What are the values of m and 0 in the diagram below?

What Are The Values Of M And 0 In The Diagram Below?

Answers

Answer 1

Answer:The correct answer is m= and θ = 30º.

Step-by-step explanation:First, we must form a triangle whose hypotenuse is the radius r=1, its adjacent leg is m, its opposite leg is  and the angle is theta.

First, we calculate the angle with theta's breast:

sin (θ) =  

where H is the hypotenuse, in this case, the radio.

θ =  ()

θ = 30º

Now, we calculate the adjacent leg, which is equal to the x-coordinate of the point:

cos (θ) =  

m = cos 30º * H

m =  

m =  

Have a nice day!


Related Questions

Phân biệt chi phí sản xuất và giá thành sản phẩm?

Answers

Answer:

* Giống nhau: đều là biểu hiện bằng tiền về lao động sống và lao động hóa trong quá trình sản xuất

* Khác nhau:

+ Về thời gian: chi phí sản xuất gắn liền với từng thời kỳ, còn giá thành sản phẩm gắn với thời hạn hoàn thành sản phẩm. ...

+ Có những chi phí được tính vào giá thành nhưng không được tính vào chi phí kỳ này.

+ Mối quan hệ chi phí và tính giá thành sản phẩm: Chi phí là cơ sở để tính giá thành, giá thành là thước đo chi phí sản xuất mà doanh nghiệp bỏ ra để có được khối lượng hoàn thành.

+ Có nhiều chi phí phát sinh trong kỳ nhưng chưa có sản phẩm hoàn thành do đó chưa có giá thành.

Step-by-step explanation:

HELP!!!!
Car Survey In a survey of 3,200 people who owned a certain type of​ car, 2,080 said they would buy that type of car again. What percent of the people surveyed were satisfied with the​ car?

___% of the people surveyed were satisfied with the car.

Answers

Answer:

65%

Step-by-step explanation:

2080/3200times100%

Find all solutions to the equation.
cos^2 x +2cosx+1=0

Answers

[tex]x= \pi[/tex]

Step-by-step explanation:

[tex]\cos^2x+\cos x+1=0[/tex]

Let [tex]u= \cos x[/tex]

Then [tex]u^2+2u+1=(u+1)^2=0[/tex]

or

[tex]\cos x = -1[/tex]

This gives us [tex]x= \pi[/tex] or all integer multiples of [tex]\pi (n \pi)[/tex]

2) A block of ice weighs 12 400 kg. It has the shape of a cylinder, with a radius of 1.2 m and
a height of 3 m. What is the density of the ice? Give your answer to one decimal place.

Answers

Answer:

= 3.6

Step-by-step explanation:

Do you know how to find the volume of a cylinder? Like any prism, it's area of base x height, in this case the base is a circle of radius 1.2m.

Density is simply mass / volume (kg / m3 ).

clarify its 1.2 x 3 = 3.6

12400 / 3.6 = 3.444 occuring

plaz..mmnj k,mnmnm 1

Answers

Answer:

Option 1

Step-by-step explanation:

3x - 7y = -7y + 3x

They have simply been moved to opposite ends of the equation.

ASAP. There are three marbles in a bag. When is red and two are black. What is the probability of picking a black marble first, putting it back in the bag and then picking a black marble? Use the following probably need to find the answer.

Answers

Answer:

Number of black balls=2

Total number of balls=3

Probability =2/3

if f(×) = [tex] \frac{1}{ \sqrt{x - 1} } [/tex]

then find [tex] \frac{f(x) - f(2)}{x - 2} [/tex]

Answers

9514 1404 393

Answer:

  (1 -x +√(x -1))/(x² -3x +2)

Step-by-step explanation:

Fill in the given function definition and simplify.

