Twice the difference of a number and 9 is 3. Use the variable b for the unknown number.

Answer:

hkkr

need school the long said

Answer:

That would indicate 20.0 ml

id appreciate a rating thanks XP

Answer: The new slope is -(2/3)

Step-by-step explanation:

Ok, we know that our line can be written as:

y = (2/3)*x + b

where b is the y-intercept, and here does not really matter.

Ok, remember that if we have a point (x, y) and we reflect it over the x-axis, the new point will be (x, -y).

For our linear equation, the point (x, y) can be written as:

(x, y = (2/3)*x + b) = (x,  (2/3)*x + b)

Now, after the reflection, our point is:

(x, - ( (2/3)*x + b)) = (x, -(2/3)*x - b)

Then our new line is y = -(2/3)*x - b

The new slope is -(2/3)

Answer:

(1) Option a

(2) 13.737

(3) 8

(4) 3.803

(5) Option a

Step-by-step explanation:

In this case, we need to determine whether the soil type effects the growth of a certain type of plant.

Perform the ANOVA test for the provided data on Excel.

Go to Data - Data Analysis - Anova: Single factor

Select the data for the growth.

Press OK.

The output is attached below.

(1)

The hypothesis for the study can be defined as follows:

H₀: The mean growth of the plant in each type of soil is the same.

Hₐ: The mean growth of the plant is different in each type of soil.

Correct option a.

(2)

The sum of square for treatment is:

[tex]\text{SS}_{trt}=\text{SS}_{BG}=13.737[/tex]

(3)

The degrees of freedom of error is:

[tex]\text{DF}_{err}=\text{DF}_{WG}=8[/tex]

(4)

The F statistic for the ANOVA is:

[tex]F=3.803[/tex]

(5)

The p-value of the test is:

[tex]p-value=0.058[/tex]

Decision Rule:

Reject H₀ if the p-value of the test is less than the level of significance.

[tex]\text{p-value}=0.058>\alpha=0.05[/tex]

The null hypothesis was failed to be rejected.

Conclusion:

There is not enough evidence to reject the claim that the mean growth of the plant is the same in each type of soil.

Correct option a.

Answer:

[tex]Probability = \frac{3}{7}[/tex]

Step-by-step explanation:

Given

Electrician = 6

Mechanic = 8

Required

Determine the probability of selecting an electrician

First, we need the total number of employees;

[tex]Total = n(Electrician) + n(Mechanic)[/tex]

[tex]Total = 6 + 8[/tex]

[tex]Total = 14[/tex]

Next, is to determine the required probability using the following formula;

[tex]Probability = \frac{n(Electrician)}{Total}[/tex]

[tex]Probability = \frac{6}{14}[/tex]

Divide numerator and denominator by 2

[tex]Probability = \frac{3}{7}[/tex]

Hence, the probability of selecting an electrician is 3/7

Answer:

A. -11

Step-by-step explanation:

In the function, replace x with -2

R(x) = x^2 - 3x - 1 ➡ R(-2) = (-2)^2 - 3 × 2 -1 = -11

Answer:

Ok, as i understand it:

for a point P = (x, y)

The values of x and y can be randomly chosen from the set {1, 2, ..., 10}

We want to find the probability that the point P lies on the second quadrant:

First, what type of points are located in the second quadrant?

We should have a value negative for x, and positive for y.

But in our set;  {1, 2, ..., 10}, we have only positive values.

So x can not be negative, this means that the point can never be on the second quadrant.

So the probability is 0.

Answer:

The value of 1/3x-3/4 when x=1/4 is 0.08333 repeated.

Step-by-step explanation:

[tex] \huge{ \underline{ \tt{ \purple{Solution:}}}}[/tex]

2) a)⚘ Refer to the attachment....

After separating, we will get two triangles △XYB and △ZYA where ∠Y is common to both the triangles, hence their measure is equal. This will be use in further proof.

b) We have,

So, here

Two pairs of corresponding angles are equal along the side contained between them. So, The above triangles are congurent by ASA criterion.

