Using the Empirical Rule, approximate the following percentages for Parts A - E.
The distribution of weights of newborn babies in one region is bell-shaped with a mean of 3000 grams and standard deviation of 500 grams. For all questions below, show all relevant work.


Part A :Approximately, what percentage of newborn babies weigh more than 3000 grams?
Part B : Approximately, what percentage of newborn babies weigh more than 2000 grams?
Part C : Approximately, what percentage of newborn babies weigh less than 4000 grams?
Part D : Approximately, what percentage of newborn babies weigh between 2000 and 4000 grams?
Part E : What is the range of birth weights that would contain the middle 68% of newborn babies' weights?

Answers

Answer 1

Part A: Approximately 50% of newborn babies weigh more than 3000 grams. Part B: Approximately 84.13% of newborn babies weigh more than 2000 grams. Part C: Approximately 84.13% of newborn babies weigh less than 4000 grams. Part D: Approximately 68% of newborn babies weigh between 2000 and 4000 grams. Part E: The range of birth weights that would contain the middle 68% of newborn babies' weights is from 2500 grams to 3500 grams.

1: Calculate the Z-scores for the given weights using the formula: Z = (X - μ) / σ, where X is the value, μ is the mean, and σ is the standard deviation.

For Part A:

Z = (3000 - 3000) / 500 = 0

Using the Z-table, we find that the percentage of babies weighing more than 3000 grams is approximately 50%.

For Part B:

Z = (2000 - 3000) / 500 = -2

Using the Z-table, we find that the percentage of babies weighing more than 2000 grams is approximately 97.72%. Since we want the percentage of babies weighing more than 2000 grams, we subtract this value from 100% to get approximately 2.28%.

For Part C:

Z = (4000 - 3000) / 500 = 2

Using the Z-table, we find that the percentage of babies weighing less than 4000 grams is approximately 97.72%.

For Part D:

To find the percentage of babies weighing between 2000 and 4000 grams, we subtract the percentage of babies weighing more than 2000 grams from the percentage of babies weighing less than 4000 grams.

Approximately 97.72% - 2.28% = 95.44%

For Part E:

Since the Empirical Rule states that approximately 68% of the data falls within one standard deviation of the mean, we need to find the weights that correspond to the boundaries of this range.

The lower boundary would be the mean minus one standard deviation: 3000 - 500 = 2500 grams.

The upper boundary would be the mean plus one standard deviation: 3000 + 500 = 3500 grams.

Therefore, the range of birth weights that would contain the middle 68% of newborn babies' weights is from 2500 grams to 3500 grams.

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Related Questions

1
Select the correct answer.
The surface area of a cone is 250 square centimeters. The height of the cone is double the length of its radius.
What is the height of the cone to the nearest centimeter?
O A.
OB.
O C.
10 centimeters
15 centimeters
5 centimeters
OD. 20 centimeters
Reset
Next

Answers

Answer:

D. 20 centimeters

Step-by-step explanation:

Surface area of a cone = surface area of a circle = pi r^2

250 = pi r^2

[tex]r = \sqrt{ \frac{250}{2} } = 5 \sqrt{5} \: cm[/tex]

Because the height (h) of the cone is double the length of its radius

Then

h = 2r

[tex]h \: = 2 \times 5 \sqrt{5} = 10 \sqrt{5} = 22.36 \: cm[/tex]

So it'll equal approximate 20 cm

Which statement about rectangles is true?
1. Only some rectangles are parallelograms.
2. Parallelograms have exactly 1 pair of parallel sides.
3. So, only some rectangles have exactly 1 pair of parallel sides.
1. All rectangles are parallelograms.
2. Parallelograms have 2 pairs of parallel sides.
3. So, all rectangles have 2 pairs of parallel sides.
1. Only some rectangles are parallelograms.
2. Parallelograms have 2 pairs of parallel sides.
3. So, only some rectangles have 2 pairs of parallel sides.
1. All rectangles are parallelograms.
2. Parallelograms have exactly 1 pair of parallel sides.
3. So, all rectangles have exactly 1 pair of parallel sides.

Answers

The correct statement about rectangles is:

1. All rectangles are parallelograms.

2. Parallelograms have exactly 1 pair of parallel sides.

3. So, all rectangles have exactly 1 pair of parallel sides.

A rectangle is a type of parallelogram that has additional properties. By definition, a rectangle is a quadrilateral with four right angles. This means that opposite sides of a rectangle are parallel. Since all four sides of a rectangle are right angles, it follows that a rectangle has exactly 1 pair of parallel sides.

Option 1 states that only some rectangles are parallelograms, which is incorrect. All rectangles are parallelograms because they have opposite sides that are parallel.

Option 2 states that parallelograms have 2 pairs of parallel sides, which is also incorrect. Parallelograms have exactly 2 pairs of parallel sides, not 4. A rectangle is a special type of parallelogram that has additional properties such as all angles being right angles.

Option 3 states that only some rectangles have 2 pairs of parallel sides, which is incorrect. All rectangles have exactly 1 pair of parallel sides, not 2. Having 2 pairs of parallel sides would make a shape a parallelogram, not a rectangle.

Therefore, the correct statement is that all rectangles are parallelograms and have exactly 1 pair of parallel sides. 1,2,3 are correct.

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the drawing shows an isosceles triangle

40 degrees


can you find the size of a

Answers

Angle "a" in the given isosceles triangle is 40 degrees.

To find the size of angle "a" in the isosceles triangle with a 40-degree angle, we can use the properties of isosceles triangles. In an isosceles triangle, the two equal sides are opposite the two equal angles.

Since the given angle is 40 degrees, we know that the other two angles in the triangle are also equal. Let's call these angles "b" and "c." Therefore, we have:

b = c

Since the sum of the angles in a triangle is always 180 degrees, we can write the equation:

40 + b + c = 180

Since b = c, we can rewrite the equation as:

40 + b + b = 180

Combining like terms, we have:

2b + 40 = 180

Subtracting 40 from both sides, we get:

2b = 140

Dividing both sides by 2, we find:

b = 70

Therefore, both angles "b" and "c" are 70 degrees.

Now, we can find angle "a" by subtracting the sum of angles "b" and "c" from 180 degrees:

a = 180 - (b + c)

= 180 - (70 + 70)

= 180 - 140

= 40

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Point C has the same y-coordinate as point B and the distance between point B and point C is equal to
the distance between point C and the y-axis. Point A has the same x-coordinate as point C and the
distance between point A and point C is twice the distance between point B and point C.
What is one possible location of point A?
How many possible locations are there for point A?
12
A?

Answers

We can conclude that point A is located at the origin (0, 0).

There is only one possible location for point A is at the origin.

Let's revisit the given information to determine the possible location of point A.

Point C has the same y-coordinate as point B.

This means that the y-coordinate of point C is equal to the y-coordinate of point B.

The distance between point B and point C is equal to the distance between point C and the y-axis.

Let's assume the distance between point B and point C is represented by "d".

According to the information given, the distance between point C and the y-axis is also "d".

Point A has the same x-coordinate as point C.

This implies that the x-coordinate of point A is equal to the x-coordinate of point C.

The distance between point A and point C is twice the distance between point B and point C.

Let's assume the distance between point B and point C is represented by "d".

According to the information given, the distance between point A and point C is 2d.

Based on this information, we can analyze the relationships between the points:

Since the distance between point B and point C is equal to the distance between point C and the y-axis, we can infer that point B lies on the y-axis.

The x-coordinate of point B is 0.

As point C has the same y-coordinate as point B, the y-coordinate of point C is also determined to be the same as the y-coordinate of point B.

Since point A has the same x-coordinate as point C, the x-coordinate of point A will also be 0.

The distance between point A and point C is twice the distance between point B and point C.

As the distance between point B and point C is "d", the distance between point A and point C is 2d.

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How do I find GBA and show all the work

Answers

Answer:

Angle ACB = 44°

There are two ways to solve it. Both are right

Solution number 1

From triangle ABC

angle BAC = 180°-(102° +44°) = 36°

Because BG is parallel with AC

Then angle GBA = angle BAC = 34°

Another solution

The sum of angles in the shape AGBC = 360°

So angle GBC = 360 - (90 + 90 + 44 + 102) = 34°

how to draw the 6th term .

Answers

To draw the 6th term, represent it visually within the context of the pattern or sequence from which it is derived.

To draw the 6th term, we need to understand the context or pattern from which the term is derived.

Drawing the term usually involves representing the elements or characteristics of the pattern in a visual form.

Without specific information about the pattern, we can provide a general approach to drawing the 6th term.

Identify the Pattern:

Determine the sequence or pattern from which the 6th term is derived.

It could be a numerical sequence, a geometric pattern, or any other pattern.

For example, if the pattern is a number sequence of multiples of 3, the first few terms would be 3, 6, 9, 12, 15, and so on.

Visualize the Pattern: Based on the identified pattern, visualize how the elements change or progress from term to term.

This could involve drawing a diagram, a graph, or any visual representation that captures the pattern.

Consider using a coordinate grid, a number line, or any other suitable visual aid.

Locate the 6th Term:

Use the information from the pattern and the visualization to determine the specific position or value of the 6th term.

In our example of multiples of 3, the 6th term would be 18.

Draw the 6th Term: Finally, represent the 6th term in your chosen visual form.

This could mean marking the position on a number line, plotting a point on a graph, or incorporating the value into a diagram.

Note that the specific method of drawing the 6th term will depend on the nature of the pattern and the context in which it is given.

Providing more details about the pattern would allow for a more accurate and specific visual representation of the 6th term.

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help me please. identify the errors in the proposed proofs

Answers

The errors in the proposed statement to prove by contradiction that 3·√2 - 7 is an irrational number, is the option;

To apply the definition of rational, a and b must be integers

What is proving by contradiction?

Proving by contradiction is an indirect method of proving a fact or a reductio ad absurdum, which is a method of proving a statement by the assumption that the opposite of the statement is true, then showing that a contradiction is obtained from the assumption.

The definition of rational numbers are numbers that can be expressed in the form a/b, where a and b are integers

The assumption that 3·√2 - 7 is a rational number indicates that we get;

3·√2 - 7 = a/b, where a and b are integers

Therefore, the error in the method used to prove that 3·√2 - 7 is an irrational number is the option; To apply the definition of rational, a and b must be integers. This is so as the value 3·√2 - 7 is a real number, which is also an irrational number, thereby contradicting the supposition.

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which equation represents the slope intercept form of the line when the y intercept is (0,-6) and the slope is -5

Answers

The values into the slope-intercept form, we have y = -5x - 6

The slope-intercept form of a linear equation is given by:

y = mx + b

where 'm' represents the slope of the line, and 'b' represents the y-intercept.

In this case, the y-intercept is (0, -6), which means that the line crosses the y-axis at the point (0, -6).

The slope is given as -5.

Therefore, substituting the values into the slope-intercept form, we have:

y = -5x - 6

This equation represents the line with a y-intercept of (0, -6) and a slope of -5.

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NO LINKS!! URGENT HELP PLEASE!!

a. Discuss the association.

b. Predict the amount of disposable income for the year 2000.

c. The actual disposable income for 2000 was $8,128 billion. What does this tell you about your model?​

Answers

Answer:

a) See below.

b) $911 billion

c) See below.

Step-by-step explanation:

 

Linear regression is a statistical technique used to model the relationship between a dependent variable and one or more independent variables by fitting a linear equation to the observed data.

It estimates the slope and y-intercept of a straight line that minimizes the overall distance between the observed data points and the predicted values. The linear regression equation is y = ax + b.

Part a

The association between year and amount of disposable income is indicated by the linear regression equation y = ax + b.

The value of a is the slope of the linear regression line, and represents the average rate of change in disposable income per year. As a = 14.0545, it means that the disposable income increases by approximately $14.0545 billion dollars each year.  

As the value of r (correlation coefficient) is very close to +1, it indicates a very strong positive linear correlation between the year and disposable income. This suggests that as the years progress, the disposable income tends to increase.

Part b

Linear regression equation:

[tex]\boxed{y=14.05454545x-27198}[/tex]

To predict the amount of disposable income for the year 2000, we can substitute x = 2000 into the linear regression equation:

[tex]y = 14.05454545 \cdot 2000 - 27198[/tex]

[tex]y=28109.0909...-27198[/tex]

[tex]y=911.0909...[/tex]

[tex]y=911[/tex]

Therefore, the predicted amount of disposable income for the year 2000 is approximately $911 billion.

Part c

The predicted value of $911 billion for the year 2000 is significantly lower than the actual value of $8128 billion. This implies that the model is not accurately capturing the increasing trend in disposable income over time, leading to an underestimation of the income level in 2000. This suggests that the model may have limitations or inaccuracies when extrapolating beyond the range of the provided data. It indicates the need for caution and further analysis when using the model to make predictions outside of the given timeframe.

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