  [tex]\dfrac{f(x)-f(2)}{x-2}=\dfrac{\dfrac{1}{\sqrt{x-1}}-\dfrac{1}{\sqrt{2-1}}}{x-2}=\dfrac{1-\sqrt{x-1}}{(x-2)\sqrt{x-1}}\\\\=\dfrac{\sqrt{x-1}-x+1}{(x-2)(x-1)}=\boxed{\dfrac{\sqrt{x-1}-x+1}{x^2-3x+2}}[/tex]

A farmer finds there is a linear relationship between the number of bean stalks, n, she plants and the yield, y, each plant produces (in ounces). When she plants 30 stalks, each plant yields 30 oz of beans. When she plants 34 stalks, each plant produces 28 oz of beans. Find an equation that gives the yield y when n stalks are planted.

Answers

Answer:

[tex]y = -\frac{1}{2}n + 15[/tex]

Step-by-step explanation:

Linear equation:

A linear equation has the following format:

[tex]y(n) = an + b[/tex]

In which a is the slope and b is the y-intercept.

When she plants 30 stalks, each plant yields 30 oz of beans. When she plants 34 stalks, each plant produces 28 oz of beans.

This means that we have these following two points: (30,30) and (34,28).

Finding the slope:

When we have two points, the slope is given by the change in the output y divided by the change in the input n.

Change in the output: 30 - 28 = 2.

Change in the input: 30 - 34 = -4. So

[tex]a = \frac{2}{-4} = -\frac{1}{2}[/tex]

So

[tex]y = -\frac{1}{2}n + b[/tex]

Finding b:

When [tex]n = 30, y = 30[/tex]. We replace this into the equation to find b. So

[tex]y = -\frac{1}{2}n + b[/tex]

[tex]b = -\frac{1}{2}(30) + 30[/tex]

[tex]b = -15 + 30 = 15[/tex]

So

[tex]y = -\frac{1}{2}n + 15[/tex]

If P = (7,-4), Find:
(180° (P)
([?], []
Enter

Answers

Step-by-step explanation:

the answer is in the above image

HW HELP ASAP PLZZZZZ

Answers

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (x - 5)(x - 4) }}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\blue{Step-by-step\:explanation}}{\blue{:}}}}}[/tex]

[tex] {x}^{2} - 9x + 20[/tex]

[tex] = {x}^{2} - 4x - 5x + 20[/tex]

Taking "[tex]x[/tex]" as common from first two terms and "[tex]5[/tex]" from last two terms, we have

[tex] = x(x - 4) - 5(x - 4)[/tex]

Taking the factor [tex](x-4)[/tex] as common,

[tex] = (x - 5)(x - 4)[/tex]

[tex]\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35♛}}}}}[/tex]

2
3
4
9
10
-1
NS
-6
-7
-8
-9
Which three statements correctly describe key features of the function graphed here?

Answers

did u add the attachment of the the statements? cuz i dont see it.

Help please i will mark brainlist !!!!

Answers

Answer:

You need to add the numbers up

0.4 +0.2+0.1=0.7

1-0.7=0.3

Ans=0.3

Given that the length of the figure below is x + 2, its width is
2- 2, and its perimeter is 24, solve for 2.

Answers

Answer:

hear is your answer in attachment please give me some thanks

Multiply the polynomials.
(4x- + 4x + 6)(7x + 5)

Answers

[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}[/tex]

[tex](4 {x}^{2} + 4x + 6)(7x + 5)[/tex]

[tex] = \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)[/tex]

[tex] = \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30[/tex]

Combining like terms, we have

[tex] = \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30[/tex]

[tex] = \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30[/tex]

[tex]\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}[/tex]

prove that 1 + sin a + cos 2A upon 1 + Sin A minus Cos 2A = 2 cot a prudent

Answers

Answer:

LHS×0=RHS×0

0=0

hence,proved

What is the greatest common factor of 35 and 45?

Answers

GCF OF 35 AND 45 IS 5

Find X in the triangle. Round answer to the nearest TENTH of a degree (GIVING BRAINLEST TO BEST ANSWER :D ) ​

Answers

Answer:

x = 59,53445508

Tan(x) = 34/20

Step-by-step explanation:

Answer:

30÷20 degree x=n

Step-by-step explanation:

Mark me as brainliest

Calculate the sample standard deviation and sample variance for the following frequency distribution of hourly wages for a sample of pharmacy assistants.

