Two shaded identical rectangular decorative tiles are first placed (one each) at the top and at the base of a door frame for a hobbit's house, as shown in Figure 1. The distance from W to H is 45 inches. Then the same two tiles are rearranged at the top and at the base of the door frame, as shown in Figure 2. The distance from Y to Z is 37 inches. What is the height of the door frame, in inches?

Answer:

22.5

Step-by-step explanation:

im smart

Beaky bought 13 yards of striped fabric and 9.5 yards of checkered fabric.

Given that,
Becky is buying fabric to make new pillows for her couch. She spends $71.50 on striped fabric and $52.25 on checkered fabric.

In mathematics, it deals with numbers of operations according to the statements. There are four major arithmetic operators, addition, subtraction, multiplication and division,

Here,
Both fabrics cost $5.50 per yard, how many total yards of fabric she buys is to be determined so,
Divide the total cost of the fabric by the cost per yard of $5.50,
Striped fabric = 71.50 / 5.50 = 13 yards
checkered fabric = 52.25/71.50 = 9.5 yards

Thus, beaky bought 13 yards of striped fabric and 9.5 yards of checkered fabric.

Learn more about arithmetic here:

https://brainly.com/question/11424589

#SPJ5

Answer:

C is a function

Step-by-step explanation:

We can use the vertical line test.  If a vertical straight lines passes through the graph more than one, it is not a function

A and B are not functions

C is a function

Answer:

25[tex]\sqrt{3}[/tex] +60

Step-by-step explanation: The first thing you need to do is realize that, this figure is a isosceles trapezoid due to the markings on each side.

So now we know both sides are 10.

We also know the the top two angles are congruent to each other and so are the bottom two angles due to the trapezoid being isosceles.

So the top two angles are 120 degrees and bottom two angles are 60 degrees.

It seems like we can't find the sides, let's try drawing two lines from each top angle all the way down to form two right triangles.

Wow, these two triangles are special right triangles in the form of

30 - 60 - 90 degrees.

shorter side = n

longer side = n[tex]\sqrt{3}[/tex]

hypotenuse = 2n

So, 2n = 10

n = 5 for the short side

The bottom base is 4[tex]\sqrt{3}[/tex] + 5 + 5 = 10 + 4[tex]\sqrt{3}[/tex]

The longer side is  5[tex]\sqrt{3}[/tex].

The area of trapezoid = (base1 + base2)/2 * height

= (4[tex]\sqrt{3}[/tex] + 10 + 4[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (10 + 8[tex]\sqrt{3}[/tex])/2 * 5[tex]\sqrt{3}[/tex] = (5+4[tex]\sqrt{3}[/tex])*5[tex]\sqrt{3}[/tex] = 25[tex]\sqrt{3}[/tex] +60

So, 25[tex]\sqrt{3}[/tex] + 60 is our answer.

Answer:

  60 +25√3

Step-by-step explanation:

In the figure of the isosceles trapezoid below, the angles at C and D are supplementary to the given angle, so are 60°. That makes triangle BDE a 30°-60°-90° right triangle, which has side length ratios ...

  DE : BE : BD = 1 : √3 : 2 = 5 : 5√3 : 10

Triangle BDE can be relocated to the other end of the figure to become triangle CAD'. Then the area of concern is that of the rectangle with height 5√3 and length 5+4√3. The area is then ...

  Area = lh = (5√3)(5 +4√3) = 5·5√3 +5·4·3

  Area = 60 +25√3 . . . square units

_____

In the figure, 6.93 = 4√3, and 8.66 = 5√3, 16.93 = 10+4√3.

Answer:

a) 2 h 45 min

b) 2 h 50 min

c) 2 h 20 min

d) 3 h 20 min

Step-by-step explanation:

Answer:

a) hours: 9 hours 15 minutes

minutes: 555

b) hours: 9hours 10 minutes

minutes: 550

c) hours: 2hours 20 minutes

minutes: 140

d) hours: 3 hours 20 minutes

minutes: 200

Step-by-step explanation:

Answer:

x=36

Step-by-step explanation:

180-x=180-2x +180-4x

180-x = 360 -6x

5x =180

36 = x

Answer:

See below.

