The average frequency will be 465.5 Hz.
The frequency of light can be described as the number of waves passing through a point in a medium (or vacuum) per second.
It is measured in units of Hertz (Hz). Electromagnetic radiation propagates through space as a wave, and one type of radiation differs from another in the frequency of this wave. Electromagnetic radiation is categorized using the electromagnetic spectrum, which is usually organized by frequency.Frequency generated by generator 1 = f1 = 460 Hz
Frequency produced by generator 2 = f2 = 471 Hz
the average frequency will be (f1 + f2) / 2
f1 + f2 = 460 + 471
f1 + f2 = 931 Hz
Average frequency = A = 931/2
A = 465.5 Hz
The average frequency we hear will be 465.5 Hz.
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A soccer player runs at 10 m/s and runs into a 80 kg referee standing on the field causing the referee to fly forward at 6.0 m/s. Assume the soccer player comes to complete stop after impact. What would be the mass of the soccer player be?
The mass of soccer player will be 120kg. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How to solve ?According to Newton's third law,
Given that a soccer player runs at 10m/s and plows into a 80kg referee standing on the field causing the referee to fly forward at 56m/s. Let
mass of the player = ?
initial velocity of the player = 10m/s
Final velocity of the player
mass of the referee = 80 kg
Initial velocity of the referee = 0 ( since he is at rest )
Final velocity of the referee = 6 m/s
Since it is a perfectly elastic collision,
U1 =V2 - V1 ........ (1)
M1U1 = M2V2 + M1V1........ (2)
Substitute all the necessary parameters into the equation (1)
10 = 6 - V1
V1 = 10 - 6
V1 = 4 m/s
Now, Substitute all the necessary parameters into the equation (2)
10M1 = (80 x 6) + (4M1)
10 M1- 4 M1 = 480
4M1 = 480
M1 = 480/4
M1 = 120kg
Therefore, the mass of soccer player will be 120kg
Collision formula: What is it?When kinetic energy (KE) and momentum (p) are conserved during a collision, the collision is said to be elastic. To put it another way, it denotes that KE0 = KEf and po = pf. Writing down 1/2 m1 will help us remember that KE = 1/2 mv2 (v1i) 2 + 1/2 m2(vi) (vi) 2 = 1/2 m1(v1f) (v1f) 2 + 1/2 m2 (v2f) (v2f) 2.
How is velocity determined?By dividing the entire distance traveled by the time it took the object to go a certain distance, you may calculate the object's initial velocity. V, d, and t are the three variables that make up the equation V = d/t.
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supply drop design proposal
an astronaut drops a rock from the top of a crater on the moon when the rock is halfwat down to the bottom of the crater its speed is what fraction of its cinal impact speed?A. 1/4–√2B.1/4C. 1/2–√2D. 1/–√2Answer:
The fraction of its final impact speed is 1/√2.
Impact speed is the speed of the vehicle at the time of impact or collision.
The rock has lost half of its gravitational potential energy, its kinetic energy at the halfway point is half of its kinetic energy at impact.
As we know kinetic energy is directly proportional to mass (m) and velocity square (v²),
KE ∝ v²
KE = (1/2)mv²
then K.E at halfway point is equal to 1/2 x K.E,
Then,
The K.E at impact, then the rock’s speed at the halfway point its speed at impact will be 1/√2 its impact speed.
Therefore option D is the correct answer, the fraction of its final impact speed is 1/√2.
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All the following statements are true. Which one makes it possible to learn of the existence of extrasolar planets without seeing the planets themselves?Planets exert gravitational tugs on their stars that cause stars to orbit around the center of mass of their planetary systems.
Planets exert gravitational tugs on their stars that cause stars to orbit around the center of mass of their planetary systems. is true
What does the term "extrasolar planet" mean?Extrasolar planets, often known as exoplanets, are any planetary bodies outside of the solar system that typically circle stars other than the Sun.A planet beyond the Solar System is referred to as an exoplanet or extrasolar planet. In 1917, the first potential sign of an exoplanet was observed, but it was not taken seriously. In 1992, the first detection confirmation took place. 1988 saw the discovery of a different planet, which was verified in 2003. Telescopes have photographed a small number of exoplanets directly, but the great majority have been discovered via indirect techniques like the transit method and the radial-velocity approach. There are 5,284 confirmed exoplanets in 3,899 planetary systems as of December 1, 2022.The complete questio is Which one makes it possible to learn of the existence of extrasolar planets without seeing the planets themselves?
