Use the initial term and the recursive formula to find an explicit formula for the sequence an. Write your answer in simplest form.

Answer:

correct ans is d

Step-by-step explanation:

click the photo to see process

Step-by-step explanation:

I hope this will help you

Answer:

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex] would ensure that at least one real root exists for this equation when solving for [tex]x[/tex].

Step-by-step explanation:

Apply the Pythagorean identity [tex]1 - \sin^{2}(x) = \cos^{2}(x)[/tex] to replace the cosine this equation with sine:

[tex](1 - \sin^{2}(x)) - (m^2 - 3)\, \sin(x) + 2\, m^2 - 3 = 0[/tex].

Multiply both sides by [tex](-1)[/tex] to obtain:

[tex]-1 + \sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 3 = 0[/tex].

[tex]\sin^{2}(x) + (m^2 - 3)\, \sin(x) - 2\, m^2 + 2 = 0[/tex].

If [tex]y = \sin(x)[/tex], then this equation would become a quadratic equation about [tex]y[/tex]:

[tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex].

However, [tex]-1 \le \sin(x) \le 1[/tex] for all real [tex]x[/tex].

Hence, the value of [tex]y[/tex] must be between [tex](-1)[/tex] and [tex]1[/tex] (inclusive) for the original equation to have a real root when solving for [tex]x[/tex].

Determinant of this quadratic equation about [tex]y[/tex]:

[tex]\begin{aligned} & b^{2} - 4\, a\, c \\ =\; & (m^{2} - 3)^{2} - 4 \cdot (-2\, m^{2} + 2) \\ =\; & m^{4} - 6\, m^{2} + 9 - (-8\, m^{2} + 8) \\ =\; & m^{4} - 6\, m^{2} + 9 + 8\, m^{2} - 8 \\ =\; & m^{4} + 2\, m^{2} + 1 \\ =\; &(m^2 + 1)^{2} \end{aligned}[/tex].

Hence, when solving for [tex]y[/tex], the roots of [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] in terms of [tex]m[/tex] would be:

[tex]\begin{aligned}y_1 &= \frac{-b + \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) + \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) + (m^{2} + 1)}{2} = 2\end{aligned}[/tex].

[tex]\begin{aligned}y_2 &= \frac{-b - \sqrt{b^{2} - 4\, a\, c}}{2\, a} \\ &= \frac{-(m^{2} - 3) - \sqrt{(m^{2} + 1)^{2}}}{2} \\ &= \frac{-(m^{2} - 3) - (m^{2} + 1)}{2} \\ &= \frac{-2\, m^{2} + 2}{2} = -m^{2} + 1\end{aligned}[/tex].

Since [tex]y = \sin(x)[/tex], it is necessary that [tex]-1 \le y \le 1[/tex] for the original solution to have a real root when solved for [tex]x[/tex].

The first solution, [tex]y_1[/tex], does not meet the requirements. On the other hand, simplifying [tex]-1 \le y_2 \le 1[/tex], [tex]-1 \le -m^{2} + 1 \le 1[/tex] gives:

[tex]-2 \le -m^{2} \le 0[/tex].

[tex]0 \le m^{2} \le 2[/tex].

[tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

In other words,  solving [tex]y^{2} + (m^2 - 3)\, y + (- 2\, m^2 + 2) = 0[/tex] for [tex]y[/tex] would give a real root between [tex]-1 \le y \le 1[/tex] if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

On the other hand, given that [tex]y = \sin(x)[/tex] for the [tex]x[/tex] in the original equation, solving that equation for [tex]x\![/tex] would give a real root if and only if [tex]-1 \le y \le 1[/tex].

Therefore, the original equation with [tex]x[/tex] as the unknown has a real root if and only if [tex]-\sqrt{2} \le m \le \sqrt{2}[/tex].

Answer:

Volume of paint required is 3.125 litres.