Step-by-step explanation:

[tex]\cos(20)-\sin(20)=\sqrt{2}\sin(25)[/tex]

First, use the co-function identity:

[tex]\sin(90-x)=\cos(x)[/tex]

We can turn the second term into cosine:

[tex]\sin(20)=\sin(90-70)=\cos(70)[/tex]

Substitute:

[tex]\cos(20)-\cos(70)=\sqrt{2}\sin(25)[/tex]

Now, use the sum to product formulas. We will use the following:

[tex]\cos(x)-\cos(y)=-2\sin(\frac{x+y}{2})\sin(\frac{x-y}{2})[/tex]

Substitute:

[tex]\cos(20)-\cos(70)=-2\sin(\frac{20+70}{2})\sin(\frac{20-70}{2})\\\cos(20)-\cos(70) =-2\sin(45)\sin(-25)\\\cos(20)-\cos(70)=-2(\frac{\sqrt{2}}{2})\sin(-25)\\ \cos(20)-\cos(70)=-\sqrt{2}\sin(-25)[/tex]

Use the even-odd identity:

[tex]\sin(-x)=-\sin(x)[/tex]

Therefore:

[tex]\cos(20)-\cos(70)=-\sqrt{2}\sin(-25)\\\cos(20)-\cos(70)=-\sqrt{2}\cdot-\sin(25)\\\cos(20)-\cos(70)=\sqrt{2}\sin(25)[/tex]

Replace the second term with the original term:

[tex]\cos(20)-\sin(20)=\sqrt{2}\sin(25)[/tex]

Proof complete.

Answer:

8

Step-by-step explanation:

x+37+x+37+90 = 180

2x + 74 = 90

2x = 16

x = 8

Answer:

x=8°

Step-by-step explanation:

JI is a diameter and K is on the circumference of a circle.

∴∠JKI=90°

also KJ=KI=x(say)

tan (x+37)=y/y=1=tan 45

so x+37=45

x=45-37=8°

Answer:

Step-by-step explanation:

Let y(t) be the amount of salt in the tank after time t.

(A) Incoming rate = 0 (due to Pure water having no salt)

(B) Mixed solution comes out at 150 L/min. Initially the tank has 15,000 L of brine with 24 kg of salt.

concentration of salt at time t  = y(t) / 15000 kg/L

Outgoing rate = y(t)/15000 * 150 = y(t) / 100

(C) we know that,

[tex]\frac{dy}{dx} =(incoming\ rate) - (outgoing\ rate)[/tex]

[tex]\frac{dy}{dx} =0-\frac{y(t)}{100} = \frac{-y(t)}{100}[/tex]

Separate variable and integrate

[tex]\int {\frac{dy}{y} } = - \int {\frac{1}{100} } \, dt[/tex]

[tex]ln|y|=-\frac{1}{100}t + D[/tex]

[tex]y=e^{D} e^{\frac{-t}{100} }[/tex]

[tex]y= Ce^{\frac{-t}{100} }\ [C=e^{D} ][/tex]

At t= 0 , y(0) = 24 kg

[tex]24=C\ e^{0}[/tex]

C= 24

(D) Therefore, the amount of salt in the tank after time t :

[tex]y(t)=24e^{\frac{-t}{100} }\ kg[/tex]

=====================================================

Explanation:

The double tickmarks for quadrilateral MATH show that MA = TH. Since TH is 5 units long, this makes MA the same length as well.

For quadrilateral ROKS, we have RO = 15. For "MATH" and "ROKS" we have "MA" and "RO" as the first two letters of each four-letter sequence; meaning that MA and RO correspond together.

The ratio of the corresponding segments is RO/MA = 15/5 = 3.

The larger quadrilateral has each side length 3 times longer than the smaller quadrilateral's corresponding side lengths.

--------------

In short,

larger side = 3*(smaller side)

--------------

Using this scale factor of 3, we can find MH

larger side = 3*(smaller side)

RS = 3*(MH)

21 = 3*MH

3*MH = 21

MH = 21/3

MH = 7

Answer:

55.5 ÷ 100 = 0.555

Step-by-step explanation:

When you ask, "What is 55.5 as a decimal?", we assume you want to know what 55.5 percent is as a decimal. In other words, 55.5 percent converted to decimal.

