Unit 8: Right Triangles & Trigonometry Date: Bell: Homework 3: Trigonometry: Ratios & Finding Missing Sides

Unit 8: Right Triangles & Trigonometry Date: Bell: Homework 3: Trigonometry: Ratios & Finding

Answers

Answer 1

The missing sides are of the given triangle are of 26.69 units and 11.33 units.

Given that:One angle of a right angled triangle measures 67 degrees.Hypotenuse of that right angled triangle measures 29 units.To find:

Missing sides of the triangle.

Calculations:

The sine trigonometric ratio gives us ratio of perpendicular to hypotenuse from perspective of the considered angle.

Referring to the figure attached below,

[tex]sin(\angle ACB)= \dfrac{AB}{AC}\\\\sin(67^\circ) = \dfrac{AB}{29}\\\\0.9205 \times 29 = AB\\\\AB = 26.69\\[/tex]

Similarly,

[tex]cos(\angle ACB)= \dfrac{BC}{AC}\\\\cos(67^\circ) = \dfrac{BC}{29}\\\\0.3907 \times 29 = BC\\\\BC = 11.33\\[/tex]

Thus, the missing sides are of the given triangle are of 26.69 units and 11.33 units.

Learn more about right angled triangles here:

https://brainly.com/question/3770177

Unit 8: Right Triangles & Trigonometry Date: Bell: Homework 3: Trigonometry: Ratios & Finding

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Step-by-step explanation:

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Answers

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-------------

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Step-by-step explanation:

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