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4. For an ideal gas, the specific heat at constant pressure Cp is greater than the specific heat at constant volume CV because the A. pressure of the gas remains constant when its temperature remains constant B. gas does work on its environment when its pressure remains constant while its temperature is in creased C. increase in the gas's internal energy is greater when the pressure remains constant than when t he volume remains constant D. heat input per degree increase in temperature is the same in processes for which either the pressure or the volume is kept constant
Whenever the gases are heated at a fixed volume, no outside work is done as well as the heat energy given is simply used to make the gas more energetic internally.
Why is CP for just an ideal gas higher than Cv?The specific heat under constant pressure for an ideal gas, Cp, is higher than Cv.This is due to the fact that when the gas' temperature rises while the pressure stays constant, the gas must perform some finite work on its surroundings.
Does CP always exceed Cpk?When the goal value and the specification's average are equal, Cpk equals Cp.Never can Cpk go above Cp.With the creation of descriptive statistic displays and histograms, Cp and Cpk can both be determined.
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what is the length of the y component shown below?
The length of the y component shown is C. 2.0.
How to find the length ?We are given the angle of the vector, and the length of one of the components of the vetor. Given the angle we have, the available component is the hypotenuse. The y component that we are to find, will then be the opposite or perpendicular component.
To solve for the length of the y - component therefore, the useful operation would be the Sin function.
The length of the y - component would be:
Sin 42 ° = Opposite / Hypotenuse
Sin 42 ° = y component / Hypotenuse
y - component = Sin 42 ° x Hypotenuse
y - component = Sin 42 ° x 3
y - component = 0. 6691 x 3
y - component = 2. 0
In conclusion, the y - component is 2.0.
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Full question is:
What is the length of the y-component of the vector shown below?
A. 2.2 B. 3 c. 2.0 D. 2.7show that the probability density for the ground state solution of the one dimensional coulomb potential energy in the schrodinger equation has its maximum at x=a0
Through Schrodinger equation probability, we can prove that the probability density for the ground state solution of the one dimensional coulomb potential energy in the Schrodinger equation has its maximum at x=a₀.
Given wave function is Ψ(1s) = 1/√π{1/a₀}^(3/2) e ^(x/a₀)
Probability refers to potential. The range of the value is 0 to 1. Mathematics has included probability to forecast the likelihood of certain events. The degree to which something is likely to happen is basically what probability means.
The Schrödinger equation is a linear partial differential equation that describes the wave function or state function of a quantum-mechanical system.
To find the most probable distance, differentiate the equation |Ψ(1s)|²x² with respect to x and equating to zero, we get
d / dr | 1/√π e(1/a₀)^3 / 2e^(-x/a₀) |² x² = 0
1 / π(1 / a₀)³ d / dr (e^-2x / e₀) (x²) = 0
[2e^(-2Zx / a₀) x + e^(-2Zx / a₀) {-2 / a₀} x²] = 0
2 + (-2 / a₀) x = 0
This gives x = a₀
Therefore, through Schrodinger equation probability, we can prove that the probability density for the ground state solution of the one dimensional coulomb potential energy in the Schrodinger equation has its maximum at x=a₀.
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g calculate the mass-to-light ratio for a globular cluster with a luminosity of 106 lsun and 105 stars. (assume that the average mass of a star in such a cluster is 1 msun.)
The mass-to-light ratio for a globular cluster is equal to 137.7 kg/lsun
To measure the mass-to-light ratio of a globular cluster, we first determine the total mass of the cluster. Since the cluster has 105 stars, and the average mass of a star in the cluster is 1 m-sun, therefore, the total mass of the cluster is 10^5 * 1 msun = 10^5 msun.
Now, we convert the luminosity of the cluster from solar units to kilograms. The luminosity of the cluster is given as 10^6 lsun, which is equal to 10^6 * 3.828 x 10^26 W.
Using the equation, [tex]E = mc^2[/tex], we can convert this energy to mass:
[tex]mass = (luminosity * time) / (c^2)[/tex]
where, c is the speed of light (3 x 10^8 m/s) and time is the amount of time over which the luminosity is measured (here, time is equal to 1 second).