Step-by-step explanation:

It would be noted that each side walls would have the shape of a trapezium. So that the areas of each wall can be determined as:

wall 1 = [tex]\frac{1}{2}[/tex](a + b) h

         =  [tex]\frac{1}{2}[/tex](0.5 + 1.5)2

        = 2 [tex]m^{2}[/tex]

wall 2 = [tex]\frac{1}{2}[/tex](a + b) h

          = [tex]\frac{1}{2}[/tex](1 + 3)2

          = 4 [tex]m^{2}[/tex]

wall 3 = [tex]\frac{1}{2}[/tex](a + b) h

         =  [tex]\frac{1}{2}[/tex](0.5 + 1.5)2

        = 2 [tex]m^{2}[/tex]

wall 4 = [tex]\frac{1}{2}[/tex](a + b) h

          = [tex]\frac{1}{2}[/tex](1 + 3)2

          = 4 [tex]m^{2}[/tex]

Total area of the walls = 2 + 2 + 4 + 4

                            = 12 [tex]m^{2}[/tex]

Area of the bottom base = l x b

                          = 1 x 0.5

                          = 0.5 [tex]m^{2}[/tex]

Total area to be painted = 12 + 0.5

                           = 12.5 [tex]m^{2}[/tex]

But to paint one square meter of a gap surface, we need 0.25 litres of a green paint color. Thus, to paint 12.5 [tex]m^{2}[/tex] of the gap surface:

12.5 x 0.25 = 3.125

The litres of paint required is 3.125.

Answer:

A

Step-by-step explanation:

We have the equation:

[tex]\displaystyle \frac{3}{8}y=2+x[/tex]

And we want to determine whether or not this represents a direct proportion.

First, let's solve for y. Multiply both sides by 8/3:

[tex]\displaystyle y=\frac{16}{3}+\frac{8}{3}x[/tex]

Remember that direct proportions must pass through the origin point on a graph. In other words, their y-intercept or constant value is zero.

Since the constant value here is not zero (it is 16/3), the equation is not direct proportion.

Our answer is A.

9514 1404 393

Answer:

  (a)  y = 2/x

Step-by-step explanation:

The vertical and horizontal asymptotes are the axes, so there is neither a vertical nor a horizontal offset to the parent function y = 1/x. There is a vertical stretch by a factor of 2, so the describing function is ...

  y = 2/x

Answer:

you would divide an equation from the multiple and then you would simplify the equation for an answer

Answer:

(- 2, - [tex]\frac{1}{3}[/tex] )

Step-by-step explanation:

Given the 2 equations

2x + 3y + 5 = 0 → (1)

5x - 3y + 9 = 0 → (2)

Rearrange (1) expressing 3y in terms of x by subtracting 2x + 5 from both sides

3y = - 2x - 5

Substitute 3y = - 2x - 5 into (2)

5x - (- 2x - 5) + 9 = 0 ← distribute parenthesis on left side and simplify

5x + 2x + 5 + 9 = 0

7x + 14 = 0 ( subtract 14 from both sides )

7x = - 14 ( divide both sides by 7 )

x = - 2

Substitute x = - 2 into either of the 2 equations and solve for y

Substituting into (1)

2(- 2) + 3y + 5 = 0

- 4 + 3y + 5 = 0

1 + 3y = 0 ( subtract 1 from both sides )

3y = - 1 ( divide both sides by 3 )

y = - [tex]\frac{1}{3}[/tex]

solution is (- 2, - [tex]\frac{1}{3}[/tex] )

Answer:

i) 9xy

ii) 75

Step-by-step explanation:

i) add those factor

ii) get that factor

hope it helps

please mark as barinliest

Thankyou.. :)

Given:

Reese read twice as many pages Saturday than she read Sunday.

She read a total of 78 pages over the weekend.

To find:

The number of pages she read on Sunday.

Solution:

Let x be the number of pages she read on Sunday.

Reese read twice as many pages Saturday than she read Sunday. So, the number of pager she read on Saturday is 2x.

Total number of page she read over the weekend is:

[tex]Total=x+2x[/tex]

[tex]Total=3x[/tex]

She read a total of 78 pages over the weekend.

[tex]3x=78[/tex]

[tex]x=\dfrac{78}{3}[/tex]

[tex]x=26[/tex]

Therefore, Reese read 26 pages on Sunday.

Answer: b and c

a) 5x + 5 = -4x - 5

9x = - 10

x = -10/9

-

b) - 4x + 5 = -4x - 4

0x = -9 (no solution)

-

c) -4x + 5 = -4x - 5

0x = -10 (no solution)

-

d) 4x + 5 = -4x + 5

8x = 0

x = 0

-

hope it helps.

Also, I think that Brainly is an awesome app, but there's an app which is doing great work for me in maths, named Gauthmath. I will suggest it. Video concepts and answers from real tutors.