First, we will tell you why it is useful to know 55.5 as a decimal.

Normally, to calculate 55.5 percent, you would multiply a number by 55.5 percent and then you would take the product of that and divide it by 100 to get the answer.

Instead, you can simply multiply a number by 55.5 as a decimal to get the answer.

55.5 percent means 55.5 per hundred. Therefore, to get 55.5 as a decimal, all you have to do is divide 55.5 by 100 like so:

55.5 ÷ 100 = 0.555

Answer:

55.5% = 0.555

Step-by-step explanation:

55.5% = 55.5/100 = 0.555

Answer:

Identity Property of Multiplication

Step-by-step explanation:

The Identity Property of Multiplication states that any number multiplied by 1 will equal the same number.

Since we have one item that costs $14.50, we know that the total cost will be $14.50 since we are multiplying $14.50 by 1.

Hope this helped!

Answer:

Identity property of multiplication.

Step-by-step explanation:

When we multiply any number by 1, we will get the same number.

5 *1 = 5

-8 * 1 = -8

Answer:

Daily pay= $18

5 days pay = $90

Step-by-step explanation:

Archer's daily pay =p

Pay for 5 days= 5p

Gas = 1/2 of 5p

= 1/2 × 5p

= 5p/2

Water = $5

Balance = $40

5p = 5/2p + 5 + 40

5p - 5/2p = 45

10p -5p /2 = 45

5/2p = 45

p= 45÷ 5/2

= 45 × 2/5

= 90/5

P= $18

5p= 5 × $18

=$90

The equation to determine Archer's daily pay is

5p = 5/2p + 5 + 40

Divide both sides by 5

p = 5/2p + 45 ÷ 5

= (5/2p + 45) / 5

p= (5/2p + 45) / 5

Answer:

[tex]\large \boxed{\sf \bf \ \ x^2-6x+45 \ \ }[/tex]

Step-by-step explanation:

Hello, please consider the following.

You need to develop the expression.

[tex]y=(x-3)^2+36\\\\=x^2-2 * 3 * x +3^2+36\\\\=x^2-6x+9+36\\\\=x^2-6x+45[/tex]

Thank you.

Answer:

D

Step-by-step explanation:

Answer:

√137

Step-by-step explanation:

[tex](x_1, y_1) = (6, 0)\\(x_2, y_2) = (-5, 4)\\\\d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} \\d = \sqrt{(-5-6)^2+(4-0)^2}\\ d = \sqrt{(-11)^2+(4)^2}\\ d = \sqrt{121+16}\\ d = \sqrt{137}\: or \:11.7[/tex]

Answer:

Scouts are on the third side in the sense they are running

Step-by-step explanation:

A regular hexagonal shape of perimeter 270 has each side of                 270/6 = 45  

Let´s call d  the run distance  then

d = 2/5 * 270      d = 108 m

We don´t have fig 9 available therefore if  X is a vertex in the hexagon or at the middle point of one side, scouts are 108 m from the starting point which means they had run 2,4 sides of the hexagon. If X is not either a vertex or a middle point of a side then, we have two solutions for the question depending on the sense the scouts took when began the run (clockwise or counterclockwise)

Answer:

Step-by-step explanation:

The diagonals of the rhombus divide it into 4 congruent right triangles.

So we can use Pythagorean theorem to calculate side of a rhombus.

[tex](\frac e2)^2+(\frac f2)^2=s^2\\\\e=30\,cm\quad\implies\quad\frac e2=15\,cm\\\\f=16\,cm\quad\implies\quad\frac f2=8\,cm\\\\15^2+8^2=s^2\\\\s^2=225+64\\\\s^2=289\\\\s=17[/tex]

Perimeter:

P = 4s = 4•17 = 68 cm

Answer:

Step-by-step explanation:

9 = m/3 + 4

5 = m/3

m = 15

Answer: m=15

Step-by-step explanation:

[tex]9=\frac{m}{3}+4[/tex]

subtract 4 on both sides

[tex]\frac{m}{3}+4-4=9-4[/tex]

[tex]\frac{m}{3}=5[/tex]

multiply 3 on both sides

[tex]\frac{3m}{3}=5\cdot \:3[/tex]

