Use NAND operator to write; P or Q, and P -Q make an everyday implication sentence using only NAND

Answer:

money

Explanation:

for working for socializing with orher

Answer:

A.

the final keyword is used to denote constants. It can be used with variables, methods, and classes. Once any entity (variable, method or class) is declared final , it can be assigned only once.

B.

Static variables are declared in the same place as instance variables, but with the keyword 'static' before the data type. While instance variables hold values that are associated with an individual object, static variables' values are associated with the class as a whole.

Answer:

All of these.

PLZ MARK ME BRAINLIEST.

Answer:

removeDuplicates() function:-

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

        //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

Explanation:

Complete Code:-

//Create Linked List Class.

class LinkedList {

       //Create head pointer.

       static ListNode head;

       //define structure of ListNode.

       //it has int val(data) and pointer to ListNode i.e, next.

   static class ListNode {

       int val;

       ListNode next;

       //constructor to  create and initialize a node.

       ListNode(int d) {

               val = d;

           next = null;

       }

   }

//removeDuplicates() function removes duplicate elements form linked list.

   void removeDuplicates() {

       //declare 3 ListNode pointers ptr1,ptr2 and duplicate.

       //initially, all points to null.

       ListNode ptr1 = null, ptr2 = null, duplicate = null;

       //make ptr1 equals to head.

       ptr1 = head;

       //run while loop till ptr1 points to second last node.

       //pick elements one by one..

       while (ptr1 != null && ptr1.next != null)

       {

               // make ptr2 equals to ptr1.

               //or make ptr2 points to same node as ptr1.

           ptr2 = ptr1;

           //run second while loop to compare all elements with above selected element(ptr1->val).

           while (ptr2.next != null)

           {

              //if element pointed by ptr1 is same as element pointed by ptr2.next.

               //Then, we have found duplicate element.

               //Now , we have to remove this duplicate element.

               if (ptr1.val == ptr2.next.val)

               {

                  //make duplicate pointer points to node where ptr2.next points(duplicate node).

                       duplicate = ptr2.next;

                       //change links to remove duplicate node from linked list.

                       //make ptr2.next points to duplicate.next.

                   ptr2.next = duplicate.next;

               }

             //if element pointed by ptr1 is different from element pointed by ptr2.next.

               //then it is not duplicate element.

               //So, move ptr2 = ptr2.next.

               else

               {

                   ptr2 = ptr2.next;

               }

           }

           //move ptr1 = ptr1.next, after check duplicate elements for first node.

           //Now, we check duplicacy for second node and so on.

           //so, move ptr1  by one node.

           ptr1 = ptr1.next;

       }

   }

   //display() function prints linked list.

   void display(ListNode node)

   {

       //run while loop till last node.

       while (node != null)

       {

               //print node value of current node.

           System.out.print(node.val + " ");

           //move node pointer by one node.

           node = node.next;

       }

   }

   public static void main(String[] args) {

       //Create object of Linked List class.

       LinkedList list = new LinkedList();

       //first we create nodes and connect them to form a linked list.

       //Create Linked List 1-> 2-> 3-> 2-> 4-> 2-> 5-> 2.

       //Create a Node having node data = 1 and assign head pointer to it.

       //As head is listNode of static type. so, we call head pointer using class Name instead of object name.

       LinkedList.head = new ListNode(1);

       //Create a Node having node data = 2 and assign head.next to it.

       LinkedList.head.next = new ListNode(2);

       LinkedList.head.next.next = new ListNode(3);

       LinkedList.head.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next = new ListNode(4);

       LinkedList.head.next.next.next.next.next = new ListNode(2);

       LinkedList.head.next.next.next.next.next.next = new ListNode(5);

       LinkedList.head.next.next.next.next.next.next.next = new ListNode(2);

       //display linked list before Removing duplicates.

       System.out.println("Linked List before removing duplicates : ");

       list.display(head);

       //call removeDuplicates() function to remove duplicates from linked list.

       list.removeDuplicates();

       System.out.println("")

       //display linked list after Removing duplicates.

       System.out.println("Linked List after removing duplicates :  ");

       list.display(head);

   }

}

Output:-

Answer:

Explanation:

The following code is written in Java. It creates the Rainfall class with two constructors, one that passes the entire array of rainfall and another that initializes an array with 0.0 for all the months. Then the class contains a method to add rain to a specific month, as well as the three methods requested in the question. The method to add rain validates to make sure that no negative value was added. 8 Test cases were provided, and any methods can be called on any of the 8 objects.

class Brainly {

   public static void main(String[] args) {

       Rainfall rain1 = new Rainfall();

       Rainfall rain2 = new Rainfall();

       Rainfall rain3 = new Rainfall();

       Rainfall rain4 = new Rainfall();

       Rainfall rain5 = new Rainfall();

       Rainfall rain6 = new Rainfall();

       Rainfall rain7 = new Rainfall();

       Rainfall rain8 = new Rainfall();

   }

}

class Rainfall {

   double[] rainfall = {0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0, 0.0};

   public Rainfall(double[] rainfall) {

       this.rainfall = rainfall;

   }

   public Rainfall() {

   }

   public void addMonthRain(double rain, int month) {

       if (rain > 0) {

           rainfall[month-1] = rain;

       }

   }

   public double totalRainfall() {

       double total = 0;

       for (double rain: rainfall) {

           total += rain;

       }

       return total;

   }

   public double averageRainfall() {

       double average = totalRainfall() / 12;

       return average;

   }

   public double rainiestMonth() {

       double max = 0;

       for (double rain : rainfall) {

           if (rain > max) {

               max = rain;

           }

       }

       return max;

   }

}

Select All that apply

Answer:

These are the things that are would be appropriate in a post.

