Answer:
Hey, could you please add the number line to the question too
if the diagonal of a square is √48 what is the area of a square
Answer:
using Pythagoras' theorem c²=a²+b²
the diagonal is the hypotenuse of one of the triangles formed
let x represent one side of the square
√48²=x²+x²
√48²=2x²
48=2x²
48/2=2x²/2
24=x²
√24=√x²
4.8989794855663561=x
~4.90
Area of the square=side x side
4.90x4.90
24.01units²
Cual de las siguientes fracciones es equivalente a 6/18
1/3
2/3
3/18
3/6
Answer:
the answer is going to be 1/3
question 3 help pls in algebra
Answer:
50
Step-by-step explanation:
simplify the radical by breaking the redicand up into a product of known factors, assuming positive real numbers.
Rewrite the expression as a simplified expression containing one term.
Answer:
-(cos α)/(sin α)
= -cot α
Step-by-step explanation:
use trigonometric identities
A house plan Is drawn to a scale 1cm to 2m. What is the length of a window 2.5cm long on the plan?
1cm = 2m
=> 1cm = 200cm
2.5cm = 2.5 × 200cm = 500 cm = 5m
So, the length of window is 500cm or 5m.
Write the following expression in exponential form:
16x16x16x1.6
0416
0164
16x4
O 16+ 4
Answer:
16x16x16x1.6
Step-by-step explanation:
here's your answer hope it helps you
A square has a perimeter of 36 cm.
What is the length of each side?
Answer:
Step-by-step explanation:
The perimeter of a square has a formula P = s + s + s + s or just P = 4s where s is the length of a side. If this perimeter has a number value, we can plug it in and solve for the length of each side, like this:
36 = 4s so
s = 9 cm. And there you go!
Determine the area of the triangle.
223.6 square units
248.7 square units
447.1 square units
458.4 square units
Answer:
223.6 square units. or 223.569 square units
Answer:A
Step-by-step explanation:I took the test
The given equation has been solved in the table. Step Statement 1 1 –7n + 11 = -10 2. -7n + 11 – 11 = -10 – 11 3 -7n = -21 4 = = =21 .In -7 -21 __7 5 n = 3 Use the table to complete each statement. In step 2, the In step 4, the property of equality was applied. property of equality was applied.
Answer:
In step 2, the subtraction property of equality was applied
In step 4, the division property of equality was applied
Step-by-step explanation:
what is the solution to -6 - -25=
Answer:
19
Step-by-step explanation:
(-6)-(-25)=(-6) +25 = 19
What is the difference between calculating the area and calculating the perimeter of a rectangle?
Answer:
For perimeter you add up the side lengths to get the perimeter but for area you multiply the length times width (L x W )to get area.
Step-by-step explanation:
Solve for x. Round to the nearest tenth, if necessary.
Answer:
3.8106327168
Step-by-step explanation:
x=2.5/sin(41) = 3.81063271676
In ΔTUV, the measure of ∠V=90°, UT = 65, VU = 56, and TV = 33. What ratio represents the cosine of ∠T?
Answer: The ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]
Step-by-step explanation:
We are given:
UV = 56 units
VT = 33 units
UT = 65 units
∠V = 90°
Cosine of an angle is equal to the ratio of base and the hypotenuse of the triangle. ΔTUV is drawn in the image below.
[tex]\cos \theta=\frac{\text{base}}{\text{hypotenuse}}[/tex]
Base of the triangle is UV and the hypotenuse of the triangle is TU
Putting values in above equation, we get:
[tex]\cos \theta=\frac{UV}{TU}=\frac{56}{65}[/tex]
Hence, the ratio that represents the cosine of ∠T is [tex]\frac{56}{65}[/tex]
What is the number of outcomes in the sample space tossing a coin and spinning a spinner with 8 equal sections?
Answer:
16
Step-by-step explanation:
[tex]solve : - \\ \\ ( \sqrt{100 - 64)} [/tex]
Answer:
[tex] \sqrt{100 - 64} \\ = 36 \\ = {6}^{2} [/tex]
HELP ME !
Please!
