what are the remaining trig functions? and how do i solve for them? pls help

What Are The Remaining Trig Functions? And How Do I Solve For Them? Pls Help

Answers

Answer 1

You're told that tan(θ) is positive, but

tan(θ) = sin(θ)/cos(θ)

and you're also told that sec(θ) = 1/cos(θ) = -3. So if cos(θ) is negative, sin(θ) must also be negative. In turn, both sec(θ) = 1/cos(θ) and csc(θ) = 1/sin(θ) are also negative.

Now, recall the Pythagorean identity,

cos²(θ) + sin²(θ) = 1

Multiply through both sides by 1/cos²(θ) to get an alternate form of the identity,

1 + tan²(θ) = sec²(θ)

Solve for tan(θ) (which we know is positive):

tan(θ) = √(sec²(θ) - 1) = 2√2

Right away, we get

cot(θ) = 1/tan²(θ) = 1/(2√2) = √2/4

Since sec(θ) = -3, it follows that cos(θ) = -1/3.

Then

tan(θ) = sin(θ)/cos(θ)   ==>   sin(θ) = 2√2 × (-1/3) = -2√2/3

and so

csc(θ) = 1/sin(θ) = -3/(2√2)


Related Questions

Factor completely 12a^3d^2 – 6ad^3

Answers

Answer:

[tex]12a^3d^2-6ad^3[/tex]

To factor an integer, we need to divide it by the ascending sequence of primes 2, 3, 5

In the end, the number of times each prime divides the original integer becomes its exponent.

Prime number 2  to the power of 2 equals 4 .

Prime number 3 to the power of 1 equals 3 .

[tex]2^{2} \times 3\times a^{3} \times b^{2} -(2\times3)ad^{3}[/tex]

Result:-  [tex]6ad^2\left(2a^2-d\right)[/tex]

 OAmalOHopeO

Find the equation (in slope-intercept form) of the line with the given slope that passes through the point with the given coordinates.
slope:
3/2
ordered pair: (3, 1)

Answers

Answer:

y = 3/2x-2

Step-by-step explanation:

slope intercept form is

y = mx+b where m is the slope and b is the y intercept

y = 3/2x+b

Substitute the point in for x and y

1 = 3/2(2)+b

1 = 3+b

1-3 =b

-2=b

y = 3/2x-2

#include
using namespace std;
int main()
{
int x,y=0;
x=1123;
while (x!=0){
y+=x%10;
x/=10;
}
cout< }

Answers

Answer:

main aapki madad karna chahti hun per Mujhe Ae Jahan question Nahin Aata sorry I don't know

sorry dear friend

Step-by-step explanation:

ok I don't know

A publisher reports that 54% of their readers own a personal computer. A marketing executive wants to test the claim that the percentage is actually different from the reported percentage. A random sample of 200 found that 44% of the readers owned a personal computer. Is there sufficient evidence at the 0.10 level to support the executive's claim

Answers

The null and alternate hypotheses are

H0 : u = 0.44  vs   Ha: u > 0.44

Null hypothesis: 44% of readers own a personal computer.

Alternate Hypothesis : greater than 44% of readers own a personal computer.

This is one tailed test and the critical region for this one tailed test for the significance level 0.1 is  Z >  ±1.28

The given values are

p1= 0.54 , p2= 0.44 ; q2= 1-p2= 0.56

Using z test

Z = p1-p2/√p2(1-p2)/n

Z= 0.54-0.44/ √0.44*0.56/200

z= =0.1/ 0.03509

z=  2.849

Since the calculated value of Z=  2.849 is greater than Z= 1.28  reject the null hypothesis therefore there is sufficient evidence to support the executive's claim.

Null hypothesis is rejected

There is sufficient evidence to support the executive's claim at 0.10 significance level.

https://brainly.com/question/2642983

What is the value of B|-|A|?

Answers

Answer:

B+A

Step-by-step explanation:

The family trip to Grandma's consisted of both a train ride and a car ride. The average speed of the train ride was 72 miles per hour, and the average speed of the car ride was 62 miles per hour. The entire trip lasted 6 hours.
Let x be the number of hours the train ride lasted. Write an expression for the total distance of the trip, in miles.

