Use the shell method to write and evaluate the integral that gives the volume of the solid generated by revolving the plane region about the x-axis. x + y2 = 4 y 2 1 X 2 4

The sum of the decimal fraction equation is:

seventy-six hundredths

The equation we are given is sixteen hundredths plus six-tenths

Now, when we talk about the decimal hundredths. Hundredths after decimal points shows 1/100th part of a whole. It represents the place value of the digit that occurs two places after the decimal.

Thus:

sixteen hundredths = 16/100

Similarly, six-tenths = 6/10

Thus:

The sum is:

16/100 + 6/10

= (16 + 60)/100

= 76/100 or seventy-six hundredths

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AAS conguerence rule states that if two congruent triangles have any two pairs of corresponding angles that are equal and one pair of corresponding sides that are equal.

Triangles that are congruent have the same area since all of their matching angles and side lengths are the same.

You are aware that a triangle's three angles add up to 180 degrees. As a result, the third pair of angles is also equal if the first two pairs are (180° - sum of equal angles). Hence, if any two pairs of angles and one pair of corresponding sides are equal, two triangles are said to be congruent. It could be referred to as the AAS Congruence Rule.

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A, C, and D. The angles that have a measure of 180-x are angles that have a measure of 180 minus the value of x. In this case, x is equal to mz1, so the angles that have a measure of 180-x are √3, √5, and √10.

Angle is a mathematical concept that is used to measure the amount of rotation of a line or a plane around a point. An angle is typically measured in degrees, which is the unit of angular measurement. Angles are used in many different fields of mathematics, such as geometry, trigonometry, and calculus. In geometry, angles are used to measure the size of a triangle, the size of a circle, or the angle between two lines. In trigonometry, angles are used to solve problems involving the length of sides and the measure of an arc. In calculus, angles are used to measure the rate of change of a function.

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The Answer: The first step is Rearranging the Equation

v=9

v=-5

Step-by-step explanation:

STEP

1

:

Rearrange this Absolute Value Equation

Absolute value equalitiy entered

     4|-v+2|-3 = 25

Another term is moved / added to the right hand side.

     4|-v+2| = 28

STEP

2

:

Clear the Absolute Value Bars

Clear the absolute-value bars by splitting the equation into its two cases, one for the Positive case and the other for the Negative case.

The Absolute Value term is 4|-v+2|

For the Negative case we'll use -4(-v+2)

For the Positive case we'll use 4(-v+2)

STEP

3

:

Solve the Negative Case

     -4(-v+2) = 28

    Multiply

     4v-8 = 28

    Rearrange and Add up

     4v = 36

    Divide both sides by 4

     v = 9

STEP

4

:

Solve the Positive Case

     4(-v+2) = 28

    Multiply

     -4v+8 = 28

    Rearrange and Add up

     -4v = 20

    Divide both sides by 4

     -v = 5

    Multiply both sides by (-1)

     v = -5

    Which is the solution for the Positive Case

STEP

5

:

Wrap up the solution

v=9

v=-5

Answer:

To solve this equation, we will first simplify the left-hand side using the fact that the square root of a number squared is equal to the absolute value of that number.

So, we have:

| x - 4 | = 4 - x

We can now split this equation into two cases, depending on whether x - 4 is positive or negative:

Case 1: x - 4 ≥ 0

In this case, | x - 4 | = x - 4, so we have:

x - 4 = 4 - x

Simplifying this equation, we get:

2x = 8

x = 4

However, we must check this solution to make sure it satisfies the original equation. Plugging x = 4 back into the original equation, we get:

√(4 - 4)^2 = 4 - 4

√0 = 0

So, x = 4 is a valid solution.

Case 2: x - 4 < 0

In this case, | x - 4 | = -(x - 4), so we have:

-(x - 4) = 4 - x

Simplifying this equation, we get:

-2x + 8 = 4

-2x = -4

x = 2

Again, we must check this solution to make sure it satisfies the original equation. Plugging x = 2 back into the original equation, we get:

√(2 - 4)^2 = 4 - 2

√4 = 2

This is a valid solution.

