Answer:
The height jumped by the person on the moon is 6 times the height jumped by the person on earth.
Explanation:
As we know that the acceleration due to gravity on moon is 1/6 of the acceleration due to gravity on earth.
So, it is false.
Let the mass of man is m and the gravity on moon is g' = g/6.
Let the height jumped on earth is h and the height jumped on moon is h'.
So,
m x g' x h' = m x g x h
g/6 x h' = g x h
h' = 6 h
So, the height jumped by the person is 6 times the height jumped by the person on earth.
The
push switch is closed and the door unlocks. Explain in detail how this happens.
Answer:
The push switch is closed and the door unlocks. ... The switch completes the circuit and a current flows through the coil. The coil becomes an electromagnet and its iron core becomes magnetised. The iron bolt is attracted to the electromagnet.
Explanation:
Please Mark me brainliest
How can you increase efficiency of a simple machine??
Answer:
Efficiency can be increase by using rollers in conjunction with the inclined plane. Wedge. The wedge is an adaptation of the inclined plane. It can be used to raise a heavy load over a short distance or to split a log.
Explanation:
Hope it helps
ASAPP PLS HELP MEE
The density of aluminum is 2.7 g/cm^3. Which of the following statement is true?
A) 1 g of aluminium has a volume of 1 cm^3
B) 2.7 g of aluminium has a volume of 1 cm^3
C) 1 g of aluminium has a volume of 2.7 cm^3
D) 2 g of aluminium has a volume of 7 cm^3
Answer:
B) 2.7 g of aluminium has a volume of 1 cm^3
Explanation:
Density can be defined as mass all over the volume of an object.
Simply stated, density is mass per unit volume of an object.
Mathematically, density is given by the equation;
[tex]Density = \frac{mass}{volume}[/tex]
If the density of aluminum is 2.7 g/cm³, it simply means that 2.7 g of aluminium has a volume of 1 cm³
Check:
Given the following data;
Mass = 2.7 grams
Volume = 1 cm³
Substituting into the formula, we have;
[tex]Density = \frac{2.7}{1}[/tex]
Density = 2.7 g/cm³
1- Un avión vuela horizontalmente con una velocidad cuya magnitud es de 100 m/s y deja caer un proyectil desde una altura de 400 m con respecto al suelo. Determinar: a) El tiempo que transcurre antes de que el proyectil se impacte en el suelo. b) ¿Qué distancia horizontal recorre el proyectil después de iniciar su caída?
2- Se lanza horizontalmente un objeto con una velocidad de 80 m/s desde una altura de 160 m. Calcular: a) El tiempo que tarda en llegar al suelo b) La magnitud de la velocidad vertical que lleva a los 3 segundos. c) La distancia horizontal a la que cae el objeto a partir del punto desde que fue arrojada.
3- Se lanza un proyectil con una velocidad inicial de 80 m/s y una inclinación, sobre la horizontal, de 30°. Calcular: a) ¿Cuál es la altura máxima que alcanza la bala? b) ¿Cuáles son las posiciones, x y y, cuando han transcurrido 5 segundos?
4- Un joven patea una pelota contra un arco con una velocidad inicial de 20 m/s y con un ángulo de 45°. Determinar: a) cual es el alcance total
Which of these is untrue about ray diagrams?
A. The arrowheads show the direction of the light
B. Lines must always be straight
C. More arrowheads on lines mean a brighter light
Answer:
The untrue option is C: "More arrowheads on lines mean a brighter light"
Explanation:
Ray diagrams are used to show how the light behaves with things like mirrors or lenses. Where we only study how the direction of the light changes when it interacts with these objects.
The "light" is represented with arrows, where again, the only thing we care is the direction of the light, so the first statement is true, the arrowheads show the direction of the light, and only that.
The intensity of the light, in this context, has no effect on how light behaves, so there is not a necessity of representing the intensity of the light, thus, more arrowheads on lines do not mean a brighter light. It may only be used to represent changes in direction of the light.