Answer:

A

Step-by-step explanation:

There are 270 minutes in 4.5 hrs.

divide that by 45, you get 6.

50*3^6 is 36,450

Hello,

If the question is simplify then

we suppose x not equal to 5 and x not equal to -5

[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\=\dfrac{(x-5)^2}{(x-5)(x+5)} \\\\=\dfrac{x-5}{x+5} \\\\[/tex]

else

if the question is to find the euclidian 's quotient then

[tex]\dfrac{x^2-10x+25}{(x-5)(x+5)} \\\\= 1 + \dfrac{-10x+30}{x^2-25} \\\\=1-\frac{10}{x+5} \\[/tex]

euclian's quotient is 1

remainder is -10/(x+5)

Answer:

270 & 30

Step-by-step explanation:

let the number is n,

the equation :

n× 1/9 n= 27(n +1/9 n)

1/9 n² = 27n + 3n

1/9 n² = 30n

1/9n²- 30n = 0

n(1/9n -30)= 0

n = 0 or

1/9n = 30 => n = 30×9 = 270

270 is a number,

the other : 270/9 = 30

Translate How is mathematical thinking established? How can we have mathematical thinking? in to Chinese.

数学思维是如何建立的？ 怎样才能有数学思维？

Answer:

24

Step-by-step explanation:

(3/6) 2 + 7 × 4 - 5

0.5 × 2 + 7 × 4 - 5

1 + 7 × 4 - 5

1 + 28 - 5

29 - 5

24

through my working i got to 41² is the hypotenuse.

21²+20²=c²

factor out the square

(21+20)²=c²

41²=c²

and 41² is 1681

Answer:

29 units

Step-by-step explanation:

i just took the quiz

Answer:

2 solutions so it can be inferred that it might be a quadratic

Step-by-step explanation:

Answer:

no solutions

Step-by-step explanation:

y = 0 and y = - 7 are horizontal parallel lines.

Since they are parallel, they never intersect and so have no solutions.

1. a = 68

b = 112

c = 68

2. a = 127

3. a = 35

b = 40

c = 35

d = 70

4. a = 20

b = 70

c = 20

d = 70

e = 110

5. a = 90

b = 90

c = 42

d = 48

e = 132

6. a = 70

b = 55

c = 25

Answer:

slope= difference in y ÷difference in x

=y-y1÷x-x1

=-3-(-1)÷-3-1

=-3+1÷-3-1

=-2÷-4

=1/2

Step-by-step explanation:

hope this is helpful

Y2 -Y1 ÷ X2-X1

-1 - 1 ÷ -3 - -3= 0.5 or 1/2

Answer:

Time = (30 ÷ 5) seconds

Step-by-step explanation:

It is moving up at the rate of 5 ft/s.

This means;

Distance moved ÷ time taken = 5 ft/s

Thus, for a distance of 30 ft above street level, the time taken will be calculated from

30 ÷ time taken = 5

Time to reach the given distance = 30 ÷ 5

In division sentence, it is composed of division symbol and equal to sign.

Hello,

Answer (1/2,-1/4)

[tex]8x^2-2x-1=0\\\\8x^2-4x+2x-1=0\\\\4x(2x-1)+2x-1=0\\\\(2x-1)(4x+1)=0\\\\sol=\{\dfrac{1}{2} ,-\dfrac{1}{4} \}\\[/tex]

Answer:  43.1 degrees (choice B)

==================================================

Work Shown:

Use the law of sines

sin(A)/a = sin(C)/c

sin(A)/20 = sin(82)/29

sin(A) = 20*sin(82)/29

sin(A) = 0.68294349

A = arcsin(0.68294349)

A = 43.074088

A = 43.1 degrees

Answer:

43.1°

Step-by-step explanation:

Hello, just finished the quiz and the correct answer is 43.1 degrees.

Answer:

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Step-by-step explanation:

The given expression to us is ,

[tex]\implies \dfrac{\frac{ 3}{x-1} -4 }{ 2 -\frac{2}{x-1}}[/tex]

Now take the LCM as ( x - 1 ) and Simplify , we have ,

[tex]\implies \dfrac{\frac{ 3 -4(x-1) }{x-1} }{ \frac{2-2(2x-1)}{x-1}}[/tex]

Simplifying further , we get ,

[tex]\implies \dfrac{ -4x+7}{2(x-2) }[/tex]

Hence the second option is correct.