Therefore, the equation has two solutions: x = 4 and x = 2.

Answer: Bro x = 4

Step-by-step explanation:

Answer:153

Step-by-step explanation:

Answer: 72°

Step-by-step explanation:

To find the interior angle of this shape, use the formula 180(n-2)/n, where n is the amount of sides. Plugging 5 in for the interior angle of a pentagon, you get 180(3)/5, or 108°.

Using the statement that PR intersects QS, we can see that triangle QOR is isosceles (to get this, look at triangle PQR, and note that because it has 2 equal side lengths, and its last length is not equivalent to the other 2 sides, it is isosceles). Solving for angle PRQ, we know one angle is 108°, and the other two are equal. The total angle in a triangle is 180°, so (180°-108°)/2 = 36° (angles QPR and PRQ).

Since the angle of R = 108°, we can find angle PRS as 108° - 36°, or 72°. Since triangles PQR and QRS are similar (share the same angles and side lengths), we can see that angle RQS and RSQ are both 36°.

Since ORS is a triangle, its angle total is 180°. Since we know the angles ORS and OSR (respectively) already as 72° and 36°, we can subtract these angles to find angle ROS. 180°-72°-36° = 72°

The weight becomes 1/4 of its original value when the distance is multiplied by 2.

According to the question, "the weight of a body above the surface of the earth is inversely proportional to the square of its distance from the center of the earth." We need to determine the effect on the weight when the distance is multiplied by 2.

Let w be the weight of a body, d be the distance from the center of the earth, and k be the constant of variation. According to the question,

w = k / d²

When the distance is multiplied by 2, the new distance is 2d. Therefore, the new weight is given by:

w' = k / (2d)²

w' = k / 4d²

w' = w / 4

Therefore, the weight becomes 1/4 of its original value when the distance is multiplied by 2.

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The equation of the circle is [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex].

Given:

Equation of the circle is [tex](x+3)^2+(y-9)^2=5^2[/tex]

Expand the equation

[tex](x+3)^2 = (x+3)(x+3) = x^2 + 3x + 3x + 9 = x^2 + 6x + 9[/tex]

[tex](y-9)^2 = (y-9)(y-9) = y^2 - 9y - 9y + 81 = y^2 - 18y + 81[/tex]

[tex]5^2 = 25[/tex]

Then, substitute the expanded expressions into the equation

[tex](x+3)^2+(y-9)^2=5^2\\(x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\[/tex]

Simplify and combine like terms

[tex](x^2 + 6x + 9) + (y^2 - 18y + 81) = 25\\x^2 + y^2 + 6x - 18y + 90 = 25[/tex]

Rearrange the equation so that one side is 0

[tex]x^2 + y^2 + 6x - 18y + 90 = 25\\x^2 + y^2 + 6x - 18y + 90 - 25 = 0\\x^2 + y^2 + 6x - 18y + 65 = 0[/tex]
Thus, the equation of a circle [tex](x+3)^2+(y-9)^2=5^2[/tex] can be rearranged using the distributive property to form [tex]x^2 + y^2 + 6x - 18y + 65 = 0[/tex], with one side equaling 0.

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The Variance Inflation Factor (VIF) measures the degree of correlation or the collinearity of the explanatory variables.

VIF quantifies how much each explanatory variable is correlated with a linear combination of the other variables in a multiple regression model. This can help identify variables that are redundant, irrelevant, or harmful to the model's accuracy. The VIF is calculated for each explanatory variable by dividing the variance of the regression coefficient estimates by the variance of the regression coefficient estimates when that variable is excluded from the model.