Finally, we know that light travels in straight pats (the pats can be curved in some cases, like with large gravitational fields, but this is not the case of a ray diagram) so the lines that represent the light should always be straight, thus option B is also true.
The untrue option is C: "More arrowheads on lines mean a brighter light"
Why is a person not a good blackbody radiator?
O A. A person emits only visible light.
OB. A person emits only infrared radiation.
O C. A person absorbs most of the light that hits him or her.
O D. A person reflects little of the light that hits him or her.
Answer:
O C. A person absorbs most of the light that hits him or her.
Explanation:
Answer:
Option D hope it's helpful mark me as brainlistWhat is kinetic and potential energy?
Answer:
the energy produced in a body due to its motion is kinetic energy.
energy produced in a body due to its position is potential energy.
Explanation:
kinetic energy is the energy possessed by a body in motion
Potential energy is the energy possessed by a body by virtue of its position with respect to a reference level
If a serve hits the net, what happens?
• Re-do
• Dead Ball
• Other teams point
• Play the ball
Answer:
Depends: Is it tennis or volleyball?
Explanation:
If it's volleyball, it's C, the other teams point.
If it's tennis, it's A, you get a re-do.
A young student drops a stone off the side of a cliff that is 41 meters high. How long does it take the stone to hit the ground below?
A)
2.89 s
B)
8.36 s
C)
3.20 s
D)
2.04 s
HELPPP ILL GIVE BRAINLIST
Answer:
1= Kidneys
2= Ureters
3=Bladders
4=Urethra
Explanation:
Functions of kidney: Regulations of water balances, excretions of nitrogenous wastes(urea)
Functions of Liver: Detoxifications, protein synthesis
Functions of Skin: Temperature regulations, Metabolic functions, Excretion
Functions of lungs: Respiration, Water balance regulations
Tip: If you want faster and correct answers you should label your questions under the correct subject.
A body of mass 5 kg moving with velocity 10m/s attains a velocity of 30m/s in 20 seconds, after applying the force. The amount of force applied will be:
a 10N
b 20N
c 5N
d 15N
Answer↷
c) 5N
➦I hope it seemed helpful to you!
A sled with mass 11.00 kg moves in a straight line on a frictionless horizontal surface. At one point in its path, its speed is 4.00 m/s; after it has traveled a distance 3.00 m beyond this point, its speed is 7.00 m/s. Use the work-energy theorem to find the force acting on the sled, assuming that this force is constant and that it acts in the direction of the sled's motion.
Answer:
The magnitude of the force acting on the sled is 60.5 newtons.
Explanation:
The Work-Energy Theorem states that the work done by the external force applied on the sled ([tex]W[/tex]), in joules, is equal to the change of its translational kinetic energy ([tex]\Delta K[/tex]), in joules:
[tex]W = \Delta K[/tex] (1)
By definitions of work and translational kinetic energy we expand the equation above:
[tex]F\cdot s = \frac{1}{2}\cdot m\cdot (v_{2}^{2}-v_{1}^{2})[/tex] (1b)
Where:
[tex]F[/tex] - External force applied on the sled, in newtons.
[tex]s[/tex] - Travelled distance, in meters.
[tex]v_{1}, v_{2}[/tex] - Initial and final velocities, in meters per second.
If we know that [tex]m = 11\,kg[/tex], [tex]v_{1} = 4\,\frac{m}{s}[/tex], [tex]v_{2} = 7\,\frac{m}{s}[/tex] and [tex]s = 3\,m[/tex], then the external force applied on the sled is:
[tex]F = \frac{m\cdot (v_{2}^{2}-v_{1}^{2})}{2\cdot s}[/tex]
[tex]F = \frac{(11\,kg)\cdot \left[\left(7\,\frac{m}{s} \right)^{2}-\left(4\,\frac{m}{s} \right)^{2}\right]}{2\cdot (3\,m)}[/tex]
[tex]F = 60.5\,N[/tex]
The magnitude of the force acting on the sled is 60.5 newtons.