Substituting the values in above equation, we find that the mass of the cluster in kilograms is approximately 1.45 x 10^31 kg.
To determine the mass-to-light ratio, divide the total mass of the cluster (in kilograms) by its luminosity (in solar units):
mass-to-light ratio = (total mass of cluster in kg) / (luminosity in solar units)
Substituting the values in above equation, we find that the mass-to-light ratio for this globular cluster is approximately:
1.45 x 10^31 kg / 10^6 lsun = 137.7 kg/lsun.
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Emily and Henry were in the lab and graphed the heating of ice to 125°C. Emily and Brad made an observation that the graph contains three sloped and two level portions. Emily and Brad determined that the two level portions in the graph represented:
The two level portions in the graph represented phase changes.
What are phase changes?
The transition of matter from one state (solid, liquid, gas, or plasma) to another is referred to as a phase change. These changes also take place when the pressure on the system varies, as well as when the system receives enough energy or loses enough energy.
The slope of the line dividing two phases is determined by the relative densities of the two phases. The solid-liquid line, for instance, slopes up and to the right if the liquid is less dense than the solid, whereas up and to the left if the liquid is denser than the solid.
Therefore the two level portions in the graph represented phase changes.
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A mass m is suspended by a massless string forming a simple pendulum of length 2.0 m. The string of the pendulum is initially at an angle of 60° with the vertically downward direction when the mass is released from rest.
The centripetal acceleration of the mass m when it is at the lowest position is 10 m/s². The correct option is A.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any object moving in a circle with an acceleration vector pointing in the direction of the circle's center.
A projectile is an object that is launched into the air and then moves only in response to the acceleration of gravity. The trajectory of the object is referred to as the projectile's trajectory.
The equation of projectile motion is:
[tex]V = \sqrt{2gh}\\\\\\V = \sqrt{2 \times 10 \times \dfrac{1}{2} } \\\\V = \sqrt{20}[/tex]
a² = v² / l = 20 / 2 = 10 m/s²
Therefore, the correct option is A, 10 m/s².
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The question is incomplete. Your most probably complete question is given below:
The centripetal acceleration of the mass m when it is at the lowest position is:
10 m/s²
5 m/s²
20 m/s²
25 m/s²
A small box of mass m is kicked up an inclined plane with an initial velocity v, and slides up the incline a distance L before it stops. The inclined plane makes an angle a with the horizontal, and the friction coefficient is u. What is the distance L the box slides up the ramp before it stops? (Hint: The known quantities are the mass, the initial speed, the angle, the coefficient of friction, and the acceleration of gravity:{m, Vo, a,u,9). Solve for the distance L in terms of these quantities.)
Main Answer:
The distance of L is [tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]
Explanation:
if the block will slide a distance 'L' then syoped;
The initial velocity given to the block is V m/s
So, Total K.E given will goes to gain in potential energy and work done by friction .
K.E=1/2mv^2
P.E at hight (Lsin[tex]\alpha[/tex]) will be = mgh
And work done by the Friction Force is given as = w.r = force*displacement= - uNL= -uMgGcos[tex]\alpha[/tex]L
so,
KE+WD by friction = gain in P.E
[tex]1/2mv^{2} +(-uMgGcos\alpha L)=MgLsin\alpha \\1/2V^{2} =glsin\alpha +uglcso\alpha \\v^{2} /2= Gl(sin\alpha +ucos\alpha )[/tex]
Hence by solving we get :
[tex]v^{2} /2g(sin\alpha +ucos\alpha )[/tex]=L
So the distance = L
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A simple pendulum on Planet X oscillates at 3.1 Hz. If the acceleration due to gravity is 31.3 m/s^2 what is the length of the pendulum in cm?
The length of the pendulum is 8.258 cm .
Given,
Frequency f= 3.1 Hz
Acceleration due to gravity
We have to find out the length of pendulum
L=g / ( 4 x (π)^2 x (f)^2 ) --------------(1)
Where,
L is length
g is acceleration due to gravity
f is frequency
Put the given value in equation (1) becomes
L= (31.3)m/s^2 / (4x (3.14)^2 x (3.1)^2)Hz
L= 31.3 / 379
L = (0.08258) m
L= (8.258)cm
The length of pendulum is
L= (8.258)cm.
The rate by which velocity changes concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
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The length of the pendulum is 8.258 cm .