Answer:

[tex] \frac{ \frac{3}{x - 1} - 4}{2 - \frac{2}{x - 1} } \\ = \frac{ \frac{3 - 4(x - 1)}{x - 1} }{ \frac{2(x - 1)}{x - 1} } \\ = \frac{3 - 4x + 4}{2x - 2} \\ \frac{ - 4x + 7}{2(x - 1)} \\ option \: b \: is \: your \: answer \\ thank \: you[/tex]

Answer:

65 percent certain to get the job

Step-by-step explanation:

The given parameters are;

The chance that she gets the job if she receives a strong recommendation, P(J|S) = 80 percent = 0.8

The chance that she gets the job if she receives a moderately good recommendation, P(J|M) = 40 percent = 0.4

The chance that she gets the job if she receives a weak recommendation = 10 percent, P(J|W) = 0.1

The probability that the recommendation will be strong, P(S) = 0.7

The probability that the recommendation will be moderate, P(M) = 0.2

The probability that the recommendation will be weak, P(W) = 0.1

Therefore, the probability that she gets the job given any condition, is given as follows;

P(J) = P(J|S)×P(S) + P(J|M)×P(M) + P(J|W)×P(W)

∴ P(J) = 0.8 × 0.7 + 0.4×0.2 + 0.1×0.1 = 0.65

Therefore, she is 65 percent certain to get the job

Answer:

Step-by-step explanation:

I'm going to take a giant leap here and guess that you are looking for how old this mammal hide is. At least that's what I'm going to work out for you. Filling in the formula is relatively easy as long as we remember that the initial amount of hide was 100%:

[tex]37=100e^{-.0001t}[/tex] and begin by dividing both sides by 100 to get

[tex].37=e^{-.0001t}[/tex] In order to get that t down from its current position, we have to take the natural log of both sides. The reason we do natural log as opposed to common log is because the natural log will cancel out the e:

[tex]ln(.37)=ln(e^{-.0001t})[/tex] and again, because the log cancels out the e we have:

ln(.37) = -.0001t and divide both sides by -.0001 to get

t = 9942.5 years

Answer:

answer is 9943

Step-by-step explanation:

Answer:

13

Step-by-step explanation:

Calculate the length using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = (- 5, 4) and (x₂, y₂ ) = (7, - 1)

d = [tex]\sqrt{(7-(-5))^2+(-1-4)^2}[/tex]

   = [tex]\sqrt{(7+5)^2+(-5)^2}[/tex]

   = [tex]\sqrt{12^2+25}[/tex]

   = [tex]\sqrt{144+25}[/tex]

   = [tex]\sqrt{169}[/tex]

   = 13

Answer:

Not sure what you are asking.

Domain is all x values .

It can be stated in coordinates (x,y). X is the input. Y is output

It can be stated in Domain Notations such as {x | x ≥ 0}

Answer:

[tex]19-\frac{28}{n}[/tex] is the expression with the value of 15 when n = 7

Step-by-step explanation:

To find the expression whose value is 15, substitute the value of n = 7 in each given expression.

Expression 1:

[tex]43-5n[/tex]

Substitute the value of n & simplify,

[tex]43-5(7)[/tex]

[tex]43-35=8[/tex]

Since the value of the expression is 8 which is not equal 15.

Hence expression [tex]43-5n[/tex] does not have value of 15 when n = 7.

Expression 2:

[tex]3n-5[/tex]

Substituting the value of n & simplify,

[tex]3(7)-5[/tex]

[tex]21-5=16[/tex]

Since the value of the expression is 16 which is not equal 15.

Hence expression [tex]3n-5[/tex] does not have value of 15 when n = 7.

Expression 3:

[tex]6n-28[/tex]

Substituting the value of n & simplify,

[tex]6(7)-28[/tex]

[tex]42-28=14[/tex]

Since the value of the expression is 14 which is not equal 15.

Hence expression [tex]6n-28[/tex] does not have value of 15 when n = 7.

Expression 4:

[tex]19-\frac{28}{n}[/tex]

Substituting the value of n & simplify,

[tex]19-\frac{28}{7}[/tex]

[tex]19-4=15[/tex]

Since the value of the expression is 15 which is equal 15.

Hence expression [tex]19-\frac{28}{n}[/tex] has the value of 15 when n = 7.