Answer:
She added the exponents instead of subtracting them.
Step-by-step explanation:
Angles 1 and 2 are supplementary. 2 lines intersect to form angles 1 and 2. Which equation represents the relationship between their measures?
Answer:
[tex]\angle 1 + \angle 2 = 180^o[/tex]
Step-by-step explanation:
Given
[tex]\angle 1[/tex] and [tex]\angle 2[/tex]
Required
The relationship between them [tex]\angle 1[/tex] and [tex]\angle 2[/tex]
From the question, we understand that [tex]\angle 1[/tex] and [tex]\angle 2[/tex] are supplementary
Supplementary angles add up to 180.
So, the relationship between [tex]\angle 1[/tex] and [tex]\angle 2[/tex] is:
[tex]\angle 1 + \angle 2 = 180^o[/tex]
Two terms of a geometric sequence are given. Find the first five terms. Please help asap
Answer:
4, 8, 16, 32, 64
Step-by-step explanation:
The nth term of a geometric sequence is
[tex]a_{n}[/tex] = a₁[tex](r)^{n-1}[/tex]
Given
a₇ = 256 and a₁₀ = 2048 , then
a₁ [tex]r^{6}[/tex] = 256 → (1)
a₁ [tex]r^{9}[/tex] = 2048 → (2)
Divide (2) by (1)
[tex]\frac{a_{1}r^{9} }{a_{1}r^{6} }[/tex] = [tex]\frac{2048}{256}[/tex]
r³ = 8 ( take the cube root of both sides )
r = [tex]\sqrt[3]{8}[/tex] = 2
Substitute r = 2 into (1)
a₁ × [tex]2^{6}[/tex] = 256
a₁ × 64 = 256 ( divide both sides by 64 )
a₁ = 4
Then
a₁ = 4
a₂ = 2a₁ = 2 × 4 = 8
a₃ = 2a₂ = 2 × 8 = 16
a₄ = 2a₃ = 2 × 16 = 32
a₅ = 2a₄ = 2 × 32 = 64
First, find the length of each edge of the cube.
Then, find the volume.
since in a cube length, width and height are equal,
h = 6
w = 6
l = 6
and volume is 6³ = 216cm³
hope it helps :)
Which is true about the solution to the system of inequalities shown?
y > 3x + 1
y < 3x – 3
they don't share any points
that's one thing, but I don't know what your options are of course.
see screenshot for illustration of the inequalities
What is the solution set to this equation?
log_4(x + 3) + log_4x = 1
Answer:
x=1
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
We know that loga(b) + loga(c) = loga(bc)
log_4(x + 3)x = 1
Raise each side to the base of 4
4^log_4(x + 3)x = 4^1
(x+3)x = 4
x^2 +3x = 4
Subtract 4 from each side
x^2 +3x -4 = 0
Factor
(x+4) (x-1) =0
Using the zero product property
x= -4 x=1
But x cannot be negative since logs cannot be negative
x=1
Answer:
A.. x = 1.
Step-by-step explanation:
log_4(x + 3) + log_4x = 1
log_4 x(x + 3) = log_4 4
Removing the logs:
x(x + 3) = 4
x^2 + 3x - 4 = 0
(x + 4)(x - 1) = 0
x = 1, -4.
We can ignore the -4 as there is no log of a negative.
The cube with side 2 is cut from the corner of rectangular prism with dimensions 4×3×5. Find the volume and total surface area of the new object.
Answer:
Volume: 52 Units Squared
Surface Area: 94 units.
Step-by-step explanation:
The volume is relatively simple to find. Just subtract the original volume by the 2x2x2 cube's volume. The original volume is 60. The cube's volume is 2x2x2 which is 8. 60-8=52.
The surface area is harder to find. Try to envision the corner of the rectangle being cut out. We see that each side of the cube has a surface area of 2x2 which is 4. In the picture, we see that three sides of the rectangle has been partially removed. But since each side of the cube has an equal surface area, it is safe to minus 3 of the sides that has been partially removed by 3. However, since that it is the corner, the "dent" that the cube made in the rectangle also needed to be counted. As we said, each of the sides of a cube has a surface area of 4, so since that the dent has 3 sides, we see that the surface area of the dent is 4x3 which is 12. Now we need to count the unaffected sides of the rectangle. There are three of them. Just multiply the edges to find the surface area of each side. Add all of the values up: 11+16+12+8+15+12+20=94 units.
How would I do this??
Part 1
[tex]\left(\frac{g}{h}\right)(x) = \frac{g(x)}{h(x)}\\\\\left(\frac{g}{h}\right)(x) = \frac{3x-5}{-2x^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{3(3)-5}{-2(3)^2+7}\\\\\left(\frac{g}{h}\right)(3) = \frac{4}{-11}\\\\\left(\frac{g}{h}\right)(3) = -\frac{4}{11}\\\\[/tex]
Answer: -4/11
====================================================
Part 2
Set the denominator function equal to zero and solve for x to find which values to kick out of the domain.