B. Checking your post for typos or grammatical errors.

C. Giving credit to the original author.

D. Including your own thoughts about the article.

Explanation:

The correct answer options B, C, and D" According to unofficial online or internet usage it is believed that sharing informative articles is a reasonable use of a website forum as much the credit goes back to the actual or original author. Also, it is believed that posts should be suitable for data analytics checked for typos and grammatical errors.

Answer:

Following are the responses to these questions:

Explanation:

It employs keywords to autonomously do work tasks. Users can type numbers directly into the formulas or use the following formulae, so any data the cells referenced provide would be used in the form.

For instance, this leadership involves accounting, and Excel is concerned with organizing and organizing numerical data. In this Equation, I can discover all its information in the data. This idea is simple me count the number many cells containing a number, and also the number of integers. It counts integers in any sorted number as well. As both financial analysts, it is helpful for the analysis of the data if we want to maintain the same number of neurons.

Answer:

kdkskskiisidiodoosooddodod

Answer:

it would have to be flow control which would be C.

Explanation:

Flow Control is restricts the ability for individuals to reveal information present in some part of the database. Hence, option C is correct.

The management of data flow between computers, devices, or network nodes is known as flow control. This allows the data to be processed at an effective rate. Data overflow, which occurs when a device receives too much data before it can handle it, results in data loss or retransmission.

A design concern at the data link layer is flow control. It is a method that typically monitors the correct data flow from sender to recipient. It is very important because it allows the transmitter to convey data or information at a very quick rate, which allows the receiver to receive it and process it.

The amount of data transmitted to the receiver side without any acknowledgement is dealt with by flow control.

Thus, option C is correct.

For more information about Flow Control, click here:

https://brainly.com/question/28271160

#SPJ5

Answer:

Read Technical Books. To improve your technical skills and knowledge, it's best to read technical books and journals. ...

Browse Online Tutorials. ...

Build-up online profile. ...

Learn new Tools. ...

Implement what you learned. ...

Enrich your skillset. ...

Try-out and Apply.

Answer:

C. log

Explanation:

The log is a sequence of log records, recording all the update activities in the database

hope this helps

Answer:

C. Log is the

answer

Explanation:

a sequence of log records recording all update activity in database

Answer:

b. 4B5B information bit rate is 80% of the total information plus overhead bit rate.

Explanation:

4B5B bit rate encoding means there is 80% of the bit rate which included all the information plus the overheads. There is 20% of lack in bit rate due to encoding code words which converts data into smaller bits.

Answer: 52

Explanation:

Following the information given in the question, we are informed that a process needs 103 KB of memory in order to run and that the system on which it is to run uses paging with 2KB pages, then the number of frames in memory that are needed will be:

= 103/2

= 51.5

= 52 approximately

Therefore, 52 frames in memory are needed.

Answer:

Explanation:

Marketing your product directly over the internet can lead to much greater profits and there are many options that you can choose from in order to target the correct audience. Unfortunately, doing so does require marketing knowledge and is basically like growing a business. If you were to use intermediaries they already have the knowledge necessary to market your product but will take a percentage of the profits, which will ultimately limit your gains. Since Gray London is a race car driver, I am assumming that he does not have any prior technological expertise or marketing expertise, therefore I would recommend using intermediaries.

Answer:

The default return data type in function is int

Answer: Option (b)

Explanation:

The default return data type in a function is int. In other words commonly if it is not explicitly mentioned the default return data type of a function by the compiler will be of an integer data type.

If the user does not mention a return data type or parameter type, then C programming language will inevitably make it an int.

mark me brainlist

Answer:

The program in Python is as follows:

def ASCIIsum(str1,str2):

   asciisum1 = 0;    asciisum2 = 0

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

   if asciisum1 > asciisum2:

       return True

   else:

       return False

str1 = input("Enter first string: ")

str2 = input("Enter second string: ")

if ASCIIsum(str1,str2) == True:

   print(str1,"has a higher ASCII value")

else:

   print(str2,"has a higher ASCII value")

Explanation:

This defines the function

def ASCIIsum(str1,str2):

This initializes the ascii sum of both strings to 0

   asciisum1 = 0;    asciisum2 = 0

This iterates through the characters of str1 and add up the ascii values of each character

   for chr in str1:

       asciisum1 += (ord(chr) - 96)

This iterates through the characters of str2 and add up the ascii values of each character

   for chr in str2:

       asciisum2 += (ord(chr) - 96)

