Una empresa fabrica dos productos, X y Y. Cada cantidad del articulo X producida requiere dos horas de trabajo en una taladradora, y cada unidad del articulo Y, cinco horas de trabajo en la taladradora. La empresa tiene un máximo de 40 horas de trabajo para la taladradora en la semana. La expresión algebraica que modela esta situación es: 2x +5y<40. a)Graficar dicha expresión b) ¿Es posible fabricar 10 unidades del producto X y 5 unidades del producto Y ?Justificar

771.05 m³ is tge answer brudah !!

Answer:

49/87 = .56 = 56%

Step-by-step explanation:

Answer:

56%

Step-by-step explanation:

Answer:

(- 3, - 7 )

Step-by-step explanation:

Given the 2 equations

y = 4x + 5 → (1)

y = x - 4 → (2)

Substitute y = 4x + 5 into (2)

4x + 5 = x - 4 ( subtract x from both sides )

3x + 5 = - 4 ( subtract 5 from both sides )

3x = - 9 ( divide both sides by 3 )

x = - 3

Substitute x = - 3 into either of the 2 equations and evaluate for y

Substituting into (2)

y = x - 4 = - 3 - 4 = - 7

solution is (- 3, - 7 )

Answer:

20 girls

Step-by-step explanation:

boys : girls  : total

3           5        3+5 = 8

There are 32 students

32/8 = 4

Multiply each term by 4

boys : girls  : total

3*4       5*4     8*4

12        20         32

There are 20 girls

Answer: 20 girls

Step-by-step explanation:

So boys to girls is 3 to 5

It asks for girls in class

Suppose there were 8 people in class, 5/8 of the people would be girls

It states that 32 people are in the class, so do 32 x 5/8 to get 20 girls

Answer:

Right angle triangle

Acute

Step-by-step explanation

1 right angle/90 degrees

2 acute angles

Answer:

4 3/4 hours per week

Step-by-step explanation:

Answer:

28.32552

Step-by-step explanation:

39.331×0.72=28.32552

Answer:

$5.6

Step-by-step explanation:

Answer:

8*30/100= 2.4

so present cost = 8.0 - 2.4 = $ 5.6

Step-by-step explanation:

Answer:

In could be mean inches? otherwise there is not enough context to know sorry :/

Step-by-step explanation:

Answer:the answer is 90

Answer:

a) csc∅ = √53/2

b) cot ∅ = 15/√514

Step-by-step explanation:

a) The value of cot ∅ = -7/2

cos ∅ < 0

We note that cos(∅) is less than 0 in Quadrant II and III, and cot(∅) is less than 0 in the Quadrant II, therefore, we have;

∅ is in the Quadrant II

csc∅ = (√((-7)² + 2²))/2 =√53/2 ≈ 3.64

csc∅ = √53/2

b) cos∅ 15/17

∅ is in Quadrant IV

∴ cot ∅ = 15/(√(15² + 17²)) = 15/√514 ≈ 0.662

cot ∅ = 15/√514

Answer:

242

Step-by-step explanation:

Rule out anything above five from being the ones number as it wouldn't be possible to be doubled for the tens.

After that it is just trial and error putting 1,2,3,4 in the tens and following the word equation.

121 = doesn't equal 8

363= doesn't

484 = doesn't

thats leaves 242 which follows the pattern and equals 8

Answer:

1. The given equation is presented as follows;

[tex]3^{2 \cdot x - 1} = \dfrac{1}{9}[/tex]

The above equation can be rewritten as follows;

[tex]3^{2 \cdot x - 1} = 3^{-2}[/tex]...(1)

Therefore, taking logarithm to base 3 of both sides of the equation, the above equation can be rewritten without an exponent as follows;

[tex]log_3 \left (3^{2 \cdot x - 1} \right) =log_3\left(\dfrac{1}{9} \right) = log_3 \left( 3^{-2} \right)[/tex]...(2)

2. Inverse relationship of exponents is given as follows;

(1/a)ˣ = a⁻ˣ

Therefore, we have;

1/9 = 1/(3²) = (3²)⁻¹ = 3⁻²

Taking log of both sides of [tex]\left (3^{2 \cdot x - 1} = \dfrac{1}{9} = 3 ^{-2}\right)[/tex] gives;

[tex]log_3 \left (3^{2 \cdot x - 1} \right)= log_3 \left( 3^{-2} \right)[/tex]

From logarithm rules, we have;

From equation (2), we have;

