Triangle ABL is an isosceles triangle in circle A with a radius of 11, PL = 16, and ∠PAL = 93°. Find the area of the circle enclosed by line PL and arc PL. Show all work and round your answer to two decimal places.
Answers
The area bounded by a chord and arc it intercepts is known as a segment of a circle segment of a circle
The area of the circle enclosed by line PL and arc PL is approximately 37.62 square units
The reason the above value is correct is as follows:
The given parameters in the question are;
The radius of the circle, r = 11
The length of the chord PL = 16
The measure of angle ∠PAL = 93°
Required:
The area of part of the circle enclosed by chord PL and arc PL
Solution:
The shaded area of the given circle is the minor segment of the circle enclosed by line PL and arc PL
The area of a segment of a circle is given by the following formula;
Area of segment = Area of the sector - Area of the triangle
Area of segment = Area of minor sector APL - Area of triangle APL
Area of minor sector APL:
Area of a sector = (θ/360)×π·r²
Where;
r = The radius of the circle
θ = The angle of the sector of the circle
Plugging in the the values of r and θ, we get;
Area of the minor sector APL = (93°/360°) × π × 11² ≈ 98.2 square units
Area of Triangle APL:
Area of a triangle = (1/2) × Base length × Height
Therefore;
The area of ΔAPL = (1/2) × 16 × 11 × cos(93°/2) ≈ 60.58 square units
Required shaded area enclosed by line PL and arc PL:
Therefore, the area of shaded segment enclosed by line PL and arc PL is found as follows;
Area of the required segment PL ≈ (98.2 - 60.58) square units = 37.62 square units
The area of the circle enclosed by line PL and arc PL ≈ 37.62 square units
Learn more about the finding the area of a segment can be found here:
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The area of the circle enclosed by line segment PL and circle arc PL is 37.80 square units.
The calculation of the area between line segment PL and circle arc PL is described below:
1) Calculation of the area of the circle arc.
2) Calculation of the area of the triangle.
3) Subtracting the area found in 2) from the area found in 1).
Step 1:
The area of a circle arc is determined by the following formula:
[tex]A_{ca} = \frac{\alpha\cdot \pi\cdot r^{2}}{360}[/tex] (1)
Where:
[tex]A_{ca}[/tex] - Area of the circle arc.
[tex]\alpha[/tex] - Arc angle, in sexagesimal degrees.
[tex]r[/tex] - Radius.
If we know that [tex]\alpha = 93^{\circ}[/tex] and [tex]r = 11[/tex], then the area of the circle arc is:
[tex]A_{ca} = \frac{93\cdot \pi\cdot 11^{2}}{360}[/tex]
[tex]A_{ca} \approx 98.201[/tex]
Step 2:
The area of the triangle is determined by Heron's formula:
[tex]A_{t} = \sqrt{s\cdot (s-l)\cdot (s-r)^{2}}[/tex] (2)
[tex]s = \frac{l + 2\cdot r}{2}[/tex]
Where:
[tex]A_{t}[/tex] - Area of the triangle.
[tex]r[/tex] - Radius.
[tex]l[/tex] - Length of the line segment PL.
If we know that [tex]l = 16[/tex] and [tex]r = 11[/tex], then the area of the triangle is:
[tex]s = \frac{16+2\cdot (11)}{2}[/tex]
[tex]s = 19[/tex]
[tex]A_{t} = \sqrt{19\cdot (19-16)\cdot (19-11)^{2}}[/tex]
[tex]A_{t} \approx 60.399[/tex]
Step 3:
And the area between the line segment PL and the circle arc PL is:
[tex]A_{s} = A_{ca}-A_{t}[/tex]
[tex]A_{s} = 98.201 - 60.399[/tex]
[tex]A_{s} = 37.802[/tex]
The area of the circle enclosed by line segment PL and circle arc PL is 37.80 square units.
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Zoe is a party planner. She orders cupcakes and sheet cakes from Creative Cakes whenever she needs beautiful cakes to serve. One sheet cake serves 24 people and 2 dozen cupcakes serve 24 people. For the Benson's bridal shower she ordered 8 dozen cupcakes and 3 sheet cakes and paid $160.81. For the Nygaard's 50th wedding anniversary she ordered 6 dozen cupcakes and 15 sheet cakes and paid $342.33. She is planning a graduation party for her niece's high school class. She wants the party to be nice but she offered to pay for the cakes herself so she wants to choose the most economical plan. Zoe estimates 250 people will attend the party.
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Full question:
Zoe is a party planner. She orders cupcakes and sheet cakes from Creative Cakes whenever she needs beautiful cakes to serve. One sheet cake serves 24 people and 2 dozen cupcakes serve 24 people. For the Benson's bridal shower she ordered 10 dozen cupcakes and 4 sheet cakes and paid $186.44. For the Nygaard's 50th wedding anniversary she ordered 2 dozen cupcakes and 15 sheet cakes and paid $259.66. She is planning a graduation party for her niece's high school class. She wants the party to be nice but she offered to pay for the she wants to choose the most economical plan. Zoe estimates 250 people will attend the party
Select the most economical choice below:
Zoe should buy sheet cakes because they cost $12.38 for one sheet cake.
Zoe should buy sheet cakes because they cost $15.66 for one sheet cake.
Zoe should buy cupcakes because they cost $12.38 for one dozen cupcakes.
Zoe should buy cupcakes because they cost $15.66 for one dozen cupcakes.
Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.
Answer:
Zoe should buy cupcakes because they cost $12.38 for two dozen cupcakes.
Explanation:
If there are 250 people attending the high school class graduation party, then 24 people each within 250 people in total would get 2 dozen cupcakes worth $12.38 each.
Therefore there are 250/24 = 10.41 groups (10 groups approximately or 10.41×2=20.82 dozens of cupcakes required)
Zoe would need to spend 10.41×$12.38= $128.88 to buy the cupcakes for the party
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Step-by-step explaination:
Given,
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Answers
Answer:
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Reduce 20/60 to its lowest common denominator
Answers
Answer:
it is 1/4
Step-by-step explanation:
20/60=10/30=1/3
Answer:
20/60=1/3
Step-by-step explanation:
20/60
HCF=20,
20*1=20, 20*3=60
1/3
or,
Remove the zeros,
2/6
Divide by 2 on both,
1/3
or divide by any common factor on both and keep dividing until u cant no more
20/60=1/3
