Answer:
[tex]\mu =2.16[/tex] --- Mean
[tex]\sigma^2 = 1.4944[/tex] -- Variance
[tex]\sigma = 1.222[/tex] --- Standard deviation
Step-by-step explanation:
Given
[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.12} & {0.2} & {0.2} & {0.36} & {0.12} \ \end{array}[/tex]
Solving (a): The population mean
This is calculated as:
[tex]\mu = \sum x * P(x)[/tex]
So, we have:
[tex]\mu =0*0.12 + 1 * 0.2 + 2 * 0.2 + 3 * 0.36 + 4 * 0.12[/tex]
[tex]\mu =2.16[/tex]
Solving (b): The population variance
First, calculate:
[tex]E(x^2)[/tex] using:
[tex]E(x^2) = \sum x^2 * P(x)[/tex]
So, we have:
[tex]E(x^2) = 0^2*0.12 + 1^2 * 0.2 + 2^2 * 0.2 + 3^2 * 0.36 + 4^2 * 0.12[/tex]
[tex]E(x^2) =6.160[/tex]
So, the population variance is:
[tex]\sigma^2 = E(x^2) - \mu^2[/tex]
[tex]\sigma^2 = 6.16 - 2.160^2[/tex]
[tex]\sigma^2 = 6.160 - 4.6656[/tex]
[tex]\sigma^2 = 1.4944[/tex]
Solving (c): The population standard deviation
This is calculated as:
[tex]\sigma = \sqrt{\sigma^2}[/tex]
[tex]\sigma = \sqrt{1.4944}[/tex]
[tex]\sigma = 1.222[/tex]
Last softball season, Pamela had 46 hits, a combination of singles (1 base), doubles (2 bases), and triples (3 bases). These 46 hits totaled 66 bases, and she had 4 times as many singles as doubles. How many doubles did she have?
Answer:
She had 8 doubles.
Step-by-step explanation:
This question is solved by a system of equations.
I am going to say that:
x is the number of singles.
y is the number of doubles
z is the number of triples.
46 hits
This means that [tex]x + y + z = 46[/tex]
46 hits totaled 66 bases
This means that:
[tex]x + 2y + 3z = 66[/tex]
4 times as many singles as doubles
This means that [tex]x = 4y[/tex]
So
[tex]x + 2y + 3z = 66[/tex]
[tex]4y + 2y + 3z = 66[/tex]
[tex]6y + 3z = 66[/tex]
And
[tex]x + y + z = 46[/tex]
[tex]4y + y + z = 46[/tex]
[tex]5y + z = 46 \rightarrow z = 46 - 5y[/tex]
Then
[tex]6y + 3z = 66[/tex]
[tex]6y + 3(46 - 5y) = 66[/tex]
[tex]6y + 138 - 15y = 66[/tex]
[tex]9y = 72[/tex]
[tex]y = \frac{72}{9}[/tex]
[tex]y = 8[/tex]
She had 8 doubles.
Question 9 of 44 What is the measure of 0 ?
A. 2.5. radians
B. 4 radians
C. 5 radians
D. 2.5 Π radians
Answer:
the answer to your question is B. 4 radians
Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May , ). Hotel occupancy data for February in two consecutive years are as follows. Current Year Previous Year Occupied Rooms 1,400 1,309 Total Rooms 1,750 1,700 a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Let population proportion of rooms occupied for current year population proportion of rooms occupied for previous year - Select your answer - - Select your answer - b. What is the estimated proportion of hotel rooms occupied each year (to decimals)
Answer:
H1 : P1 - P2 = 0
H1 : P1 - P2 > 0
Step-by-step explanation:
The test to be performed on the given data is ; difference in proportion ;
P1 = proportion od rooms in current year
P2 = proportion of rooms
The null hypothesis ``, H0 : p1 - p2 (this onstage null hypothesis and it is the initial truth, representing the notion that no difference in proportion exists.