[tex]m=15[/tex]

Answer:

<4=<2

x+30=2x+15

x=15

therefore <4=(15)+30

=45°

Answer:

27500

Step-by-step explanation:

meters are 100 times more than kilometers hope this helps:)

Answer:

1

Step-by-step explanation:

split the shape to triangle and a rectangle

the rectangle at the original trapezoid has 2 squares in width and 3 squares for height multiply those numbers by 1/2 you will get 1 square for width and 1.5 squares for the height which is showen in option 1

━━━━━━━☆☆━━━━━━━

▹ Answer

Y = 1

▹ Step-by-Step Explanation

[tex]\frac{10}{2} = \frac{5}{y} \\\\10/5 = 2\\2/2 = 1\\\\Y =1[/tex]

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

16 feet.

Step-by-step explanation:

Please refer to the attached diagram for the clear understanding of the given question statement.

A is the position of tour guide on deck.

B is the sea level. (Can be considered as zero on the number line)

C is the position of Diver and

D is the point on ocean floor.

Below sea level dimensions are given as negative in the question statement.

As per given statement,

AB = 5 feet

BC = 11 feet (Ignoring the negative sign as negative sign only depicts that it is below sea level)

BD = 18 feet

To find:

Distance from tour guide to the diver = ?

Solution:

We have to actually find the value of AC here as per the image attached.

AC = AB + BC = 5 + 11 = 16 feet

Answer:

D. 1 real; 4 complex  

Step-by-step explanation:

1. Calculate the total number of roots

The fundamental theorem of algebra states that any polynomial of degree n has n roots.

Your polynomial is fifth degree, so it has five roots.

2. Calculate the number of real roots

We can use Descartes' rule of signs to determine the number of real roots:

The number of positive real roots is the same as the number of changes in the sign of the coefficients of ƒ(x) or less than by an even number.

The number of negative real roots is the same as the number of changes in sign of the coefficients of the terms of f(-x) or less than this by an even number.

(a) Number of positive real roots

The coefficients of ƒ(x) are

+1 +3 +8 +14 +16 + 8  

There are no changes of sign, so there are no positive real roots.

(b) Number of negative real roots

(i) Find f(-x)

f(-x) = -x⁵+ 3x⁴ - 8x³ + 14x² - 16x + 8

(ii) Count the changes of sign

The coefficients of f(-x) are

-1 ∥ +3 ∥ -8 ∥+14 ∥ -16 ∥ +8

There are five changes of sign.

Thus, the number of negative roots is five, three, or one.

So far, we know that we have five roots. None is positive, and there could be one, three, or five negative real roots.

3. Confirm by sketching the graph

The real roots are the points at which the graph crosses or touches the x-axis.

The graph (see below) crosses the x-axis at only one point.

Thus. we have

Answer:

3(6)

??

Step-by-step explanation:

Answer:

  9 square units

Step-by-step explanation:

The function f(x) describes a parabola opening downward, with a vertex at (3, 9). The maximum value of f(x) is found at the vertex, where it is f(3) = 9.

The maximum area is 9 square units.

Answer:

9 c

Step-by-step explanation:

[tex]\displaystyle f(x)=\sin(3x)\\\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3(x+h))-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{\sin(3x+3h)-\sin(3x)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{3x+3h+3x}{2}\right)\sin\left(\dfrac{3x+3h-3x}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{h}\\\\f'(x)=\lim_{h\to0}\dfrac{2\cos\left(\dfrac{6x+3h}{2}\right)\sin\left(\dfrac{3h}{2}\right)}{\dfrac{3h}{2}}\cdot\dfrac{3}{2}[/tex]

[tex]\displaystyle f'(x)=\lim_{h\to0}2\cos\left(\dfrac{6x+3h}{2}\right)\cdot\dfrac{3}{2}\\\\f'(x)=\lim_{h\to0}3\cos\left(\dfrac{6x+3h}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x+3\cdot 0}{2}\right)\\\\f'(x)=3\cos\left(\dfrac{6x}{2}\right)\\\\f'(x)=3\cos(3x)[/tex]

The derivative of sin 3x using first principles is; 3cos(3x)

We want to find the derivative of sin 3x using first principles.

