Uma empresa do ramo de confecções produz e comercializa calças jeans. Se x representa a quantidade produzida e comercializada (em milhares de reais) e L(x) = -x² + 8x – 16 representa o lucro (em milhares de reais) da empresa para x unidades, então quando L(x) = 0 a empresa terá produzido e comercializadas quantas unidades dessas calças jeans? *

Answer:

2

Step-by-step explanation:

(5y + 1)/10 = x

Multiply each side by 10

(5y + 1)/10*10 =10 x

(5y + 1) = 10x

Subtract 1

5y +1-1 = 10x-1

5y = 10x-1

Divide by 5

5y/5 = 10x/5 - 1/5

y = 2x-1/5

This is in slope intercept form y = mx+b where m is the slope and b is the y intercept

The slope is 2

Writing down the formulas on charts and pasting it in your room,by seeing this daily it helps to memorize the formulas.

Saying the formulas louder also helps to memorize the formula.

Watching videos related to maths formulas and equations helps to remember the formulas easier.

Doing many problems regularly will helps you to remember the formulas.

lastly study to Understand The Formula not to memorize

Answer:

The answer to your question is 1, or answer choice A.

Step-by-step explanation:

x+ 2 /7 = 3 /7 x+ 6 /7

x+ 2 /7 − 3 /7 x= 3 /7 x+ 6 /7 − 3 /7 x

4 /7 x+ 2 /7 = 6 /7

4 /7 x+ 2 /7 − 2 /7 = 6 /7 − 2 /7

4 /7 x= 4 /7

( 7 /4)*( 4 /7 x)=( 7 /4 )*( 4 /7 )

x=1  

Answer:

y=2x-8

Step-by-step explanation:

Hi there!

We want to find an equation of the line parallel to y=2x-4 but has the same x intercept as 3x-4y=12

Parallel lines have the same slope, but different y intercepts

In y=2x-4, which is written in y=mx+b form, m is the slope and b is the y intercept

2 is in the place of where the slope would be, so the slope of that line is 2

That means the slope of the line parallel to it would also have a slope of 2

Here is the equation of the parallel line so far:

y=2x+b

We need to find b, the y intercept

Typically, we'll substitute a point into the equation to solve for b, but we don't have a point, yet

We're given that the new line has the same x intercept as 3x-4y=12

The x intercept is the point where the line passes through the x axis, and so the value of y at that point is 0

Let's substitute 0 for y in 3x-4y=12 and solve for x to find the x intercept

3x-4(0)=12

Multiply

3x=12

Divide both sides by 3

x=4

So the value of the x intercept is 4. As a point, it's (4,0)

So now substitute the values of the point (4,0) into y=2x+b to find b

0=2(4)+b

Multiply

0=8+b

Subtract 8 from both sides

-8=b

Substitute -8 as b into the equation

y=2x-8

Hope this helps!  

Answer:

The area of the circle is exactly π times the square of its radius. If you are given that the radius is within 0.1cm of 8.5cm, i.e. lies between 8.4 cm and 8.6 cm, its square will lie between p=8.4² = 70.56 and q=8.6² = 73.96 cm².

Answer:

The area of the circle is exactly π times the square of its radius. If you are given that the radius is within 0.1cm of 8.5cm, i.e. lies between 8.4 cm and 8.6 cm, its square will lie between p=8.4² = 70.56 and q=8.6² = 73.96 cm².

Step-by-step explanation:

thanks for question dear

Answer:

So the equation of the parabola is x2=8y i don't really know

Answer:

(3+a)

Step-by-step explanation:

3a + a^2

-------------

a

Factor out an a in the numerator

a(3+a)

-------------

a

Cancel like terms

(3+a)

Step-by-step explanation:

[tex] \frac{3a + {a}^{2} }{a} \\ = \frac{3a}{a} + \frac{ {a}^{2} }{a} \\ = 3 + a \\ thank \: you[/tex]

Answer:

3n -4

Step-by-step explanation:

We are adding 3 each time

-1+3 =2

2+3 = 5

The formula for an arithmetic sequence is

an = a1+d(n-1) where a1 is the first term and d is the common difference

an = -1+3(n-1)

    = -1 +3n -3

    = 3n -4

Answer:

Heights of 29.5 and below could be a problem.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The heights of 2-year-old children are normally distributed with a mean of 32 inches and a standard deviation of 1.5 inches.

This means that [tex]\mu = 32, \sigma = 1.5[/tex]

There may be a problem when a child is in the top or bottom 5% of heights. Determine the heights of 2-year-old children that could be a problem.