H1 : P1 - P2 = 0
The alternative hypothesis takes takes the side that there is an increase on proportion of rooms occupied :
H1 : P1 - P2 > 0
Factorize 5b2-11b+6=0
Answer:
5b^2-(5+6)b+6=0
5b^2-5b-6b+6=0
5b(b-1)-6(b-1)=0
(5b-6)(b-1)=0
either
(5b-1)=0
5b=1
b=1/5
or
b-1=0
b=1
Step-by-step explanation:
firstly find out the mid term factor i e in above qn 11 should be break down so that its multiple should be coefficient of b and constant and additiqn should be equals to 11 .so we find out 5 and 6
what is the answer to this equation4
5
+ v =
41
20
Answer:
4075
Step-by-step explanation:
How to solve and what is the answer
Answer:
5
Step-by-step explanation:
PLS HELP QUICK I WILL GIVE YOU BRAINLIEST:
Given that angle abc=70° and angle bcd=110°. Is it possible (consider all cases): That line AB intersects line CD?
Answer:
Given that angle abc = 70° and angle bcd = 110°. Is it possible (consider all cases): That line AB intersects line CD?
yes.Step-by-step explanation:
#CarryOnLearning
If a procedure meets all of the conditions of a binomial distribution except the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the xth trial is given by
P(x) = p(1−p)x−1
where p is the probability of success on any one trial. Subjects are randomly selected for a health survey. The probability that someone is a universal donor (with group O and type Rh negative blood) is 0.15. Find the probability that the first subject to be a universal blood donor is the fifth person selected.
Answer:
0.0783
Step-by-step explanation:
The probability of getting the first success on xtg trial ; this is a geometric distribution :
P(x) = p(1−p)^x−1
The probability of being a universal donor , p = 0.15
The probability of obtaining someone who is a universal donor on 5th trial will be :
P(5) = 0.15(1 - 0.15)^(5 - 1)
P(5) = 0.15(0.85)^4
P(5) = 0.15(0.52200625)
P(5) = 0.0783009375
P(5) = 0.0783
I need help with this word problem.
Answer:
$3.22 per square feet
Step-by-step explanation:
To solve, I usually set up an equation:
sq ft = 12 1/2 = 1
$ 40.21 x
Then, use cross multiplication.
(12 1/2)x=40.21
Divide both sides by 12 1/2 or 12.5
x = 3.2168
Round to the hundredths place [because we're dealing with money]
$3.22
I hope this helps!
Answer:
3.22 per sq ft
Step-by-step explanation:
Take the total cost and divide by the amount of tiles
40.21 / 12.5
3.2168 per sq ft
Rounding to the nearest cent
3.22 per sq ft
Suppose f(x,y,z) = x2 + y2 + z2 and W is the solid cylinder with height 7 and base radius 2 that is centered about the z-axis with its base at z = −2. Enter θ as theta.
A) As an iterated integral, ∭WfdV = ∫BA∫DC∫FE dzdrdθ with limits of integration.
B) Evaluate the integral.
In cylindrical coordinates, W is the set of points
W = {(r, θ, z) : 0 ≤ r ≤ 2 and 0 ≤ θ ≤ 2π and -2 ≤ z ≤ 5}
(A) Then the integral of f(x, y, z) over W is
[tex]\displaystyle\iiint_W(x^2+y^2+z^2)\,\mathrm dV = \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta[/tex]
(B)
[tex]\displaystyle \int_0^{2\pi}\int_0^2\int_{-2}^5r(r^2+z^2)\,\mathrm dz\,\mathrm dr\,\mathrm d\theta = 2\pi \int_0^2\int_{-2}^5(r^3+rz^2)\,\mathrm dz\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(zr^3+\frac13rz^3\right)\bigg|_{z=-2}^{z=5}\,\mathrm dr \\\\\\= 2\pi \int_0^2\left(\frac{133}3r+7r^3\right)\,\mathrm dr \\\\\\= 2\pi \left(\frac{133}6r^2+\frac74r^4\right)\bigg|_{r=0}^{r=2} \\\\\\= 2\pi \left(\frac{110}3\right) = \boxed{\frac{220\pi}3}[/tex]
AY
5
The slope of the graphed line is 2. Which formulas HELP PLEASEEEE
3
represent the line that is graphed? Check all that apply.
4
1(4,4)
3
(1/2)
Oy-1 = {(x-2)
Oy-2 = {(x - 1)
Oy-4 = (x - 4)
x
2 3 4 5
2
o flux) = { x + 1
3
47
4
f(x) = 2 x + 4
5
Answer:
y - 2 = 2/3 (x-1)
ORy - 4 = 2/3(x-4)
NOTE ;ALL WILL GIVE THE SAME RESULTStep-by-step explanation:
With this graph,the equation can be found on a straight line as the graph is .
