Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Answers

Answer 1

Answer:Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Explanation:

Two electrons are separated by 2.00 nm. What is the magnitude of the electric force each electron exerts on the other?

Answer 2
An electric force is given by F = (kqQ)/(r^2) where k is the constant 9x10^9, q and Q are the charges, and r is the distance between the charges.

Given that the charge of an electron is -1.6 x 10^-19 C, we can write the force equal to

((9x10^9)(-1.6x10^-19)^2)/(2x10^-9)

=> 1.152 x 10^-19 N

Note that the force is repulsive since the electrons are both negatively charged (the same sign).

Related Questions

Colette launches an air rocket in the upward, positive direction. It launches with an initial velocity of 25.5 m/s. It accelerates in the downward, negative direction at a rate of 9.81 m/s2. After 3.5 seconds, what is the magnitude of the rocket's displacement?

Answers

Answer:

Give me some hint please

A bicyclist travels 30 km in 2 hours east. Calculate its velocity?

Answers

Answer:

Its velocity would be

15 km per hour

or

0.00416667 per second

 what is the difference between repelling and attracting

Answers

Answer:

Attracting means pulling toward you and repelling means pushing away

Explanation:

Answer: Repelling is when something will not connect with another object. The force will cause a repel between the two objects. Attracting is when something is attracted or being pulled to another object.

Explanation: Hope this helps!

A proton is released in a uniform electric field and it experiences an electric force of 2.18x10^-14N toward south .What are the magnitude and direction of the electric field

Answers

Answer:

F = E q

E = 2.18E-14 / 1.6E-19 = 1.36E5 N/C

The direction of the field will be the same as force on the proton - southerly

Am object of mass in a circular path of radius 100metres with the speed of 10metres/second.calculate the acceleration towards the center​

Answers

Answer:

is 6

Explanation:

h

Market researchers were interested in the relationship between the number of pieces in a brick-building set and the
cost of the set. Information was collected from a survey and was used to obtain the regression equation ý =
0.08x + 1.20, where x represents the number of pieces in a set and ŷ is the predicted price in dollars) of a set.
What is the predicted price of a set that has 500 pieces?
$40
$41.20
$600
$6,235

Answers

Plug in 500 for x and solve. 500(0.08) = 40

Then do 40 + 1.2 = 41.20

Answer B

Alex is x years old . June is 7years older than Alex . their total combined ages is 29 years . find June,s age . show all work algebraically

Answers

Answer:

18 years

Explanation:

Given,

Let Alex be = x years

Then June will be = (7 + x) years

We know that,

Their total combined age is 29 years

Therefore,

By the problem,

=> x + (7 + x) = 29

=> 2x = 29 - 7

=> 2x = 22

=> x = 22 ÷ 2

=> x = 11

So,

Required age of June is = (7 + x) years

= (7 + 11) years

= 18 years (Ans)

Can someone help me .. please I don’t understand.

Answers

I would go wit B but I’m not sure

1.25 is closer to 1.04 or not ?
plz heelp plz

Answers

Answer:

No, it is closer to 1.30

Explanation:

A certain laser outputs pure blue light (photon energy 3.1 eV) with power 650 milliwatts (0.65 watts). How many photons per second does this laser emit

Answers

The number of photons per second emitted by the laser is [tex]7.64 \times 10^{-19} \ photons /s[/tex].

The given parameters:

energy of the photon, E = 3.1 eVpower of the laser, P = 650 mW

The number of photons per second emitted by the laser is calculated as follows;

[tex]n(P \times t ) = E[/tex]

where;

n is the number of photons1 ev = 1.602 x 10⁻¹⁹ J

[tex]n = \frac{E}{P\times t} \\\\n = \frac{3.1 \times 1.602 \times 10^{-19}}{0.65 \times t} \\\\n = 7.64 \times 10^{-19} \ photons/s[/tex]

Thus, the number of photons per second emitted by the laser is [tex]7.64 \times 10^{-19} \ photons /s[/tex].

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Which language style would be most appropriate for the given situation?
dinner at a neighbor's birthday party
o informal language
o formal language
o technical language

Pls help

Answers

Answer:

informal language

Explanation:

you do not need to be formal! you are not at a business conference. technical is not needed either since you are not discussing the intricacies of your job or some computer language.

An object is moving due north at 31m/s. Does this tell you the speed of the velocity of the object or both?

Answers

Answer:

speed

Explanation:

its the speed

because the formula for deriving speed is distance/time

the unit for distance is metre

the unit for time is seconds

so speed is metre/seconds

so speed us m/s.

A meter stick is attached to one end of a rigid rod with negligible mass of length l = 0.302 m. The other end of the light rod is suspended from a pivot point, as shown in the figure below. The entire system is pulled to a small angle and released from rest. It then begins to oscillate. A meter stick hung from a rod of length l. The rod is attached to the ceiling. The rod and meter stick extend downward in a straight line making a small angle with the vertical. (a) What is the period of oscillation of the system (in s)? (Round your answer to at least three decimal places.)

Answers

The period of oscillation of the system nearest to three decimal places

= 1.092 seconds

The period of an oscillation occurring in a system is the time taken to complete one cycle.

The formula that is used to calculate the period of oscillation (T) is

                = 2π√[tex]\frac{l}{g}[/tex]

But,

π = 3.14159 (constant)

g= 10m/s² (acceleration due to gravity)

l = 0.302 m

Therefore T = 2 × 3.14159 × √[tex]\frac{0.302}{10}[/tex]

                    = 6.28318 x √0.0302

                    = 6.28318 x 0.17378

                    = 1.09189s

                    = 1.092 seconds ( to the nearest three decimal places)

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Acceleration of a car that speeds from 4.3 m/s to 12.9 m/s in 2 seconds

Answers

Explanation:

let v1 = 4.3 m/s

v2 = 12.9 m/s

t = 2 seconds

v2 = v1 + at

12.9 = 4.3 + a×2

2a = 12.9 - 4.3 = 8.6

a = 8.6/2

a = 4.3 m/s^2

Câu 9. Một dây dẫn đồng chất, tiết diện đều 20mm2 có dòng điện không đổi 12A đi qua. Tính trị trung bình mật độ dòng điện j ?

Answers

Answer:

Sorry I can't understand you

A Scooter has a mass of 250 kg. A constant force is exerted on it for 6.0 s. During the time the force is exerted, the scooter increases its speed from 6.00 m/s to 280 m/s. What is the magnitude of the force exerted on the scooter

Answers

Answer:

917 N

Explanation:

917 N, this is your answer!!

Glad to help.

Which scientist is credited with having the greatest contribution to early microscopy and was the first to observe and describe single-celled organisms?

Answers

Answer:

Antonie van Leeuwenhoek

Explanation:

In a car crash, how are force, mass, acceleration, and velocity related?

Answers

Answer:

the answer is simple but click on the brainiest and thank me.

Explanation:

F=force, m=mass, a=acceleration, v=velocity

v=displcement/time

a= v/t

F= m×a

F= m× (v/t)

When an elastic object is changed from its original shape:
A:Energy is released
B:Work is done
C:It is ruined
D:It makes a twanging sound

Answers

Answer:

deformation : elastic deformation is reversed when the force is removed. inelastic deformation is not fully reversed when the force is removed – there is a permanent change in shape.

Explanation:

tysm

Before the collision, the toy train is travelling at 0.5 m/s. The train and the stationary
truck both have a mass of 75 g.
Calculate the momentum of the toy train before the collision?

Answers

Answer:

Explanation:

p = mv = 0.075(0.5) = 0.0375 kg•m/s

A driver entering the outskirts of a city takes her foot off the accelerator so that the car slows down from 90 km/h to 50 km/h in 10.0s. Find the car’s average acceleration

Answers

Answer:

Explanation:

a = (vf - vi) / t

a = (50 - 90) / 10.0

a = -4 km/h/s(1000 m/km / 3600 s/h)

a = - 1.11 m/s²

Which force, in real life, will have the least effect on a bowling ball rolling down a lane toward bowling pins?

A) magnetism

B) air resistance

C) gravity

D) friction

Answers

Answer:

Its Friction

Explanation:

the pins are not floating and they are not a magnet and not involved with air

The force, in real life, that will have the least effect on a bowling ball rolling down a lane toward bowling pins is magnetism. The correct option is A.

What is magnetism?

Magnetism is basically the force which indeed magnets exert when they attract or even repel one another. The movement of electric charges resulting in magnetism.

Every substance is composed of tiny units referred to as atoms. Each atom contains electrons, which are charged particles.

To increase stability, the pins themselves have a low center of gravity. Because they are spherical in shape, they can roll and strike other pins in a variety of directions.

The force acting on the bowling ball is friction and air resistance. The friction force is equal to the friction coefficient multiplied by the normal force, and thus mass times acceleration.

Thus, the correct option is A.

For more details regarding magnetism, visit:

https://brainly.com/question/2841288

#SPJ2

A girl of mass m1=60.0 kilograms springs from a trampoline with an initial upward velocity of vi=8.00 meters per second. At height h=2.00 meters above the trampoline, the girl grabs a box of mass m2=15.0 kilograms. (Figure 1)

For this problem, use g=9.80 meters per second per second for the magnitude of the acceleration due to gravity.