What is pendulum?
A weight suspended from a pivot such that it can freely swing is called a pendulum. Gravity's restoring force will cause a pendulum to accelerate back toward its equilibrium position if it is sideways moved from its resting, equilibrium position.
Given,
Frequency f= 3.1 Hz
Acceleration due to gravity
We have to find out the length of pendulum
L=g / ( 4 x (π)^2 x (f)^2 ) --------------(1)
Where,
L is length
g is acceleration due to gravity
f is frequency
Put the given value in equation (1) becomes
L= (31.3)m/s^2 / (4x (3.14)^2 x (3.1)^2)Hz
L= 31.3 / 379
L = (0.08258) m
L= (8.258)cm
The length of pendulum is
L= (8.258)cm.
The rate by which velocity changes concerning time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
The pace at which a body's velocity varies is represented by acceleration, which is a vector quantity.
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if you weight 100 pounds on earth,
what would you weight on the moon
Answer: 16 Pounds.
To figure out how much YOU would weigh on the moon, take your weight and divide it by 6. So, if you weighed 100 pounds on Earth, you would weigh only about 16 pounds on the moon.
how does the final temperature of the gas compare with its initial temperature? express your answer using two significant figures. tcta
Step 1: Calculate the ratio of the final and beginning temperatures using the ideal gas law solved for temperature.
Step 2: Calculate the ratio after eliminating any constant values.
Step 3:Solve for the final temperature after substituting the beginning temperature into the ratio.
Perfect Gas Law: According to the ideal gas law, a gas's pressure, P, is inversely proportional to its volume, V, temperature, T, and the number of moles it contains, n, in the sample. The equivalent statement is: For these issues, we'll use the ratio of two temperatures. Because the ratio of starting to end volume and pressure will be the same regardless of the units used to express them, the volume and pressure can be expressed in any form. exhibited in (as long as the initial and final of each are expressed in the same units).PV= nRT
However, for this method to work properly, the temperature must be stated in Kelvin. This is true because Kelvin's zero point is absolute zero. Theoretically, molecules are entirely immobile at 0 Kelvin.
T = PV/nR
The ideal gas law equivalency is used to compute the final temperature in the next two issues.
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explain how doping can increase the conductivity of a semiconductor. match the words in the left column to the appropriate blanks in the sentence on the right.
The left column to the appropriate blanks in the sentence on the right.: The conductivity of semiconductors is increased by adding an appropriate amount of suitable impurity or doping. Doping can be done with an impurity.
A semiconductor is a fabric, which has an electrical conductivity price falling between that of a conductor, including copper, and an insulator, inclusive of glass. Its resistivity falls as its temperature rises; metals behave in the opposite manner.
A semiconductor is a material, which has an electrical conductivity cost falling among that of a conductor, consisting of copper, and an insulator, such as glass. Its resistivity falls as its temperature rises; metals behave in the opposite manner.
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when a man loves a magnetic continually changes magnitude and direction a voltage is continually being induced in the coil this voltage is called voltage
When a magnetic field continually changes magnitude and direction, a voltage is continually induced in the coil. This voltage is called induced voltage.
Induced voltage is the type of voltage that is a product of electromagnetic induction. It is generally defined as the rate of change of magnetic flux with respect to time via a closed circuit.
A wire that is carrying a current will experience an induced voltage along its length if the current changes. The changes in current change the magnetic field flux perpendicular to the wire.
Induced voltage is calculated using the Faradays equation:
e = N(dΦ/dt)
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short 10g rope is used to pull a 50g toy across a horizontal surface without friction. if a force of 3.0 x 10 -2 n is applied horizontally to the free
0.025 N the force of the string on the toy, at the other end of the rope.
What is friction?Friction is a force that resists the relative motion of two objects that are in contact with each other. It is caused by the interaction of the surfaces of the two objects and the molecules that make them up. Friction can be either static or kinetic. Static friction occurs when the two surfaces are not moving relative to each other, while kinetic friction occurs when the two surfaces are moving relative to each other. Friction is a type of force that can be both beneficial and detrimental.
Mass of the string (m) = 10 grams or 10⁻² kg
Mass of the toy (M) = 50 g or 5 x10⁻² kg
Mass of the system = M + m
= 10⁻² + 5 x 10⁻²
= 6 x 10⁻² kg
Force applied (F) = 3.0 x 10⁻² N
Acceleration of toy + string = (0.03/6) x 10⁻²
= 0.5m/s²
Thus force on the toy = 5 x10⁻² x 0.5
= 0.025 N
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The complete question is as follows:
A short 10g string is used to pull a 50g toy across a frictionless horizontal surface. if a 0.03N force is applied horizontally to the free end, the force of the string on the toy, at the other end, is:
In the figure, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.945 m and distance L is 1.95 m. His center of mass is distance d = 0.89 m from the feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
The coefficient of static friction between feet and ground is 0.2522.
What is static friction?Static friction is defined as when there is no motion between the two surfaces, the force that one surface applies to another. The friction that exists between two or more objects when they are not moving relative to one another is referred to as static friction.
The coefficient of static friction between his feet and the ground, denoted by the symbol s, determines how to express the frictional force as
fs =μsFN1
The μs can be calculated as
μs = a / √L² - a² x d / L
μs = 0.945 / √(1.95)² - (0.945)² x 0.89 / 1.95
μs = 0.945 / √2.91225 x 0.89 / 1.95
μs = 0.2522
Thus, the coefficient of static friction between feet and ground is 0.2522.
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During the collision, the car and truck exert forces on each other. Which of the following is a correct statement about these forces and gives evidence to support this statement? The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the truck changes. B The forces the truck and car exert on each other must be external to the truck-car system because the momentum of the car changes. С The forces the truck and car exert on each other must be external to the truck-car system because the momentum of both the truck and car change. D The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same E The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system changes.
The forces the truck and car exert on each other must be internal to the truck-car system because the momentum of the center of mass of the truck-car system stays the same. Option D
What is the Collison?We know that it is possible for an object to be able to bump into another object when this occurs, we would have to apply the law of the conservation of linear momentum. Recall that from the law of the conservation of linear momentum, momentum before collision is equal to the momentum after collision.
We would also have to consider the fact that the weight of the truck is much lager than the weight of the car. The forces that the two vehicles would exert on each other can not be the same. It is clear that the truck is going to exert more force than the car.
With that said, we must have in mind that the total momentum of the system does not change because we are going to approximate the system to function as a closed system.
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What is the Force of Gravity acting on the object in the diagram?
The force of gravity acting on the 23 Kg object in the diagram is 225.4 N
How do I determine the force of gravity?The force of gravity is defined as follow:
Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Using the above formula, we can easily obtain the force gravity acting on the 23 Kg object. This is shown below:
Mass (m) = 23 KilogramsAcceleration due to gravity (g) = 9.8 m/s²Force of gravity (F) =?Force of gravity (F) = mass (m) × acceleration due to gravity (g)
Force of gravity = 23 Kg × 9.8 m/s²
Force of gravity = 225.4 N
Thus, from the calculation made above, we can conclude that the gravitaional force is 225.4 N
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The Sun's evolution from youngest to oldest stage is:
A) white dwarf, red giant, main-sequence, protostar
B) red giant, main-sequence, white dwarf, protostar
C) protostar, red giant, main-sequence, white dwarf
D) protostar, main-sequence, red giant, white dwarf
D) The Sun's evolution from youngest to the oldest stage is protostar, main-sequence, red giant, a white dwarf.
A protostar is the very beginning stage of a star's life. It is a cloud of gas and dust that starts to collapse due to its own gravitational pull. As it collapses, the gas and dust heat up, and eventually, nuclear fusion begins, creating a star.
The main-sequence stage is the longest and most stable period of a star's life. During this stage, the star is converting hydrogen into helium in its core, producing energy and light. This stage can last for billions of years.
Once a star has used up its hydrogen fuel, it enters the red giant phase. This is when the star expands, becoming much larger and much brighter. The star is now converting helium into other elements in its core, such as carbon and oxygen.
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A large water tank with cross sectional area A and height of h is filled to the top with water (density= rho). There is a hole of cross sectional area a located at the bottom of the tank. The velocity of the water exiting the small hole is
A large water tank with cross sectional area A and height of h is filled to the top with water (density= rho). There is a hole of cross sectional area a located at the bottom of the tank. The velocity of the water exiting the small hole will raise to a height and then stop.
what is density?The mass of a substance per unit volume is used to define its density.Mass/Volume is the formula for density.Unit of Density = Unit of Mass/Unit of VolumeSI unit of density equals kg/m3 CGS unit of density equals g/ml (1 cm3 = ml).However, we typically employ g/cm3.A substance's distinctive quality is its density.How tightly a substance's molecules are packed into a specific volume is determined by its density.The amount of mass in a given space is measured as density. It is a means to gauge how small an object is.It is the quantity of molecules present in a space or the mass of matter per unit volume.To learn more about density refer to:
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Calculate the total momentum of the system comprising the two carts and the two people.
Christine and Daemon both have a momentum of 81.69kgm/s
The momentum of the system can now be obtained as 163.38kgm/s.
What is the momentum of the cart and the peopleWe know that momentum is a vector quantity and as such, we know that we must have to look at the direction If we are talking about the vector and this is important to our discussion.
We must note that if we consider the two objects that we have, they are moving in the same direction and as such, the velocity of the momentum of the objects would have to be added accordingly in the way that we work with vector
Then we have;
Total momentum of the system = Momentum of Christine + momentum
Daemon
In order to obtain the total momentum of the system we can now add up and we have;
81.69kgm/s + 81.69kgm/s
= 163.38kgm/s
Thus the combined system would be found to have a momentum of 163.38kgm/s.
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What quantity describes how long an object is moving for?
compare the time it takes for light to travel 1000 m on the surface of the earth and in outer space.
Since light is faster in space, it takes less time for light to travel a distance of 1000m, a time difference of 0.977ns.
Light travels more slowly in a transparent medium than in the vacuum of empty space. The speed of light in any medium (air, water, glass) is determined by the refractive index of the medium. However, this exponent itself may be wavelength dependent (ie different colored rays travel at different speeds). In fact, this is why a prism splits white light into the colors of the rainbow.
The main reason that a light beam slows down in a medium has to do with the fact that the photons, or 'raw light beams', are excited by an electromagnetic field. When the field is in the ground state (vacuum), these excitations actually propagate at the vacuum speed of light. However, when there are positively charged atoms and negatively charged electrons, the electromagnetic field does not go to the ground state. There are many virtual photons. Yes, some of the photons of the passing light beam can be absorbed. After all, no material is completely transparent. But even those who aren't are moving in an environment so different from the vacuum that their paths will be different. It also depends on the structure that the molecule forms.
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Question
A rabbit moves a distance of 85 meters in 13 seconds.
What is the rabbits average speed?
7.26 m/s
0.15 m/s²
6.54 m/s
6.54 m/s²
Important Formula:
[tex]s=\dfrac{d}{t}[/tex]
__________________________________________________________
[tex]d=85m[/tex] (measured in meters)
[tex]t=13s[/tex] (measured in seconds)
[tex]s=?[/tex] (measured in meters per second; m/s)
__________________________________________________________
[tex]s=\dfrac{d}{t}[/tex]
[tex]s=\dfrac{85}{13}[/tex]
__________________________________________________________
[tex]\fbox{6.54 m/s},\fbox{Option C}[/tex]
Determine the momentum of …
a. … an electron (m= 9.1 x10-31 kg) moving at 2.18 x 106 m/s (as if it were in a Bohr orbit in the H atom).
b. … a 0.45 Caliber bullet (m = 0.162 kg) leaving the muzzle of a gun at 860 m/s.
c. … a 110-kg professional fullback running across the line at 9.2 m/s.
d. … a 360,000-kg passenger plane taxiing down a runway at 1.5 m/s
A. The momentum of the electron is 1.98×10⁻²⁴ Kg.m/s
B. The momentum of the Caliber bullet is 139.32 Kg.m/s
C. The momentum of the professional fullback is 1012 Kg.m/s
D. The momentum of the passenger plane is 540000 Kg.m/s
What is momentum?Momentum is defined as the product of mass and velocity. It is expressed mathematically as:
Momentum = mass × velocity
A. How do I determine the momentum of the electron?
Mass of electron = 9.1×10⁻³¹ KgVelocity of electron = 2.18×10⁶ m/sMomentum of electron =?Momentum = mass × velocity
Momentum of electron = 9.1×10⁻³¹ × 2.18×10⁶
Momentum of electron = 1.98×10⁻²⁴ Kg.m/s
B. How do I determine the momentum of the Caliber bullet?
Mass of Caliber bullet = 0.162 KgVelocity of Caliber bullet = 860 m/sMomentum of Caliber bullet =?Momentum = mass × velocity
Momentum of Caliber bullet = 0.162 × 860
Momentum of Caliber bullet = 139.32 Kg.m/s
C. How do I determine the momentum of the professional fullback?
Mass of professional fullback = 110 KgVelocity of professional fullback = 9.2 m/sMomentum of professional fullback =?Momentum = mass × velocity
Momentum of professional fullback = 110 × 9.2
Momentum of professional fullback = 1012 Kg.m/s
D. How do I determine the momentum of the passenger plane?
Mass of passenger plane = 360000 KgVelocity of passenger plane = 1.5 m/sMomentum of passenger plane =?Momentum = mass × velocity
Momentum of passenger plane = 360000 × 1.5
Momentum of passenger plane = 540000 Kg.m/s
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Calibration of a bomb calorimeter is performed with: Select the correct answer below: a. a specific volume of water b. a specific mass of copper c. a reaction with known.
d. manually entered data
A reaction with a known q, such as a measured amount of benzoic acid ignited by a spark from a nickel fuse wire that is weighed before and after the reaction, is used to calibrate bomb calorimeters.
How is a bomb calorimeter calibrated?By releasing a known amount of thermal energy through an electric heater and measuring the subsequent rise in temperature, the calorimeter is calibrated. The energy released when a certain amount (for example, 1 mol, 1 g, or 1 L) of a substance burns entirely in oxygen is known as the heat of combustion.
What type of fuel is the reference fuel for bomb calorimeter calibration?A typical standard used in Bomb calorimeters, which keep a constant volume, is benzoic acid. If. Burning 1.2 g of benzoic acid at a temperature of 24 degrees, with excess oxygen present, releases 31.723 J of energy.
What does calorimeter calibration entail?When calibrating CALORIMETERS, a known electric current is frequently generated inside of them, and the measuring device is then watched for deflection while the system is in a steady condition. Heat loss along the leads through which the calibrating current is injected could be a drawback for this procedure.
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A large cannon is mounted on a cart with frictionless wheels that is initially at rest on a horizontal surface. The cannon fires a large cannonball to the right with a speed v_b which is then caught by a trap firmly attached to the cart. What is the final speed of the cannoncart-cannonball system? V > v_b, to the left
The final velocity of the cannonball-cart system is less than the initial velocity of the cannonball and the system will move in the direction of the cannonball ( V < v_b ).
What is the law of conservation of linear momentum?
The law of conservation of linear momentum states that the sum of the initial momentum is equal to sum of the final momentum, provided that the system is Isolated.
Mathematically, the law of conservation of linear momentum is given as;
Pi = Pf
where;
Pi is the sum of the initial momentumPf is the sum of the final momentumm₁u₁ + m₂u₂ = v ( m₁ + m₂ )
where;
m₁ is the mass cannon ballu₁ is the initial velocity of the cannon ballm₂ is the mass of the cartu₂ is the initial velocity of the cartv is the final velocity of the cannoncart-systemsince the cart is initially at rest, the initial velocity of the cart = 0
m₁u₁ + 0 = v ( m₁ + m₂ )
m₁u₁ = v ( m₁ + m₂ )
v = ( m₁u₁ ) / ( m₁ + m₂ )
given initial velocity of the cannon ball = v_b
The final velocity of the cannonball-cart system is calculated as follows;
V = ( m₁v_b ) / ( m₁ + m₂ )
Hence, V < v_b
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(a) A Carnot engine working in a forward direction (i.e. taking heat from a hot body and rejecting remaining heat after work to a cold body) is a heat engine. Therefore the engine to be used as a heat engine operates in a direction. as it is in contact with the heat reservoir during this segment; and, as its is in contact with cold sink.
A heat engine, symbolized by a circle in this illustration, uses some of the heat transfer to produce work.
The most effective heat engine that is theoretically possible—i.e., any machine that can transform thermal energy (heating) into mechanical energy—is the Carnot engine (work).The heat and cold reservoirs are the names given to the hot and cold items. Only the hot temperatures' absolute values affect efficiency. A portion of the heat QH that is extracted from the high-temperature source TH in the case of a heat engine is transformed into work. The ratio of net work completed to heat absorbed throughout one full cycle is known as a heat engine's thermal efficiency.
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