[tex](2 \cdot x - 1) \cdot log_3 3 = -2 \cdot log_3 3[/tex]

Therefore, the equation can be simplified by dividing both sides by the common factor, [tex]log_3 3[/tex], as follows;

[tex]\dfrac{(2 \cdot x - 1) \cdot log_3 3 }{log_3 3} = \dfrac{-2 \cdot log_3 3}{log_3 3}[/tex]

Therefore, we get;

2·x - 1 = -2...(3)

3. Solving 2·x - 1 = -2, gives;

2·x - 1 = -2

2·x = -2 + 1 = -1

x = -1/2 = -0.5

x = -0.5

EQUATION 3

The given equation is presented as follows;

[tex]125^{x - 1} = 5^x[/tex]

1. By the property of exponents, we have;

[tex]\left(a^b \right)^x = a^{b \times x}[/tex]

125 = 5³

Therefore, we get;

[tex]125^{x - 1}= \left(5^3\right)^{x - 1} = 5^{3\times (x - 1)} = 5^{(3\times x - 3)}[/tex]

[tex]125^{x - 1}= 5^{(3\times x - 3)}[/tex]

2. Given that we can rewrite the given equation as follows;

[tex]125^{x - 1} = 5^{(3\times x - 3)} = 5^x[/tex]

Therefore;

[tex]5^{(3\times x - 3)} = 5^x[/tex]

Both sides of the equation are given in powers of 5, therefore, the appropriate base logarithm to use on both sides to rewrite the equation is logarithm to base 5

3. Using logarithm, by applying logarithm to both sides, we get;

[tex]log_5 \left (5^{(3\times x - 3)} \right) = log_5 \left(5^x \right)[/tex]

[tex](3\times x - 3) \cdot log_5 5 = x \cdot log_5 5[/tex]

Dividing both sides by log₅5 gives;

[tex]\dfrac{ (3\times x - 3) \cdot log_5 5}{log_5 5} = \dfrac{ x \cdot log_5 5}{log_5 5}[/tex]

∴ 3 × x - 3 = x

3 × x - x = 3

2·x = 3

x = 3/2 = 1.5

x = 1.5

Step-by-step explanation:

Answer to this equation:

4 3/4

Answer:

4.75

Step-by-step explanation:

This is what I got. have a nice day:)

Answer:

16 elements

0 elements

Step-by-step explanation:

U = { 1 , 2 , 3 , 4 , 5 , 6 , 7 , 8 , 9 , 10 , 11 , 12 , 13 , 14 , 15 , 16 , 17 }

Let sets A , B , and C be subsets of U , where:

A = { 2 , 3 , 5 , 6 , 7 }

B = { 1 , 3 , 9 , 10 , 11 , 14 }

C = { 5 , 9 , 12 , 13 , 15 }

(A U B U C) = elements in either A, or B or C

(A U B U C) = {1,2,3,5,6,7,9,10,11,12,13,14,15}

(A U B U C) n (A U B U C) = elements on both intersecting set ; this will contain the same set as (A U B U C) are the same.

Number of elements = 13

(A n B n C) = elements occurring in both A, B and C

(A n B n C) = {} = empty set

(A n B n C) n (A n B n C) = {} = 0

By simplifying the given expression, the expression [tex]\sqrt[3]{3}[/tex] * [tex]\sqrt[5]{3^6}[/tex] is equivalent to [tex]3^(23/15).[/tex]

To simplify the given expression,  combine the two radicals using the property of exponentiation.

First, simplify the expression inside the second radical:

√[5]{[tex]3^6[/tex]}

Since the index is 5,  rewrite the expression as:

[tex](3^6)^(1/5)[/tex]

Using the property of exponentiation, multiply the exponents:

[tex]3^(6/5)[/tex]

Now combine this result with the first radical:

[tex]3\sqrt3 * 3^(6/5)[/tex]

Since ∛3 can be written as [tex]3^(1/3)[/tex],  rewrite the expression as:

[tex]3^(1/3) * 3^(6/5)[/tex]

To multiply two numbers with the same base, add the exponents:

[tex]3^(1/3 + 6/5)[/tex]

To simplify further, we need a common denominator for the fractions:

[tex]3^(5/15 + 18/15)[/tex]

Combining the fractions:

[tex]3^(23/15)[/tex]

Therefore, the given expression is equivalent to [tex]3^(23/15).[/tex]

Learn more on equivalent on https://brainly.com/question/2972832

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Answer:

The Number of Zeroes In The Results is Always equal To the Powers of 10.