Heights at the 5th percentile and below. The 5th percentile is X when Z has a p-value of 0.05, so X when Z = -1.645. Thus

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]-1.645 = \frac{X - 32}{1.5}[/tex]

[tex]X - 32 = -1.645*1.5[/tex]

[tex]X = 29.5[/tex]

Heights of 29.5 and below could be a problem.

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Answer:

230 children

Step-by-step explanation:

Answer:

[tex]4\sqrt{5}[/tex]

Step-by-step explanation:

In order to solve this problem, we can use the pythagorean theorem, which is

a^2 + b^2 = c^2, where and b are the legs of a right triangle and c is the hypotenuse. Since we are given the leg lengths, we can substitute them in. So, where a is we can put in a 4 and where b is we can put in an 8:

a^2 + b^2 = c^2

(4)^2 + (8)^2 = c^2

Now, we can simplify and solve for c:

16 + 64 = c^2

80 = c^2

c = [tex]\sqrt{80}[/tex]

Our answer is not in simplified radical form because the number under is divisible by a perfect square, 16. We can divide the inside, 80,  by 16, and add a 4 on the outside, as it is the square root of 16:

c = [tex]4\sqrt{5}[/tex]

The length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

To find the length of the hypotenuse in a right triangle, we can use the Pythagorean theorem. According to the theorem, in a right triangle, the square of the hypotenuse's length is equal to the sum of the squares of the lengths of the other two sides.

In this case, let's label the lengths of the legs as 'a' and 'b', with 'a' being 4 and 'b' being 8. The hypotenuse, which we need to find, can be represented as 'c'.

Applying the Pythagorean theorem, we have:

[tex]a^2 + b^2 = c^2[/tex]

Substituting the given values:

[tex]4^2 + 8^2 = c^2[/tex]

16 + 64 = [tex]c^2[/tex]

80 = [tex]c^2[/tex]

To find the length of the hypotenuse 'c', we need to take the square root of both sides:

√80 = √ [tex]c^2[/tex]

√80 = c

The square root of 80 is approximately 8.94.

Therefore, the length of the hypotenuse in the given right triangle, with legs measuring 4 and 8, is approximately 8.94.

To know more about  hypotenuse , here

https://brainly.com/question/2217700

#SPJ2

Answer:

2

Step-by-step explanation:

Replace the number with x, then the equation would be:

7x-4=x+8

7x-x=8+4

6x=12

6x/6=12/6

x=2

Answer:

64percents

Step-by-step explanation:

25-9=16 grams - weight of copper

(16/25)*100=64 percents

what nice question that we can understand ok

If n = 0.151515…, then 100n = 15.151515…

Then

100n - n = 15.151515… - 0.151515…

99n = 15

n = 15/99 = 5/33

28

How?

We can see that 28 is the lowest common multiple also it is <30

Answer: 28.

Step-by-step explanation: 28 is divisible by 4: 28 / 4 = 7. 28 is divisible by 14: 28 / 14 = 2. And 28 is less than 30

Answer:

C

Step-by-step explanation:

The sum of distances from any point on the ellipse to each foci equals a certain amount, no matter what point on the ellipse it starts from. The foci are on the major radius of the ellipse (the longer length of horizontal/vertical). The foci are of equal distance from the center, with one on each side.

If you wanted to find where the foci are using the major and minor radius, we can find that, representing the distance between the center and any foci as g,

g² = major radius² - minor radius². Then, the distance between the center and the foci is equal to g

Answer:

1.5

Step-by-step explanation:

y=2x - 3

0 = 2x - 3

-2x = - 3 /÷(-2)

x = 3 ÷ 2

x = 1.5 3/2

Answer:

Hello,

Step-by-step explanation:

[tex]\dfrac{f(x)}{3} =\dfrac{x^4+x^3+x^2+1}{(x-1)(x+2)} \\\\=\dfrac{(x^2+3)(x-1)(x+2)-3x+7}{(x-1)(x+2)} \\=x^2+3-\dfrac{3x-7}{(x-1)(x+2)} \\\\=x^2+3-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} =-\dfrac{3}{x-1} +\dfrac{1}{(x-1)(x-2)} \\\\\\ \lim_{x \to +\infty} (\dfrac{f(x)}{3}-\dfrac{3x^2+9}{3} )\\\\=0+0=0\\\\\\P(x)=-x^2-3[/tex]

Answer:

[tex]g(x)=-3x^2-9[/tex]

Explanation:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

We need p(x) need to be a degree 2 polynomial so the numerator of the second fraction is degree 4. Our goal is to cancel the terms of the first fraction's numerator that are of degree 2 or higher.