Step 1;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin3(x + h)) - sin(3x)}{h}[/tex]

Step 2; Expand the bracket to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{(sin(3x + 3h)) - sin(3x)}{h}[/tex]

Step 3: According to trigonometric identities, we know that;

sin A - sin B = [tex]2cos\frac{A + B}{2} sin\frac{A - B}{2}[/tex]

Applying that to the answer in step 2 gives;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(3x + 3h + 3x)}{2}) sin\frac{(3x + 3h - 3x)}{2})}{h}[/tex]

Step 4; Simplify the brackets to obtain;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{h}[/tex]

Step 5; Rewrite the denominator to get;

f'(x) = [tex]\lim_{h \to \ 0} \frac{2(cos\frac{(6x + 3h)}{2}) sin\frac{(3h)}{2})}{\frac{3h}{2}*\frac{2}{3}}[/tex]

Step 6; Input the limit of 0 for h to get;

f'(x) = [tex]\frac{2(cos\frac{(6x)}{2}) sin\frac{(0)}{2})}{\frac{0}{2}*\frac{2}{3}}[/tex]

⇒ f'(x) = [tex]\frac{2(cos3x)}{2/3} \frac{ 0}{{0}}[/tex]

0/0 = 1. Thus;

f'(x) = 3cos(3x)

Read more about differentiation from first principles at; https://brainly.com/question/5313449

Answer:

6:30 pm

Step-by-step explanation:

Given the following :

Four machines give out a signal at intervals of 24 seconds, 27 seconds, 30 seconds and 50 seconds respectively.

Time when all four machines gave out signal simultaneously = 5:00 pm

To find the time all four will give out the next simultaneous signal :

Take the lowest common factor of the four intervals :

L. C. M of 24, 27, 30, 50

Using the Lowest Common Multiple calculator :

L. C. M. = 5400

5400 seconds.

Adding 5400 seconds to the last time a simultaneous signal was produced :

5:00 pm + 5400 seconds

5400 seconds = (5400/60) = 90 minutes = 1hour 30 minutes

5:00 pm + (1 hour 30 minutes)

= 6:30 pm

Greetings from Brasil...

In this case, we can say:

Domain = [0; 6]

Image = [3; 192]

see attachment

Answer:

768 libras de fuerza

Step-by-step explanation:

Tenemos que encontrar la ecuación que los relacione.

F = Fuerza necesaria para evitar que el automóvil patine

r = radio de la curva

w = peso del coche

s = velocidad de los coches

En la pregunta se nos dice:

La fuerza requerida para evitar que un automóvil patine alrededor de una curva varía inversamente con el radio de la curva.

F ∝ 1 / r

Y luego con el peso del auto

F ∝ w

Y el cuadrado de la velocidad del coche

F ∝ s²

Combinando las tres variaciones juntas,

F ∝ 1 / r ∝ w ∝ s²

k = constante de proporcionalidad, por tanto:

F = k × w × s² / r

F = kws² / r

Paso 1

Encuentra k

En la pregunta, se nos dice:

Suponga que 400 libras de fuerza evitan que un automóvil de 1600 libras patine alrededor de una curva con un radio de 800 si viaja a 50 mph.

F = 400 libras

w = 1600 libras

r = 800

s = 50 mph

Tenga en cuenta que desde el

F = kws² / r

400 = k × 1600 × 50² / 800

400 = k × 5000

k = 400/5000

k = 2/25

Paso 2

¿Cuánta fuerza evitaría que el mismo automóvil patinara en una curva con un radio de 600 si viaja a 60 mph?

F = ?? libras

w = ya que es el mismo carro = 1600 libras

r = 600

s = 60 mph

F = kws² / r

k = 2/25

F = 2/25 × 1600 × 60² / 600

F = 768 libras

Por lo tanto, la cantidad de fuerza que evitaría que el mismo automóvil patine en una curva con un radio de 600 si viaja a 60 mph es de 768 libras.

Answer:

25 + 10h = 50+5h

Step-by-step explanation:

Black Diamond Ski Resort

25 + 10h

Bunny Hill Ski Resort

50+5h

We want when they are equal

25 + 10h = 50+5h

Answer:

10x + 25 = 5x + 50

Step-by-step explanation: