tex]

[tex] \therefore x=\frac{2\sqrt 7(\sqrt 3)}{\sqrt 3(\sqrt 3)}[/tex]

[tex] \huge \therefore x=\frac{[2] \sqrt {[21] }}{[3] }[/tex]

Answer:

10,000 different PINS are possible

Step-by-step explanation:

Fundamental counting principle:

States that if there are p ways to do a thing, and q ways to do another thing, and these two things are independent, there are p*q ways to do both things.

In this question:

Four each digit on the PIN, there are 10 possible outcomes. The digits are independent. So, by the fundamental counting principle:

[tex]T = 10^4 = 10000[/tex]

10,000 different PINS are possible

Step-by-step explanation:

jnx-avkj-uup p.l.z join

Answer:

2, 3, 5, 8, 13 missing number is 18.

Answer:

40% of policyholders are expected to have an accident next year

Step-by-step explanation:

Given the data in the question;

P( collision coverage ) = 60% = 0.6

P( comprehensive coverage ) = 70% = 0.7

Now, we make use of the Law of addition of probability, so

P( collision coverage and comprehensive coverage ) = P( collision coverage )  + P( comprehensive coverage ) - P( collision coverage or comprehensive coverage )

P( collision coverage and comprehensive coverage )  = 0.6 + 0.7 - 1

P( collision coverage and comprehensive coverage ) = 0.3

Now,

P( comprehensive coverage only ) = P( comprehensive coverage ) - P( collision coverage and comprehensive coverage )

P( comprehensive coverage only ) = 0.7 - 0.3

P( comprehensive coverage only ) = 0.4

And

P( collision coverage only) = P( collision coverage ) - P( collision coverage and comprehensive coverage )

P( collision coverage only) = 0.6 - 0.3 = 0.3

Next  we make use of the Law of total probability;

P( accident ) = [P( accident ║ collision coverage only) × P( collision coverage only)] + [P( accident ║ comprehensive coverage only) × P( comprehensive coverage only)] + [P( accident ║ collision coverage and comprehensive coverage only) × P( collision coverage and comprehensive coverage only)]

so we substitute in our values;

P( accident ) = [ 30% × 0.3 ] + [ 40% × 0.4 ] + [ 50% × 0.3 ]

P( accident ) = [ 0.3 × 0.3 ] + [ 0.4 × 0.4 ] + [ 0.5 × 0.3 ]

P( accident ) = 0.09 + 0.16 + 0.15

P( accident ) = 0.4 or 40%

Therefore,  40% of policyholders are expected to have an accident next year

Answer:

Cost of adult ticket = $12.5

Cost of child ticket = $7.5

Step-by-step explanation:

Given:

Cost of 6 adult ticket and 5 child ticket = $112.5

Cost of 8 adult ticket and 4 child ticket = $130

Find:

Equation and solution

Computation:

Assume;

Cost of adult ticket = a

Cost of child ticket = b

So,

6a + 5b = 112.5....eq1

8a + 4b = 130 ......eq2

Eq2 x 1.25

10a + 5b = 162.5 .....eq3

eq3 - eq1

4a  = 50

Cost of adult ticket = $12.5

8a + 4b = 130

8(12.5) + 4b = 130

Cost of child ticket = $7.5

Yes, they are quite similar. the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation - based method (p < 0.0001)

P- value is the probability of obtaining a value of test statistic more extreme in the direction of alternative hypothesis than the observed one. In easy words if p -value < level of significance we reject H0 in favor of H1.

Here:

p-value < 0.0001 => we reject H0.

If the statistical software renders a p value of 0.000 it means that the value is very low, with many "0" before any other digit.

So the interpretation would be that the results are significant, same as in the case of other values below the selected threshold for significance.

Therefore, yes they are quite similar.