Which of the following tables represents a function?
A tortoise moves forward 15 meters in one hour. It turns around and crawls 10 meters in the
next hour. Finally, in the third hour, it turns around again and crawls 8 more meters. How
much did the tortoise walk in total in 3 hours?
Answer:
Below.
Step-by-step explanation:
15+10+8=33.
Answer:
13 meters
Step-by-step explanation:
It went 15 meters, but then it went back 10 meters.
[tex]15-10=5[/tex]
Then it went 8 more meters.
[tex]5+8=13[/tex]
Hope this helped! Please mark brainliest :)
A circular garden is surrounded by a circular path of 7m width.If the area of path is 770m²,find the area of the garden without path.
help me this question ⁉️
Answer:
Answer:
Radius of the circular garden
= 210 sq
=105m
Radius of the region covering the garden and the path =105m+7m
=112m
Area of the region between two concentric circles
with radius of outer circle R, and inner circle r =π(R sq−r sq)
Hence, the area of the path
=π(112sq−105 sq)= 7/22
(12544−11025)
= 33418/7
=4774m sq
HOPE THIS WILL HELP YOU MATE
Figure A is a scale image of Figure B. What is the value of x?
khan academy
Answer:
maybe 12 because
Step-by-step explanation:
30/25=1.2
10×1.2=12
W=VI. Make V the subject of formula
Answer:
hope that is helpful
Step-by-step explanation:
W= VI
W= VI
I. I
V= W
I
Answer:
V = [tex]\frac{W}{I}[/tex]
Step-by-step explanation:
Given
W = VI ( isolate V by dividing both sides by I )
[tex]\frac{W}{I}[/tex] = V
the base of a right prism is an equilateral triangle each of whose sides measures 4cm.the altitude of the prism measures 5cm.Find the volume of the prism
Answer:
[tex]V=34.64\ cm^3[/tex]
Step-by-step explanation:
Given that,
The side of an equilateral prism = 4 cm
The altitude of the prism = 5 cm
We need to find the volume of the prism. The formula for the volume of a prism is as follows :
[tex]V=A\times h[/tex]
Where
A is the area of equilateral triangle, [tex]A=\dfrac{\sqrt3}{4}a^2[/tex]
So,
[tex]V=\dfrac{\sqrt3}{4}a^2\times h\\\\V=\dfrac{\sqrt3}{4}\times 4^2\times 5\\\\V=34.64\ cm^3[/tex]
So, the volume of the prism is equal to [tex]34.64\ cm^3[/tex].
Area of this figure
Let the universal set U = {weekdays}. If T = {Tuesday, Thursday}, what is T'?
Answer:Monday, Wednesday and Friday.
Step-by-step explanation:
It’s the other weekdays.
what is the measure of angle D?
Answer:
57
Step-by-step explanation:
The table below shows how much Joe earns, y, after working x hours.
Joe’s Earnings
Hours worked
Money earned
4
$30
10
$75
12
$90
22
$165
The relationship between money earned and hours worked is linear. Joe computes the slope between (4, 30) and (12, 90), then computes the slope between (4, 30) and (10, 75). How do the two slopes compare?
The slope between (4, 30) and (12, 90) is greater because the ordered pairs are farther apart on the x-axis.
The slope between (4, 30) and (12, 90) is greater because the ordered pairs are farther apart on the y-axis.
The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.
The slope between (4, 30) and (12, 90) is less because 4 is a factor of 12 and 30 is a factor of 90.
Answer: Given : Joe’s Earnings and hour worked
The relationship between money earned and hours worked is linear.
Joe computes the slope between (4, 30) and (12, 90), then computes the slope between (4, 30) and (10, 75).
To Find : How do the two slopes compare?
Solution:
Hours worked Money earned
4 $30
10 $75
12 $90
22 $165
slope between (4, 30) and (12, 90),
= (90 - 30)/(12 - 4)
= 60/8
= 15/2
slope between (4, 30) and (10, 75)
= (75 - 30)/(10-4)
= 45/6
= 15/2
The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.
Both Slopes are same.
i hope this helped and have a nice day/night
The slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same. The correct answer is the third option.