Step-by-step explanation:

Example:-

345*[tex]10^{2}[/tex] = 34500

345*[tex]10^{5}[/tex] = 34500000

345*[tex]10^{7}[/tex] = 3450000000

345*[tex]10^{8}[/tex] = 34500000000

(In the Above examples, There is All The Numbers of Zeroes In The Results is equal To the Powers of 10)

Answer:

A, y = 3x/2 - 12

Step-by-step explanation:

Use the equation y = mx + b.

m = 3/2

b = -12

y = 3x/2 - 12

Answer:

Here is your Answer

Step-by-step explanation:

Its A

A. Y = 3/2x - 12

Answer:

-54

Step-by-step explanation:

[tex]-6\sqrt{100} +\sqrt{36}[/tex]

-6 * 10 + 6

-60 + 6

= -54

100 = 50 *2

       = 25 * 2 * 2

       = 5 * 5 * 2 * 2

       = [tex]5^{2} *2^{2}[/tex]

 5 * 2 = 10

~~~~~~~~~~

36 = 6 * 6 = 3 * 3 * 2 * 2 = 3^2 ^ 2^2

3*2 = 6

Answer:

A

Step-by-step explanation:

third angle=180-(35+73)=180-108=72°

Answer: 2^-3 = 1/8

2^-1 = 1/2

you have to multiply 2^-3 by 4 to get to 2^-1

Step-by-step explanation:

Answer:

its option d

Step-by-step explanation:

hope it helps

Answer:

x = 30

Step-by-step explanation:

The 2 angles lie on a straight line and sum to 180° , then

x - 3 + 153 = 180

x + 150 = 180 ( subtract 150 from both sides )

x = 30

Answer:

x = 30

Step-by-step explanation:

180° = total

153° = part

180° - 153° = 27°

Then use the equation to find the value of x

(x - 3) = 27

(x + 3) = +3       Add 3 to both sides!

x = 30

Answer:

1) V

2) V

3) V

4) V

5) V

Step-by-step explanation:

Answer:

0.125

Step-by-step explanation

one eighth = 1/8

Divide the numerator by denominator and the answer is 0.125

Answer:

I expect the correct answer

_6

.

Answer:

6

Step-by-step explanation:

because if u minus 39 from 45 u get six and same for the others

Answer:

A.[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]

Step-by-step explanation:

We are given that

[tex]\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})[/tex]

We have to find the quotient.

[tex]\frac{6}{\sqrt[3]{9}}-3(\frac{\sqrt[3]{6}}{\sqrt[3]{9}})[/tex]

[tex]\frac{2\times 3}{\sqrt[3]{3^2}}-3(\frac{\sqrt[3]{3\times 2}}{\sqrt[3]{3^2}})[/tex]

[tex]2\times\frac{3}{3^{\frac{2}{3}}}-3(\frac{2^{\frac{1}{3}}\times 3^{\frac{1}{3}}}{3^{\frac{2}{3}}})[/tex]

Using the property

[tex](ab)^n=a^n\cdot b^n[/tex]

[tex]2\times 3^{1-\frac{2}{3}}-3(2^{\frac{1}{3}}\times 3^{\frac{1}{3}-\frac{2}{3}})[/tex]

Using the property

[tex]\frac{a^x}{a^y}=a^{x-y}[/tex]

[tex]2(3^{\frac{1}{3}})-3(2^{\frac{1}{3}}\times 3^{-\frac{1}{3}})[/tex]

[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{1-\frac{1}{3}}[/tex]

[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times 3^{\frac{2}{3}}[/tex]

[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{3^2}[/tex]

[tex]2(3^{\frac{1}{3}})-2^{\frac{1}{3}}\times \sqrt[3]{9}[/tex]

[tex]2(3^{\frac{1}{3}})-\sqrt[3]{2\times 9}[/tex]

[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]

Hence, the quotient of [tex]\frac{6-3(\sqrt[3]{6}}{\sqrt[3]{9}})[/tex] is given by

[tex]2(3^{\frac{1}{3}})-\sqrt[3]{18}[/tex]

Option A is correct.

Answer:

A

Step-by-step explanation:

3 (- 15 + 4) = -45 + 12

This is the answer

Hello,

We know that :

a * b = ab² - a²b

We know that : 2 * 3 = 6 but we want to try this formula.

We have :

a = 2 and b = 3

So :

2 * 3

= 2 * 3² - 2² * 3

= 2 * 9 - 4 * 3

= 18 - 12

= 6

It works :)