[tex]h(x) = 0\\\\-2x^2+7 = 0\\\\7 = 2x^2\\\\2x^2 = 7\\\\x^2 = 7/2\\\\x^2 = 3.5\\\\x = \sqrt{3.5} \ \text{ or } x = -\sqrt{3.5}\\\\[/tex]
This shows that if x is equal to either of those values, then the denominator h(x) will be zero. These are the values to kick out of the domain to prevent a division by zero error. Any other value of x is valid in the domain.
Answer: [tex]x = \sqrt{3.5} \text{ and } x = -\sqrt{3.5}\\\\[/tex]
If 4 tickets to a show cost $17.60, what is the cost of 7 such tickets.
Answer:
30.80
Step-by-step explanation:
We can use a ratio to solve
4 tickets 7 tickets
------------------- = ----------------
17.60 dollars x dollars
Using cross products
4x = 17.60 * 7
4x =123.2
Divide each side by 4
4x/4 = 123.2/4
x=30.8
A square has an area of 49 cm squared what is the length of each side
Answer:
7
Step-by-step explanation:
[tex]s = {a}^{2} \: thus \: a = \sqrt{s } = \sqrt{49} = 7[/tex]
Which angle number represents an angle adjacent to /EHD?
In the diagram, ∠5 is adjacent to ∠EHD.
Angle
Angles are formed when two rays intersect at a point. An angle is also formed when to lines intersect each other, thereby the two lines share a common endpoint.
Adjacent angles are two angles that have a common side and a common vertex (corner point). They are placed side by side to each other.
In the diagram, ∠5 is adjacent to ∠EHD.
Find out more on Angle at: https://brainly.com/question/25770607
FIND the product
(5a³-3a²+8)(3a-4)
find the angle measures given the figure is a rhombus.
[tex] \large \tt{{❃ \: S \: O \: L \: U \: T \: I \: O \: N : }}[/tex]
A rhombus is a parallelogram in which all sides are equal i.e AB = BC = CD = CA Let ∠ A be x. In the ∆ ABC , AB = AC which means they are isosceles triangle and we know the opposite angles of isosceles triangle are equal i.e ∠ A = ∠ C = x. The sum of angles of a triangle is always 180°. Now , Find out the value of x :[tex] \large{ \tt{❁ \:x + x + 98 = 180 \degree \: [ Sum\: of \: angle \: of \: a \: triangle ]}}[/tex]
[tex] \large{ \tt{⟶2x + 98 \degree= 180 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: 2x = 180 \degree - 98 \degree}}[/tex]
[tex] \large{ \tt{⟶ \: 2x = 82 \degree}}[/tex]
[tex] \large{ \tt{ ⟶x = \frac{82 \degree}{2} }}[/tex]
[tex] \large{ \tt{⟶ \: x = 41 \degree}}[/tex]
The value of x is 41°. Now , Find the measure of ∠ 1 :[tex] \large{ \tt{ ↔\angle \: 1 = x \degree = \boxed{41 \degree}}}[/tex] [ Being alternate angles ]
Hence , Our final answer is 41° .- Alternate angles are the non-adjacent interiors pair of angles lying to the opposite side of a transversal when it intersects two straight line segments. Alternate angles form ' Z ' shape.
Hope I helped! Let me know if you have any questions regarding my answer. :)Describe the steps to dividing imaginary numbers and complex numbers with two terms in the denominator?
Answer:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Step-by-step explanation:
Let be a rational complex number of the form [tex]z = \frac{a + i\,b}{c + i\,d}[/tex], we proceed to show the procedure of resolution by algebraic means:
1) [tex]\frac{a + i\,b}{c + i\,d}[/tex] Given.
2) [tex]\frac{a + i\,b}{c + i\,d} \cdot 1[/tex] Modulative property.
3) [tex]\left(\frac{a+i\,b}{c + i\,d} \right)\cdot \left(\frac{c-i\,d}{c-i\,d} \right)[/tex] Existence of additive inverse/Definition of division.
4) [tex]\frac{(a+i\,b)\cdot (c - i\,d)}{(c+i\,d)\cdot (c - i\,d)}[/tex] [tex]\frac{x}{y}\cdot \frac{w}{z} = \frac{x\cdot w}{y\cdot z}[/tex]
5) [tex]\frac{a\cdot (c-i\,d) + (i\,b)\cdot (c-i\,d)}{c\cdot (c-i\,d)+(i\,d)\cdot (c-i\,d)}[/tex] Distributive and commutative properties.