So the formula is
[tex]y - y1 = m(x - x1)[/tex]
where your m is your gradient or slope as already said,the equation can be used by this formula (note;after finding your normal slope (not on a straight line ) firstly)
When you are done take any of the points connecting to the x axis and y axis directly as in (4,-4) or (2,1)
Let your first number be x1 and second y1 and place it in the formula .
NOTE: Y and x is constant and your general solution should be in the form;y = mx +cwhere m is still your normal slope.
What is the y-intercept of y = 3x-
2?
Answer:
-2
Step-by-step explanation:
y = mx + b
y = 3x - 2
y-intercept = b
A die is rolled nine times and the number of times that two shows on the upper face is counted. If this experiment is repeated many times, find the mean for the number of twos.
Answer:
[tex]E(x) = 1.5\\[/tex]
Step-by-step explanation:
Given
[tex]n = 9[/tex] -- number of rolls
Required
The mean of 2's
The distribution follows binomial distribution where:
[tex]X \to Binomial(n,p)[/tex]
In this case:
[tex]p= \frac{1}{6}[/tex] ---- the theoretical probability of rolling 2
So, the mean of 2's is calculated using:
[tex]E(x) = np[/tex]
[tex]E(x) = 9 * \frac{1}{6}[/tex]
[tex]E(x) = \frac{9}{6}[/tex]
Simplify
[tex]E(x) = \frac{3}{2}[/tex] or
[tex]E(x) = 1.5\\[/tex]
pls help me and answer it correctly:)
Answer:
the biggest frequency is 6
and the least frequency is 4
The maintenance department at the main campus of a large state university receives daily requests to replace fluorecent lightbulbs. The distribution of the number of daily requests is bell-shaped and has a mean of 54 and a standard deviation of 3. Using the 68-95-99.7 rule, what is the approximate percentage of lightbulb replacement requests numbering between 54 and 63?
Answer:
The approximate percentage of lightbulb replacement requests numbering between 54 and 63 is of 49.85%.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
Approximately 68% of the measures are within 1 standard deviation of the mean.
Approximately 95% of the measures are within 2 standard deviations of the mean.
Approximately 99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 54, standard deviation = 3.
What is the approximate percentage of lightbulb replacement requests numbering between 54 and 63?
63 = 54 + 3*3
So between the mean and 3 standard deviations above the mean.
The normal distribution is symmetric, which means that 50% of the values are below the mean and 50% are above.
Of those 50% above, 99.7% are below 63. So
0.5*0.997 = 0.4985
0.4985*100% = 49.85%
The approximate percentage of lightbulb replacement requests numbering between 54 and 63 is of 49.85%.
Find the quotient of the following
Answer:
you simply have to do ide the coefficients and subtract the power
Which description of the graph of the linear inequality y > 3x – 8 is correct?
Options :
A.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded below the line
B.The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded above the line.
C. The graph will be a solid line with a y-intercept of three and a slope of negative eight. The graph will be shaded below the line.
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
Answer:
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
Step-by-step explanation:
The equation y > 3x – 8
Interpreting as a linear relation :
y > ax + b
Where, a = slope ; b = intercept
a = 3 ; that is a slope value of 3
b = -8 ; that is an intercept value of - 8
Since the inequality is >, a dashed line is used (dashed like is used for > and <) ; since we a have a greater than sign, the graph will be shaded above the dashed line.
Answer: The answer is D on edu 2021
Step-by-step explanation:
D.The graph will be a dashed line with a y-intercept of negative eight and a slope of three. The graph will be shaded above the line
The cost of renting a car is $46/week plus $0.25/mile traveled during that week. An equation to represent the cost would be y = 46 + 0.25x, where x is the number of miles traveled.
what is your cost if you travel 59 miles
cost: 60.75
if your cost Is $66.00, how many miles were you charged for traveling?
miles: ?
you have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?
max miles: ?
Answer:
If your cost Is $66.00, how many miles were you charged for traveling?
y = cost = $66[tex]66=46+0.25x\\66-46=0.25x\\20=0.25x\\x=\frac{20}{0.25} =80[/tex]80 miles
You have a max of $100 to spend on a car rental. what would be the maximum number of miles you could Travel?
y = cost = $100[tex]100=46+0.25x\\100-46=0.25x\\54=0.25x\\x=\frac{54}{0.25} =216[/tex]216 miles
Gil wants to have $9,500 in 7 years. Use the present value formula to calculate how much he should invest now at 2% interest, compounded semiannually in order to reach his goal.
