What are the solution(s) to the quadratic equation x2 – 25 = 0?

x = 5 and x = –5
x = 25 and x = –25
x = 125 and x = –125
no real solution

Answer:

190%

Step-by-step explanation:

$1.56 is close to nearly 2x the value of $0.87

You can start by multiplying $0.87 by 2 to get $1.74

Now put $1.56 / $1.74

This gets you 0.89655172

By rounding this, you can get to 0.90

Move the decimal places two spots over to get a percentage = 90%

Since the eggs didn't decrease in value, you can add the 100% from the beginning of the problem.

100+90=190%

Answer:

Second option

Step-by-step explanation:

Let's assume that x is 1 and y is 3

a) [tex]\frac{1}{2}[/tex] < [tex]\frac{3}{2}[/tex] = true

b) -1 < -3 = false

c) 1+2 < 3+2 = true

d) 2 x 1 < 2 x 3 = true

Given:

The expression is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

To find:

The correct form of the partial fraction decomposition for the given expression.

Solution:

We have,

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}[/tex]

By partial fraction decomposition, it can be written as:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{A}{x+1}+\dfrac{B}{(x+1)^2}+\dfrac{Cx+D}{x^2+7}[/tex]           ...(i)

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B}{(x+1)^2(x^2+7)}[/tex]

[tex]4x^3+3x^2=(x+1)^2(Cx+D)+(x+1)(x^2+7)A+(x^2+7)B[/tex]

[tex]4x^3+3x^2=x^3A+x^3C+x^2A+x^2B+2x^2C+x^2D+7xA+xC+2xD+7A+7B+D[/tex]

[tex]4x^3+3x^2=x^3(A+C)+x^2(A+B+2C+D)+x(7A+C+2D)+7A+7B+D[/tex]

On comparing both sides, we get

[tex]A+C=4[/tex]

[tex]A+B+2C+D=3[/tex]

[tex]7A+C+2D=0[/tex]

[tex]7A+7B+D=0[/tex]

On solving these equations, we get

[tex]A=\dfrac{23}{32},B=-\dfrac{1}{8},C=\dfrac{105}{32},D=-\dfrac{133}{32}[/tex]

Substituting these values in (i), we get

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Therefore, the required partial fraction decomposition is:

[tex]\dfrac{4x^3+3x^2}{(x+1)^2(x^2+7)}=\dfrac{\dfrac{23}{32}}{x+1}+\dfrac{-\dfrac{1}{8}}{(x+1)^2}+\dfrac{\dfrac{105}{32}x-\dfrac{133}{32}}{x^2+7}[/tex]

Answer:

A on Edg

Step-by-step explanation:

got it right

Answer:

100%_$40.80

? × _$38.76

Step-by-step explanation:

100%×$38.76÷$40.80=95%

Answer:

40.80

Step-by-step explanation:

Answer:

3/5

Step-by-step explanation:

cos A = adjacent side / hypotenuse in a right triangle

cos A = 24/40

Cos A = 6/10

cos A = 3/5

Answer:

9/10 or 90 %

Step-by-step explanation:

There are 54+27+5+4 total people = 90

The people with diploma is 54+27 = 81

P (diploma) = number with diploma / total

                  = 81/90

                  =9/10

                   90%

Answer:

b)48 km/hr (12 km in .25 hrs)

c) avg speed: 60/3 = 20 km/hr

Step-by-step explanation:

a)

.5  18

.75 18

1      30

1.5   30

2     40

2.25  40

3        60

Answer:

Step-by-step explanation:

x+y=17 is NOT the equation for any circle. You have omitted the exponents. The equation for the circle should be

x^2 + y^2 = 17.

:::::

Plug the coordinates of D into the equation.

(-4)² + (-1)² = 17, so D is on the circle.

Plug the coordinates of E into the equation.

1² + 4² = 17, so E is on the circle.

:::::

Slope of DE = (-1 - 4)/(-4 - 1) = 1

Slope of perpendicular to DE is -1.

Midpoint of DE:  ((-4+1)/2, (-1+4)/2) = (-1.5, 1.5)

Point-slope equation for perpendicular bisector:

y-1.5 = -(x+1.5)

y = -x

:::::

Center of circle is (0,0)

0 = -0, so y=-x passes through the center.

Answer:

usual number of yellow eggs = 12

Usual maximum = 21

Usual minimum = 3

Step-by-step explanation:

To solve this, we will use the expected value of a binomial probability.

The formula is;

E(X) = np

Where;

n is sample size

p is probability of success.