Class Frequency
8.26 20
10.01-11.75 38
11.76 36
13.51-15.25 25
15.26-17.00 27

Sample Variance: ___________
Sample Standard Deviation: _________

Answers

Answer:

(a) The sample variance is 16.51

(a) The sample standard deviation is 4.06

Step-by-step explanation:

Given

[tex]\begin{array}{cc}{Class} & {Frequency} & 8.26 - 10.00 & 20 &10.01-11.75 & 38 &11.76 - 13.50& 36 & 13.51-15.25 &25&15.26-17.00 &27 &\ \end{array}[/tex]

Solving (a); The sample variance.

First, calculate the class midpoints.

This is the mean of the intervals.

i.e.

[tex]x_1 = \frac{8.26+10.00}{2} = \frac{18.26}{2} = 9.13[/tex]

[tex]x_2 = \frac{10.01+11.75}{2} = \frac{21.76}{2} = 10.88[/tex]

[tex]x_3 = \frac{11.76+13.50}{2} = \frac{25.26}{2} = 12.63[/tex]

[tex]x_4 = \frac{13.51+15.25}{2} = \frac{28.76}{2} = 14.38[/tex]

[tex]x_5 = \frac{15.26+17.00}{2} = \frac{32.26}{2} = 16.13[/tex]

So, the table becomes:

[tex]\begin{array}{ccc}{Class} & {Frequency} & {x} & 8.26 - 10.00 & 20&9.13 &10.01-11.75 & 38 &10.88&11.76 - 13.50& 36 &12.63& 13.51-15.25 &25&14.38&15.26-17.00 &27 &16.13\ \end{array}[/tex]

Next, calculate the mean

[tex]\bar x = \frac{\sum fx}{\sum f}[/tex]

[tex]\bar x = \frac{20*9.13 + 38 * 10.88+36*12.63+25*14.38+27*16.13}{20+38+36+25+27}[/tex]

[tex]\bar x = \frac{1845.73}{146}[/tex]

[tex]\bar x = 12.64[/tex]

Next, the sample variance is:

[tex]\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}[/tex]

So, we have:

[tex]\sigma^2 = \frac{20*(9.13-12.63)^2 + 38 * (10.88-12.63)^2 +...........+27 * (16.13 -12.63)^2}{20+38+36+25+27-1}[/tex]

[tex]\sigma^2 = \frac{2393.6875}{145}[/tex]

[tex]\sigma^2 = 16.51[/tex]

The sample standard deviation is:

[tex]\sigma = \sqrt{\sigma^2}[/tex]

[tex]\sigma = \sqrt{16.51}[/tex]

[tex]\sigma = 4.06[/tex]

247 1372 as a number​

Answers

Answer:

Do you mean in words?

Step-by-step explanation:

then it is

Two million,four hundred and seventy one thousand,three hundred and seventy two.

A sports trainer has monthly costs of $80 for phone service and $40 for his website and advertising. In addition he pays a $15 fee to the gym for each session in which he works with a client.

Required:
a. Write a function representing the average cost
b. Find the number of sessions the trainer needs if he wants the average cost to drop below $16 per session.

Answers

Answer:

Step-by-step explanation:

The average cost for the training session provided he is a sports trainer can be computed as follows:

Let's assume that;

average cost = C(x)

the no. of session = x

Then:

[tex]C(x) = \dfrac{\text{Total cost}}{\text{no. \ of sessions}}[/tex]

[tex]C(x) = \dfrac{\text{80 + 40 + 15x}}{\text{x}}[/tex]

[tex]C(x) = \dfrac{\text{120+ 15x}}{\text{x}}[/tex]

Now, suppose the trainer wants the average cost C(x) to drop below $16;

Then, we have the following function:

[tex]\dfrac{120+15x}{x}\leq C(x)[/tex]

[tex]\dfrac{120+15x}{x}\leq16[/tex]

By cross multiply:

120 + 15x ≤ 16x

120 ≤ 16x - 15x

120 ≤ x

Therefore, the required no. of session, if the average cost should drop below $16, is 120.