So let p(x)=ax^2+bx+c.

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{p(x)(x^2+x-2)}{x^2+x-2}[/tex]

Plug in our p:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{(ax^2+bx+c)(x^2+x-2)}{x^2+x-2}[/tex]

Take a break to multiply the factors of our second fraction's numerator.

Multiply:

[tex](ax^2+bx+c)(x^2+x-2)[/tex]

=[tex]ax^4+ax^3-2ax^2[/tex]

+[tex]bx^3+bx^2-2bx[/tex]

+[tex]cx^2+cx-2c[/tex]

=[tex]ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)-2c[/tex]

Let's go back to the problem:

[tex]3\frac{x^4+x^3+x^2+1}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex]

Let's distribute that 3:

[tex]\frac{3x^4+3x^3+2x^2+3}{x^2+x-2}[/tex]

+[tex]\frac{ax^4+(a+b)x^3+(-2a+b+c)x^2+(-2b+c)x-2c}{x^2+x-2}[/tex

So this forces [tex]a=-3[/tex].

Next we have [tex]a+b=-3[/tex]. Based on previous statement this forces [tex]b=0[/tex].

Next we have [tex]-2a+b+c=-3[/tex]. With [tex]b=0[/tex] and [tex]a=-3[/tex], this gives [tex]6+0+c=-3[/tex].

So [tex]c=-9[tex].

Next we have the x term which we don't care about zeroing out, but we have [tex]-2b+c[/tex] which equals [tex]-2(0)+-9=-9[/tex].

Lastly, [tex]-2c=-2(-9)=18[/tex].

This makes [tex]p(x)=-3x^2-9[/tex].

This implies [tex]g(x)\frac{(-3x^2-9)(x^2+x-2)}{x^2+x-2}[/tex] or simplified [tex]g(x)=-3x^2-9[/tex]

Answer:

the log function is the "inverse" function of an exponential function

by definition  [tex]log_{a} b = c[/tex]  then [tex]a^{c} = b[/tex]

in this problem you have [tex]log_{10} 100[/tex]

thus what x solves this ?  [tex]10^{x} = 100[/tex]  the answer is [tex]10^{2}[/tex]

thus (100,2)

B) the x intercept is when y = 0

   [tex]10^{0} = 1[/tex]

   x intercept at (1,0)

C) at 100, the curve will hit y = 5000

Step-by-step explanation:

Answer:

The inverse is 1/2x - 3/2

Step-by-step explanation:

y = 2x+3

To find the inverse, exchange x and y

x = 2y+3

Solve for y

x-3 =2y+3-3

x-3 = 2y

Divide by 2

1/2x - 3/2 = 2y/2

1/2x - 3/2 = y

The inverse is 1/2x - 3/2

Answer: [tex]\dfrac{11}{12}[/tex]

Step-by-step explanation:

Given

The odds against winning in a chess tournament are 1 to 11.

Odds is defined as the ratio of the probability of occurrence to the non-occurrence of event.

[tex]\therefore \text{Probability that event will occur is P'=}\dfrac{1}{1+11}\\\\\Rightarrow P'=\dfrac{1}{12}[/tex]

Probability of non-occurrence i.e. she wins the first prize is

[tex]\Rightarrow P=1-\dfrac{1}{12}\\\\\Rightarrow P=\dfrac{11}{12}[/tex]

Answer:

A

For something to be a function every x value bust have at most 1 y value and in A 9 has 2 y values so it cant be a function

=========================================================

Explanation:

It's a bit strange why your teacher has the "26 degree" label pointing at a side length, rather than an actual angle. I'm assuming your teacher meant to aim it at angle C. In other words, I'm assuming they meant to say angle C = 26 degrees.

If that assumption is correct, then,

A+B+C = 180

38+B+26 = 180

B+64 = 180

B = 180-64

B = 116

Then we can use the law of sines like so:

a/sin(A) = b/sin(B)

a/sin(38) = 10/sin(116)

a = sin(38)*10/sin(116)

a = 6.84986152123146

a = 6.8

Side 'a' is approximately 6.8 inches long. So that's why the answer is choice A.

Answer:

-9

Step-by-step explanation:

Answer:

Shane=x

Abha=y

x+y>=2000

x-y=178 Which leads to x=178+y ..... #1

hence by substitution in the inequality

178+2y>=2000

2y>=2000-178

2y>=1822

y>=911 ......in #1

x>=178+911

x>=1089

Solutions x>=1089 & y>=911