Two long parallel wires placed side by side on a horizontal table carry the same currents in opposite directions. The wire on your right carries current toward you, and the wire on your left carries current away from you. Determine the direction of the magnetic field at the point exactly midway between the two wires from your point of view. Explain your answer with the aid of labelled diagram. [5 marked
Answers
To find:-
Magnetic field at the centre between the wires.Answer:-
We are here given that two long current carrying wires are having same current. We need to find out the magnetic field at the centre between the wires .
We know that for a point between two ends of a wire , magnetic field is given by,
[tex]\implies B =\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}\\[/tex]
where ,
B is magnetic field.i is the current.d is the distance .Now since magnetic field is a vector quantity we need to find out the direction of the field . We can do so by using Right Hand thumb rule .
Right hand thumb rule :-
Hold the wire , in your hand with thumbs towards the direction of the current, then the curling of the fingers would give you the direction of the magnetic field.
For wire AB :-
The direction comes to be down the page .
For wire CD :-
The direction comes to be down the page .
Calculating net magnetic field:-
The net magnetic field will be the sum of both the fields .
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{2i}{d}+\dfrac{\mu_0}{4\pi}\dfrac{2i}{d} \\[/tex]
[tex]\implies B_{net}=\dfrac{\mu_0}{4\pi}\dfrac{4i}{d}\\[/tex]
[tex]\implies \underline{\underline{\green{ B_{net}=\dfrac{\mu_0i}{ \pi d}}}}\\[/tex]
The direction is down the page .
and we are done!
Related Questions
125cm³ of a gas was collected at 15 °C and 755 mm of mercury pressure. Calculate the volume of the gas that will be collected at standard temperature and pressure
Answers
Answer:
119,2 см³
Explanation:
по формуле Клопейрона (P1×V1):T1=(P2×V2):T2
если из этой формулы найти V2, ответ будет равен примерно на 119,2 см³
Two pieces of clay, one white and one gray, are thrown through the air. The
m
white clay has a momentum of 25 kg, and the gray clay has a
S
momentum of -30 kg immediately before they collide.
What is the magnitude and direction of their final momentum immediately
after the collision?
Your answer should have one significant figure.
h
kg.
m
-
m
S
S
Answers
we can't give a specific direction for the final momentum.
What is momentum?
Momentum is a physical quantity that describes the motion of an object. It is defined as the product of an object's mass and its velocity. Mathematically, momentum is expressed as:
Momentum (p) = mass (m) x velocity (v)
p = m x v
To solve this problem, we need to apply the law of conservation of momentum, which states that the total momentum of a system remains constant if no external forces act on it.
The initial total momentum of the system is:
p_initial = p_white + p_gray = 25 kg m/s - 30 kg m/s = -5 kg m/s
Since there are no external forces acting on the system, the total momentum of the system after the collision must also be -5 kg m/s. Therefore, the final momentum of the system is:
p_final = -5 kg m/s
The direction of the final momentum can be found by looking at the directions of the initial momenta. Since the white clay has positive momentum and the gray clay has negative momentum, we can say that the white clay is moving to the right and the gray clay is moving to the left before the collision.
During the collision, the two clays will exert forces on each other, causing them to change direction and possibly even break apart. Without more information about the collision, we can't say for sure what the direction of the final momentum will be. It could be to the left or to the right, or some combination of the two. Therefore, we can't give a specific direction for the final momentum.
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Estimat the number and wattage of lamps. which would be required to illuminate a workshop space 60x1.5 meteres by means of lamps mounted 5 metres above the working Plane The average illumination required is about 100 wt. coefficient of utilisation = 0.4 luminous efficiency 16 lumens per watt. Assume a space-height ratio of unity and a cundle Power depreciation of 20%
Answers
The number and wattage of lamps required to illuminate the workshop would be approximately 8 lamps and 70 watts respectively.