Following are the solution to the required points:

Assuming that he's also a sports trainer, the typical cost of such a training program is just as follows:

        Total cost = C(x)

        Total session = x  

Then:

[tex]\to C(x)=\frac{\text{Total cost}}{\text{Total sessions}}=\frac{80+40+15x}{x}= \frac{120+15x}{x}[/tex]

Assume the trainer desires that the average cost C(x) be less than $16. So function is therefore available:

[tex]\to \frac{120+15x}{x} \leq C(x)\\\\\to \frac{120+15x}{x} \leq 16\\\\[/tex]

By cross multiply:

[tex]\to 120 + 15x \leq 16x\\\\\to 120 \leq 16x - 15x\\\\ \to 120 \leq x[/tex]

As a result, if the average cost drops below $16, the required number of sessions is 120.

Learn more:

brainly.com/question/24859268

Solve the simultaneous equations.
Show all your working.
3x + 4y = 14
5x+2y=21

Answers

Step-by-step explanation:

hear is your answer in attachment

Use the formula v = IR for current flowing through a resistor, where V is the voltage in volts, I is current in amps, and R is resistance in ohms. Find the current through a resistor with resistance 15 ohms if the voltage across it is 3 volts.

Answers

Answer:

0.2 amps

Step-by-step explanation:

Given data

The formula V=IR is the formula for ohms law

Which state that  the voltage is directly proportional to the current and the resistance in an electric circuit

Now

R= 15 ohms

V= 3volts

V= IR

3= I*15

I= 3/15

I= 0.2 amps

Hence he current flowing is 0.2 amps

Here is some record keeping from a coffee shop about their paper cups. Cups are delivered 2,000 at a time. day change Monday +2000 Tuesday -125 Wednesday -127 Thursday +1719 Friday -356 Saturday -782 Sunday 0 2. How many paper cups are left at the end of the week?


Do only number 2 ​

Answers

Answer:

2329

Step-by-step explanation:

2000 - 125 - 127 + 1719 - 356 - 782 = 2329

Help me calculate Lim for this lesson

Answers

Answer:

I'm acutally not too sure on this but give me a moment to solve this

Step-by-step explanation:

A die is rolled twice. What is the probability of showing a 3 on the first roll and an even number on the second roll?

Answers

Answer:

1/6 * 1/2 = 1/12

Step-by-step explanation:

1 number on a 6 sided die is 1 out of 6 (1/6) and an even number (2,4,6) on a 6 sided die is 3/6 or 1/2 (always simplify when multiplying fractions)

so 1 times 1 = 1 and 6 times 2 = 12 making it 1/12

Find the volume of a sphere with a radius of 9 inches. Use 3.14 for π
.

Round your answer to the nearest hundredth.

Answers

Answer:

The volume of the sphere is 3053. 63 inches.

Step-by-step explanation:

Formula for volume of a sphere is : V = 4 /3 · π · r³

V = 4/3 · π · 9³

V ≈ 3053. 63

The volume of the sphere is 3053. 63 inches.

Graph the line with y-intercept-2 and slope -3/5 .

Answers

Answer:

MATH

Dior H. asked • 01/13/21

graph the line with the slope 1/2 and y-intercept -2

i need help badly i am crying because its hard

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1 Expert Answer

By:

Raymond B. answered • 01/14/21

TUTOR 5 (1)

Math, microeconomics or criminal justice

ABOUT THIS TUTOR ›

y=mx + b is the standard slope intercept form for a line

m=1/2, b =-2

y=(1/2)x -2. y-intercept is -2 or the point (0,-2)

x intercept is found by setting y=0 and solving for x

0=(1/2)x - 2

(1/2)x = 2

x = 4 = the x intercept or (4,0)

plot the 2 intercepts (0,-2) and (4,0)

(4,0) is on the x axis, 4 units to the right of the origin (0,0)

(0,-2) is on the y axis, 2 units below the origin

once you plot those two points, draw a straight line connecting them. That's the graph of the line

what is a 36% markup to $150 dallors

Answers

Answer:

Markup amount: $54

New price with markup: $204

Step-by-step explanation:

36% markup to $150

We can find the amount of markup by finding 36% of 150.

36% of $150

Write 36% as a decimal and multiply it by the price

0.36(150) = $54

The amount of markup (36%) is equal to $54

When this is added to the original price, the new price is $150 + $54 = $204

Let me know if you have any questions!