✤ No more additional information Required to prove the above triangles be congurent.

➝ △XYB ≅ △ZYA (By ASA Criterion)

c) By using flow chart proof:

[tex] \boxed{ \sf{ \angle X = \angle Z}} \searrow[/tex]

[tex] \boxed{ \sf{\small{ \angle Y = com.}}} \rightarrow \boxed{\small{ \sf{ \triangle XYB \cong \triangle ZYA}}}\rightarrow \small{\boxed{ \sf{AZ= XB}}}[/tex]

[tex] \boxed{ \sf{XY = ZY}} \nearrow[/tex]

━━━━━━━━━━━━━━━━━━━━

Step-by-step explanation:

Hey mate ut answer is in the given attachment.

hope i help u

Answer:

35%

Step-by-step explanation:

[tex]Principal = 2500\\\\Simple\:Interest = 3500\\\\Time = 4 \:years\\\\Rate = ?\\\\Rate = \frac{100 \times Simple \: Interest }{Principal \times Time}\\\\Rate = \frac{100 \times 3500}{2500 \times 4} \\\\Rate = \frac{350000}{10000}\\\\ Rate = 35 \%[/tex]

[tex]S.I = \frac{PRT}{100}\\\\ 100S.I = PRT\\\\\frac{100S.I}{PT} = \frac{PRT}{PT} \\\\\frac{100S.I}{PT} = R[/tex]

Answer:

35%

Step-by-step explanation:

I REALLY HOPE I HELPED

HOPE I HELPED

PLS MARK BRAINLIEST

DESPERATELY TRYING TO LEVEL UP

 ✌ -ZYLYNN JADE ARDENNE

JUST A RANDOM GIRL WANTING TO HELP PEOPLE!

                                PEACE!

Answer:

92 inches squared

Step-by-step explanation:

T/P = 8 * 3

L/R = 3 * 2

F/B = 8 * 2

Solving for surface area!

2(24) + 2(6) + 2(16) = 92

Answer:

[tex]\boxed{22,500}[/tex]

Step-by-step explanation:

Hey there!

Well, half of 300 is 150, and 150•150 = 22500

So 150 and 150 are it's highest numbers.

Hope this helps :)

Answer:

D. [tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]

Step-by-step explanation:

Given

[tex]y = \frac{2}{5}x - 5[/tex]

Required

Determine its equivalent

From the list of given options, the correct answer is

[tex]x - \frac{5}{2}y = \frac{25}{2}[/tex]

This is shown as follows;

[tex]y = \frac{2}{5}x - 5[/tex]

Multiply both sides by [tex]\frac{5}{2}[/tex]

[tex]\frac{5}{2} * y = \frac{5}{2} * (\frac{2}{5}x - 5)[/tex]

Open Bracket

[tex]\frac{5}{2} * y = \frac{5}{2} * \frac{2}{5}x - \frac{5}{2} *5[/tex]

[tex]\frac{5}{2}y = x - \frac{25}{2}[/tex]

Subtract x from both sides

[tex]\frac{5}{2}y - x = x -x - \frac{25}{2}[/tex]

[tex]\frac{5}{2}y - x = - \frac{25}{2}[/tex]

Multiply both sides by -1

[tex]-1 * \frac{5}{2}y - x * -1 = - \frac{25}{2} * -1[/tex]

[tex]-\frac{5}{2}y + x = \frac{25}{2}[/tex]

Reorder

[tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]

Hence, the correct option is D

[tex]x-\frac{5}{2}y = \frac{25}{2}[/tex]

Answer:

The 4th option

Step-by-step explanation:

Answer: a. 0.4 × 0.15 = 0.060

Step-by-step explanation: Probability of the complement of an event is the one that is not part of the event.