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Incomplete Question:

Student researchers investigated whether balsa wood is less elastic after it has been immersed in water. They took 60 pieces of balsa wood and randomly assigned half to be immersed in water and the other half not to be. They measured the elasticity by seeing how far (in inches) the piece of wood would project a dime into the air.

Does the p-value obtained using the theory-based method (p < 0.0001) agree with that obtained using the randomization/simulation-based method (p < 0.0001)?

A. No, they are different.

B. Yes, they are quite similar.

Answer:

15 mph

Step-by-step explanation

i used a calculator but correct me if im wrong pls

mass = force / area

this is second law of motion ( Newton's 2nd law)

[tex]\longrightarrow{\blue{ m = \frac{F}{a} }}[/tex] 

[tex]\large\mathfrak{{\pmb{\underline{\red{Explanation}}{\red{:}}}}}[/tex]

F = ma

➺ m = [tex]\frac{F}{a} [/tex]

where,

F = Force

m = mass

a = acceleration

"F = ma" is Newton's second law of motion, which states that force is equal to mass times acceleration.

The SI unit of force is newton, symbol N.

[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]

Answer:

(26.2252 ; 27.3748)

Step-by-step explanation:

The confidence interval is given by :

x ± Margin of error

The margin of error = Zcritical * (σ/√(n))

σ = 7.5 ; n = 654

Zcritical = Zα/2 = 1.96

The margin of error = 1.96 * (7.5/√654) = 0.5748

The confidence interval :

Upper boundary = 26.8 + 0.5748 = 27.3748

Lower boundary = 26.8 - 0.5748 = 26.2252

(26.2252 ; 27.3748)

We are 95% confident that the mean BMI of the entire population will fall in between (26.2252 ; 27.3748)

Answer:

Balance will be £3.92

Step-by-step explanation:

Cost of  1 loaf = £1.52

Therefore, cost of 4 loaves = 4 x 1 . 52 = £6.08

So if you pay with £10 your balance will be = 10.00 - 6.08 =  £3.92

The solution is  £ 3.92

The amount of money after the purchase of 4 loaves of bread is given by the equation A = £ 3.92

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

The total amount of money = £ 10

The cost of one loaf of bread = £ 1.52

Now , the number of loaves of bread = 4 loaves

So , the cost of 4 loaves of bread = 4 x cost of one loaf of bread

Substituting the values in the equation , we get

The cost of 4 loaves of bread = 4 x 1.52

The cost of 4 loaves of bread = £ 6.08

The amount of money after the purchase A = total amount of money - cost of 4 loaves of bread

Substituting the values in the equation , we get

The amount of money after the purchase A = £ 10 - £ 6.08

The amount of money after the purchase A = £ 3.92

Therefore , the value of A is £ 3.92

Hence , the amount is £ 3.92

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Answer:

b.  [tex]\frac{7+\sqrt{61} }{6} ,\frac{7-\sqrt{61} }{6}[/tex]

Step-by-step explanation:

[tex]3x^{2} -1=7x[/tex]

Quadratic equations are suppose to be written as: [tex]ax^2+bx+c=0[/tex]

so the new quadratic equation for this problem will be: [tex]3x^{2} -1-7x=0[/tex]

Now rearrange the terms: [tex]3x^{2} -7x-1=0[/tex]

Then use the Quadratic Formula to Solve for the Quadratic Equation

Quadratic Formula = [tex]x=\frac{-b±}{} \frac{\sqrt{b^2-4ac} }{2a}[/tex]

Note: Ignore the A in the quadratic formula

Once in standard form, identify a, b and c from the original equation and plug them into the quadratic formula.

[tex]3x^{2} -7x-1=0[/tex]

a = 3

b = -7

c = -1

[tex]x=-(-7)±\frac{\sqrt{(-7)^2-4(3)(-1)} }{2(3)}[/tex]

Evaluate The Exponent

[tex]x=\frac{7±\sqrt{(49)-4(3)(-1)} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{49+12} }{2(3)}[/tex]

Add The Numbers

[tex]x=\frac{7±\sqrt{61} }{2(3)}[/tex]

Multiply The Numbers

[tex]x=\frac{7±\sqrt{61} }{6}[/tex]

Given:

v = 150d

v represents company's production for the coming year

d represents the number of days

150 is the daily production

The rate of change of the function representing the number of vehicles manufactured for the coming year is CONSTANT (150) , and its graph is a STRAIGHT LINE . So, the function is a LINEAR function.

I hope this helps!

Answer:

v = 150d

v represents company's production for the coming year

d represents the number of days

150 is the daily production

Answer:

4)8 goats, 3 hens.

Step-by-step explanation:

8*4=32

3*2=6

32+6=38

Answer:

5⁴a²

Step-by-step explanation:

(5³a³)÷5a-¹×5-²a²

5³a³÷5a-¹×5-²a²

5³a³÷5¹-²×a-¹+²

5³a³÷5-¹a

5³a³/5-¹a

5³-(-¹)a³-¹

5⁴a²

Answer:

Step-by-step explanation:

-1<x<3.   I hope it helpful!

Answer:

I guess it is the Answer C

Answer:

C

The distance around the edge of the circle

C.(f-g)(x) = 4x^3 +5x²-7x-1

Step-by-step explanation:

Given information :

[tex]f(x) = 4 {x}^{3} + 5 {x}^{2} - 3x - 6 \\ g(x) = 4x - 5[/tex]

Find :

[tex](f - g)(x) = \\ (4 {x}^{3} + 5 {x}^{2} - 3x - 6) \\ - 4x -5[/tex]

Open bracket and Simplify

[tex]4 {x}^{3} + 5 {x}^{2} - 3x - 6 - 4x + 5 \\ 4 {x}^{3} + 5 {x}^{2} - 7x - 1[/tex]

Answer:

The intersection region shown in the graph attached is the solution of the system of inequalities

Answer:

0.73 = 73% probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year.

Step-by-step explanation:

I am going to treat these events as Venn probabilities, considering that:

Event A: Lying to the teacher.

Event B: Male

48% of high school students would admit to lying at least once to a teacher during the past year and that 25% of students are male and would admit to lying at least once to a teacher during the past year

This means that [tex]P(A) = 0.48, P(A \cap B) = 0.25[/tex]

Assume that 50% of the students are male.

This means that [tex]P(B) = 0.5[/tex]

What is the probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year?

This is:

[tex]P(A \cup B) = P(A) + P(B) - P(A \cap B)[/tex]

Considering the values we were given:

[tex]P(A \cup B) = 0.48 + 0.5 - 0.25 = 0.73[/tex]

0.73 = 73% probability that a randomly selected student is either male or would admit to lying to a teacher, during the past year.

Answer:

n + 4

Step-by-step explanation:

Given

⅕(m + m + 1 + m + 2 + m + 3 + m + 4) = n

Required

⅑(m + 2 + m + 3 +.......+ m + 10)

We have:

⅕(m + m + 1 + m + 2 + m + 3 + m + 4) = n

Multiply both sides by 5

m + m + 1 + m + 2 + m + 3 + m + 4 = 5n

Collect like terms

m + m + m + m + m = 5n - 1 - 2 - 3 - 4

5m = 5n - 10

Divide both sides by 5

m = n - 2

So, we have:

⅑(m + 2 + m + 3 + m + 4 + m + 5 + m + 6 + m + 7 + m + 8 + m + 9 + m + 10)

Collect like terms

= ⅑(m+m+m+m+m+m+m+m+m+2+3+4+5+6+7+8+9+10)

= ⅑(9m + 54)

= m + 6

Substitute n - 2 for m

= n - 2 + 6

= n + 4

Answer:

x=-1

Step-by-step explanation:

the middlepoint is where its symetrical, and so you take the x part of the point. the point is (-1,4), and all we need is x, so you have x=-1