For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains below a critical value y0 (a deficit), preceded by and followed by periods in which the supply exceeds this critical value (a surplus). An article proposes a geometric distribution with p = 0.365 for this random variable. (Round your answers to three decimal places.)

a. What is the probability that a drought lasts at most 3 intervals?
b. What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

Answers

Solution :

a). P(X = x)

     =   [tex]$p(1-p)^x$[/tex]  for x = 0, 1, 2, ....

   P(x ≤ 3) = 0.837

b). Expectation = [tex]$\frac{(1-p)}{p}$[/tex]

                        = 1.7397

  Variance = [tex]$\frac{(1-p)}{p^2}$[/tex]

                 = 4.7663726

  Standard deviation = 2.1832

 Therefore, mean + standard deviation

                  = 1.7397 + 2.1832

                  = 3.9229

[tex]$P(x > 3.9229) = 0.1626$[/tex]

So the required P = 2 x 0.1626

                             = 0.325

The hourly earnings (in dollars) for a sample of 25 railroad equipment manufacturers are:15.60 18.7514.60 15.8014.3513.90 17.5017.5513.8014.20 19.05 15.35 15.20 19.45 15.95 16.50 16.30 15.2515.05 19.10 15.20 16.22 17.75 18.40 15.25Find the median and the mode(s)(if they exist) of the data. What is the interquartile range

Answers

Answer:

[tex]Median = 15.80[/tex]

[tex]Mode = 15.20\ \&\ 15.25[/tex]

[tex]IQR = 2.35[/tex]

Step-by-step explanation:

Given

[tex]15.60,\ 18.75,\ 14.60,\ 15.80,\ 14.35,[/tex]

[tex]13.90,\ 17.50,\ 17.55,\ 13.80,\ 14.20,[/tex]

[tex]19.05,\ 15.35,\ 15.20,\ 19.45,\ 15.95,[/tex]

[tex]16.50,\ 16.30,\ 15.25,\ 15.05,\ 19.10,[/tex]

[tex]15.20,\ 16.22,\ 17.75,\ 18.40,\ 15.25.[/tex]

Solving (a): The median and the mode

First, we sort the data.

[tex]13.80,\ 13.90,\ 14.20,\ 14.35,\ 14.60,\ 15.05,\ 15.20,\ 15.20,\ 15.25,\ 15.25,[/tex]

[tex]15.35,\ 15.60,\ 15.80,\ 15.95,\ 16.22,\ 16.30,\ 16.50,\ 17.50,\ 17.55,\ 17.75,[/tex]

[tex]18.40,\ 18.75,\ 19.05,\ 19.10,\ 19.45.[/tex]

The median position is:

[tex]Median = \frac{n + 1}{2}th[/tex]

[tex]Median = \frac{25 + 1}{2}[/tex]

[tex]Median = \frac{26}{2}[/tex]

[tex]Median = 13th[/tex]

The 13th item is: 15.80

Hence:

[tex]Median = 15.80[/tex]

The modes are:

[tex]Mode = 15.20\ \&\ 15.25[/tex] --- they both have frequency of 2 while others occur once

Solving (b): The interquartile range

This is calculated as:

[tex]IQR = Q_3 - Q_1[/tex]

Since the median is at the 13th position, Q1 is:

[tex]Q_1 = \frac{1 + 13}{2}th[/tex]

[tex]Q_1 = \frac{14}{2}th[/tex]

[tex]Q_1 = 7th[/tex]

The 7th item is: 15.20

[tex]Q_1 = 15.20[/tex]

Similarly, Q3 is:

[tex]Q_3 = \frac{13+n}{2}[/tex]

[tex]Q_3 = \frac{13+25}{2}[/tex]

[tex]Q_3 = \frac{38}{2}[/tex]

[tex]Q_3 = 19th[/tex]

The 7th item is: 17.55

So:

[tex]Q_3 = 17.55[/tex]

Hence,

[tex]IQR = 17.55 - 15.20[/tex]

[tex]IQR = 2.35[/tex]

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