DO U KNOW CARRYMINATI
Change the following as indicated in the brackets.
8m (km,cm)
metres to kilometres = 1/1000
8 m ⇒ 0.008 km
metres to centimetres = × 100
8 m ⇒ 800 cm
Answer:
1000m=1km
so, 8m=8/1000 = 0.008km
1m=100cm
so, 8m=8×100=800
The dependent variable measured was the ______
a. fan speed
b. mass
c. acceleration
Answer:
a
Explanation:
Fan speed is the answer
A stone is thrown upward with a kinetic energy of 10J. If it goes up to a maximum height of 5 m, find the initial velocity and mass of the stone
Answer:
Explanation:
Begin by remembering that at the stone's max height, the final velocity there is 0. Being in possession of that information along with the fact that the pull of gravity due to acceleration is -9.8 m/s/s, we can use the equation
[tex]v^2=v_0^2+2a[/tex]Δx where v is the final velocity, v₀ is the initial velocity, a is the pull of gravity, and Δx is the displacement. Filling in:
[tex]0^2=v_0^2+2(-9.8)(5.0)[/tex]
0 = v₀² - 98 so
98 = v₀² and
v = 9.9 m/s Now we can put that into the KE equation.
[tex]10=\frac{1}{2}m(9.8)[/tex] and
[tex]m=\frac{2(10)}{98}[/tex] so
m = .20 kg
If the amplitude of a sound wave is increased by a factor of four,how does the energy carry by the sound wave in each time interval change?
Answer:
The energy will be increased by a factor 16
Explanation:
Mathematically, we have it that the energy carried by the sound wave is directly proportional to the square of the amplitude
So we have it that;
E = k * A^2
where E is the wave energy
K is the constant value
A is the amplitude value
So;
If E1 = k * (A1)^2
E2 = k * (A2)^2
But A2 = 4A1
E2 = k * (4A1)^2
E2 = k * 16(A1)^2
Divide E2 by E1
E2/E1 = k/k * 16(A1)^2/(A1)^2
E2/E1 = 16
E2 = 16 * E1
so simply, the energy will be increased by a factor of 16
how do you do question 1?
Answer:
DONT KNOW SORRY XD
Explanation:
BEC I AM BRAINLESS USING BRAINLY
Answer:
Ok, so at point 20 on the x axis you put 12 on the y-axis, then draw a line from 0, 0 to that point, this demonstrates the acceleration to 12 m/s.
Next, calculate the time he cycled for if he suckled the distance of 4800m :
4800/12 = 400 s
Put a dot at 400, 12. The time changed but the speed remained constant, line is horizontal.
For the last one, he had to decelerate at an equal speed. Since there is 100 s left of the journey at that stage, You need to draw a straight line from the previous point to 500, 0. So at time 500 he was not accelerating at all, he came to rest.
a) ?
b) -0.16 meters a second acceleration
(Please help if you can, I need this last answer done by tonight.)
Use the universal law of gravitation to solve the following problem.
Hint: mass of the Earth is = 5.97 x 1024 kg
A scientific satellite of mass 1300 kg orbits Earth 200 km above its surface. If Earth has a radius of 6378 km, what is the force of gravity acting on the scientific satellite?
a. Write out the formula for this problem.
b. Plug in the values from this problem into the formula.
c. Solve the problem, writing out each step.
d. Correct answer
Answer:
a.
[tex]F =G \cdot \dfrac{M \cdot m}{r^{2}}[/tex]
b.
[tex]F =6,378 \times 10^{-11} \times \dfrac{5.97 \times 10^{24} \times 1,300}{6,578^{2}}[/tex]
c.
