Una pastelería es famosa por dos de sus especialidades de pasteles: el Especial y el Supremo. El Especial requiere para su elaboración medio kilo de azúcar y 8 huevos, teniendo un precio de venta de $200. El Supremo necesita un kilo de azúcar y 8 huevos, teniendo un precio de venta de $270. En el almacén les quedaban 10 kilos de azúcar y 120 huevos.

Answers

Answer 1

Given statement solution is :-The ingredients available in the warehouse, a maximum of 15 "Special" cakes and 10 "Supreme" cakes can be made.

To determine how many cakes they can make of each specialty, we need to review the amount of ingredients available in the warehouse and then calculate how many cakes can be made with that amount.

Amount of ingredients in the warehouse:

Sugar: 10 kilos

Eggs: 120

For the "Special" cake:

It requires half a kilo of sugar per cake.

It requires 8 eggs per cake.

Sale price: $200 per cake.

To calculate how many "Special" cakes can be made, we divide the amount of sugar and eggs available in the store by the ingredients required per cake:

"Special" cakes that can be made:

Available sugar / Sugar required per cake = 10 kilos / 0.5 kilos = 20 cakes

Eggs Available / Eggs Required per Cake = 120 Eggs / 8 Eggs = 15 Cakes

Therefore, with the ingredients available in the store, a maximum of 15 "Special" cakes can be made.

For the "Supreme" cake:

It requires a kilo of sugar per cake.

It requires 8 eggs per cake.

Sale price: $270 per cake.

To calculate how many "Supreme" cakes can be made, we again divide the amount of sugar and eggs available in the store by the ingredients required per cake:

"Supreme" cakes that can be made:

Available sugar / Sugar required per cake = 10 kilos / 1 kilo = 10 cakes

Eggs Available / Eggs Required per Cake = 120 Eggs / 8 Eggs = 15 Cakes

Thus, with the ingredients available in the warehouse, a maximum of 10 "Supreme" cakes can be made.

In short, with the ingredients available in the warehouse, a maximum of 15 "Special" cakes and 10 "Supreme" cakes can be made.

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Related Questions

Need help with top problem. Maybe bottom too

Answers

1) The area of a circle circumscribed about a square is 307.7 cm².

2.a.) The angle ACB is 39 degrees.°.

2b.) The value of x is 5.42.

How to determine the area of a circle?

We shall find the radius to determine the area of a circle.

First,  find the side length of the square:

Since the perimeter of the square = 56 cm, then, each side of the square is 56 cm / 4 = 14 cm.

Next, find the diagonal of the square, using the Pythagorean theorem:

Diagonal = the diameter of the circumscribed circle.

Diagonal² = side length² + side length²

= 14 cm² + 14 cm²

= 196 cm² + 196 cm²

= 392 cm²

Take the square root of both sides:

Diagonal = √392 cm ≈ 19.80 cm (rounded to two decimal places)

Then, the radius of the circle which is half the diagonal:

Radius = Diagonal / 2 ≈ 19.80 cm / 2 ≈ 9.90 cm (rounded to two decimal places)

Finally, compute the area of the circle using the formula:

Area = π * Radius²

Area = 3.14 * (9.90 cm)²

Area ≈ 307.7 cm² (rounded to two decimal places)

Therefore, the area of the circle that is circumscribed about a square with a perimeter of 56 cm is 307.7 cm².

2. a) We use the property of angles in a circle to solve for angle ACB: an angle inscribed in a circle is half the measure of its intercepted arc.

Given that arc AB has a measure of 78°, we can find angle ACB as follows:

Angle ACB = 1/2 * arc AB

= 1/2 * 78°

= 39°

Therefore, the angle ACB is 39 degrees.

2b.) To solve for the value of x, we use the information that the angle ADB =  (3x - 12)⁴.

Given that angle ADB is (3x - 12)⁴, we can equate it to the measure of the intercepted arc AB, which is 78°:

(3x - 12)⁴ = 78

Solve the equation for x, by taking the fourth root of both sides:

∛∛((3x - 12)⁴) = ∛∛78

Simplify,

3x - 12 = ∛(78)

Isolate x by adding 12 to both sides:

3x - 12 + 12 = ∛(78) + 12

3x = ∛(78) + 12

Finally, divide both sides by 3:

x = (∛(78) + 12) / 3

x = (4.27 +12) / 3

x = 5.42

So, x is 5.42

Therefore,

1) The area of the circle is 154 cm².

2a.) Angle ACB is equal to 102°.

2b.) The value of x is 5.42

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