6) [tex]\frac{a\cdot c + a\cdot (-i\,d) + (i\,b)\cdot c +(i\,b) \cdot (-i\,d)}{c^{2}-c\cdot (i\,d)+(i\,d)\cdot c+(i\,d)\cdot (-i\,d)}[/tex] Distributive property.
7) [tex]\frac{a\cdot c +i\,(-a\cdot d) + i\,(b\cdot c) +(-i^{2})\cdot (b\cdot d)}{c^{2}+i\,(c\cdot d)+[-i\,(c\cdot d)] +(-i^{2})\cdot d^{2}}[/tex] Definition of power/Associative and commutative properties/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction.
8) [tex]\frac{(a\cdot c + b\cdot d) +i\cdot (b\cdot c -a\cdot d)}{c^{2}+d^{2}}[/tex] Definition of imaginary number/[tex]x\cdot (-y) = -x\cdot y[/tex]/Definition of subtraction/Distributive, commutative, modulative and associative properties/Existence of additive inverse/Result.
Please help…
As soon as possible..
note: you may need to leave off the pi term if your teacher just wants to know what goes in the green box
======================================================
Work Shown:
C = 2*pi*r
C = 2*r*pi
C = 2*5*pi
C = 10pi
find cosØ if sinØ=-12/13 and tanØ>0.
A) -5/12
B) -5/13
C) 12/5
D) -13/12
Answer:
-5/13
Step-by-step explanation:
sin theta = opp / hyp
sin theta = -12 /13
we can find the adj side by using the pythagorean theorem
adj^2 + opp ^2 = hyp^2
adj^2 +(-12)^2 = 13^2
adj^2 +144 =169
adj^2 = 169-144
adj^2 = 25
Taking the square root of each side
adj = ±5
We know that it has to be negative since it is in the third quad
adj = -5
cos theta = adj / hyp
cos theta = -5/13
Answer:
B) -5/13
Step-by-step explanation:
i hope it will help
plzz mark as brainliest if you want
pls pls pls help meeeeee
Answer:
i think you just extend the coordinates to the side, except the right point, by 3, and then the bottom ones go down by 3, and the top one goes up by 3
Step-by-step explanation:
3(-4x - 3) + 50 - 5= 0
Answer:
-12x-9+50-5=0
-12x+41-5=0
-12x+36=0
-12x=0-36
x= -36/-12
x = 3 Answer...
hope it helps
Answer:
[tex]x=3[/tex]
Step-by-step explanation:
[tex]3(-4x - 3) + 50 - 5= 0[/tex]
⇒ Subtract 50- 5 from both sides:-
[tex]3\left(-4x-3\right)+50-5-\left(50-5\right)=0-\left(50-5\right)[/tex]
[tex]3\left(-4x-3\right)=-45[/tex]
⇒ Divide both sides by 3:-
[tex]\frac{3\left(-4x-3\right)}{3}=\frac{-45}{3}[/tex]
[tex]-4x-3=-15[/tex]
⇒ Add 3 to both sides:-
[tex]-4x-3+3=-15+3[/tex]
[tex]-4x=-12[/tex]
⇒ Divide both sides by -4:-
[tex]\frac{-4x}{-4}=\frac{-12}{-4}[/tex]
[tex]x=3[/tex]
OAmalOHopeO
Use the box plots comparing the number of males and number of females attending the latest superhero movie each day for a month to answer the questions.
Two box plots shown. The top one is labeled Males. Minimum at 0, Q1 at 3, median at 10, Q3 at 15, maximum at 35. The bottom box plot is labeled Females. Minimum at 0, Q1 at 2, median at 6, Q3 at 9, maximum at 14, and a point at 31.
Part A: Estimate the IQR for the males' data. (2 points)
Part B: Estimate the difference between the median values of each data set. (2 points)
Part C: Describe the distribution of the data and if the mean or median would be a better measure of center for each. (4 points)
Part D: Provide a possible reason for the outlier in the data set. (2 points)
PLEASE HELP ME!!! IVE BEEN AVOIDING THIS FOR SO LONG
(a) The IQR for the males' data is 12, because Q3 is at 15 and Q1 is at 3.
(b) The difference between the median values of each data set is 4 because 10-6 = 4
(c) For the males' data, the median would be a better measure of center, since the data is skewed right. For the females' data, the mean would be a better measure of center, because the data is pretty balanced (except for the outlier).
(d) Maybe a superhero movie had their opening night one day of this month, which would explain the outlier.
Find a if ZB = 25°, ZC = 48°, AC = 5.
Answer:
11.3
Step-by-step explanation:
a = AC × sin(A)/sin(B)
Now <A =180-25-48 = 107
a = 5×sin(107)/sin(25)
a ≈ 11.3
Answered by GAUTHMATH
Combine these radicals.
Anyone pls I need
Answer:
-26 sqrt(3)
Step-by-step explanation:
-12 sqrt(12) - 2 sqrt(3)
Rewriting
-12 sqrt(4*3) - 2 sqrt(3)
We know sqrt(ab) = sqrt(a)sqrt(b)
-12 sqrt(4)sqrt(3) - 2 sqrt(3)
-12 (2) sqrt(3) - 2 sqrt(3)
-24 sqrt(3) - 2 sqrt(3)
-26 sqrt(3)
Given the arithmetic sequence 2, -7, -16, -25, ..., determine the
general term tn.
Answer:
Step-by-step explanation:
Common difference is -9.
t_1 = 2
t_n = t_1 - (n-1)9
= t_1 - (9n - 9)
= 2 - (9n - 9)
= 11 - 9n
Diagnostic
Analytics
When completing an online shopping transaction, a typical shopper takes 7 seconds to
select each product and another 9 seconds to complete the check-out process. If it takes 37
seconds to complete a transaction, how many products are being purchased?
products
Submit
Answer:
In 26 seconds to complete a transaction, 2 products are being purchased.
Step-by-step explanation:
1 item = 9 seconds
Time taken in all to check out = 8 seconds
Time taken to shop = 26 seconds
Now as check out process takes 8 seconds, so the
Time left to ACTUALLY SHOP = Total Time - Time Used to check out
= 26 seconds = 8 seconds = 18 seconds
Shopping of 1 item = 8 seconds
Shopping of 2 items = 2 x ( Time taken in 1 item) = 2 x 9 = 18 seconds
So, in 18 seconds, 2 clothing item can be selected.
Hence,in 26 seconds to complete a transaction, 2 products are being purchased.
Problem 1 Find the mBC.
Answer:
m BC = 100
Step-by-step explanation:
Since the angle is at the center, the arc has the same measurement as the angle
m BC = 100
In isoceles triangle the length of a leg is 17cm, and the base is 16cm. Find the length of the altitude to the base
This triangle has base 16 therefore the sides must be 17cm and 17 cm
When we make a altitude it divides it into two right triangles and there is a property in which the altitude of the isoceles triangle divides the base in 2 equal halves
So the side of the right triangle will be x , 8 , 17
Using pythgoreus theorem
x²+8²=17²
x = √225
x = 15
So the altitude is 15 cm
Must click thanks and mark brainliest
Help anyone can help me do this question,I will mark brainlest.
Answer:
Step-by-step explanation:
Economy Hardware Store ordered items retailing for $2,500. They received a chain discount of 20/5/2. Find the net cost.
The net cost after discounts will be $ 2,450.
Given that Economy Hardware Store ordered items retailing for $ 2,500, and they received a chain discount of 5/20/2, the following calculation must be performed to find the net cost, knowing that the net cost is equal to the initial cost minus the discounts made about it:
First, the discount percentage must be calculated.
5/20/2 = X
4/2 = X
2 = X
Then, this percentage must be subtracted from the initial value.
2500 x (1-0.02) = X
2500 x 0.98 = X
2450 = X
Therefore, the net cost after discounts will be $ 2,450.
Learn more in https://brainly.com/question/17003148.
Differentiate y= ln (6 – 3x)^4
Step-by-step explanation:
[tex] \frac{dy}{dx} = \frac{1}{ {(6 - 3x)}^{4} } \times {4(6 - 3x)}^{3} ( - 3) \\ = \frac{ - 12 {(6 - 3x)}^{3} }{ {(6 - 3x)}^{4} } \\ = - \frac{12}{6 - 3x} [/tex]
I hope I'm correct. I've never learnt differentiation for log and exponents before
Find the value of x for which l||m
Answer:
30 =x
Step-by-step explanation:
The angles are correcting angle and corresponding angles are equal when the lines are parallel
55 = x+25
Subtract 25 from each side
55-25 = x+25
30 =x
The quantity of milk consumed in five households in a week is 10L.12.13 L. 11 L and
14 L Find the mean weekly consumption of milk by these bouseholds. Also find the number
of households whose consumption is more than the mean weekly consumption
Answer:
12
Step-by-step explanation:
Add 10l to 12l to13l to11l to 14l=60l the divide 60l by the number of houses which will be 12 and there is your correct answer
A man invested a certain amount of money in a bank at a simple interest rate of 5percent per annum. At the end of the year, his total amount un the bank was GHC 840,000.00. How much sid he invest in the bank.
Answer: He invested 8,00,000.
Step-by-step explanation:
R = 5%
A = 840,000
T = 1 year
so
so
I = A-P
so
I = PTR/100
or, A-P = (p*1*5)/100
or, 840,000-P = 5p/100
or, 8,40,00,000-100P = 5p
or, 8,40,00,000 = 105P
so, p = 8,40,8,40,00,000
so, P = 8,00,000