[tex]F =6,378 \times 10^{-11} \times \dfrac{5.97 \times 10^{24} \times 1,300}{6,578^{2}} = \dfrac{9.519165 \times 10^{18}}{832117} \approx 1.144 \times 10^{13}[/tex]
d. 1.144 × 10¹³ N
Explanation:
The universal law of gravitation is presented as follows;
[tex]F =G \cdot \dfrac{M \cdot m}{r^{2}}[/tex]
The given mass of the scientific satellite, m = 1,300 kg
The height of the orbit of the satellite, r = 200 km above the Earth's surface
The length of the radius of the Earth, R = 6378 km
The mass of the Earth = 5.97 × 10²⁴ kg
a. The formula for the universal law of gravitation is presented as follows;
[tex]F =G \cdot \dfrac{M \cdot m}{r^{2}}[/tex]
Where;
M = The mass of the Earth = 5.97 × 10²⁴ kg
m = The mass of the satellite = 1,300 kg
r = The distance between the Earth and the satellite = R + r = 6,378 km + 200 km = 6,578 km
G = The Gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²
b. Plugging in the values from the problem into the formula gives;
[tex]F =6,378 \times 10^{-11} \times \dfrac{5.97 \times 10^{24} \times 1,300}{6,578^{2}}[/tex]
c. Solving gives;
[tex]F =6,378 \times 10^{-11} \times \dfrac{5.97 \times 10^{24} \times 1,300}{6,578^{2}} = \dfrac{9.519165 \times 10^{18}}{832117} \approx 1.144 \times 10^{13}[/tex]
The force acting between the Earth and the satellite, F ≈ 1.144 × 10¹³ N
d. 1.144 × 10¹³ N
A cell has an emf of 1.5 V and an internal resistance of 0.65 Q.
The cell is connected to a resistor R.
[0[8].[4] State what is meant by an emf of 1.5 V.
[2 marks]
I
[0] 8]-[2] The current in the circuit is 0.31 A.
Show that the total power output of the cell is approximately 0.47 W.
[1 mark]
[o[s).[3] Calcutate the energy dissipated per second in resistor R.
[2 marks]
energy dissipated per second = Ist
[o[si.[4] The cell stores 14 kJ of energy when it is fully charged. The cell's emf and internal resistance are constant as the cell f discharged.
Calculate the maximum time during which the fully-charged cell can deliver energy to
resistor R.
[2 marks)
maximum time = 5
Answer:
14000 J / 0.40 J/s = 35 000 s or about 9.75 hrs
Please help!!!!! I will give brainliest. Describe four examples of acceleration you see during your day. Choose an object that is slowing down, one that is speeding up, one that is moving at a constant speed but changing direction, and one that is moving at a constant velocity with zero acceleration.
When the brake is applied to the car and comes to rest after some time is an example of an object that is slowing down.
What is acceleration?The rate of change of velocity with respect to time is known as acceleration. According to Newton's second law, the eventual effect of all forces applied to a body is its acceleration.
1. When the brake is applied to the body and comes to rest after some time is an example of an object that is slowing down.
2. When a person accelerates the car and the velocity is increasing is an example of speeding up.
3. An object moves in a circular motion moving at a constant speed but changing direction,
4. Acceleration is the rate of change of velocity. If the change in the velocity is constant the acceleration is zero is an example of moving at a constant velocity with zero acceleration.
To learn more about acceleration, refer to the link;
https://brainly.com/question/2437624
#SPJ1
A partially inflated balloon is faded over the open end of a glass beaker that contains water the beaker is placed in an ice bath which cause the water and causes the balloon to the flea what are the correct designs for the heat and work changes to the beaker and balloon system
Answer:
a
Explanation:
Brass is made by melting a mixture which contain 67% by mass of copper and 33% by mass of zinc if no change in volume.Calculate the density of brass
Answer:
The density of brass is approximately 8,261.73 kg/m³
Explanation:
The percentage composition by mass of brass is given as follows;
The percentage by mass of copper = 67%
The percentage by mass of zinc = 33%
The density of copper, ρ₁ = 8.96 g/cm³
The density of zinc, ρ₂ = 7.133 g/cm³
Therefore, where we have, m = 100 g of brass, we have;
The mass of copper, m₁ = 67 g
The volume of copper, V₁ = m₁/ρ₁
∴ V₁ = 67 g/(8.96 g/cm³) ≈ 7.47767857 cm³
The volume of zinc, V₂ = m₂/ρ₂
∴ V₂ = 33 g/(7.133 g/cm³) ≈ 4.62638411 cm³
The volume of the brass, V = V₁ + V₂
V = 7.47767857 cm³ + 4.62638411 cm³ ≈ 12.104 cm³
The density of brass, ρ = m/V
∴ ρ = 100 g/(12.104 cm³) ≈ 8.26 g/cm³
The density of brass, ρ ≈ 8.26 g/cm³ = 8,261.73 kg/m³
What is the volume occupied by 15.0 moles of the gas at 280 K at a pressure of 100 Pa?
Consider. R=831 Pa m (mol-K)
Answer:
34902
Explanation:
Pv=nRt
v=nrt/p
subsitute
v=15*831*280/100
v=34902
is our body in thermal equilibrium with the environment ?
Answer:
The human body runs at a constant 37 ºC but the air around you at room temperature is about 20-25 ºC which means heat is constantly leaving your body to warm your surroundings and maintain thermal equilibrium. You don't lose much energy doing this however as air heats reasonably quickly
Explanation:
which of the following items has the most inertia while at rest
Answer:
wats the following items
Two parallel circular rings of radius R have their centres in the X axis separated by a distance L. If each ring carries a uniformly distributed charge Q,find the electric field at points along the X axis
Answer:
E" = Q/4πε₀√[(x² + R²)]³(x - (L - x)/√[(L - 2x)L/(x² + R²) + 1]³})
Explanation:
The electric field due to a charged ring of radius R at a distance x from the center of the ring when the axis of the ring is located on the x - axis is
E = Qx/4πε₀[√(x² + R²)]³
Since the rings are separated by a distance L, the electric field at point x due to the second ring is E' = -Q(L - x)/4πε₀[√((L - x)² + R²)]³. It is negative since it points in the negative x - direction.
So, the resultant electric field at x is E" = E + E' = Qx/4πε₀[√(x² + R²)]³ + {-Q(L - x)/4πε₀[√((L - x)² + R²)]³}
E" = Qx/4πε₀√[(x² + R²)]³ - Q(L - x)/4πε₀√[((L - x)² + R²)]³
E" = Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[((L - x)² + R²)]³})
E" = Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[(L² - 2Lx + x² + R²)]³})
E" = Q/4πε₀(x/√[(x² + R²)]³ - (L - x)/√[(L - 2x)L + (x² + R²)]³})
E" = Q/4πε₀√[(x² + R²)]³(x - (L - x)/√[(L - 2x)L/(x² + R²) + 1]³})
So, the electric field at points along the x axis is
E" = Q/4πε₀√[(x² + R²)]³(x - {(L - x)/√[(L - 2x)L/(x² + R²) + 1]³})
when a car drives in a circle there must be ?
no net force axting on it
Answer:
I think none of above
Explanation:
hioe it's right answer
Behaviors in deer such as herding and male deer using antlers to compete for females increase the chances of successful reproduction.
True or False
Answer:
True
Explanation:
The reproductive success of any species is the capability to produce their offspring per breeding lifetime or event.
Most of the species have to attract their partners by their physical capability and build up so that the mother can choose her partner in order to breed the best kind of off spring.
In the context, in case of deer, the size of the their antlers as well as behavior in herding is considered as the best chances for a successful reproduction to compete among the males and find their breeding mate.
Thus the answer is TRUE.
QUESTION 30 A tennis ball moves back and forth 10 times in 5 sec. The frequency of its motion is
Answer:
so in 1 sec 2 times
so frequency = 2
Explanation: