Use the coordinates of the labeled point to find the point-slope equation of
the line
-5
5
-5
(3.-5)
O A. y+ 5 = -3(x - 3)
B. y- 5 = -3(x+3)
C. y + 5 = 3(x+3)
O D. Y-3 - (x+5)

Answer:

An enzyme is a type of protein found within a cell. Enzymes create chemical reactions in the body. They actually speed up the rate of a chemical reaction to help support life.

Answer:

d. rehabilitation

Explanation:

Technology-associated rehabilitation is an ecological practice that allows a degraded area to be restored, rehabilitating all its degraded habitats. However, this restoration is not done naturally, but is caused by human intervention, which can cultivate the entire plant population in the area, even adding non-native species, which are selected to leave the productive area, but ecologically harmonious.

Answer:

B. Ancient sea life

Answer:

c

Explanation:

i dont care

Answer:

623 monomers

Explanation:

In a dehydration synthesis reaction, one water molecule is removed for every bond that is created between 2 monomers.

Linking 3 monomers together would remove 2 water molecules.

Following this pattern, the number of water molecules removed will always be one less than the number of monomers that were joined together.

So, if 622 water molecules were removed, then 623 monomers were joined together.

The answer is 623 monomers.

Answer:

The answer to this would be B

Explanation:

B:It can restock lakes depleted by recreational fishing

Answer:

The approximate size of the field mice population is 2500 individuals.

Explanation:

There are different methods to study population density. There are direct methods and indirect methods. Among these last ones, we might find the "Mark-Recapture technique".

The Mark-Recapture technique assumes that the population is closed,  during the sampling season there is no mortality nor natality, marks in the individual last the whole sampling season, and these do not affect the marked individual or their behavior. These marked individuals are randomly distributed in the population, and all the individuals have the same probability of being sampled.

The method consists of capturing a sample of individuals belonging to the population under study, in this case, the field mice population. After capturing the individuals, the researcher marks them and release them again. The third step is to sample again, capture a new amount of individuals, and count how many of them are marked. These marked individuals belong to the first sample. We can calculate the population size by using the Lincoln Index or any other index.

The Lincolns Index states that to obtain the population size, the research must follow the following procedure:

1) Take an initial sample with n1 number of individuals

2) Mark all the sampled individuals and release them

3) Take a second sample with n2 number of individuals

4) Count the number of marked individuals m

To estimate the total number of individuals in this population, N, the following equation must be considered:

N = (n1 x n2)/m

In the exposed example, this is:

• n1= 500 individuals in the first sample

• n2= 200 individuals in the second sample

• m= 40 individuals in the second sample that were previously marked  

             as they were part of the first sample    

N = (n1 x n2)/m = (500 x 200) / 40 = 2500 individuals

The approximate size of the field mice population is 2500 individuals.  

Answer:

tetanus

Explanation:

Tetanus causes a strong tonic contraction in skeletal muscles. This triggers a series of intermittent, progressive, and extremely painful muscle spasms. Tetanus is presented by patients who have stimulated a muscle too often, without allowing a moment of rest.

Answer:

3:1

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

Complete question:

Two species of closely related frogs are found in the same pond high in the Andes of South America. Both species only have teeth on the top jaw. One has small teeth for holding small live prey prior to swallowing. The other species has very large sharp teeth for injuring and killing large prey prior to biting off pieces of flesh for consumption. The above is an example of:

Answer:

Explanation:

Competition is an ecological and evolutive process very common in nature. Competition might be intra- or interspecific. Competition between different species in a community or ecosystem might be due to the same resource use, or the same territory, shelter, etcetera. When a resource is useful for two or more species, and limited, they compete to gain it.

The principle of competitive exclusion states that different species with the same requirements sharing the niche can not coexist indefinitely based on the same limited resource. When two competing species coexist, this is because of niche partitioning or niche differentiation.

Differentiation of effective niche is closely related to character displacement.

Character displacement is the result of interspecific competition, in which two or more species that live in the same habitat manage to avoid competition by developing different traits. Morphological divergence, or any adaptative trait development, fixated genetically, is the product of niche segregation. Species tend to differentiate morphologically in the presence of strong competitors. Traits divergence favors coexistence in the same place.

In the exposed example, both species live in the same pond. But to avoid competition and competitive exclusion, species developed different teeth sizes to feed on different prey items.  

Answer:

Pisces are known as amazingly imaginative, creative, empathetic, and kind, they can also be overly sentimental, impressionable, and closed off.

Explanation:

Hope this helps!

Answer:

aa

Explanation:

In genetics, a test cross is a cross performed to determine the unknown genotype of a phenotypically dominant organism. The test cross is done by crossing the unknown genotype with a homzygous recessive organism. The result of this cross tell us whether the unknown genotype is heterozygous or homzygous dominant.

According to this question, a test cross was conducted involving a pure breeding plant with a plant suspected to be heterozygous (Aa). Based on the explanation of a test cross above, the genotype of the pure-breeding plant will be "aa". Note; it must be recessive.

Answer:

c) peat is not a fossil fuel because it has biologic origins, making it biofuel

Explanation:

Peat is soil/ turf

Answer:

yes

Explanation:

Because science &biology have a connection

Answer:

Concentric contraction.

Explanation:

Concentric contraction is a type of contraction that the muscles in arms experiencing when an individual lifting 24 bottles of water up the stairs. A concentric contraction is a type of muscle activation that creates tension on your muscle as it shortens. As your muscle shortens, it produces enough force to move an object in the upward direction. In weight training we can easily see concentric movement.