Answers

Answer:

432

Step-by-step explanation:

x=1hr (6x)=6hours x= 72 hours through train so (6x)=72x6=432

The family trip to Grandma's consisted of both a train ride and a car ride. The average speed of the train ride was 72 miles per hour, and the average speed of the car ride was 62 miles per hour. The entire trip lasted 6 hours.
Let x be the number of hours the train ride lasted. Write an expression for the total distance of the trip, in miles.
Answer-432

write your answer in simplest radical form​

Answers

Answer:

a = 3√6 in

Step-by-step explanation:

From the question given above, the following data were obtained:

Angle θ = 60°

Adjacent = 3√2 in

Opposite = a =?

The value of 'a' can be obtained by using the tan ratio as illustrated below:

Tan θ = Opposite / Adjacent

Tan 60 = a / 3√2

√3 = a / 3√2

Cross multiply

a = √3 × 3√2

Recall:

c√d × n√m = (c×n) √(d×m)

Thus,

√3 × 3√2 = (1×3)√(3×2)

√3 × 3√2 = 3√6

a = 3√6 in

Evaluate: 2-4
1
O A.
loo
O B.-8
O c.
1
16
O D.-16

Answers

Answer:

c is the answer

[tex] \frac{1}{16} [/tex]

Find the sum : (i) 23123, 11001 and 21302 (iii) 21031, 12301 and 32211 (v) 21003, 12346 and 21220 (ii) 32101, 12301 and 1032 (iv) 301242, 123310 and 10002

Answers

Answer:

(i) 23123 +  11001 + 21302 =  55426(ii) 32101 + 12301 + 1032 = 45434(iii) 21031 + 12301 + 32211 =  65543(iv) 301242 + 123310 + 10002 = 434554(v) 21003 + 12346 + 21220 = 54569

1:-

[tex]\\ \sf\longmapsto 23123+11001+21302[/tex]

[tex]\\ \sf\longmapsto 55426[/tex]

2:-

[tex]\\ \sf\longmapsto 21031+12301+32211[/tex]

[tex]\\ \sf\longmapsto 65543[/tex]

3:-

[tex]\\ \sf\longmapsto 21003+12346+21220[/tex]

[tex]\\ \sf\longmapsto 54569[/tex]

4:-

[tex]\\ \sf\longmapsto 32101+12301+1032[/tex]

[tex]\\ \sf\longmapsto 45434[/tex]

5:-

[tex]\\ \sf\longmapsto 301242+123310+10002[/tex]

[tex]\\ \sf\longmapsto 434554[/tex]

find the value of n . 80×π×n=1100000​

Answers

Answer:

110000/8π

Step-by-step explanation:

Divide 1100000 by 80 and cancel 0. Then divide pi

Write an equation and solve it to answer each question. A pile of 55 coins consisting of nickels and dimes is worth $3.90. Find the number of each. I only need the equation plz. WILL MARK BRAINLIEST.

Answers

Answer:

0.05x + 0.1(55 - x) = 3.9

Step-by-step explanation:

There are 55 coins.

Let x = number of nickels.

The number of dimes is 55 - x.

The value of a nickel is $0.05, and the value of a dime is $0.10.

The value of x nickels is 0.05x

The value of 55 - x dimes is 0.1(55 - x)

The total value of the coins is 0.05x + 0.1(55 - x)

The total value of the coins is $3.90

0.05x + 0.1(55 - x) = 3.9

For what value of x is the parallelogram a rhombus.

Answers

Answer:

Step-by-step explanation:

2 × ( 3x + 6 )° + ( 16x + 14 )° = 180°

22x + 26 = 180

22x = 154

x = 7

Please help me to find this answer

Answers

Step-by-step explanation:

question 1

angle DBA=90°, meaning to find m<D you have to add 90+38 then subtract by 180, because ABD is a triangle

90+18+m<D=180

108+m<D=180

m<D=180-108

=72°

question 2

m<D again in this case angle ABD is also 90

m<D=180-(90+48)

=180-138

=42°

I hope this helps

Which values of a and b make this system of equations have infinitely many solutions?
2y + 16 = 6x
y = ax + b
a = -3, b = 8
a = -3, b = -8
a = 3, b = -8
a = 3, b = 8

Answers

9514 1404 393

Answer:

  a = 3, b = -8

Step-by-step explanation:

Solving the first equation for y, we get ...

  2y +16 = 6x . . . . . given

  y = 8 +3x . . . . . . . divide by 2

  y = 3x -8 . . . . . . . subtract 8

In order for the system of equations to have infinitely many solutions, the second equation must be the same as this:

  y = ax +b

  a = 3, b = -8

Fixed costs are $2000, and the cost of producing each pair of skies is $100. The selling price is $220 (per pair). How many pairs should be sold to make a profit of $29200?

Answers

260 pairs

Step-by-step explanation:

220-100= 120

(29200+2000)÷120= 260

There would be 260 Pairs

A tank filled with water begins draining. The number of minutes t since the water began draining from the tank is a function of the number of gallons of water in the tank, v. We will call this function f so that f(t) = v.

Required:
a. Using function notation, represent the of gallons of water in me tank 4 minutes after the water darning from the Ink.
b. Suppose that f(4) = 7, what does this mean in the context of the problem?

Answers

Answer:

[tex](a)\ f(4) = v[/tex]

(b) There are 7 gallons left in the tank after 4 minuted

Step-by-step explanation:

Given

[tex]f(t) = v[/tex]

[tex]t \to[/tex] time since water began draining

[tex]v \to[/tex] gallons in the tank

Solving (a): Notation for gallons remaining at 4 minutes

This means that [tex]t=4[/tex]

[tex]f(t) = v[/tex] becomes

[tex]f(4) = v[/tex]

Solving (b): Interpret f(4) = 7

We have:

[tex]f(t) = v[/tex]

[tex]t \to[/tex] time since water began draining

[tex]v \to[/tex] gallons in the tank

This means that:

[tex]t =4[/tex]

[tex]v =7[/tex]

It can be interpreted as:

There are 7 gallons left in the tank after 4 minuted

It is claimed that the average child has no time to go to school. For the child spends 8 hours per day,or one third of his/her time sleeping. Based on a 365 day year, that’s 121.67days sleeping. Also the child spends three hours per day eating. That’s a total of 45 days in the year spent eating. Also the child spends 90 days taking summer vacation. Also the child spends 21 days on Christmas and Easter holiday. Finally, the child has each Saturday and Sunday off. That’s a total of 104 days. In short, we (rounding to whole days accounted for 122+45+90+21+104=382 days of the year taken up by ordinary child inlike activities. This is already more than the 365 days that are known to comprise a year. We conclude that there is certainly no time for the child to attend school. What is wrong with this reasoning?

Answers

Answer:

See below.

Step-by-step explanation:

Sleeping:

8/24 * 365 = 121.76 days

Eating:

3/24 * 365 = 45.63 days

Total sleeping and eating: 167 days

Summer Vacation & Holidays:

90 + 21 = 111 days

Saturdays and Sundays: 52 + 52 = 104 days

Vacation + Holidays Saturdays + Sundays = 111 + 104 = 215 days

It may be true that all days of vacation, holiday, Saturdays, and Sundays combined are a total of 215 days, but these 215 days cannot be added to the 167 days above because these 215 days include time for sleeping and eating which was already included in the sleeping and eating times for the entire year. The mistake in the reasoning is counting twice the time of sleeping and eating on the 215 days in which there is no school.

Rachael needs to rent a car while on vacation. The rental company charges $17.95, plus 19 cents for each
mile driven. If Rachael only has $40 to spend on the car rental, what is the maximum number of miles she
can drive?

Answers

Answer:

116 miles

Step-by-step explanation:

We can solve this by first writing an equation for the cost of the car rental. To begin, the base cost is $17.95, so any further costs must be added to that. Next, the car costs 19 cents (0.19 dollars) for each mile driven, so for each mile, we add 19 cents. This can be written as 0.19 *x if x represents the amount of miles driven. Therefore, we can add the two input costs of the car (the base cost and cost per mile) to get

17.95 + 0.19 * x = total cost.

After that, we want to maximize x/the number of miles with only 40 dollars. We can do this by setting this equal to the total cost, as going over the total cost is impossible and going under would be limiting the amount of miles (this because we are adding money for each mile, so more money means more miles). Therefore, we have

17.95 + 0.19 * x = 40

subtract 17.95 from both sides to isolate the x and its coefficient

22.05 = 0.19 * x

divide both sides by 0.19 to isolate x

22.05/0.19 = x = 116.05

The question asked us to round down, and 116.05 rounded down is 116 for our answer

Find the slope of the graphed line

Answers

Answer:

4

Step-by-step explanation:

Pick two points on the line

(0,-5)  and (1,-1)

We can find the slope using

m = (y2-y1)/(x2-x1)

   = ( -1 - -5)/(1 - 0)

  (-1+5)/(1-0)

    4/1

  = 4

Last year at a certain high school, there were 56 boys on the honor roll and 150 girls on the honor roll. This year, the number of boys on the honor roll decreased by 25% and the number of girls on the honor roll decreased by 12%. By what percentage did the total number of students on the honor roll decrease?

Answers

Answer:

15.534% decrease

Step-by-step explanation:

Find the new number of boys and girls on the honor roll:

56(0.75) = 42 boys

150(0.88) = 132 girls

Find the new total number of students on the honor roll:

42 + 132 = 174

Find the percent decrease by dividing the difference in the number of students by the original number.

There were originally 206 total students on the honor roll. Find the difference:

206 - 174 = 32

Divide this by the original amount:

32/206

= 0.15534

So, the number of students on the honor roll decreased by approximately 15.534%

what is 3/16 of 200 written as a percentage?​

Answers

Answer:

Step-by-step explanation:

3/16 = 0.1875

As a % this is 18.75%

18.75/100 * 200 = 37.5

I'm not sure from the question, exactly what you want. 18.75% of 200 is one possibility.

3/16 of 200 as a percentage is 3750%

The question can be represented as:

[tex]\frac{3}{16} * 200[/tex]

Rewrite as:

[tex]\frac{3}{16} * 200 =\frac{3* 200}{16}[/tex]

Multiply the numerator

[tex]\frac{3}{16} * 200 =\frac{600}{16}[/tex]

[tex]\frac{3}{16} * 200 =37.5[/tex]

Multiply by 100% to represent it as a percentage

[tex]\frac{3}{16} * 200 =37.5 * 100\%[/tex]

[tex]\frac{3}{16} * 200 =3750\%[/tex]

Read more at:

https://brainly.com/question/19994306

a film lasts 45 minutes what fraction of the film is left after 15 minutes and 25 minutes ?

Answers

Answer: i) [tex]\frac{1}{3}[/tex]

              ii) [tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Total length of film = 45 mins

Fraction of time left after 15 mins = [tex]\frac{15}{45}[/tex]

                                                       = [tex]\frac{1}{3}[/tex]

Fraction of time left after 25 mins = [tex]\frac{25}{45}[/tex]

                                                        = [tex]\frac{5}{9}[/tex]

If anyone knows answer with steps that will be greatly appreciated :)

Answers

Answer:

The area formula is= 1/2(a+b)×height

1/2×20×6=60metres squared

Step-by-step explanation:

kindly correct me if am wrong

Whats the volume of this aquarium?
PLZ HELP!!

Answers

Find the lxwxh and then multiply all of them together and then u should get your answer

Cho hình thang ABCD vuông tại A và D biết AB=AD=3cm, BC=6cm. Tính góc C và D

Answers

Answer:

C=6cm

D=3cm

Step-by-step explanation:

C=6×6cm

36cm

D=3×3cm

=9cm

The diameter of a cone is 34 ft. the height is 16 ft what is the volume in cubic ft?

Answers

Answer:

4842.24 cubic feet

Step-by-step explanation:

Use the formula for the volume of a cone, V = [tex]\pi[/tex][tex]\frac{h}{3}[/tex]

The diameter of the cone is 34 ft, so the radius is 17 ft.

Plug in the radius and height into the formula, and solve for the volume:

V = [tex]\pi[/tex]r²[tex]\frac{h}{3}[/tex]

V = [tex]\pi[/tex](17)²[tex]\frac{16}{3}[/tex]

V = [tex]\pi[/tex](289)[tex]\frac{16}{3}[/tex]

V = 4842.24

So, the volume of the cone is 4842.24 cubic feet

Answer:

4,841.32 ft³.

Step-by-step explanation:

Let’s assume that this is a right circular cone and that the radius of the cone is r.

For our problem, r = (1/2)d = (1/2)34 = 17.

The volume of the cone is:

V = (1/3)pi r^2 h, where r is the radius and h is the height.

So, V = (1/3)pi(17^2)16 = 4,841.32 ft³.

What’s v=(324pie)(3)

Answers

V=972 pi Have A nice day/night!

Can you please me with the word problem thank you so much

Answers

Answer:

4. 53

5. 66

6. 89

7. 31

Step-by-step explanation:

4.  14 + 18 + 21

     ^      ^

        33 + 21

            53

5.  86 - 20

        66

6.  34 + 55

        89

7.  14 + 11 + 6

     ^     ^

      25 + 6

          31

In a study of 806 randomly selected medical malpracticeâ lawsuits, it was found that 513 of them were dropped or dismissed. Use a 0.01 significance level to test the claim that most medical malpractice lawsuits are dropped or dismissed. What is the hypothesis test to beâ conducted?

Answers

Solution :

[tex]$H_0: p = 0.5$[/tex]

[tex]$H_a: p > 0.5$[/tex]

Alpha, α = 0.01

The sample proportion is :

[tex]$p'=\frac{x}{n}$[/tex]

   [tex]$=\frac{513}{806}$[/tex]

   = 0.636

Test statistics, [tex]$z=\frac{p'-p}{\sqrt{\frac{pq}{n}}}$[/tex]

[tex]$z=\frac{0.636-0.5}{\sqrt{\frac{0.5\times 0.5}{806}}}$[/tex]

[tex]$z=\frac{0.136}{0.0176}$[/tex]

z = 7.727

The p value = 0.00001

Here we observe that p value is less than α, and so we reject the hypothesis [tex]H_0[/tex].

Therefore, there is sufficient evidence,

The number of defective circuit boards coming off a soldering machine follows a Poisson distribution. During a specific ten-hour period, one defective circuit board was found. (a) Find the probability that it was produced during the first hour of operation during that period. (Round your answer to four decimal places.) (b) Find the probability that it was produced during the last hour of operation during that period. (Round your answer to four decimal places.) (c) Given that no defective circuit boards were produced during the first five hours of operation, find the probability that the defective board was manufactured during the sixth hour. (Round your answer to four decimal places.)

Answers

Answer:

a) the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c) the required probability is 0.2000

Step-by-step explanation:

Given the data in the question;

During a specific ten-hour period, one defective circuit board was found.

Lets X represent the number of defective circuit boards coming out of the machine , following Poisson distribution on a particular 10-hours workday which one defective board was found.

Also let Y represent the event of producing one defective circuit board, Y is uniformly distributed over ( 0, 10 ) intervals.

f(y) = [tex]\left \{ {{\frac{1}{b-a} }\\\ }} \right _0[/tex];   ( a ≤ y ≤ b )[tex]_{elsewhere[/tex]

= [tex]\left \{ {{\frac{1}{10-0} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

f(y) = [tex]\left \{ {{\frac{1}{10} }\\\ }} \right _0[/tex];   ( 0 ≤ y ≤ 10 )[tex]_{elsewhere[/tex]

Now,

a) the probability that it was produced during the first hour of operation during that period;

P( Y < 1 )   =   [tex]\int\limits^1_0 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^1_0 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^1_0[/tex]

= [tex]\frac{1}{10} [ 1 - 0 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the first hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

b) The probability that it was produced during the last hour of operation during that period.

P( Y > 9 ) =    [tex]\int\limits^{10}_9 {f(y)} \, dy[/tex]

we substitute

=    [tex]\int\limits^{10}_9 {\frac{1}{10} } \, dy[/tex]

= [tex]\frac{1}{10} [y]^{10}_9[/tex]

= [tex]\frac{1}{10} [ 10 - 9 ][/tex]

= [tex]\frac{1}{10}[/tex] or 0.1000

Therefore, the probability that the defective board was produced during the  last hour of operation is [tex]\frac{1}{10}[/tex] or 0.1000

c)

no defective circuit boards were produced during the first five hours of operation.

probability that the defective board was manufactured during the sixth hour will be;

P( 5 < Y < 6 | Y > 5 ) = P[ ( 5 < Y < 6 ) ∩ ( Y > 5 ) ] / P( Y > 5 )

= P( 5 < Y < 6 ) / P( Y > 5 )

we substitute

 [tex]= (\int\limits^{6}_5 {\frac{1}{10} } \, dy) / (\int\limits^{10}_5 {\frac{1}{10} } \, dy)[/tex]

[tex]= (\frac{1}{10} [y]^{6}_5) / (\frac{1}{10} [y]^{10}_5)[/tex]

= ( 6-5 ) / ( 10 - 5 )

= 0.2000

Therefore, the required probability is 0.2000

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