What is the speed vbefore of the girl immediately before she grabs the box?
Express your answer numerically in meters per second.

What is the speed vafter of the girl immediately after she grabs the box?
Express your answer numerically in meters per second.

What is the maximum height hmax that the girl (with box) reaches? Measure hmax with respect to the top of the trampoline.

Answers

The conservation of momentum and energy allows to shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

 

Kinematics studies the movement of bodies, looking for relationships between the position, velocity and acceleration of bodies.

The momentum is defined by the product of mass and the velocity, when a system is isolated the momentum is conserved.

The mechanical energy is the sum of the kinetic energy plus the potential energies, when there is no friction in the system the mechanical energy is conserved.

Let's solve this exercise in parts:

a) Let's use kinematics to find the speed of the girl before she grabs the box

              v² = v₀² - 2 g y₁

              v² = 8² - 2 9.8 2.00

              v = R 24.8 = 4.98 m / s

b) Let's use momentum conservation for when the speed of the girl and the box together. Let's write the moment in two moments.

Initial instant. Just before you grab the box.

              p₀ = M v + 0

Final moment. Right after taking the box

             [tex]p_f[/tex]  = (m + M) [tex]v_f[/tex]

         

In system this form by the girl and the box therefore it is an isolated system and the momentum is conserved.

           [tex]p_o = p_f[/tex]  

           mv = (m + M) [tex]v_f[/tex]  

           [tex]v_f = \frac{m}{m+M} \ v[/tex]

Let's calculate

           [tex]v_f = \frac{15}{15+ 60} \ 4.98[/tex]  

           [tex]v_f[/tex]  = 0.996 m / s

c) Now we use conservation of energy after the girl has the box.

Starting point. When the girl has the box

           Em₀ = K + U

           Em₀ = ½ (m + M) v² + (m + M) g y₁

Final point. At the highest point of the trajectory

          [tex]Em_f[/tex]  = U

         [tex]Em_f[/tex] = (m + M) g y₁

As there is no friction, the energy is conserved.

           [tex]Em_o = Em_f[/tex]  

          ½ (m + M) v² + (m + M) g y₁ = (m + M) g y

          y = [tex]\frac{v^2}{2g} + y_1[/tex]  

Let's calculate

           y = [tex]\frac{0.996^2}{2 \ 9.8} + 2.0[/tex]

           y = 2.05 m

In conclusion using the conservation of momentum and energy we can shorten the results for the movement of the girl on the trampoline holding the box are:

     a) the girl's speed is v = 4.98 m / s

     b) The speed of the girl + box system is: v_f = 0.996 m / s

     c) the maximum height is: y = 2.05 m

Learn more here: brainly.com/question/15095150

Answer:

Vbefore = 4.98 m/s

Vafter = 3.98 m/s

Hmax = 2.81 m

Explain how friction keeps a nail in place in a block of wood. If you try pull out the nail which way does friction act? I will give brainliest!

Answers

Answer:

Friction acts in the opposite direction of the velocity. As static friction acts in the opposite direction to the acceleration. (opposite way)

Explanation:

A soccer ball is kicked from the roof of a building with a height of 45.0m, near the surface of the Earth, with an initial velocity vi=14.2m/s. The ball exists the surface of the roof moving horizontally.

A) How long is the ball in the air?

B)How far away from the base of the building does the ball land?

C) How fast is the ball moving just before it strikes the ground?

D) At what angle does the ball strike the ground? This angle is measured with respect to the horizontal direction.

Answers

Answer:

its c

Explanation:

It is c how fast is the ball moving just before it strikes the ground

If you do 72 J of work in 1.2 seconds, how much power is produced

Answers

Answer:

Explanation:

Power is the rate of doing work

P = 72 / 1.2 = 60 Watts

What is non examples of enlarged

Answers

reduction

deflation

these are examples of the opposite of enlarged to make something smaller is really the key thing here

What on earth is equal to 9.8m/s/s

Answers

Answer:

Acceleration due to gravity

Which of the following scenarios would have the MOST friction force between the object and the surface?
A. a 7 kilogram bicycle with rubber tires on concrete
B. a 7 kilogram bicycle with rubber tires on ice
C. a 0.25 kilogram toy car with rubber tires on ice
D. a 0.25 kilogram toy car with rubber tires on concrete

Answers

Answer: A

Explanation: mass and friction are proportional if the mass increases the friction increases

Geologists collect and study hand samples because they can be used to understand

which

Answers

Geologists use a lot of tools to aid their studies. Some of the most common tools used are compasses, rock hammers, hand lenses, and field books.

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