If the VIF is greater than 1, it indicates that the variance of the regression coefficient estimate for that variable is inflated by the presence of the other variables, which reduces the model's accuracy. Therefore, a VIF greater than 1 is considered to be an indication of collinearity or multicollinearity in the explanatory variables. The VIF measures the degree of correlation or the collinearity of the explanatory variables, and it can identify variables that are redundant, irrelevant, or harmful to the model's accuracy.

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Multiplication and division of regular numbers are the same as fractions and we will learn them with the multiplication and division of rational numbers worksheet.

To do the multiplication, first find the greatest common divisor of the numerator and the denominator. The factors are then grouped together so that the score equals one. Then multiply by the remaining factors. To divide, first rewrite the division as multiplication by the inverse of the denominator.

Cuemath's interactive math worksheets contain visual simulations to help your child visualize the concepts being taught, "see things as they really are, and reinforce learning from them". The Rational Numbers Multiplication and Division Worksheet follows a step-by-step learning process that helps students better understand concepts, identify errors, and eventually develop strategies for solving future problems.

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we can use the notation P(A) and apply the definition of probability: P(A) = P(B), P (A ∩ B), and P (A ∪ B) if we have the necessary information.

I believe you meant to say, "Venn diagram". A Venn diagram is a type of graphical representation used to illustrate relationships between sets or groups of objects, concepts, or ideas. It consists of a series of overlapping circles or other closed shapes, with each circle representing a set or group and the overlapping areas representing the relationships or intersections between them.

by the question.

Let A be the event that a student is a cast member of Seussical, and let B be the event that a student is a cast member of Wizard of Oz. Then, we can define the following:

A ∩ B: The event that a student is a cast member of both Seussical and Wizard of Oz.

A ∪ B: The event that a student is a cast member of either Seussical, Wizard of Oz, or both.

A': The event that a student is not a cast member of Seussical.

B': The event that a student is not a cast member of Wizard of Oz.

Based on the information given, we do not know how many students are in each of these events, but we can still make some general observations. For example:

If A and B have no students in common (i.e., A ∩ B = ∅), then the number of students in A ∪ B is equal to the sum of the number of students in A and the number of students in B.

If some students are in both A and B (i.e., A ∩ B is not empty), then the number of students in A ∪ B is equal to the sum of the number of students in A, the number of students in B, and the number of students in A ∩ B. In other words, some students are counted twice when we add up the number of students in A and the number of students in B, so we need to subtract the number of students in A ∩ B to avoid double-counting.

We do not know whether the events A and B are mutually exclusive (i.e., whether A ∩ B = ∅) or not. If they are mutually exclusive, then P(A ∩ B) = 0, and we can use the addition rule of probability to find P (A ∪ B) = P(A) + P(B). If they are not mutually exclusive, then we need to use the general addition rule of probability: P(A ∪ B) = P(A) + P(B) - P(A ∩ B).

Finally, if we want to find the probability that a student chosen at random is a cast member of Seussical,

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The coordinate of centroid of the triangle is (2, 8/3), the coordinate of the circumcenter is (-7/32, 121/24) and the coordinate of orthocenter is (2, 9/2)

a. To find the centroid of a triangle, we take the average of the x-coordinates and the average of the y-coordinates of the vertices. Therefore, the x-coordinate of the centroid is:

(x₁ + x₂ + x₃) / 3 = (-4 + 2 + 8) / 3 = 2

Similarly, the y-coordinate of the centroid is:

(y₁ + y₂ + y₃) / 3 = (0 + 8 + 0) / 3 = 8/3

So the coordinate of the centroid is (2, 8/3).

b. The circumcenter of a triangle is the point where the perpendicular bisectors of the sides of the triangle intersect. To find the circumcenter, we can find the equations of the perpendicular bisectors of any two sides of the triangle and solve for their intersection point.

