Using the following system of equations to help, what is the value of x-2y?
3x + 2y =48
2x +3y =12
Please help.

[tex]\boxed{\underline{\bf \: Answer}}[/tex]

[tex] \sf100 \times 20 + 30[/tex]

First multiply 100 & 20 together.

[tex] \sf= 2000 + 30[/tex]

Now add 2000 & 30. You'll get :-

[tex]= \boxed{ \bf 2030}[/tex]

____

Hope it helps.

RainbowSalt2222

[tex]\\ \rm\longmapsto 100\times 20+30[/tex]

[tex]\\ \rm\longmapsto (100\times 20)+30[/tex]

[tex]\\ \rm\longmapsto 2000+30[/tex]

[tex]\\ \rm\longmapsto 2030[/tex]

Given the data provided, it follows that the farmers must wait for 26 days before feeding the hay to cows.

The term half life is defined as the time taken for half of the original amount of the radioactive sample to remain.

Now we know that;

half life = 8 days

Original amount = No

Amount left after t days = 0.1No

time taken = t days

Hence;

0.693/8 = 2.303/t log (No/0.1No)

0.087 = 2.303/t

t = 2.303/0.087

t = 26 days

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[tex]\\ \sf\longmapsto 2x^2=10x[/tex]

[tex]\\ \sf\longmapsto x^2=\dfrac{10x}{2}[/tex]

[tex]\\ \sf\longmapsto x^2=5x[/tex]

[tex]\\ \sf\longmapsto x=5[/tex]

Answer:

the answers for x and y are both 12

Answer:

I think the answer is

x-16

since 16 is subtracted from x.

I hope this helps

Answer:

Step-by-step explanation:

When you're looking to find things like f(2) and f(4) and f(-3000), etc. the number inside the parenthesis is an x value. Look to the graph, find that x value, and locate the y value that corresponds to it. f(2) = -8. f(-1) = 4. f(1) = -4. See?

Answer:

does not exist

Step-by-step explanation:

that what i put hope it helps

Answer:

6 or 5 or 4...........

Step-by-step explanation:

Answer:

x=N :x<7

Step-by-step explanation:

123456

hope it's helpful

Answer:

in 8 days

Step-by-step explanation:

soln

given,

total days=120

department=15

we know,

120/15

=8

•°•8days are given to each department.

Answer:

plato screenshot!

Step-by-step explanation:

I don't personally know *how* to find the answers, but here's the screenshot of the suggested answer on Plato

Answer:

A B Slope of  C Slope of Line Through C

(−5,4) (−1,−1) −1.25 (1,2) 0.8

(−5,4) (−3, 5) 0.5 (−2, 1) −2

(−4, 1) (−3, 5) 4 (−2, −2) −0.25

(−5, −2) (−1, 1) 0.75 (−4, 3) −1.33

(−5, −2) (1, −1) 0.17 (−3, 1) −6

Step-by-step explanation:

that way you can copy and paste each one but Plato

Answer:

The total number of branches = total possibilities = the denominator of a probability.

So the second choice is correct.

Let me know if this helps!

Answer:

Step-by-step explanation: answer B (the denominator of a probability)

Answer:

Step-by-step explanation:

The cost is:

Percentage gain:

Answer:1.5

Step-by-step explanation:

Answer:

25x + 100 = 11300

25x = 11200

448 = x

Step-by-step explanation:

the certain number is 448

Answer:

[tex]\displaystyle x \approx 30.8[/tex]

Step-by-step explanation:

Note that the figure is a right triangle, and that we are given the length of the side adjacent to x and the hypotenuse of the triangle.

Therefore, we can use the cosine ratio. Recall that:

[tex]\displaystyle \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}}[/tex]

The adjacent side is 8.5 and the hypotenuse is 9.9. Therefore:

[tex]\displaystyle \cos x = \frac{8.5}{9.9}[/tex]

We can take the inverse cosine of both sides:

[tex]\displaystyle x = \cos^{-1} \frac{8.5}{9.9}[/tex]

Use a calculator. Hence:

[tex]\displaystyle x \approx 30.8[/tex]

Answer:

9.725%

Step-by-step explanation:

(1.0475)^2 =1.09725

one year 2 periods 4.75% per period

The volume of prism is,

⇒ V = 42.09 cubic units

To multiply means to add a number to itself a particular number of times. Multiplication can be viewed as a process of repeated addition.

Given that;

Base = 5.12

height = 4.11

Lenght = 4

Now, We can formulate;

The value of volume of prism is,

⇒ V = 1/2 (b x h) l

⇒ V = 1/2 (5.12 x 4.11) 4

⇒ V = 42.09 cubic units

Thus, The volume of prism is,

⇒ V = 42.09 cubic units

Learn more about the multiplication visit:

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Answer:

15/4

Step-by-step explanation:

sin60 =z/15

z=15sin60 =(15√3)/2

cos30 =b/z

b = zcos30 = (15√3)/2 * √3/2 = 45/4

a = 15-b = 15-45/4 = 15/4

The value of a is 15/4

A right triangle is defined as a triangle in which one angle is a right angle or two sides are perpendicular.

According to the given figure,

Here is a right triangle

Let, The hypotenuse = 15

perpendicular = z and base = 15 = a + b

⇒ sin60 = perpendicular/hypotenuse = z/15

⇒ z = 15sin60 = (15√3)/2

⇒ cos30 = base/hypotenuse = b/z

⇒ b = zcos30 = (15√3)/2 * √3/2 = 45/4

⇒ a + b = 15

Substitute the value of b in the above equation,

⇒ a = 15-b = 15-45/4 = 15/4

Hence, the value of a is 15/4.

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Answer:

85/100

Step-by-step explanation:

0.85 from a decimal is equal to 85/100 in fractions

Step-by-step explanation:

Which correlation coefficient indicates the data set with the strongest linear correlation?

0.66

The correlation coefficient indicates the data set with the strongest linear correlation is -0.83

"It measures the strength of the relationship between two relative variables."

"When the rate of change is constant between two variables then it is said to be linear correlation."

For given example,

We have been given correlation coefficients.

We need to find the correlation coefficient that indicates the data set with the strongest linear correlation.

We know, the correlation coefficient lies between -1 to 1.

So, the strongest linear correlation is indicated by a correlation coefficient of -1 or 1.

From given correlation coefficients,

-0.83 is close to -1.

Therefore, the correlation coefficient indicates the data set with the strongest linear correlation is -0.83

Learn more about linear correlation coefficient here:

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First check the characteristic solution. The characteristic equation to this DE is

r ² - r = r (r - 1) = 0

with roots r = 0 and r = 1, so the characteristic solution is

y (char.) = C₁ exp(0x) + C₂ exp(1x)

y (char.) = C₁ + C₂ exp(x)

For the particular solution, we try the ansatz

y (part.) = (ax + b) exp(x)

but exp(x) is already accounted for in the second term of y (char.), so we multiply each term here by x :

y (part.) = (ax ² + bx) exp(x)

Differentiate this twice and substitute the derivatives into the DE.

y' (part.) = (2ax + b) exp(x) + (ax ² + bx) exp(x)

… = (ax ² + (2a + b)x + b) exp(x)

y'' (part.) = (2ax + 2a + b) exp(x) + (ax ² + (2a + b)x + b) exp(x)

… = (ax ² + (4a + b)x + 2a + 2b) exp(x)

(ax ² + (4a + b)x + 2a + 2b) exp(x) - (ax ² + (2a + b)x + b) exp(x)

= x exp(x)

The factor of exp(x) on both sides is never zero, so we can cancel them:

(ax ² + (4a + b)x + 2a + 2b) - (ax ² + (2a + b)x + b) = x

Collect all the terms on the left side to reduce it to

2ax + 2a + b = x

Matching coefficients gives the system

2a = 1

2a + b = 0

and solving this yields

a = 1/2, b = -1

Then the general solution to this DE is

y(x) = C₁ + C₂ exp(x) + (1/2 x ² - x) exp(x)

For the given initial conditions, we have

y (0) = C₁ + C₂ = 6

y' (0) = C₂ - 1 = 5

and solving for the constants here gives

C₁ = 0, C₂ = 6

so that the particular solution to the IVP is

y(x) = 6 exp(x) + (1/2 x ² - x) exp(x)

Answer:

(a) [tex]P" = (-4,-3)[/tex]

(b) [tex](x,y) \to (4,-8)[/tex]

Step-by-step explanation:

Given

[tex]P = (4,3)[/tex]

Solving (a): Reflect across x and y-axis.