Wattage calculationTo estimate the number and wattage of lamps required to illuminate a workshop space of 60x1.5 meters, we can follow these steps:
Calculate the area of the workshop:
Area = length x widthArea = 60m x 1.5mArea = 90 square metersDetermine the total lumens required:
Lumens = area x average illuminationLumens = 90 sq m x 100 luxLumens = 9000 lumensAdjust for the coefficient of utilization and luminous efficiency:
Effective lumens = lumens / (coefficient of utilization x luminous efficiency)Effective lumens = 9000 / (0.4 x 16)Effective lumens = 1406.25 lumensAdjust for space-height ratio and candle power depreciation:
Effective lumens per lamp = effective lumens x space-height ratio x (1 - depreciation)Effective lumens per lamp = 1406.25 x 1 x (1 - 0.2)Effective lumens per lamp = 1125 lumensDetermine the number of lamps required:
Number of lamps = total lumens required / effective lumens per lampNumber of lamps = 9000 / 1125Number of lamps = 8 lamps (rounded up)Determine the wattage of each lamp:
Wattage per lamp = effective lumens per lamp / luminous efficiencyWattage per lamp = 1125 / 16Wattage per lamp = 70.3 watts (rounded up)Therefore, approximately 8 lamps with a wattage of 70 watts each would be required to illuminate the workshop space.
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3. Large amplitude vibrations produced when the of receiver of the applied forced vibration matches the
Answers
An object's amplitude dramatically increases when the frequency of the applied forced vibrations matches the object's natural frequency. Resonance describes this behavior.
Theory A wave's amplitude directly relates to the quantity of energy it can carry. A wave with a high amplitude carries a lot of energy, whereas one with a low amplitude carries only a little. A wave's strength is determined by the typical energy that moves through a given area in a certain amount of time and in a particular direction.The sound wave's amplitude grows in proportion to its strength. We perceive louder noises to be of higher intensity. Comparative sound intensities are frequently expressed using decibels (dB)For more information on amplitude of vibration kindly visit to
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A metal wire, fixed at one end, has length l and cross-sectional area A. The wire extends a distance e which mass m is hung from the other end of the wire.What is an expression for the Young Modulus E of the metal?
Answers
The expression for the Young Modulus E of the metal is E = mgl / Ae. The Young Modulus E of the metal is calculated using the equation E = (F l) / (A e2 m), where F is the force applied to the wire.
To find the expression for the Young modulus E of a metal wire with length l, cross-sectional area A, and mass m hung from the other end of the wire, we need to use the following formula:Stress (σ) = Load (F) / Area (A)Strain (ε) = Extension (Δl) / Original length (l)Young Modulus (E) = Stress (σ) / Strain (ε)We know that the metal wire is fixed at one end and the wire extends a distance e when a mass m is hung from the other end of the wire. Therefore, the extension Δl is equal to e.
Let's assume that g is the acceleration due to gravity. Therefore, the load F is equal to m * g.Substituting the values of F, A, and Δl in the above formula, we get:Stress (σ) = F / A = (m * g) / AStrain (ε) = Δl / l = e / lYoung Modulus (E) = Stress (σ) / Strain (ε)= (m * g) / (A * e / l) = mgl / AeTherefore, an expression for the Young Modulus E of the metal is E = mgl / Ae.
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A beam consisting of five types of ions labeled A, B, C, D, and E enters a region that contains a uniform magnetic field as shown in the figure below. The field is perpendicular to the plane of the paper, but its precise direction is not given. All ions in the beam travel with the same speed. The table below gives the masses and charges of the ions. Note: 1 mass unit = 1.67 x 10â€"27 kg and e = 1.6 x 10â€"19 C
Which ion falls at position 2?
Answers
At position 2, ion B falls. It is less deflected because it has a lesser mass than ions C, D, and E and the same charge as ion A.
A force perpendicular to the charged particle's velocity and the magnetic field's direction is applied when it reaches the magnetic field. The right-hand rule asserts that the palm will face the direction of the force if the thumb of the right hand points in the direction of the particle's velocity and the fingers point in the direction of the magnetic field. The particle's charge, velocity, and magnetic field intensity all affect how much force is generated.
Since all ions are moving at the same speed in this scenario, the force exerted on each ion is proportional to its charge to mass ratio. Ion B has the smallest mass of all the ions, so the least force and is least deflected of the ions, falling at position 2.
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