This returns true if the first string has a greater ascii value

   if asciisum1 > asciisum2:

       return True

This returns false if the second string has a greater ascii value

   else:

       return False

The main begins here

This gets input for first string

str1 = input("Enter first string: ")

This gets input for second string

str2 = input("Enter second string: ")

If the returned value is True

if ASCIIsum(str1,str2) == True:

Then str1 has a greater ascii value

   print(str1,"has a higher ASCII value")

If otherwise

else:

Then str2 has a greater ascii value

   print(str2,"has a higher ASCII value")

Answer:

The use of twisted pair cable ( category 5e/6 ) to connect the computers on each register and also the use of switches to connect each register to the server

Explanation:

The local area network ( LAN ) solution  that will be used to interconnect all the POS  registers is ; The use of twisted pair cable ( category 5e/6 ) to connect the computers on each register and also the use of switches to connect each register to the server .  

This is because category 5e/6 twisted pair cable has a data rate transfer of up to 10 Mbps and it is best used for LAN connections

while The function of the three switches is to connect each cash register to the the central server been used .

attached below is a schematic representation

Answer:

yes when rating ads you should only consider your personal feelings on the ad

Answer:

Hence the code is given as follows,

import java.util.Scanner;

public class LabProgram {

   public static String createAcronym(String userPhrase){

       String result = "";

       String splits[] = userPhrase.split(" ");

       for(int i = 0;i<splits.length;i++){

           if(splits[i].charAt(0)>='A' && splits[i].charAt(0)<='Z')

               result += splits[i].charAt(0);

       }

       return result;

   }

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       String s = scan.nextLine();

       System.out.println(createAcronym(s));

   }

}

Answer:

Here are the top benefits of using the latest leads automation tool for your personal pursuit, professional service, and other types of businesses.

Importance of Leads Automation Tool For LinkedIn

Unlike a traditional and non-automation approach, the best LinkedIn leads automation tool 2020 makes the process far more easier and efficient. It helps to win a good number of connections which would eventually make it easier for businesses to pitch their products and turn newly gained connections into potential customers.  

Moreover, businesses will also get more views and new messages in your LinkedIn inbox. The best leads automation tool free are especially useful when you have multiple LinkedIn accounts as you will get rid of time-consuming hectic tasks.

(c) 4

The function strpos() is a function in php that returns the position of the first occurrence of a particular substring in a string. Positions are counted from 0. The function receives two arguments. The first argument is the string from which the occurrence is to be checked. The second argument is the substring to be checked.

In this case, the string is "Get Well Soon!" while the substring is "Well"

Starting from 0, the substring "Well" can be found to begin at position 4 of the string "Get Well Soon!".

Therefore, the function strpos("Get Well Soon!", "Well") will return 4.

Then, with the echo statement, which is used for printing, value 4 will be printed as output of the code.

there are ten letters in the word, so for the first position we can choose out of 10 option.

no matter wich specific option we choose, we will have 9 letters left for the 2nd letter.

and 8 for the third place.

...

when we will have used up 9 of 10 letters, there will be only one option for the last place.

the number of possible decision-paths is therefore given by this expression:

10*9*8*7*6*5*4*3*2*1

wich is 3,628,800

there are quite a few ways to rearrange 10 letters

The sorting method which commands entries in a going to head predicated on each character without regard to space as well as punctuation, therefore there are 3628800 ways.

So, as [tex]\bold{ 10\times 9 \times 8.... \times 3 \times 2 \times 1 = 362,8800}[/tex] ways, we have such a total number of ways.

Learn more:

brainly.com/question/17276660

Answer: D. in addition to threats caused by malicious users, data can be lost by accident; for example: rats gnawing backup tapes

Explanation:

Data security is essential to protecting unwanted people from having access to ones data, malicious attack should also be prevented and unusual behavior should be monitored.

Data security has many facets such as threat nature, the nature of intruders, and cryptography. Furthermore, data integrity means that unauthorized users should not be able to modify any data without the owner's permission. Also, the statement that a common category of intruders are driven by determined attempts to make money; for example: bank programmers attempting to steal from the bank they work for is correct.

It should be no noted that rats gnawing backup tapes cannot prevent data loss. Therefore, the correct option is D

Answer:

caca

Explanation:

Answer:

Answer:

True

Explanation:

Spending plans serve as a tool to analyze program execution, an indicator of potential problems, and a predictor of future program performance.

Answer:

1. Wrong as per my knowledge, SQLite may be an electronic database software that stores data in relations(tables).

2. Wrong. Content provider interface controls the flow of knowledge from your android application to an external data storage location. Data storage is often in any database or maybe it'll be possible to store the info in an SQLite database also.

3.Right. SQLite uses one file to store data. It also creates a rollback file to backup the stored data/logs the transactions.

4. Wrong. The queries are almost like a traditional electronic database system, the queries are going to be answered as per the conditions given and should return a group of answers or one answer depending upon the info and sort of query used.

5. Right. A cursor helps to point to one entry within the database table. this may be very helpful in manipulating the present row of the query easily.