For P(A):

P(A') = 1 - 0.6

P(A') = 0.4

For P(B):

P(B') = 1 - 0.85

P(B') = 0.15

To determine probability of A' and B':

P(A' and B') = P(A')*P(B')

P(A' and B') = 0.4*0.15

P(A' and B') = 0.06

Probability of the complement of the event is 0.060

Answer:

Step-by-step explanation:

To find the ratio first find the diameter of the larger circle

Diameter of first circle = 6 inches

Diameter of second circle = 4 × diameter of the first circle

Which is

Diameter of second circle

= 4 × 6 = 24 inches

Area of a circle = πr²

r is the radius

Area of smaller circle

Diameter = 6 inches

Radius = 6 / 2 = 3 inches

Area = (3)² π = 9π in²

Area of larger circle

Diameter = 24 inches

Radius = 24 / 2 = 12 inches

Area = (12)²π = 144π in²

The ratio of the smaller circle to the larger circle is

[tex] \frac{9\pi}{144\pi} [/tex]

Reduce the fraction by 9π

That's

[tex] \frac{1}{16} [/tex]

We have the final answer as

Hope this helps you

Answer:

C. 1:16

Step-by-step explanation:

Area of a circle is:

[tex]\pi \times {r}^{2} [/tex]

Small circle Area:

radius = diameter/2

radius = 6/2 = 3

[tex]area \: of \: a \: circle \: = \pi {3}^{2} [/tex]

a = 28.27

Large circle 4 times larger diameter

6*4 = 24

diameter = 24

r = 24/2

r = 12

[tex]a \: = \pi {12}^{2} [/tex]

a = 452.39

area of large circle/ area of small circle

452.39/28.27 = 16.00

ratio is 1:16

Answer:

12 - 6 x (0 + 15) = 34

How I got my answer

First, how i got my answer was that I had to solve the equation first, ignoring the answer. I got 0 x 6 = 0, then I did 124 - 0 = 124, then I did 124 - 15 = 109, which clearly isn't 34. I figured that we have to put the parentheses around the zero because if we don't, we are going have to multiply something by zero, which always gets zero. After that, I decided that I should put the parentheses around either the 6, or the 15. I did both, and saw which one was correct. If we put it around the 6, we get, 124 - (6 x 0) + 15 = 124 - 0 - 15 = 124 - 15 = 109, which isn't 34. Then I checked 124 - 6 x (0 + 15) = 124 - 6 x 15 = 124 - 90 = 34, and we just got the answer.

P.S. Sorry if it was confusing, I didn't really know how to explain it

area of Arc subtending [tex]360^{\circ}[/tex] (i.e. the whole circle) is $\pi r^2$

so area of Arc subtending $\theta^{\circ}$ is, $\frac{ \pi r^2}{360^{\circ}}\times \theta^{\circ}$

$\theta =72^{\circ}$ so the area enclosed by one such arc is $\frac{\pi (10)^272}{360}$

abd there are 2 such arcs, so double the area.

[tex] \LARGE{ \underline{ \boxed{ \rm{ \purple{Solution}}}}}[/tex]

For solving this question, Let's know how to find the area of a sector in a circle?

[tex] \large{ \boxed{ \rm{area \: of \: sector = \frac{\theta}{360} \times \pi {r}^{2} }}}[/tex]

Here, Θ is the angle of sector and r is the radius of the circle. So, let's solve this question.

We have,

By using formula,

⇛ Area of shaded region = 2 × Area of each sector

⇛ Area of shaded region = 2 × Θ/360° × πr²

⇛ Area of shaded region = 2 × 72°/360° × 22/7 × 10²

⇛ Area of shaded region = 2/5 × 100 × 22/7

⇛ Area of shaded region = 40 × 22/7

⇛ Area of shaded region = 880/7 inch. sq.

⇛ Area of shaded region = 125.71 inch. sq.

☄ Your Required answer is 125.71 inch. sq(approx.)

━━━━━━━━━━━━━━━━━━━━

Answer:

Step-by-step explanation:

x^2+20=4 first isolate the variable by subtracting 20 on both sides.

x^2=-16 again isolate the variable but this time you square root both sides.