Reflection across x-axis has the following rules

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex]P' = (4,-3)[/tex]

Reflection across y-axis has the following rules

[tex](x,y) \to (-x,y)[/tex]

So, we have:

[tex]P" = (-4,-3)[/tex]

Hence, the new point is: (-4,-3)

Solving (b): Rx . Do,2 (2,4)

[tex]R_x \to[/tex] reflect across the x-axis

Reflection across x-axis has the following rules

[tex](x,y) \to (x,-y)[/tex]

So, we have:

[tex](2,4) = (2,-4)[/tex] ---- when P is reflected across the x-axis

[tex]D_{o,2} \to[/tex] dilate by a scale factor of 2

The rule is:

[tex](x,y) \to 2 * (x,y)[/tex]

So, we have

[tex](x,y) \to 2 * (2,-4)[/tex]

Open bracket

[tex](x,y) \to (4,-8)[/tex]

Answer:

14.36 AND 9.89 ===> 14 or 10

Step-by-step explanation:

Y =  Ax2 Bx C

Enter coefficients here >>>  -4 97 -568

Standard Form: y = -4x²+97x-568    

-24.25 -12.125 147.015625 -588.0625 20.0625

Grouped  Form: No valid Grouping      

Graphing Form: y = -4(x-12.13)²+20.06    

Factored Form: PRIME    

Solution/X-Intercepts: 14.36 AND 9.89    

Discriminate =321 is positive, two real solutions    

VERTEX: (12.13,20.06)     Directrix: Y=20.13    

Answer:

There is a   min     value of   376     located at (x,y) =   (9,7)  

============================================================

Explanation:

Solve the second equation for y

x+y = 16

y = 16-x

Then plug it into the first equation

f(x,y) = 3x^2+4y^2 - xy

g(x) = 3x^2+4(16-x)^2 - x(16-x)

g(x) = 3x^2+4(256 - 32x + x^2) - 16x + x^2

g(x) = 3x^2+1024 - 128x + 4x^2 - 16x + x^2

g(x) = 8x^2-144x+1024

The positive leading coefficient 8 tells us we have a parabola that opens upward, and produces a minimum value (aka lowest point) at the vertex.

Let's compute the derivative and set it equal to zero to solve for x.

g(x) = 8x^2-144x+1024

g ' (x) = 16x-144

16x-144 = 0

16x = 144

x = 144/16

x = 9

The min value occurs when x = 9. Let's find its paired y value.

y = 16-x

y = 16-9

y = 7

The min value occurs at (x,y) = (9,7)

Lastly, let's find the actual min value of f(x,y).

f(x,y) = 3x^2+4y^2 - xy

f(9,7) = 3(9)^2+4(7)^2 - 9*7

f(9,7) = 376

The smallest f(x,y) value is 376.

Answer:

Hello,

Answer D

Step-by-step explanation:

Each value of the graph, y=f(x) is multiplied by 2

Red graph has for eqution y=2*f(x) or y/2=f(x)

OSEAMENTE no se la respuesta

Answer:

95% confidence level should be used for a confidence​ interval.

The given confidence interval contains the value of 85 ​sec, so there is not sufficient evidence to support the claim that the mean is greater than 85 sec.

Step-by-step explanation:

0.05 significance level

1 - 0.05 = 0.95

0.95*100% = 95%

This means that a 95% confidence level should be used for a confidence​ interval.

Confidence interval is found to be −1.8 sec<μ<213.5 ​sec, what should we conclude about the​ claim?

Contains the value of 85 sec, thus there is not sufficient evidence to support the claim that the mean is greater than 85 sec.