Let's take the sides formed by vertices (-4, 0) and (2, 8), and vertices (-4, 0) and (8, 0). The midpoint of the first side is ((-4+2)/2, (0+8)/2) = (-1, 4), and the slope of the line passing through the two points is (8-0)/(2-(-4)) = 8/6 = 4/3. Therefore, the equation of the perpendicular bisector passing through (-1, 4) is:

y - 4 = (4/3)(x + 1)

Simplifying this equation, we get:

y = (4/3)x + 13/4

Similarly, the midpoint of the second side is ((-4+8)/2, (0+0)/2) = (2, 0), and the slope of the line passing through the two points is (8-0)/(2-8) = -8/6 = -4/3. Therefore, the equation of the perpendicular bisector passing through (2, 0) is:

y = -(4/3)(x - 2)

To find the intersection point of these two lines, we can set the equations equal to each other and solve for x:

(4/3)x + 13/4 = -(4/3)(x - 2)

x = -7/32

Substituting x = -7/32 into either of the equations, we get:

y = (4/3)(-7/32 + 1) + 4 = 121/24

So the coordinate of the circumcenter is (-7/32, 121/24).

c. The orthocenter of a triangle is the point where the altitudes of the triangle intersect. An altitude of a triangle is a line segment from a vertex of the triangle perpendicular to the opposite side.

Let's take vertex (-4, 0) and find the equation of the line passing through this vertex and perpendicular to the opposite side formed by vertices (2, 8) and (8, 0). The slope of the opposite side is (0-8)/(8-2) = -8/6 = -4/3, so the slope of the line we want is the negative reciprocal of this, which is 3/4. Therefore, the equation of the altitude passing through (-4, 0) is:

y - 0 = (3/4)(x + 4)

Simplifying this equation, we get:

y = (3/4)x + 3

Let's now take vertex (2, 8) and find the equation of the altitude passing through it. The slope of the opposite side formed by vertices (-4, 0) and (8, 0) is (0-0)/(8-(-4)) = 0, which means the altitude passing through (2, 8) is a vertical line passing through (2, 0). Therefore, the equation of this altitude is:

x = 2

Now we need to find the intersection point of these two altitudes. Substituting y = (3/4)x + 3 into the equation x = 2, we get:

y = 9/2

The coordinate of the orthocenter is (2, 9/2)

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The Verde River's discharge and sediment load determine how much eroded material it can move beyond a given site in 6 hours, or 1/4 of a day. We cannot accurately determine the amount of eroded material carried by the river without knowing these numbers.

The amount of water that flows past a specific place in a river per unit of time is known as its discharge. The amount of sediment (including eroded material) that a river carries is referred to as its sediment load.

Both of these numbers can fluctuate considerably based on a number of variables, including the time of year, regional geology, and weather patterns.

In order to precisely determine the amount of eroded debris carried by the Verde River past a specific point in 1/4, thus we need further information.

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Hence, AA"B"Ccoordinates "'s in green are: A" (0, 0), B" (-4, -5), and C" (1, -4).

An illustration of data or mathematical functions is a graph. It is a method for presenting numerical data in a way that is simple to comprehend and interpret. A set of axes, one for each variable being represented, and one or more plots or lines that reflect the data or function being graphed are the main components of a graph. There are many distinct graph kinds, each of which is appropriate for displaying various sorts of data, including line graphs, bar graphs, scatter plots, and pie charts.

given

The axes cannot be identified because they are not specified in the query.

The blue ABC bar graph is as follows:

Using the equation (x, y) (y, -x), rotate AABC 90 degrees clockwise by applying the following transformation to each point:

A(-3, 0) → A' (0, 3) (0, 3)

B(-2, 4) → B' (-4, -2) (-4, -2)

C(1, -1) → C' (1, -1) (1, -1)

The red A'B'C' coordinates are as follows: A' (0, 3), B' (-4, -2), and C' (1, -1).

We take the y-coordinate of each point and subtract 3 to translate AA'B'C' three units down:

A' (0, 3) → A" (0, 0) (0, 0)

B' (-4, -2) → B" (-4, -5) (-4, -5)

C' (1, -1) → C" (1, -4) (1, -4)

Hence, AA"B"Ccoordinates "'s in green are: A" (0, 0), B" (-4, -5), and C" (1, -4).

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The complete question is:-  

1. Label the axes.

2. Graph: A(-3, 0) B(-2, 4) C(1,-1) Draw ABC in blue.

3. Rotate AABC 90° clockwise to

create ▲A'B'C' in red. List the coordinates below:

Formula: (x, y) → (y, -x)

A(-3, 0) A' ()

B(-2, 4)→ B' ()

C(1, -1) C' ()

4. Translate AA'B'C' three units down to create ▲A"B"C" in green. What are the coordinates of AA"B"C"?

Christian's company charges $0.8 per mile than Samantha's.

In Mathematics and Geometry, the rate of change can be calculated by using the following mathematical equation (formula);

Rate of change, m = (Change in y-axis, Δy)/(Change in x-axis, Δx)

Rate of change, m = (y₂ - y₁)/(x₂ - x₁)

Next, we would determine the rate of change of the value of y with respect to the value of x for Christian's company;

Rate of change, m = (43.50 - 22.50)/(20 - 10)

Rate of change, m = 21/10

Rate of change, m = 2.1

Therefore, the difference between the charges by Christian's company and Samantha's company can be calculated as follows;

Difference in charges = 2.1 - 1.30

Difference in charges = $0.8.

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Given, X has a uniform distribution on the interval (-1,1]. We are to determine the incorrect statement among the following:

Statement 5: The variance of a uniform distribution is (b-a)^2/12. Here, a=-1 and b=1. Hence, Var(X) = (1-(-1))^2/12 = 1/3. This statement is correct .Therefore, the incorrect statement is P(X ≤ 0.5) = 0.5.

Statement 1: f(x) = 0.5 for -1 < x ≤ 1Statement 2: P(X ≤ 0.5) = 0.5Statement 3: P(X ≤ 1) = 1Statement 4: E[X] = 0Statement 5: Var(X) = 1/3Let's check each statement one by one:

Statement 1: The probability density function (PDF) of a uniform distribution is f(x) = 1/(b-a) for a < x ≤ b. Here, a=-1 and b=1. Hence, f(x) = 1/(1-(-1)) = 0.5 for -1 < x ≤ 1. This statement is correct.

Statement 2: The cumulative distribution function (CDF) of a uniform distribution is F(x) = (x-a)/(b-a) for a < x ≤ b. Here, a=-1 and b=1. Hence, [tex]P(X ≤ 0.5) = F(0.5) = (0.5-(-1))/(1-(-1)) = 0.75[/tex], which is not equal to 0.5. Therefore, this statement is incorrect.

Statement 3: P(X ≤ 1) = F(1) = (1-(-1))/(1-(-1)) = 1. This statement is correct.

Statement 4: The expected value of a uniform distribution is (a+b)/2. Here, a=-1 and b=1. Hence,[tex]E[X] = (-1+1)/2 = 0.[/tex] This statement is correct.

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If the school has population of 2,462, then approximately 1,784 students at the school wore their school shirt on Friday.

If 19 out of 26 students wore their school shirt on Friday, then the fraction of students who wore their school shirt is:

[tex]\frac{19}{26}[/tex]

We can use this fraction to estimate the number of students who wore their school shirt on Friday. If there are approximately 2,462 students in the school, then the estimated number of students who wore their school shirt on Friday is:

[tex](\frac{19}{26}) * 2,462 = 1,783.69[/tex]

Rounding this to the nearest whole number, we get an estimate of 1,784 students who wore their school shirt on Friday.

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The concentration of hydrogen ions in a liter of the sports drink is approximately 3.98 x 10^(-3) moles per liter.

The pH of a substance is a measure of its acidity or basicity and is defined as the negative logarithm (base 10) of the hydrogen ion concentration [H+]. The formula for pH is given as pH = -log[H+].

To find the concentration of hydrogen ions in a liter of a sports drink that has a pH of 2.4, we can use the formula pH = -log[H+]. Rearranging this formula, we get [H+] = 10^(-pH).

Substituting the given value of pH into this expression, we get [H+] = 10^(-2.4).

It's worth noting that the hydrogen ion concentration is related to the acidity of a solution; the higher the hydrogen ion concentration, the more acidic the solution. The pH scale ranges from 0 (most acidic) to 14 (most basic), with a pH of 7 being neutral. The sports drink in question has a relatively low pH, indicating that it is quite acidic.

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The order of events from least likely to most likely are as follows:

The reason for this order is because of the chances of each event occurring. Event D has the least chance of occurring because no numbers in the set have a value less than or equal to 0. Event A is the next least likely because only one number in the set is greater than 0, which is the number 1. Event C is the next least likely because only two numbers in the set are at least 2 (2 and 3). Event B is the next least likely, as there are only five even numbers in the set (2, 4, 6, 8, and 10). Events E, F, G, and H are the most likely to occur, because of the number of numbers that are divisible by 3, and 5, and are prime numbers.

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The number 2 is the first even counting number,4 is the second even number, 6 is the third even number, and so forth. the sum of the first 25th even counting numbers is 650.

Since we are given that the first even counting number is 2 and each subsequent even counting number can be obtained by adding 2 to the previous one. so  by using the formula for finding the 25th term of an arithmetic series  which :

an=a+(n-1)d, where the nth term d is a common difference and a is the first term so, the  25th term is 2 + (25-1)*2 = 2 + 48 = 50. Now for finding the sum of the first 25 even counting numbers, we use the formula which is Sn = n /2 * (a1 + an),  where Sn is the sum of the first n terms of the series, a1 is the first term, and an is the nth term. since in this  n=25, a1=2 and an=50, so  after substituting the  values we get  S25 = 25/2 * (2 + 50) = 25/2 * 52 = 650

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In conclusion, we can prove that[tex](A -B) U (A C)[/tex] is a superset of[tex]A - (B nC)[/tex] using both the choose-an-element method and the algebra of sets.

To answer this question, let's first draw two Venn diagrams to represent the sets A, B, and C. In the first Venn diagram, shade the region that represents[tex]A - (B nC)[/tex].

This is the region outside of the intersection of B and C and inside of A. In the second Venn diagram, shade the region that represents [tex](A -B) U (A C).[/tex] This is the union of the region outside of B and the region outside of C, both of which are inside of A. Based on these diagrams, we can make the conjecture that (A -B) U (A C) is a superset of A - (B nC).

To prove this conjecture, we can use the choose-an-element method. Let a be an element of A - (B nC). This means that a is in A, but not in B or C. Since a is in A, it is also in (A -B) U (A C), and therefore (A -B) U (A C) is a superset of A - (B n C).

We can also use the algebra of sets to prove this conjecture.[tex]A - (B n C) = (A -B) U (A -C) since A - (B n C)[/tex]is the union of the regions outside of B and outside of C, both of which are inside of A. This implies that (A -B) U (A C) is a superset of A - (B nC).

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The value of x that makes the average between 3.15 and x equal to 40 is 76.85.

In this problem, we are given two numbers, 3.15 and x, and told that the average between them is 40. We can set up an equation to solve for x as follows:

(3.15 + x) / 2 = 40

To find the average between 3.15 and x, we add the two numbers together and divide by 2, which gives us the equation above.

To solve for x, we can start by multiplying both sides of the equation by 2:

3.15 + x = 80

Next, we can subtract 3.15 from both sides of the equation:

x = 76.85

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Answer:

0% (0/40)

Step-by-step explanation:

I feel like this is a trick question. since chicken is not indicated on the graph, I believe chicken is nobodies favorite food

The integers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12 have been written on a chalkboard by Dayna. She then erased the integers from 1 through 6, as well as their multiplicative inverse $\mod{13}$.

We can find the multiplicative inverse of an integer { a modulo 13 } by using the extended Euclidean algorithm.The integers from 1 to 6 are 1, 2, 3, 4, 5, and 6.The multiplicative inverse of : 1 modulo 13 is 1, 2 modulo 13 is 7,  3 modulo 13 is 9, 4 modulo 13 is 10, 5 modulo 13 is 8, and 6 modulo 13 is 11.The only integer that Dayna does not erase is 12.

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The total volume of the sample is 0.0067 m³ and the density of the sample is 2753.73 kg/m³.

An ore sample weighs 18.5 N in air. When the sample is suspended by a light cord and totally immersed in water, the tension in the cord is 11.8 N. When the ore sample is immersed in water, the tension in the cord is given as 11.8 N.

Thus, the buoyancy force experienced by the ore sample is given by the difference between the weight of the sample in the air and the tension in the cord.

Buoyancy force experienced by the ore sample = Weight of the sample in the air - Tension in the cord

Buoyancy force experienced by the ore sample = (18.5 N) - (11.8 N)

Buoyancy force experienced by the ore sample = 6.7 N

Also, we know that the weight of the ore sample in air is equal to the weight of the ore sample when immersed in water.

Weight of the ore sample = Weight of the displaced water

Weight of the ore sample = Buoyancy force experienced by the ore sample

Weight of the ore sample = 6.7 N

The density of the ore sample

Density is given by the formula Density = Mass/Volume

Where Density is measured in kg/m³

Mass is measured in kg

Volume is measured in m³

Also, the density of water is given as 1000 kg/m³.

The density of the ore sample = Mass/Volume

Mass = Density x Volume

Volume of the ore sample can be obtained from volume of the displaced water.

Volume of the displaced water = Weight of the ore sample/Density of water

Volume of the displaced water = (6.7 N)/(1000 kg/m³)

Volume of the displaced water = 0.0067 m³

Density of the ore sample = (18.5 N)/(0.0067 m³)

Density of the ore sample = 2753.73 kg/m³

Therefore, 0.0067 m³ is the sample's total volume and 2753.73 kg/m³ is the density of the sample.

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Answer:

1. first, add the amount of people who cannot swim. they need swim lessons.

2.  add up the people in 5th grade who can swim and the people who cannot. same with the 4th graders.

4.  the students that cannot swim, add up the 5th and 6ths graders that cannot swim.

5. add up all of the SOHO swimmers.

6. subtracts SOHO swimmers from swim academy.

set up an equation like this for #7

total number of students that can swim/ total amount of 5th graders = x/100

use the fraction on the left and multiply it by 100.

same with number 8

Step-by-step explanation:

The statement "Ten cards are selected out of a 52 card deck without replacement and the number of Jacks is observed. This is an example of a Binomial Experiment" is false.

A binomial experiment is an experiment that is repeated multiple times with each repetition having only two potential outcomes. In a binomial experiment, the probability of success remains constant from trial to trial.

The criteria for a binomial experiment are as follows:

P(x) = (ⁿCₓ)(pˣ)(q^(n-x))

Where p is the probability of success, q is the probability of failure (q = 1 - p), and ⁿCₓ is the combination formula.

Therefore, the statement "Ten cards are selected out of a 52-card deck without replacement and the number of Jacks is observed. This is an example of a "Binomial Experiment" being false. This is because the probability of drawing a jack changes with each trial, as the deck's composition changes after each card is drawn.

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Answer:the triangles are similar to each other by AA rule and EF = 8.

Step-by-step explanation:

the triangles are similar to each other by AA rule and EF = 8.

this should help if wrong sorry im in middle school so