The slope between two points (x₁,y₁) and (x₂, y₂) on a straight line is given by (y₂ - y₁)/(x₂ -x₁ ).
Let's calculate the slopes:
The slope between (4, 30) and (12, 90):
Slope = (90 - 30) / (12 - 4)
= 60 / 8
= 7.5
The slope between (4, 30) and (10, 75):
Slope = (75 - 30) / (10 - 4)
= 45 / 6
= 7.5
As we can see, the slopes between the two sets of ordered pairs are the same.
Thus, the slope between (4, 30) and (12, 90) and between (4, 30) and (10, 75) is the same.
Hence, the correct answer is the third option.
Learn more about the slope of the line here:
brainly.com/question/14511992
#SPJ7
# If two vectors whose direction ratios are 1,2,3 and -k,2,1 are perpendicular to each other then, a) k=7 b) k=4 c) k=3 O d) k=6 me especially since we had be 1 poir 82) I don't know why he turned friends for so long.
Answer:
(a)k=7
Step-by-step explanation:
We are given that
Two vectors whose direction ratios are 1,2,3 and -k,2,1.
Let
[tex]a_1=1,b_1=2,c_1=3[/tex]
[tex]a_2=-k,b_2=2,c_2=1[/tex]
We have to find the value of k.
We are given that two vectors are perpendicular to each other.
We know that two vectors are perpendicular to each other then
[tex]a_1a_2+b_1b_2+c_1c_2=0[/tex]
Substitute the values
[tex]1(-k)+2(2)+3(1)=0[/tex]
[tex]-k+4+3=0[/tex]
[tex]-k+7=0[/tex]
[tex]\implies k=7[/tex]
Hence, option a is correct.
Team members Corinne, Kevin, and Tomas decide to share the cost
of 2 motor controllers and 4 wheels equally. How much does each
member need to contribute?
Please help(write step by step and upload pic or do it here please I appreciate it so much !
Answer:
each member needs to put in 91.70 dollars in.
Step-by-step explanation:
you add the costs of all the tools needed. in this case the two controllers and wheels which adds up to 275.1.
then you divide by the amount of people which is three. so 275.1/3 and you get 91.7
A and B are two similar 2D shapes
A 12cm
B 15cm
The area of the shape A is 200cm^2.
Calculate the area of shape B
Answer: [tex]312.5\ cm^2[/tex]
Step-by-step explanation:
Given
A and B are two similar shape with lengths of 12 cm and 15 cm
A has an area of [tex]200\ cm^2[/tex]
For similar figures, ratio of the square of corresponding length is equal to the ratio of the area
[tex]\Rightarrow \dfrac{200}{A_b}=\dfrac{12^2}{15^2}\\\\\Rightarrow A_b=\dfrac{15^2}{12^2}\times 200\\\\\Rightarrow A_b=312.5\ cm^2[/tex]
Plz help me.
I WILL GIVE BRAINLY
Answer:
p = T - a - b
Step-by-step explanation:
T = a + p + b
p = T - a - b
I have no idea how to do this, it is due in two days. Hopefully someone sees this before then.
Hello,
[tex]m\ \widehat{ABC}=x\\m\ \widehat{BAC}=2*x\\\\So:\\ x+2x=90^o\\x=30^o\\[/tex]
[tex]cos(30^o)=\dfrac{\sqrt{3} }{2} \\[/tex]
In the triangle ABC,
[tex]cos(30^o)=\frac{BC}{BA} \\\\BA=\dfrac{cos(30^o)}{BC} \\\\BA=\frac{\dfrac{\sqrt{3} }{2} }{24} =16*\sqrt{3} \\\\[/tex]
[tex]sin(30^o)=\dfrac{1 }{2} =\dfrac{AC}{AB} \\\\AC=\dfrac{1}{2} *16\sqrt{3} =8\sqrt{3}[/tex]
In the triangle ACB,
[tex]cos(30^o)=\dfrac{AC}{AL} \\\\AL=\dfrac{8\sqrt{3} *2}{\sqrt{3} } =16\\[/tex]