We are given;

n = 58

p = 21%

Thus;

usual number of yellow eggs in samples = np = 58 × 21% = 12.18 ≈ 12

From USL(Upper specification limit) and LSL(Lower specification limit) formula, we can find the maximum usual number and minimum usual number of eggs respectively.

Thus;

USL = n(p + 3√(p(1 - p)/n)

USL = 58(0.21 + 3√(0.21(1 - 0.21)/58)

USL = 21.48 ≈ 21

LSL = n(p - 3√(p(1 - p)/n)

LSL = 58(0.21 - 3√(0.21(1 - 0.21)/58)

LSL = 2.87 ≈ 3

Answer:

C. 2x

Step-by-step explanation:

Let

B's age = x years

A's age = 2 times older than B

= 2 * x

= 2x years

A's age = 2x years

For instance, if B's age is 17 years

Then,

A's age = 2x

= 2(17)

= 34 years old

Answer:

A

Step-by-step explanation:

Answer:

in neighbourhood q the total number of people in the nine families I higher than that in neighbourhood s because of we add up the number of people in the families in neighbourhood q we get a total of 35 yet we have a total of only 27 people in the nine families in neighbourhood s

hope that helps ❤

Last year He was 7 years old.

His father is 4 times the age 7 x 4 = 28

Last year his dad was 28, so this year he is 29.

Combined age this year = 29 + 8 = 37

51 - 37 = 14 years

14/ 2 people = 7 years

8 + 7 = 15

29 + 7 = 36

15 + 36 = 51

It will take 7 years.

Answer:

4 > [tex]-\frac{n}{4}[/tex]

-16 > n

Step-by-step explanation:

Greater than would mean that the "arrow" is not facing the number. It would mean it is larger than the other number. Also, you have to construct the other part of the inequality which would be [tex]-\frac{n}{4}[/tex].

4×4 > [tex]-\frac{n}{4}[/tex]×4

16 > -n

-16 > n

Answer:

[tex]AB^{2} =AD^{2} +BD^{2}[/tex]

[tex]AB^{2} =(7.5)^{2} +(4.9)^{2}[/tex]

[tex]AB=\sqrt{80.26}[/tex]

[tex]=8.96[/tex]

ΔABC tan C=AB/BC

⇒ tan 55.8= 8.96/BC ⇒BC= 8.96/tan 55.8

BC=x= 6.09

--------------------------

Hope it helps...

Have a great day!!

Answer:

40 pupils speak French and English

5 pupils speak only English

Step-by-step explanation:

**The grammar has some errors, but I hope I understood it correctly to answer your question correctly!**

Here's what we know about the question:

- 1/10 of the 50 pupils speak only FRENCH

- 4/5 of the 50 pupils speak FRENCH and ENGLISH

- rest of the pupils speak only ENGLISH

Here's what we're trying to find:

- # of pupils that speaks FRENCH and ENGLISH

- # of pupils that speak only ENGLISH

Let's start of with find how many pupils speak French:

1/10 of the 50 pupils speak French. To find the # of pupils, divide 50 by 10:

50/10 = 5

5 pupils speak only French

Now let's find out how many pupils speak French and English:

4/5 of the 50 pupils speak French and English. We are going to divide 50 by 5 and then multiply the result by 4:

50/5 = 10

10 * 4 = 40

40 pupils speak French and English

Finally, let's find the number of pupils that speak only English:

The question only says that the rest of the 50 pupils speak only English.

We are going to add the other pupils who don't speak only English, then subtract that value from 50:

40 + 5 = 45

50 - 45 = 5

5 pupils speak only English

Hope that helps (●'◡'●)

Answer:

d. The APR helps compare loans with the same payback period, but with different monthly rates and different fees.

Step-by-step explanation:

A loan can be defined as an amount of money that is being borrowed from a lender and it is expected to be paid back at an agreed date with interest.

Generally, the financial institution such as a bank lending out the sum of money usually requires that borrower provides a collateral which would be taken over in the event that the borrower defaults (fails) in the repayment of the loan.

An annual percentage rate (APR) is an amount of money paid as interest by borrowers or earned on loans by lenders such as banks, expressed as a percentage of the amount borrowed or invested over a 12-month period i.e on an annual basis.

Generally, the annual percentage rate (APR) helps compare loans with the same payback period, but with different monthly rates and different fees.

Answer:

A- If you have good credit, you will get a higher APR

Step-by-step explanation:

Answer:

p = 26.3

Step-by-step explanation:

Using the law of sines

sin 101        sin 38

---------  = ------------

42               p

Using cross products

p sin 101 = 42 sin 38

p = 42 sin 38 / sin 101

p=26.34175

To the nearest tenth

p = 26.3

Answer:

H0 : The mean difference in strikes between pre and post strike is equal to 0

H1 : The mean difference in strikes between pre and post strike is not equal to 0

Step-by-step explanation:

The scenario described abibe meets the condition for a paired (dependent) sample t test as the same subject is involved in both the pre and post strike data. Therefore measurement from the strike(pre) must be paired with measurement from the strike(post) data.