[tex]\sqrt{x}^2[/tex]=[tex]\sqrt{-16[/tex] then simplify

x= ±4

Answer:

[tex]\Large \boxed{\sf True}[/tex]

Step-by-step explanation:

[tex]\sf A \ diameter \ that \ is \ perpendicular \ to \ a \ chord \ bisects \ the \ chord.[/tex]

Answer:

True!!

I just did the assignment and got it right

Answer:

B. 152 cm²

Step-by-step explanation:

To find the surface area using a net, do this:

Take apart the figure. We see that there are three rectangles and two triangles. Find the area of each ([tex]A=l*w[/tex]) and then add the values together:

The first rectangle on the left is the same as the one on the right.

[tex]5*8=40[/tex]

Two measures are 40 cm².

The middle rectangle is:

[tex]6*8=48[/tex]

48 cm²

The formula for the area of a triangle is [tex]A=\frac{1}{2}*b*h[/tex]:

[tex]A=\frac{1}{2}*6*4\\\\A=\frac{1*6*4}{2}\\\\A=\frac{24}{2}\\\\ A=12[/tex]

The area of the two triangles is 12 cm².

Now add the values:

[tex]40+40+48+12+12=152[/tex]

The area of the figure is 152 cm².

:Done

Answer:

(x,y) -> (x+6, y-3)

Step-by-step explanation:

I followed c and it translated like the  last ans choice.

Step-by-step explanation:

Hi, there!!!

It's so simple..

Let me clear you, alright.

Here, On the fig line, OE is just a confusing line. If you look it in simple way,

AB and CD are interested at a point O.

so, angle AOD and angle COB are equal.{ because they are vertically opposite angle}

so, angle AOD= angle COB

or, 4x°=45°+15°

or, 4x°= 60°

or, x= 60°/4

Therefore, x= 15°.

Hope it helps....

Answer:

3/6 = 1/2 = 0.5

Step-by-step explanation:

3 / 6 = 1/2 = 0.5

Answer:

[tex]\approx \bold{6544\ in^3/sec}[/tex]

Step-by-step explanation:

Given:

Rate of change of radius of cylinder:

[tex]\dfrac{dr}{dt} = +7\ in/sec[/tex]

(This is increasing rate so positive)

Rate of change of height of cylinder:

[tex]\dfrac{dh}{dt} = -6\ in/sec[/tex]

(This is decreasing rate so negative)

To find:

Rate of change of volume when r = 20 inches and h = 16 inches.

Solution:

First of all, let us have a look at the formula for Volume:

[tex]V = \pi r^2h[/tex]

Differentiating it w.r.to 't':

[tex]\dfrac{dV}{dt} = \dfrac{d}{dt}(\pi r^2h)[/tex]

Let us have a look at the formula:

[tex]1.\ \dfrac{d}{dx} (C.f(x)) = C\dfrac{d(f(x))}{dx} \ \ \ (\text{C is a constant})\\2.\ \dfrac{d}{dx} (f(x).g(x)) = f(x)\dfrac{d}{dx} (g(x))+g(x)\dfrac{d}{dx} (f(x))[/tex]

[tex]3.\ \dfrac{dx^n}{dx} = nx^{n-1}[/tex]

Applying the two formula for the above differentiation:

[tex]\Rightarrow \dfrac{dV}{dt} = \pi\dfrac{d}{dt}( r^2h)\\\Rightarrow \dfrac{dV}{dt} = \pi h\dfrac{d }{dt}( r^2)+\pi r^2\dfrac{dh }{dt}\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2r \dfrac{dr }{dt}+\pi r^2\dfrac{dh }{dt}[/tex]

Now, putting the values:

[tex]\Rightarrow \dfrac{dV}{dt} = \pi \times 16\times 2\times 20 \times 7+\pi\times 20^2\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 22 \times 16\times 2\times 20 +3.14\times 400\times (-6)\\\Rightarrow \dfrac{dV}{dt} = 14080 -7536\\\Rightarrow \dfrac{dV}{dt} \approx \bold{6544\ in^3/sec}[/tex]

So, the answer is: [tex]\approx \bold{6544\ in^3/sec}[/tex]

Answer:

p0 = 0.05

Step-by-step explanation:

━━━━━━━☆☆━━━━━━━

▹ Answer

6 phones

▹ Step-by-Step Explanation

$445 - $175 = $270

$270 ÷ $45 = 6

6 phones

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer: The answer is C.