Answer:

a. The maternal copy of UBE3A is expressed and the paternal copy is silenced.

Explanation:

When UBE3A chromosome is in neurons, paternal allele is silent and maternal allele is expressed in process of genomic imprinting. In some cases UBE3A is expressed from both paternal and maternal chromosomes. The paternal chromosome is blue whereas maternal chromosome is magenta.

Answer:

Answer:

The correct answer is: automaticity.

Explanation:

Cardiac muscle has several properties. These properties are: automaticity (given by the pacemaker cells), conductivity (meaning that each cardiac cell can transmit the electrical impulse to the next cardiac cells), contractility (like other types of muscles, cardiac muscle cells can contract), and irritability (each cell can contract on its own without the external stimuli).

Cardiac pacemaker cells are the ones with the capacity to initiate the electrical impulse by creating rhythmic impulses called action potentials, and thus directly regulating heart rate.

Pacemaker cells are located in the sinoatrial (SA) node, in the upper portion of the right atrial wall. In these cells, depolarization of the cardiac muscle begins, and the electrical impulse generated by it is transmitted to the atrioventricular (AV) node, the His bundle and then the Purkinje fibers - this order of events is necessary for the correct contraction of the heart to occur. All of these structures are part of the Conduction System of the heart.

Answer:

where is option I can't see

Answer:

where's the options for this question?

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there is no option?? ?

Answer:

Suppose that we have a given function f(x)

The average rate of change of the function between two values x₁ and x₂ is given by:

[tex]r = \frac{f(x_2) - f(x_1)}{x_2 - x_1}[/tex]

a) We want to find the average (rate) of change on the size of population from 1985 to 1995.

We have that:

f(1985) = 750

f(1995) = 1500

Then we have:

[tex]r = \frac{1500 - 750}{1995 - 1985} = 750/10 = 75[/tex]

This means that the population of trees increases, in average, at a rate of 75 trees per year.

b) What is the density of trees each year that they were counted?

This will be equal to the quotient between the number of trees and the area.

1985: number of trees = 750 pines

         area = 250 ha

Then the density is:

D(1985) = (750 pines)/(250 ha) = 3 pines/ha

So 1985, there were 3 pines per hectare.

1990: number of trees = 1250 pines

         area = 250 ha

Then the density is:

D(1990) = (1250 pines)/(250 ha) = 5 pines/ha

1995: number of trees = 1500 pines

         area = 250 ha

The density is:

D(1995) = (1500 pines)/(250 ha) = 6 pines/ha

3) now we want to get the average change between 1985 and 1995 in the density, this will be:

[tex]r = \frac{D(1995) - D(1885)}{1995 - 1985} = \frac{6 pines/ha - 3pines/ha}{10} = 0.3 pines/ha[/tex]

So, on average, each year the number of pines per hectare increases by 0.3

Answer:

Oxygen is carried by blood to all the cells of the body in the form of haemoglobin.​

Explanation:

Oxygen is carried in the blood in two forms:

(1) dissolved in plasma and red blood cells water (about 2% of the total)

(2) reversibly bound to haemoglobin (about 98% of the total).

Haemoglobin is a protein in the red blood cells and carries oxygen around our bodies. At the same time, carbon dioxide that is dissolved in the blood comes out of the capillaries back into the air sacs, ready to be breathed out.

Answer:

D

Explanation:

Answer:

ex. where you are standing now

a perspective that one uses to determine if an object is moving.

Explanation:

in physics, a frame of reference, or reference frame, is a perspective that one uses to determine if an object is moving. ... For example, when you see a ball roll down a street, you can tell the ball is moving because the frame of reference is the streets, whatever may be on the side of the roads, or the Earth.

wikipedia

Answer:

D. A silent variant near the 5' end of the TBX1 gene.

Explanation:

TBX1 gene is wild type human being. It gives instructions for making protein called T-box 1. It plays an important role in tissue formation and organs during embryonic development.

Answer:

A-B-C-D

Explanation:

PROPHASE; 1. chromosomes become thicker

2. nuclear membrane disintegrates

3. centrosome divide to form centrioles

4. centrioles move to the opposite polls of the cell

METAPHASE; 1. chromosomes get arranged at the equator

2. centrioles produce spindle fibre that attach to the middle of the chromosomes

ANAPHASE; 1. shortest stage of mitosis

2. spindles will pull apart each chromosomes to form chromatids

TELLOPHASE; 1.  each chromatid moves to opposite polls of the cell

2. nuclear membrane appears around both of them

3. the centrioles sill stop producing spindles

4. centrosomes will then form again

cytokinesis then divides by the cleavage furrow to form the two daughter cells

Answer:

Primary consumers

They eat the majority of prey

Answer:

1. Phosphatases hydrolyze key phosphorylated residues.

Explanation:

Receptor Tyrosine Kinases (RTKs) are high-affinity transmembrane protein receptors that bind to a wide variety of ligands (e.g., growth factors, cytokines, hormones). These receptors (RTKs) have a transmembrane domain and therefore these proteins act as membrane receptors, as well as exhibit catalytic activity. The intracellular C terminal region of RTKs contains catalytic domains responsible for both autophosphorylation and tyrosine phosphorylation of their protein substrates. Moreover, Protein Tyrosine Phosphatase (PTPs) are critical enzymes that remove phosphate groups from tyrosine residues in different substrates (including RTKs), thereby regulating key signaling pathways such as cell proliferation, cell differentiation, and cell-cell adhesion.