Answer:
9500 × 1.02^7
Step-by-step explanation:
9500 × 1.02^7
Calculate that
A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the speed of the dog to catch with the cat in 1 minute?
Answer:
[tex]3.8\:\mathrm{m/s}[/tex]
Step-by-step explanation:
Use the formula [tex]d=rt[/tex] (distance is equal to rate/speed multiplied by time) to solve this problem.
We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to [tex]d=3\cdot 60=180\text{ meters}[/tex].
To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover [tex]180+48=228[/tex] meters in one minute.
Therefore, we have:
[tex]228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}[/tex]
Answer:
[tex] \boxed{3.8 \: m/s} [/tex]
Explanation
The first step is to set the speed and the distance equal to the unknown rate of the dog.
3 m/s + 48 m = x m/60s.
Then substitute 60s in for both rates to get distance.
180m + 48m = x m/60
228m = 60x m
÷60 ÷60
3.8m = x m/s.
x = 3.8m/s
Question 1 of 10
Estimate the difference of the decimals below by rounding to the nearest
whole number. Enter your answer in the space provided.
46.327
-4.801
Answer:
Step-by-step explanation:
46.327=46 ( neaarest whole number)
-4.801=-5 (nearest whole number)
46-(-5)=46+5=51
PLEASE HELP!!! Choose the best graph that represents the linear equation:
6x = y + 8
Graph A
On a coordinate plane, a line goes through (negative 2, 4) and (0, negative 8).
Graph B
On a coordinate plane, a line goes through (0, negative 8) and (2, 4).
Graph C
On a coordinate plane, a line goes through (negative 2, negative 4) and (0, 8).
Graph D
On a coordinate plane, a line goes through (0, 8) and (2, negative 4).
a.
Graph A
c.
Graph C
b.
Graph B
d.
Graph D
Please select the best answer from the choices provided
A
B
C
D
Answer:
b.
Graph B
Step-by-step explanation:
We are given the following linear equation:
[tex]6x = y + 8[/tex]
When x = 0:
[tex]6(0) = y + 8[/tex]
[tex]y = -8[/tex]
Thus, the line goes through (0,-8).
When y = 4:
[tex]6x = y + 8[/tex]
[tex]6x = 4 + 8[/tex]
[tex]6x = 12[/tex]
[tex]x = \frac{12}{6} = 2[/tex]
So also through (2,4).
Thus means that the correct answer is given by Graph B.
A radioactive material is known to decay at a yearly rate proportional to the amount at each moment. There were 1000 grams of the material 10 years ago. There are 980 prams right now. What will be the amount of the material right after 20 years?
a. 10 ln 2/ln(1000/980)
b. 10^6/980
c. 980^3/10^6
d. 980^2/10^3
Answer:
Amount left is 941.95 g.
Step-by-step explanation:
initial amount = 1000 g
time = 10 years
amount left = 980 grams
Now
[tex]980 = 1000 e^{-\lambda t}\\\\e^{\lambda\times 10}= 1.02\\\\10 \lambda = ln 1.02\\\\\lambda = 1.98\times10^{-3} per year[/tex]
time t = 20 years
Let the amount is N.
[tex]980 = 1000 e^{-\lambda t}\\\\e^{\lambda\times 10}= 1.02\\\\10 \lambda = ln 1.02\\\\\lambda = 1.98\times10^{-3} per year\\N = 980 e^{- 1.98\times 10^{-3}\times 20}\\\\ln N = ln 980 - 0.0396\\\\ln N = 6.88 - 0.0396 = 6.86\\\\N = 941.95 g[/tex]
RESUELVE USANDO LAS PROPIEDADES DE LA POTENCIA
PLISSSSSSSSS CON PROCEDIMIENTOOOOOOO
Answer:
Tenemos dos propiedades de la potencia en este caso:
Para un numero real A:
[tex]A^0 = 1[/tex]
[tex](A^n)^m = A^{n*m}[/tex]
En este caso nuestra ecuación es:
[tex][ [(\frac{0.1234}{-3.2098})^4]^3]^0[/tex]
usando la segunda propiedad, podemos reescribir como:
[tex][ [(\frac{0.1234}{-3.2098})^4]^3]^0 = (\frac{0.1234}{-3.2098})^{4*3*0} = (\frac{0.1234}{-3.2098})^0[/tex]
Y acá tenemos un numero real a la potencia 0, sabemos que esto es igual a 1, entonces:
[tex](\frac{0.1234}{-3.2098})^0 = 1[/tex]
What is the next three-term of the geometric sequence? 60, 30, 15...?
Answer:
7.5
Step-by-step explanation:
it is feometeic progression
r=0.5
Mr. Alvarado bought a total of 20 pounds of grass seed at the nursery for $168. He paid $9 per pound for Kentucky blue grass and $6 per pound for Tall Fescue. Which system of equations can be used to find the amount x (in pounds) of Kentucky blue grass and the amount y (in pounds) of Tall Fescue Mr. Alvarado purchased?
Answer:
K+T=20
$9K + $6T = $168
K is the Kentucky blue grass in pounds
T is the Tall fescue in pounds
Step-by-step explanation:
You can start with the first equation. We don't know the exact amounts of each but we know that there was a total of 20 pounds, and there were 2 types of grass seeds, so we can get that the amount of pounds of Kentucky blue grass(K) and the pounds of Tal Fescue(T) has a sum of 20.
K + T = 20
For the second equation we know that there is a sum of $168 so we'll start with that. Then, we know he paid $9 per pound of K so $9* the value of K is the amount paid for Kentucky blue grass total. This can be represented as 9K. We do the same for T, 6T. Since the sum of the cost of $9T and $6K must be $168 we can write this as:
$9K + $6T = $168
SOMEONE HELP PLEASE! So for this problem the answer I got is $4000. Is that the correct or incorrect answer? Can someone please help me if it is the incorrect answer. Thank you for your time.
Answer:
You're correct
Step-by-step explanation:
I really don’t understand graphs
John runs a computer software store. Yesterday he counted 125 people who walked by the store, 58 of whom came into the store. Of the 58, only 21 bought something in the store. (Round your answers to two decimal places.)
(a) Estimate the probability that a person who walks by the store will enter the store.
(b) Estimate the probability that a person who walks into the store will buy something.
(c) Estimate the probability that a person who walks by the store will come in and buy something.
(d) Estimate the probability that a person who comes into the store will buy nothing.
Answer:
a) 0.46 = 46% probability that a person who walks by the store will enter the store.
b) 0.36 = 36% probability that a person who walks into the store will buy something.
c) 0.17 = 17% probability that a person who walks by the store will come in and buy something.
d) 0.64 = 64% probability that a person who comes into the store will buy nothing.
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
(a) Estimate the probability that a person who walks by the store will enter the store.
58 out of 125. So
[tex]p = \frac{58}{125} = 0.46[/tex]
0.46 = 46% probability that a person who walks by the store will enter the store.
(b) Estimate the probability that a person who walks into the store will buy something.
58 walked, 21 bought. So
[tex]p = \frac{21}{58} = 0.36[/tex]
0.36 = 36% probability that a person who walks into the store will buy something.
(c) Estimate the probability that a person who walks by the store will come in and buy something.
21 came in and bought out of 125 that walked by. So
[tex]p = \frac{21}{125} = 0.17[/tex]
0.17 = 17% probability that a person who walks by the store will come in and buy something.
(d) Estimate the probability that a person who comes into the store will buy nothing.
0.36 probability that a person buys something, so 1 - 0.36 = 0.64 = 64% probability that a person who comes into the store will buy nothing.
A bottle maker believes that 23% of his bottles are defective.If the bottle maker is accurate, what is the probability that the proportion of defective bottles in a sample of 602 bottles would differ from the population proportion by less than 4%? Round your answer to four decimal places.
Answer:
The appropriate answer is "0.9803".
Step-by-step explanation:
According to the question,
The probability of sample proportion differs from population proportion by les than 4% will be:
= [tex]P(-\frac{0.04}{\sqrt{\frac{0.23\times 0.77}{602} } }<z<\frac{0.04}{\sqrt{\frac{0.23\times 0.77}{602} } } )[/tex]
= [tex]P(-\frac{0.04}{\sqrt{\frac{0.1771}{602} } }<z<\frac{0.04}{\sqrt{\frac{0.1771}{602} } } )[/tex]
= [tex]P(-2.33<z<2.33)[/tex]
= [tex]0.9803[/tex]