Step-by-step explanation:

Hi, there!!!

The answer is option C.

The solution is in picture.

I hope it helps....

Answer: 0.2358

Step-by-step explanation:

Using Normal Distribution, under the  standard normal curve

The area to the right of z is given by P(Z>z)=1-P(Z<z)

So, the area to the right of z= 0.72 under the  standard normal curve would be:

P(Z>0.72)=1-P(z<0.72)

=1-0.7642   [By using p-value table]

= 0.2358

Hence, the area to the right of z= 0.72 under the  standard normal curve is 0.2358 .

Step-by-step explanation:

Hello, there!!

The answer would be 41/9.

The reason for above answer is to change any mixed fraction into improper fraction we should follow a simple step:

look here,

=[tex] \frac{4 \times 9 + 5}{9} [/tex]

we get 41/9.

Hope it helps...

The given fraction into the improper fraction should be [tex]\frac{41}{9}[/tex]

Given that,

[tex]= 4\frac{5}{9}\\\\ = \frac{41}{9}[/tex]

Here we multiply the 9 with the 4 it gives 36 and then add 5 so that 41 arrives.

learn more about the fraction here: https://brainly.com/question/1301963?referrer=searchResults

Answer and Step-by-step explanation:

The computation of points on the ellipse is shown below:-

Distance between any point on the ellipse

[tex](3 cos t, sin t) and (\frac{4}{3},0) is\\\\ d = \sqrt{(3 cos\ t - \frac{4}{3}^2) } + (sin\ t - 0)^2\\\\ d^2 = (3 cos\ t - \frac{4}{3})^2 + sin^2 t[/tex]

To minimize

[tex]d^2, set\ f' (t) = 0\\\\2(3cos\ t - \frac{x=4}{3} ).3(-sin\ t) + 2sin\ t\ cos\ t = 0\\\\ 8 sin\ t - 16 sin\ t\ cos\ t = 0\\\\ 8 sin\ t (1 - 2 cos\ t) = 0\\\\ sin\ t = 0, cos\ t = \frac{1}{2} \\\\ t= 0, \ 0, \pi,2\pi,\frac{\pi}{3} , \frac{5\pi}{3}[/tex]

Now we create a table by applying the critical points which are shown below:

t            [tex]d^{2} = (3\ cos t - \frac{4}{3})^{2} + sin^{2}t[/tex]

0           [tex]\frac{25}{9}[/tex]

[tex]\pi[/tex]           [tex]\frac{169}{9}[/tex]

[tex]2\pi[/tex]         [tex]\frac{25}{9}[/tex]

[tex]\frac{\pi}{3}[/tex]          [tex]\frac{7}{9}[/tex]

[tex]\frac{5\pi}{3}[/tex]         [tex]\frac{7}{9}[/tex]

When t = [tex]\frac{\pi}{3}[/tex], x is [tex]\frac{3}{2}[/tex] and y is [tex]\frac{\sqrt{3} }{2}[/tex]. So, the required points are [tex](\frac{3}{2},\frac{\sqrt{3} }{2})[/tex]

When t = [tex]\frac{5\pi}{3}[/tex], x is [tex]\frac{3}{2}[/tex] and y is [tex]\frac{-\sqrt{3} }{2}[/tex]. So, the required points are [tex](\frac{3}{2},\frac{-\sqrt{3} }{2})[/tex]

Answer:

the length has dimension 1, the area has the dimension 2, the volume has dimension 3, etc. And the angle has dimension 0.

Step-by-step explanation: