Answer:
48.6
Step-by-step explanation:
Given the equation for the line of best fit ; f(x) ≈ 1.8x − 5.4 ;
This equation is used to make prediction for any given value of x ; Here, we are to make prediction for when x = 30
f(x) ≈ 1.8x − 5.4 ; we substitute into the equation, x = 30
f(30) = 1.8(30) - 5.4
f(30) = 54 - 5.4 = 48.6
Prediction at x = 30 is 48.6
Suppose a quadratic equation is given as follows:
(k – 1)x² + x + 1 = 0
Select all values of k for which the above equation has two real and unequal roots
0
.25
0.5
0.75
1
1.25
1.5
1.75
Answer:
k>1.25
Step-by-step explanation:
The given quadratic equation is :
(k – 1)x² + x + 1 = 0
We need to find all values of k for which the above equation has two real and unequal roots.
For a quadratic equation ax²+bx+c=0, for real and unequal roots,
b²-4ac>0
Here, a = (k-1), b = 1 and c = 1
Put all the values,
1²-4×(k-1)1>0
1-4k+4>0
5-4k>0
k>1.25
S, k can take values more than 1.25. Hence, it can take values 1.5, 1.75.
i need help, this is for a final
Step-by-step explanation:
Since the two triangles are similar
Then the ratio of sides are equal
Then MK:ML =JH:JI
Sub in this and you will get x =64.1
Solve the solution as an ordered pair
X + 9 = y
X = 4y - 6
Answer:
-10, -1
Step-by-step explanation:
See Image below:)
Without using mathematical table or calculator simplify 3 4/9 ÷(5 1/3 _ 2 3/4) + 5 9/10
Answer:
[tex]{ \tt{3 \frac{4}{9} \div (5 \frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} }} \\ \\ = { \tt{ \frac{31}{9} \div ( \frac{31}{12} ) + \frac{59}{10} }} \\ \\ { \tt{ = \frac{4}{3} + \frac{59}{10} }} \\ \\ { \bf{ = \frac{217}{30} }} \\ \\ { \boxed{ \tt{answer : 7 \frac{7}{30} }}} \\ \\ { \underline{ \blue{ \tt{becker ⚜jnr}}}}[/tex]
Answer:
[tex]7 \frac{7}{30}[/tex]
Step-by-step explanation:
[tex]3 \frac{4}{9} \div ( 5\frac{1}{3} - 2 \frac{3}{4}) + 5 \frac{9}{10}\\\\\frac{31}{9} \div (\frac{16}{3} - \frac{11}{4} ) + \frac{59}{10} \\\\\\Solving \ using \ BODMAS\\\\First \ Solve \ expression \ inside \ Bracket \\\\\frac{31}{9} \div (\frac{(16 \times 4) - ( 11 \times 3)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div (\frac{64- 33)}{12}) + \frac{59}{10} \\\\\frac{31}{9} \div \frac{31}{12} + \frac{59}{10} \\\\\\ \\\\\\Next \ solve \ Dvision \\\\\frac{\frac{31}{9}}{\frac{31}{12}} + \frac{59}{10}\\\\[/tex]
[tex](\frac{31}{9}} \times {\frac{12}{31}) + \frac{59}{10}[/tex]
[tex]\frac{4}{3} + \frac{59}{10}\\\\ Now \ solve \ final \ expression \\\\\\\frac{(4 \times 10) + ( 59 \times 3)}{30}\\\\\frac{40 + 177}{30}\\\\\frac{217}{30}\\\\7 \frac{7}{30}[/tex]
Alice has a total of 12 dimes and nickels.She h as 2 more nickels than dimes. Write an equation
Answer:
Step-by-step explanation: She has 2 more nickels then dimes not 2 times more therefore answers B and D are incorrect. C is incorrect because it has that there are 2 more dimes than nickels. A is correct because it says that there are c dimes, and then c +2 nickels.
I need help with this pls help and write the Correct answer
An item was marked down 64% from its original price, x. The amount discounted was $30. Which equation can be
used to find the original price?
0.64(x) = 30
0.64(30) = x
30 +0.64 = x
x + 0.064 = 30
Answer:
0.64(x) = 30
Step-by-step explanation:
Hope that's correct.
What is the equivalent recursive definition for an = 12+ (n - 1)3?
A. a1 = 3, An = An-1 + 12
B. a1 = 12, An = 30n-1
C. a1 = 12, Un = On-1 +3
D. a1 = n, an= 1201-1+3
Answer:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
Step-by-step explanation:
Given
[tex]A_n =12+(n-1)3[/tex]
Required
Write as recursive
We have:
[tex]A_n =12+(n-1)3[/tex]
Open bracket
[tex]A_n =12+3n-3[/tex]
[tex]A_n =12-3+3n[/tex]
[tex]A_n =9+3n[/tex]
Calculate few terms
[tex]A_1 =9+3*1 = 9 + 3 = 12[/tex]
[tex]A_2 =9+3*2 = 9 + 6 = 15[/tex]
[tex]A_3 =9+3*3 = 9 + 9 = 18[/tex]
The above shows that the rule is to add 3.
So, we have:
[tex]A_1 = 12[/tex]
[tex]A_n = A_{n-1} + 3[/tex]
If the length of EG is 22, find the length of a EQ
Answer:
A. 11
Step-by-step explanation:
EQ is half of EG
so 22/2 = 11
the sumof 8pq and -17 pq is
Answer:
= -9pq
Step-by-step explanation:
=8pq + (-17pq)
=8pq-17pq
= -9pq
What is m∠CDE? pls help
Answer:
68
Step-by-step explanation:
∠ACB = ∠DCE
= 180-92/2
=44
∠CDE = 180 - 44 / 2
68
find the derivative
f (x ) = (x-5)^2 (3-x)^2
Given:
The function is
[tex]f(x)=(x-5)^2(3-x)^2[/tex]
To find:
The derivative of the given function.
Solution:
Chain rule of differentiation:
[tex][f(g(x))]'=f'(g(x))g'(x)[/tex]
Product rule of differentiation:
[tex][f(x)g(x)]'=f(x)g'(x)+g(x)f'(x)[/tex]
We have,
[tex]f(x)=(x-5)^2(3-x)^2[/tex]
Differentiate with respect to x.
[tex]f'(x)=(x-5)^2\dfrac{d}{dx}(3-x)^2+(3-x)^2\dfrac{d}{dx}(x-5)^2[/tex]
[tex]f'(x)=(x-5)^2[2(3-x)(0-1)]+(3-x)^2[2(x-5)(1-0)][/tex]
[tex]f'(x)=(x^2-10x+25)(-6+2x)+(9-6x+x^2)(2x-10)[/tex]
[tex]f'(x)=(x^2)(-6)+(-10x)(-6)+(25)(-6)+(x^2)(2x)-10x(2x)+25(2x)+(9)(2x)+(-6x)(2x)+x^2(2x)+9(-10)+(-6x)(-10)+x^2(-10)[/tex]
On further simplification, we get
[tex]f'(x)=-6x^2+60x-150+2x^3-20x^2+50x+18x-12x^2+2x^3-90+60x-10x^2[/tex]
[tex]f'(x)=(2x^3+2x^3)+(-6x^2-20x^2-12x^2-10x^2)+(60x+50x+18x+60x)+(-90-150)[/tex]
[tex]f'(x)=4x^3-48x^2+188x-240[/tex]
Therefore, the derivative of the given function is [tex]f'(x)=4x^3-48x^2+188x-240[/tex].
Solve x2+y3 = 1 for x.
Answer:
x = 3 + 2y
Step-by-step explanation:
x - 2y = 3 ( Isolate x on the left side by adding 2y to both sides )
x = 3 + 2y
Step-by-step explanation:
Step 1: Add -y^3 to both sides.
y3+x2+−y3=1+−y3
x2=−y3+1
Step 2: Take square root.
x=√−y3+1 or x=−√−y3+1
Answer:
x=√−y3+1 or x=−√−y3+1
(I think this is right) (tell me if im right plz and thx)
please help. no links!
Answer:
I think B
Step-by-step explanation:
121.346° is more close to 121.3°, than 121.4°
if i'm wrong, the i'm sorry
If g(x)=x2 - 5 and 1(x)=7x-11, then what is the value of h(g(3)) ?
Answer:
The value of h(g(3)) is 17.
Step-by-step explanation:
We are given these following functions:
[tex]g(x) = x^2 - 5[/tex]
[tex]h(x) = 7x - 11[/tex]
h(g(3)) ?
[tex]h(g(x)) = h(x^2-5) = 7(x^2-5) - 11 = 7x^2 - 35 - 11 = 7x^2 - 46[/tex]
At x = 3
[tex]h(g(3)) = 7(3)^2 - 46 = 63 - 46 = 17[/tex].
The value of h(g(3)) is 17.
what is the mean mark of 847 ÷ 30?
Answer:
Step-by-step explanation:
x+y=13
2x-y=5
solve using any method
Answer:
x = 6 , y = 7
Step-by-step explanation:
solving by substitution method
x + y = 13
x = 13 - y equation (i)
2x - y = 5
substitute the value of x
2(13 - y) - y = 5
26 - 2y - y = 5
26 - 3y = 5
26 - 5 = 3y
21/3 = y
7 = y
substitute the value of y in equation (i)
x = 13 - y
x = 13 - 7
x = 6
Sam asks five of his friends in his accelerated ELA class.
He finds that the average number of books read for this sample was 6.
Give two reasons why this sample might not be representative of the population that Sam is
trying to study
Answer:
1) Sam only interviewed five people out of his entire ELA class, so he doesn't have a very wide demographic to study
2) All of these people were Sam's friends, so they might all have similar interests or only enjoy certain things, and that doesn't allow for a wide range of data collection
A store donated a percent of every sale to charity The total sales were $9,850 so the store donated $591. What percent of $9,850 was donated?
I need the answer asap!
Answer:
Well, 10% of 6640 is $664, and $332 is half of that, so 5%
Missing: $9850 $591.
Step-by-step explanation:
Answer:
espero ayudarte ..............
3. The simple interest on $6,000 for 4 years is $1,680. *
Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 450 newtons stretches a spring 30 centimeters. How much work is done in stretching the spring from 30 centimeters to 60 centimeters?
Answer:
The work done is 202.50Nm
Step-by-step explanation:
Given
[tex]F =450N[/tex]
[tex]x_1 = 30cm[/tex]
[tex]x_2 = 60cm[/tex]
Required
The work done
First, we calculate the spring constant (k)
[tex]F = kx_1[/tex]
[tex]450N = k *30cm[/tex]
[tex]k = \frac{450N}{30cm}[/tex]
[tex]k =15N/cm[/tex]
So:
[tex]F = kx_1[/tex]
[tex]F(x) = 15x[/tex]
The work done using Hooke's law is:
[tex]W =\int\limits^a_b {F(x)} \, dx[/tex]
This gives:
[tex]W =\int\limits^{60}_{30} {15x} \, dx[/tex]
Rewrite as:
[tex]W =15\int\limits^{60}_{30} {x} \, dx[/tex]
Integrate
[tex]W =15 \frac{x^2}{2}|\limits^{60}_{30}[/tex]
This gives:
[tex]W =15 *\frac{60^2 - 30^2}{2}[/tex]
[tex]W =15 *\frac{2700}{2}[/tex]
[tex]W =15 *1350[/tex]
[tex]W =20250N-cm[/tex]
Convert to Nm
[tex]W =\frac{20250Nm}{100}[/tex]
[tex]W =202.50Nm[/tex]
wich one is the answer
A stamp gets more expensive each year. It increases in value by 60 % each year. Wha
is the growth FACTOR?
9514 1404 393
Answer:
1.60
Step-by-step explanation:
The growth factor is 1 more than the growth rate:
1 + 60% = 1 + 0.60 = 1.60 = growth factor
3p(2p - 9) - 2p(-9 + p)
Answer:
4p² - 9p
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightDistributive Property
Algebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
3p(2p - 9) - 2p(-9 + p)
Step 2: Simplify
[Distributive Property] Distribute 3p: 6p² - 27p - 2p(-9 + p)[Distributive Property] Distribute -2p: 6p² - 27p + 18p - 2p²[Subtraction] Combine like terms (p²): 4p² - 27p + 18p[Addition] Combine like terms (p): 4p² - 9pHow would write 0.5, 0.65, 2.35, and 1.06 in expanded forms
Answer:
0 + 0.5, 0 + 0.6 + 0.05, 2 + 0.3 + 0.05, 1 + 0.06
Step-by-step explanation:
expanded form is just taking the number apart from ones to tenths to hundreds and so on, or from ones to tens to hundreds and then so on. then you just split it and put the numbers in added form.
What is the probability that a randomly selected day in the summer will be rainy if it’s cloudy?
Answer:
0.872
Step-by-step explanation:
Given that :
P(cloudy) = P(C) = 0.94
P(cloudy and rainy) = P(C n R) = 0.82
Probability that a given day will be rainy if it is cloudy ; this is a conditional probability problem:
Recall ; P(A|B) = P(AnB) / P(B)
P(R|C) = P(C n R) / P(C) = 0.82 / 0.94 = 0.872
A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these fish. Bass require 2 units of food A and 4 units of food B,
and trout require 5 units of food A and 2 units of food B. If the owner has 400 units of each food, find the maximum number of fish the lake can support.
fish
Need Help?
Read
Watch it
Answer:
133 fishes
Step-by-step explanation:
Units of food A = 400 units
Units of food B = 400 units
Fish Bass required 2 units of A and 4 units of B.
Fish Trout requires 5 units of A and 2 units of B.
i. For food A,
total units of food A required = 2 + 5
= 7 units
number of bass and trout that would consume food A = 2 x [tex]\frac{400}{7}[/tex]
= 114.3
number of bass and trout that would consume food A = 114
ii. For food B,
total units of food B required = 4 + 2
= 6 units
number of bass and trout that would consume food B = 2 x [tex]\frac{400}{6}[/tex]
= 133.3
number of bass and trout that would consume food B = 133
Thus, the maximum number of fish that the lake can support is 133.
Find the area of the sector in
terms of pi.
90°
24
Area = [?]
Enter
Step-by-step explanation:
area of a circle is r x r x pi
so one quarter of it us r x r x pi /4
I’ll give brainliest
Answer:
y = 1.19x
Step-by-step explanation:
y is the dependent variable (total cost)
x is the independent variable (number of pounds)
can someone answer this please
Answer:
x = 14
Step-by-step explanation:
Please note, the word trapezium is a synonym for the word trapezoid.
This problem gives one the area of the trapezoid, a well as one of the measurements of a base and the height of the figure. One is asked to find the length of the other base. This can be done by using the formula to find the area of a trapezoid. This formula is the following,
[tex]A=(h)(\frac{b_1+b_2}{2})[/tex]
Where (A) represents the area of a trapezoid, ([tex]b_1[/tex]) and ([tex]b_2[/tex]) represents the bases and (h) represents the height. Substitute in the given values and solve for the unknown base.
[tex]b_1=7\\h=6\\A=84[/tex]
[tex]A=(h)(\frac{b_1+b_2}{2})\\[/tex]
Substitute,
[tex]84=6(\frac{7+b_2}{2})\\[/tex]
Inverse operations,
[tex]84=6(\frac{7+b_2}{2})[/tex]
[tex]14=\frac{7+b_2}{2}[/tex]
[tex]28=7+b_2[/tex]
[tex]14=b_2[/tex]