For a paired test involving a single subject ; The mean difference in the two sample is 0 ; that is both are the same while the alternative negates the null by claiming that the mean difference is not equal to zero.

Answer:

Step-by-step explanation:

So, yearly $2100 is paid, plus the 1.73% interest, so 1.73% interest is $2136.33every year interest stacks on itself so youll take 1.73% of the year 1 total with interest.  

Year 1 total: $2136.33

Year 2 total:$2173.29

Year 3 total:$2210.89

Year 4 total:$2249.14

Year 5 total:$2288.05

Total Paid After 5 years:$11057.70

Year 1 total interest:$36.33

Year 2 total interest:$36.96Year 3 total interest:$37.60Year 4 total interest:$38.25Year 5 total interest:$38.91

Total Interest paid after 5 years:$188.05

Given:

The expression is:

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

To find:

The simple product.

Solution:

We have,

[tex]\dfrac{25x^2}{2x+6}\cdot \dfrac{2}{5x}[/tex]

It can be written as:

[tex]=\dfrac{5\times 5\times x\times x}{2(x+3)}\cdot \dfrac{2}{5x}[/tex]

Cancel out the common factors.

[tex]=\dfrac{5\times x}{x+3}[/tex]

[tex]=\dfrac{5x}{x+3}[/tex]

Therefore, the correct option is C.

Answer:

2 × 10⁻⁶

Step-by-step explanation:

( 1 × 10⁻³ ) ÷ ( 5 × 10² )

→ Rewrite into normal form

0.001 ÷ 500

→ Simplify

2 × 10⁻⁶

Answer:

[tex]\frac{1}{500,000}=2*10^{-6}[/tex]

Step-by-step explanation:

[tex]\frac{1*10^{-3} }{5*10^{2} } =\frac{1}{5} *10^{-3-2}=\frac{1}{5} *10^{-5} = 500,000^{-1}= \frac{1}{500,000} = 2*10^{-6}[/tex]

We have:

[tex]\frac{a^{x} }{a^{y} } = a^{x-y}[/tex]

In this case: [tex]\frac{10^{-3} }{10^{2} } = 10^{(-3)-2} =10^{-5} =\frac{1}{100,000}[/tex]

Answer:

Step-by-step explanation:

7) PQ // RS,  RQ is transversal

x = 38 {Alternate interior angles are congruent}

In ΔPQR ,

x + y + ∠P  = 180   {Angle sum property of triangle}

38 + 90 + y = 180

  128 + y =  180

           y = 180 - 128

y = 52

9) Construct XY // AB

XY // AB  & AC is transversal

∠1 = ∠4     ---------(I)      {alternate interior angles are equal}

XY // AB  & BC is transversal

∠3 = ∠5     ---------(II)      {alternate interior angles are equal}

∠1 + ∠2 + ∠3 = 180   {straight line angles}

∠4 + ∠2 + ∠5 = 180    {From (I) & (II) }

Sum of three angles of triangle is 180.Hence proved.

Answer:

1) 44  

a) 7 + 37

b) 3 + 41

c) 13 + 31

2) 36

a) 5 + 31

b) 7 + 29

c) 17 + 19

3) 24

a) 5 + 19

b) 7 + 17

c) 11 + 13

4) 18

a) 5 + 13

b) 7 + 11

Expressing the numbers as sum of two odd primes we have,

Prime numbers are numbers which are only divisible by 1 and itself.

Prime Numbers are: 2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,...

Odd numbers are numbers which are not divisible by 2.

Odd numbers are give by: 1,3,5,7,9,11,.....

2 is the only even number which is prime. So all prime numbers except 2 are odd numbers.

So odd prime numbers are given by: 3,5,7,11,13,17,19,23,29,31,37,41,43,47,....

Expressing the give numbers as the sum of odd prime numbers we get,

A) 44

41+3 = 44

37+7 = 44

31+13 = 44

B) 36

31+5 = 36

29+7 = 36

23+13 = 36

19+17 = 36

C) 24

19+5 = 24

17+7 = 24

13+11 = 24

D) 18

13+5 = 18

11+7 = 18

Learn more about Odd Prime Numbers here -

https://brainly.com/question/1593928

#SPJ2

Answer:

Step-by-step explanation:

Hope this Helps ;)